What is x^3-2x^2-4x-1 divided by X+1?

Answer:

A

Step-by-step explanation:

64

Answer:

cos B = 0.4706

Step-by-step explanation:

The cosine of an angle in a right-angled triangle is the ratio of its adjacent side and the hypotenuse, so:

 [tex]cos B = \frac{adjacent}{hypotenuse}\\\\cos B = \frac{8}{17} \\\\cos B = 0.4706[/tex]

Option B

The correct answer is option C which is 3.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The given expression will be solved as follows:-

E = 3( x² +6 -3x)- ( 2x² - 8 ) +3(x² + 4x )

E = 3x²+18-9x-2x²+8+3x²+12x

E= 4x² +3x+8

We can see the coefficient of x is 3.

Therefore the correct answer is option C which is 3.

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The statements that would complete the proof where ∠2 ≅ ∠7 by the transitive property are:

∠2 ≅ ∠3

∠3 ≅ ∠7

The transitive property states that if x = y, and y = z, then x = z.

From the image given below, we have:

∠2 ≅ ∠3 because they are vertical angles which must be congruent.

∠3 ≅ ∠7 because corresponding angles are congruent.

Applying the transitive property, we can state that: ∠2 ≅ ∠7.

Therefore, the statements that would complete the proof are:

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Step-by-step explanation:

I have done it go and check it once

Answer:

0.6

Step-by-step explanation:

You can literally put 3/5 into a calculator and you would get the answer 0.6, so I don't know what else to say. Whoever asked you this question, give them the above answer ask them what they were on, because the person was probably way high on LSD.

Answer:

1/5

Step-by-step explanation:

2 units divided into 5 marks each = 10 marks

2/10 = 1/5 unit each mark

Using an exponential function, it is found that the substance is 7,535 years old.

The function is given by:

[tex]A(t) = A(0)e^{-kt}[/tex]

In which:

Carbon-14 has a half life of 5700 years, that is, A(5700) = 0.5A(0), hence we use this to find k.

[tex]A(t) = A(0)e^{-kt}[/tex]

[tex]0.5A(0) = A(0)e^{-5700k}[/tex]

[tex]e^{-5700k} = 0.5[/tex]

[tex]\ln{e^{-5700k}} = \ln{0.5}[/tex]

[tex]k = -\frac{\ln{0.5}}{5700}[/tex]

k = 0.00012160476

Hence:

[tex]A(t) = A(0)e^{-0.00012160476t}[/tex]

It was 40% of the amount when A(t) = 0.4A(0), hence we solve for t.

[tex]A(t) = A(0)e^{-0.00012160476t}[/tex]

[tex]0.4A(0) = A(0)e^{-0.00012160476t}[/tex]

[tex]\ln{e^{-0.00012160476t}} = \ln{0.4}[/tex]

[tex]t = -\frac{\ln{0.4}}{0.00012160476}[/tex]

t = 7535.

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Answer:

as we know that in cricket there is use of tan while doing bating

Answer:

Step-by-step explanation:

Write 5.54 million in ordinary form

5.54 * [tex]10^{6}[/tex] =

5540000

or

5.54 * 1000000 =

5540000

A consistent and independent system of equations describes the given system of equations.

The consistent and independent system of equations are given below.

A consistent equation is a system of linear equations that is consistently unbiased when it has precisely one solution. While this is the case, the graphs of the lines within the system move at exactly one point. In inconsistent, a system of linear equations is inconsistent if it has no solutions.

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Answer:

added in picture

Step-by-step explanation:

added in picture

Answer:

$71,744.53

Step-by-step explanation:

The earnings triple every day, so you can calculate them for the 15 days. For the total, you also have to add them up.

See the calculations in below picture.

Answer:

9/2 or 6/2

Step-by-step explanation:

The sum of nine should be amended by adding 6 + 2 +1 = 9

so when adding these numbers you will get the sum of 9

The missing words to complete the proof are respectively; Vertical Angles; Corresponding angles; Transitive Property

The image of the transversal line is attached.

1) We know that lines a and b are parallel and that line c is a transversal because that is given.

2) We can tell that angles 2 and 5 are congruent because vertical angles are congruent.

3) Angles 5 and 7 are congruent because corresponding angles by parallel lines cut by a transversal are congruent.

4) Therefore, angles 2 and 7 are congruent based on the transitive property.

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Answer: vertical, corresponding, and transitive property

Step-by-step explanation: I got the correct answer on Edge 2022. The answer is correct trust me! Proof is shown down below.

The function is shown to be positive throughout the whole range [-3, -2] in graph (B).

According to the question,

Looking at the graph, we can see that the graph B has positive y-values in the range [-3, -2].

Hence The function is shown to be positive throughout the whole range [-3, -2] in graph (B).

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Answer:

[tex]3x^3 + 4x^2 -3x + 2[/tex]

Step-by-step explanation:

The area of the swimming pool will be equal to [tex]length * width[/tex].

We know that the length is [tex]3x^2-2x+1[/tex] and the width is [tex]x+2[/tex].

Therefore we can substitute those into the equation:

[tex](3x^2-2x+1)(x+2)\\[/tex]

Then, we expand the brackets using a grid (attached).

After this, we collect like terms to find the final answer:

[tex]3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2[/tex]

Our final answer is: [tex]3x^3 + 4x^2 -3x + 2[/tex]

Answer:

4x82x929wjdjdejdjekke

[tex] \frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9 } \\ \frac{(x + 3 ) + (x + 2)}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ \frac{2x + 5}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ 2( {x}^{2} + 5x + 6) = (x + 9)(2x + 5) \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 5x + 18x + 45 \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 23x + 45 \\ 2 {x}^{2} - 2 {x}^{2} + 10x - 23x + 12 - 45 = 0 \\ - 13x - 33 = 0 \\ - 13x = 33 \\ x = \frac{33}{ - 13} \\ x = - 2.54[/tex]

Hope it helps

Please give brainliest

The unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

The question is incomplete.

The complete question is:

The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown. What is the greatest possible whole-number value of the congruent side lengths?

9 cm

10 cm

14 cm

15 cm

We have:

The longest side of an isosceles obtuse triangle measures 20 centimeters.

Let's assume the unknown side length is x:

In the isosceles obtuse triangle, two sides are congruent.

As we know the sum of the two sides in a triangle is greater than the third side length:

x + x > 20

2x > 20

x > 10

a² + b² < c²

14 will satisfy the above two inequaility.

Thus, the unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.

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[tex]\bullet\:{\boxed{\tt{\red{{Given :}}}}}[/tex]

• Length of the wooden box [tex](l)[/tex] = 80cm.

• Breadth of the wooden box [tex](b)[/tex] = 40cm.

• Height of the wooden box [tex](h)[/tex] = 20cm.

• Side of the square sheet paper = 40cm.

[tex]\bullet\:{\boxed{\tt{\red{{To : Find :}}}}}[/tex]

The number of sheets required.

[tex] \bullet\:{\boxed{\tt{\red{{Formula \: \: used :}}}}}[/tex]

[tex] \star{\underline{\boxed{{\sf{{{TSA}} = \underline{\underline{{\purple\sf 2(lb+bh+hl)}}}}}}}} \star[/tex]

[tex]\star{\underline{\boxed{{\sf{{{Area \: of \: square}} = \underline{\underline{{\purple{\sf side \times side }}}}}}}}}\star[/tex]

[tex]\star{\underline{\boxed{{\sf{{{Number \: of \: sheets \: required} = {{{\purple{\sf \dfrac{TSA}{area \: of \: one \: sheet}}}}}}}}}}} \star[/tex]

[tex] \bullet\:{\boxed{\tt{\red{{Concept :}}}}}[/tex]

As Quayleen wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. So for knowing the number of sheets required, we need two things one the TSA and Area of one sheet. Once, we will get the values we will divide them to get the answer. Let's Start !!

[tex] \bullet\:{\boxed{\tt{\red{{Solution :}}}}}[/tex]

As we know that ::

Total surface area of cuboid [tex]\large[ \sf 2(lb+bh + hl)][/tex]

Here,

✧ Length [tex](l)[/tex] = 80cm

✧ Breadth [tex](b)[/tex] = 40cm

✧ Height [tex](h)[/tex] = 20cm

Now, by putting the values we get :

[tex] \longrightarrow 2 \bigg[ (80 \times 40) + (40 \times 20) + (20 \times 80) \bigg]\sf {cm}^{2}[/tex]

[tex]\longrightarrow 2 \bigg[ (3200) + (800) + (1600) \bigg] \sf {cm}^{2} [/tex]

[tex] \longrightarrow 2 \bigg[ 5600 \bigg] \sf {cm}^{2} [/tex]

[tex] \longrightarrow 11200 \: \sf {cm}^{2}[/tex]

Hence, the total surface area of the wooden box is 11200 cm²

Now,

The area of each sheet of paper will be :

[tex] \sf \longrightarrow side \times side[/tex]

[tex]\sf \longrightarrow (40 \times 40) \: {cm}^{2} [/tex]

[tex]\longrightarrow \sf (1600) \: {cm}^{2} [/tex]

Hence, the area of each sheet of paper is 1600 cm²

Now,

For finding the number of sheets required

[tex] \longrightarrow \tt \dfrac{total \: surface \: area \: of \: box}{ area \: of \: one \: sheet} [/tex]

[tex]\longrightarrow \sf\dfrac{ \cancel{11200}_{7}}{\cancel{1600}_{1}}[/tex]

[tex] \longrightarrow \purple{ \sf 7}[/tex]

Therefore, Quayleen requires 7 sheets.

[tex]\rule{280pt}{2pt}[/tex]

C. y= |x-5|

you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.

Answer:

Domain: All real numbers

Range: y≤4

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

Part 1

Using the distance formula,

[tex]AB=\sqrt{(-2-1)^{2}+(2-7)^{2}}=\sqrt{34}\\\\BC=\sqrt{(-2-4)^{2}+(2-2)^{2}}=6\\\\AC=\sqrt{(1-4)^{2}+(7-2)^{2}}=\sqrt{34}[/tex]

So, the measure of the longest side is 6 units.

Part 2

Triangle ABD will have vertices A(1,7), B(-2, 2), and D(1,2).

We already know that [tex]AB=\sqrt{34}[/tex]

Using the distance formula,

[tex]AD=\sqrt{(1-1)^{2}+(7-2)^{2}}=5\\\\BD=\sqrt{(-2-1)^{2}+(2-2)^{2}}=3[/tex]

So, ABD is a scalene triangle.

Part 3

From part 2, we know that the length of side AD is 5 units.

Answer: [tex]x=65^{\circ}, y=65^{\circ}, z=65^{\circ}[/tex]

Step-by-step explanation:

All radii of a circle are congruent, so by the base angles theorem

Also, angles x and y are inscribed in the same arc, and they are thus congruent, meaning x = 65.

The true statements are:

The lines are given as:

Lines mn, pq, mp, mn, nq and pq

From the question, the lines are either parallel lines or perpendicular lines

As a general rule,

Parallel lines have equal slope

This means that:

Lines mn and pq have the same slope

Assume two perpendicular lines have slopes m and n.

The relationship between their slopes is:

m * n = -1

This means that:

The product of the slopes of perpendicular lines mn and mp is -1

Hence, the true statements are (a) and (c)

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Complete question

Line mn is parallel to line pq, mp is perpendicular to mn, and nq is perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer.

Pptions:

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

i hope this is helpful!........

Answer:

4/9 miles

Step-by-step explanation:

                 [tex]\sf Area = \dfrac{2}{3} \ square \ miles\\[/tex]

               [tex]\sf length = 1\dfrac{1}{2}=\dfrac{3}{2} \ miles[/tex]

[tex]\sf Width \ of \ rectangle = \dfrac{Area}{length}[/tex]

                             [tex]\sf = \dfrac{2}{3} \div \ \dfrac{3}{2}\\\\ =\dfrac{2}{3}*\dfrac{2}{3}\\\\ =\dfrac{4}{9} \ miles\\[/tex]

Use KCF method for faction division.

K- Keep the first fraction.

C - Change the division to multiplication.

F - Flip the second fraction.

Answer:

y = 90 -5/2 x

Step-by-step explanation:

The angle on the left equals x+3x+x = 5x

The angle on the right equals 2y

The two angles are same side interior angles which are supplementary because the lines are parallel

5x+2y = 180

Solving for y

2y = 180-5x

Divide by 2

2y/2 = 180/2 -5x/2

y = 90 -5/2 x

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

The two lines are parallel, henceforth we can apply Angle pair rules.

[tex]\qquad \tt \rightarrow \:(x + 3x + x) + 2y = 180[/tex]

[ Co - interior angles ]

[tex]\qquad \tt \rightarrow \:5x + 2y = 180[/tex]

[tex]\qquad \tt \rightarrow \:2y = 180 - 5x[/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{180 - 5x}{2} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{180 }{2} - \cfrac{5x}{2} [/tex]

[tex]\qquad \tt \rightarrow \:y = 90 \degree - \cfrac{5x}{2} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞