What is the work done by a force equivalent to the weight of 100kg that moves an object 200km in 7.0min?
Please guys can somebody helps me :(

Answers

Answer 1

The work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min would be 196000 kJ.

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force ×  Displacement

As given in the problem we have to calculate the work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min.

The weight of the 100 kg = 100 × 9.8

                                          = 980 N

The work done = 980 × 200 × 1000

                          = 196000000

                          = 196000 kJ

Thus, the work done by a force equivalent to the weight of 100 kg that moves an object 200 km in 7.0 min would be 196000 kJ.

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Related Questions

Una pelota cae con una energía de 1 J y bota al llegar al suelo. Si tras el bote su energía es de 0,998 J, ¿podemos afirmar que la energía se ha destruido?

Answers

Answer:

The energy is not destroyed, the energy has been transformed into another kind of energy, in this case to heat with energy of 0,002 J

Explanation:

One of the fundamental principles of physics states that energy is neither created nor destroyed, it is only transformed.

In this case, when the ball with an energy of 1 J bounces on the ground, it loses an energy equivalent to 1-0.998 J = 0.002 J. This energy of 0.002 J is not destroyed in the process, but is transformed into another type of Energy. In this case, said energy has been converted to heat. A heat equivalent to 0.002 J of energy.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Translation to spanish

Uno de los principios fundamentales de la física afirma que la enegía no se crea ni se destruye, sólo se transforma.

En este caso, cuando la pelota con una energía de 1 J rebota en el suelo pierde una energía equivalente a 1-0,998 J = 0,002 J. Esta energía de 0,002 J no se destruye en el proceso, sino que se transforma en otro tipo de energía. En este caso dicha energía se ha convertido en calor. Un calor equivalente a 0,002 J de energía.

What is the kinetic energy of a 108 kg object that is moving with a speed of 11.1 m/s ?

Answers

Answer:

6,653.34 J

Explanation:

Kinetic energy can be found using the following formula.

[tex]KE=\frac{1}{2} mv^2[/tex]

where m is the mass in kilograms and v is the velocity in m/s.

The object is 108 kilograms and is moving at a speed of 11.1 m/s. Therefore, the mass is 108 kg and the velocity is 11.1 m/s.

m=108 kg

v=11.1 m/s

Substitute these values into the formula.

[tex]KE=\frac{1}{2}*108*11.1^2[/tex]

Evaluate the exponent first. 11.1^2 is the same as 11.1*1.11, which is equal to 123.21

[tex]KE=\frac{1}{2} *108*123.21[/tex]

Multiply 108 and 123.21

[tex]KE=\frac{1}{2}*13306.68[/tex]

Multiply 1/2 and 13306.68

[tex]KE=6653.34[/tex]

The kinetic energy of the object is 6,653.34 Joules (kg m2/s^2)

A 5.0 V battery contains 775 C of charge. How much electricity energy can it produce?

Answers

Answer:

3875J

Explanation:

Energy is defined as the power × time

And it's defined as

Power = IV - I- current and V- voltage

Now quantity of electricity; Q = I × t

Where I is current and t is time

Now Energy = I ×V×t = V× I×t = V× Q;

where Q is quantity of electricity 775C and V is 5.0volt

Hence 775 × (5) =3875J

4. A moped travels 20 kilometers in 30 minutes. Calculate its average speed in km/h?

Answers

Answer:

[tex] \boxed{Average \: speed = 40 km/h} [/tex]

Explanation:

Distance travelled = 20 km

Time taken = 30 min

= [tex] \frac{30}{60} [/tex] h

= [tex] \frac{1}{2} [/tex] h

[tex]Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{20}{ \frac{1}{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \div \frac{1}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40km/h[/tex]

Average speed = 40km/h

Which statement best describes the movement of particles when a wave travels through a medium?

Answers

Answer:

The particles of the medium just vibrate in place. Particles of the medium don’t actually travel along with the wave. Only the energy of the wave travels through the medium.

Explanation:

I NEED HELP ASAP
please please please​

Answers

Answer:

B AND D

HOPE ITS HELF FUL .........

ANSWER:
Options C) and D) are incorrect about balanced forces.
HOPE IT HELPS!!!
PLEASE MARK BRAINLIEST!!!!

An object started at
x = -22 meters and undergoes
a displacement of -10.4 meters.
What is its final position?
(Unit = m)

Answers

Answer:

According to me, I think this is the answer

Explanation:

initial position= -22 meters.

this indicates that object is in the negative direction as a negative sign is used to represent the location.

displacement is indicated as -10.4 meters. this is also in the negative direction.

initial + displacement= final

= -22 + (-10.4)

= -32.4 meters

this would be the final position, away from the origin.

displacement is a vector quantity; both magnitude and direction matter.

What is "In an isolated system two cars, each with a mass of 2,000 kg, collide. Car 1 is initially at rest , while car 2 was moving at 20 m/s. what is their combined momentum after the collision?"

Answers

Answer:

Final velocity of the combining cars = 10m/s

combined momentum = 40000kgm/s

Explanation:

Given the following :

Mass of both colliding cars = 2000kg

Initial Velocity of car 1 (U1) = 0

Initial Velocity of car 2 (U2) = 20m/s

Combuned momentum after collision =?

This is an inelastic collision which is calculated thus :

M1U1 + M2U2 = M1V + M2V

M1U1 + M2U2 = (M1 + M2) V

Where V = "final Velocity of the colliding bodies

2000 × 0 + 2000 × 20 = (2000 + 2000) V

0 + 40000 = 4000V

V = 40000 / 4000

V = 10m/s

Therefore combined momentum = (M1 + M2) V

(2000 + 2000) 10

4000(10) = 40000kgm/s

What is the main reason for using a data table for collecting data?
If you put a question in the answer box or anything that isn't a answer in the answer box I will report you!

Answers

Answer:

to make calculation more easy to get

Explanation:

if you are using chart or calculate Thermodynamic problems you will not never solve this problem with out using data table for thermodynamic

Please help me out
1. A 5.0 V battery contains 775 C of charge. How much electricity energy can it produce?
2. 200 C of charge passes through a circuit in 20 minutes. What is the current?
3. A battery can produce 337 joules of energy for every 9.5 coulombs of charge. What is its voltage?

Answers

Answer:

1.3875 Joules. 2. 0.17A 3. 35.47volts

Explanation:

1. Energy = Q × V = 5 × 775 = 3875 Joules.

Q is quantity of electricity in Columbs

V is Voltage in volts

2. From Q = I × t

Q is quantity of electricity in Columbs

T is time taken

I is current

Now we define I as the quantity of electricity in 1 sec; hence;

200= I × 20× 60 [ 20minutes converted to seconds ]

I = 200/ 20× 60.= 200/1200=0.1667

= 0.17A( to the nearest hundredth)

3.v = E/ Q ( from equation in question 1)

V = 337/9.5 = 35.47volts

Convert-
a) 42° to kelvin
b) 56k to °C
c) 37° to °F
d) 32° to °C

Answers

Answer:

k is celcius/farhneit +273

c is 5/9 f-32

f is 9/5 (c+32)

Answer:

A. 318.15

B.-217.15

C. 132.8

D. 0

Explanation:

K − 273.15 = °C/°F

°C/ °F + 273.15 = K

(°C × 9/5) + 32 = °F

(°F − 32) × 5/9 = 0°C

Which statement describes the energy involved in diffusion?

Answers

hope that helps

Explanation:  Diffusion requires energy only to move material in through the cell membrane. Diffusion does not require energy in any situation. Diffusion requires energy only to move material out through the cell membrane.

Answer:

The answer is B >:3

Explanation:

The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give the values r = 32700 ft, r¨ = 85 ft/sec2, and θ˙ = 0.019 rad/sec. Calculate the magnitudes of the velocity and acceleration of the rocket at this position.

Answers

Answer:

velocity = 1527.52 ft/s

Acceleration = 80.13 ft/s²

Explanation:

We are given;

Radius of rotation; r = 32,700 ft

Radial acceleration; a_r = r¨ = 85 ft/s²

Angular velocity; ω = θ˙˙ = 0.019 rad/s

Also, angle θ reaches 66°

So, velocity of the rocket for the given position will be;

v = rθ˙˙/cos θ

so, v = 32700 × 0.019/ cos 66

v = 1527.52 ft/s

Acceleration is given by the formula ;

a = a_r/sinθ

For the given position,

a_r = r¨ - r(θ˙˙)²

Thus,

a = (r¨ - r(θ˙˙)²)/sinθ

Plugging in the relevant values, we obtain;

a = (85 - 32700(0.019)²)/sin66

a = (85 - 11.8047)/0.9135

a = 80.13 ft/s²

The magnitude of the linear velocity of the rocket at the given position is 1,667.2 ft/s.

The magnitude of the acceleration of the rocket at the given position is 90.73 ft/s².

The given parameters;

angular distance, θ = 66⁰radius of the path, r = 32700 ftcentripetal acceleration, ac = 85 ft/s²initial angular velocity, ωi = 0.019 rad/s

The linear velocity and final angular velocity of the rocket is calculated as follows;

[tex]a_c = \frac{v^2}{r} \\\\v^2 = a_c \times r\\\\v = \sqrt{a_c r} \\\\v = \sqrt{85 \times 32700}\\\\v = 1667.2 \ ft/s\\\\\omega_f = \frac{v}{r} = \frac{1667.2}{32700} = 0.051 \ rad/s[/tex]

The radial acceleration of the rocket is calculated as follows;

[tex]\omega_f^2 = \omega_i^2 + 2\alpha _r \theta\\\\(0.051)^2 = (0.019)^2 + 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r)\\\\(0.051)^2 - (0.019)^2 = 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r) \\\\0.00224 = 2.304\alpha _r\\\\\alpha _r = \frac{0.00224 }{ 2.304} \\\\\alpha _r = 0.00097 \ rad/s^2[/tex]

The tangential acceleration is calculated as follows;

[tex]a_t = \alpha_r \times r\\\\a_t = 0.00097 \times 32700\\\\a_t = 31.72 \ ft/s^2[/tex]

The resultant acceleration of the rocket is calculated as follows;

[tex]a = \sqrt{a_t^2 + a_c^2} \\\\a = \sqrt{31.72^2 \ + \ 85^2} \\\\a= 90.73 \ ft/s^2[/tex]

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At which of the following points does a roller coaster have the most potential energy? As it is going down a hill. At the top of the hill. As it is climbing a hill. At the bottom of the hill.

Answers

Answer:

At the top of the hill.

Explanation:

As the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases .

As it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum .

As it goes down the hill, K.E starts to increase and G.P.E decrease .

At the bottom of the hill, K.E reaches maximum and G.P.E becomes zero .

(Correct me it I am wrong)

At the top of the hill.

The following information should be considered:

In the case when the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases . When it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum . When it goes down the hill, K.E starts to increase and G.P.E decrease . When it is the bottom of the hill, K.E reaches maximum and G.P.E becomes zero.

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A 15cm long cube made of Oak and of side floats
in water 10.5 cm of its depth below the surface

and with its sides vertical what is the density
of cube. of Water = 1000 kg m-3 ans 7ooR g/m 3
density​

Answers

Answer: 700 kg/m³

Explanation: Check the solutions , 3 ways :-

The density of cube  will be 700 kg/m^3.

What is the density of cube.

Length of cube(l) =15 cm =0.15m

Volume of cube ([tex]V_{c}[/tex]) = l^3=(0.15 m)^3

Volume of water displaced ([tex]V_{w}[/tex]) = Volume of cube inside water

[tex]V_{w}[/tex] =0.15*0.15*0.105 m^3

we know that,

Density of water ([tex]D_{w}[/tex]) =1000 kg/m^3

from law of floatation ,

Weight of floating body= Weight of displaced liquid

[tex]V_{c}[/tex][tex]D_{c}[/tex]g = [tex]V_{w}[/tex][tex]D_{w}[/tex]g

[tex]V_{c}[/tex][tex]D_{c}[/tex]=[tex]V_{w}[/tex][tex]D_{w}[/tex]

0.15*0.15*0.15*[tex]D_{c}[/tex]=0.15*0.15*0.105*1000

[tex]D_{c}[/tex]=0.105*1000/0.15

[tex]D_{c}[/tex] =700

Hence, The density of cube  will be 700 kg/m^3.

Learn more about problems on density

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how much work is done by a force of 20N while moving an object through distance 10 m of the force ​

Answers

Answer:

  200 J

Explanation:

Work = Force × Distance

Work = (20 N)(10 m) = 200 N·m = 200 J

200 joules of work are done by a force of 20 N over a distance of 10 m.

Jack plays floor hockey. He moves with a velocity of 7.5 m/s [East] for 2.25 seconds. What is his displacement during this time? show your work below.

Answers

Answer:

16.875 m [East]

Explanation:

In a velocity time displacement problems

displacement is given by

displacement of moving body = velocity of the that body  * time

displacement will be in the direction of velocity of body.

Given

velocity = 7.5 m/s [East]

time = 2.25 seconds

displacement = 7.5 m/s [East] *2.25 seconds

displacement = 16.875 m [East]

Thus, displacement of jack is 16.875 m [East].

which statement BEST compares the force of gravity on a school bus on a school day and a weekend? *

(A) The force would be lower on the school day than the weekend.
(B) The force would be higher on the school day than the weekend.
(C) The force would be different on the school day than the weekend.
(D) The force would stay the same on the school day and the weekend.

Answers

Answer:

(A) The force would be lower on the school day than the weekend.

Explanation:

In  a  school  day  the  bus  is  on  the  road  travelling  with  kids.  But  in  a  weekend  it  is  parked.  When  a  object  stays  still  that  means  the the  force  which  is  working  on  the  earth  by  the  bus  is  equal  to  the  force which  works  on  the  bus  by  the  earth. we  can  understand  it  clearly by,  Newton's second law of motion.  

This pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.  so  as  it  is  when  it  is  balanced  it  is  not  moving.

And  on  a  school  day  the  bus  is  moving  so  it  has  a  force  pulling  itself  forward .  so  it  means  that  the  force  which  the  bus  has  is  greater  than  the  gravitational  force.

Which change will increase the speed of a sound wave traveling in a solid aluminum rod?

Answers

Yessss sirrr it willllll

Answer:

Increasing the temperature of the rod

Explanation:

When you push with a horizontal 15-N force on a book that slides at constant
velocity, the force of friction on the book is
A.Slightly more than 15 N
B.0N
C.Slightly less than 15 N
D.15 N

Answers

Answer:

f = 15 N

Explanation:

It is given that, when you push with a horizontal 15-N force on a book that slides at constant  velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.

The balloon contain no gas initially.When it is connected to the cylinder gas enters the balloon the pressure in the cylinder decreases.Explain why the molecules inside the cylinder exerts a large pressure initially

Answers

Answer:

17

Explanation:

121354

Rutherford predicted that an atom has a dense core called a(n) __________

Answers

The answer is nucleus !

Rutherford predicted that an atom has a dense core called a nucleus.

What is nucleus of atoms?

Ernest Rutherford discovered in 1911 that every atom has a nucleus in its center. Electrically charged protons and electrically neutral neutrons make up atomic nuclei. The strongest fundamental force known to science, often known as the strong force, holds these things together.

The nucleus normally comprises more than 99.9% of the atom's mass but occupies far less than.01% of its volume. The negatively charged electrons that surround a substance's nucleus determine its chemical makeup. In most cases, the number of protons in the nucleus corresponds to the number of electrons.

Some nuclei are unstable and can decay radioactively, releasing photons (gamma decay), electrons or positrons (beta decay), helium nuclei (alpha decay), or a combination of these. Eventually, these unstable nuclei reach a stable state.

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A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.

Answers

Answer:

Mass, m = 0.49 kg

Explanation:

It is given that,

A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.

We need to find the mass of the ice.

On a sloping surface, the force with which it strikes is given by :

[tex]F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg[/tex]

So, the mass of the ice block is 0.49 kg.

PLEASE HELP An object is thrown upward with an initial velocity of 32.1 m/s. What is its velocity in 4.0 s? (use g = 9.81 m/s2). Please include step by step process. -7.14 11.2 7.14 -4.6

Answers

Answer:

-7.14

Explanation:

According to equation of motion

v = u + at

where

v is the final velocity at any time t

u is the initial velocity

a is the acceleration

and t is the time

___________________________________________

Given

An object is thrown upward it means

its initial velocity is in upward direction

but acceleration due to gravity is in downward direction which will cause to decrease the velocity of object.

Intial velocity u = 31.1 m/s

final velocity v at 4 second we have to find.

t = 4 second

a = g = 9.81 m/s2 (it is acting in opposite direction of motion hence its sign will be negative ).

Thus

a = -  9.81 m/s2

using the above values in v = u + at

v = 32.1 - 9.81*4

v = 32.1 - 39.24

v = -7.14

Thus, correct option is -7.14.

A bowling ball collides with a tennis ball. Which object has the larger impact force on the other considering that they have the same acceleration? Why?
This is for an exam could you please answer fast

Answers

Answer:

The tennis ball experiences a larger impact force due to its smaller mass.

Explanation:

Considering that they have the same acceleration, and F = ma where F is force and m = mass, the object with the smaller mass has a greater impact force on it.

This is because since force F = ma and a = constant, the object with a larger mass (the bowling ball)has a larger impact force with which it acts on the object with the smaller mass (the tennis ball). So, the tennis ball experiences a larger impact force due to its smaller mass.

60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop​

Answers

Answer:

[tex]0.25\ cm^3[/tex]

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

[tex]= \frac{Final\ readings - first\ readings}{number\ of\ drops}[/tex]

[tex]= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}[/tex]

[tex]= 0.25\ cm^3[/tex]

Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

Answer:

0.25\ cm^30.25 cm

3

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

= \frac{Final\ readings - first\ readings}{number\ of\ drops}=

number of drops

Final readings−first readings

= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}=

60 drops

43 cm

3

−28 cm

3

= 0.25\ cm^3=0.25 cm

3

which household items can combust

Answers

Answer:

Explanation:

Rubbing Alcohol

Nail polish and nail polish remover

Linseed oil

Aerosol cans

Non-dairy creamer

Gasoline, turpentine, and paint thinner

Hand sanitizer

Flour

Oranges

Thermal insulators have _____.

A. high specific heat
B. high kinetic energy
C. lots of air pockets
D. low latent heat
E. strong molecular bonds​

Answers

Answer:

The correct answer to the following question will be Option A (High specific heat).

Explanation:

A thermal or heat insulator has been used to help avoid heat from travelling from one location to the another.

Specific heat seems to be important unless you consider whether the temperature including its insulator becomes evolving. Whether it has a high specific heat, it will take more energy just to increase the temperature, as well as it can also allow somewhat when it happens to come to insulating material, and therefore heat transaction or energy transactions are often influenced by a temperature gradient.

Other given choices are not related to the given scenario. So that Option A seems to be the right answer.

What are the materials necessary to create an electromagnet?
A) power source, metallic core, and electrical conductor

B) metallic core and power source only

C)metallic core magnet, and power source

D)electrical conductor and power source only​

Answers

Answer:

A

Explanation:

Electromagnet: It is a temporary magnet. It consists of wrapping coils around iron core and the power source. When the current passes through the coils around the iron core then it will get magnetized. The domains of the electromagnet gets aligned.

As long as the current passes through it, it will get magnetized. It will loose its magnetism easily when the power is switched off.

In the electromagnet, the strength of the magnetism can be increased or decreased. The poles of the electromagnet are not fixed.

I think answer is b. Please give me brainlest I hope this helps let me know if it’s correct or not thanks I appreciate it

quantities that are pure numbers​

Answers

Answer:

All pure numbers are dimensionless quantities, for example 1, i, π, e, and φ. Units of number such as the dozen, gross, googol, and Avogadro's number may also be considered dimensionless

Explanation:

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