Chemistry College

When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potassium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the product mixture. However, when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the product mixture. What percent of 2-methyl-1-butene would be in the mixture if potassium propoxide were the base

Answers

Answer 1

Answer:

The percentage mixture of 2-methyl-1-butene would be in between the 45% and 70%.

Explanation:

Potassium prop oxide is the intermediate base as compared to the potassium hydroxide which is less bulky strong base and potassium tert-butoxide which is bulky base. Bulky base can minimize the substitution reaction by causing hinders the approach of carbon attack and KOH is the strong base which less effective in minimizing the substitution reaction.

Related Questions

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . What is the theoretical yield of sodium sulfate formed from the reaction of of sulfuric acid and of sodium hydroxide

Answers

Answer:

71g (assuming experimental data)

Explanation:

The balanced equation for this reaction:

[tex]H_{2} SO_{4}(aq)[/tex] + [tex]2NaOH (s)[/tex] → [tex]Na_{2}SO_{4} (l)[/tex] + [tex]2H_{2} O (l)[/tex]

Molar mass of H2SO4 = 98.1 g/mol

molar mass of NaOH = 40g/mol

Molar mass of Na2SO4 = 142.04g/mol

⇒ 1 mole or 98.1g of H2SO4 will yield 1 ole of NaSO4; alternately, 2 moles or 49 ×2 = 80g of NaOH produces 1 mole of NaSO4.

Therefore, limiting reactant is NaOH.

Assuming actual experiment is 20g of NaOH,

1 mole - 40g

x moles - 20g = [tex]\frac{20}{40}[/tex] = 0.5 moles

⇒1 mole of Na2SO4 - 142.04g

∴ 0.5 moles = 142.04 × 0.5

= 71.02g

Answer:

71 grams

Explanation:

Match each ion with the noble guess whose electron configuration it shares

Answers

Answer:

These should be matched to either: Helium, Neon, or Argon. Na+. Be2+. Ca2+. Cl-.

Explanation:

According to the electronic configuration, Li[tex]^+[/tex] and Be[tex]^2+[/tex] have electronic configuration similar to helium while N[tex]^3-[/tex],Na[tex]^2+[/tex],O[tex]^2-[/tex] have electronic configuration similar to neon and rest have electronic configuration similar to argon.

What is electronic configuration?

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

Learn more about electronic configuration,here:

https://brainly.com/question/13497372

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