Answer:
D
Explanation:
A growing body of scientific evidence shows that the felling of tropical forests creates optimal conditions for the spread of mosquito-borne scourges, including malaria and dengue. Primates and other animals are also spreading disease from cleared forests to people.
Q1. Consider respiration, one of the most common chemical reactions on earth occur according
to the reaction:
C6H1206 +602 = 6CO2 + 6H2O + energy
What mass of CO2 forms in the reaction of 25g of glucose with 40g of oxygen?
Answer: First we need to know how many moles of each reactant there are.
C6H12O6 : 25g/180.06g/mol=0.1388mol
O2: 40g/32g/mol=1.25mol
The equation tells us we need 6 moles of O2 for every 1 mole of Glucose.
6 x 0.1388 = 0.8328
So, we have more O2 then needed – it is in excess.
Glucose is the limiting reagent – we use this for the calculation.
The equation tells us we make 6 moles of CO2 for every 1 mole of Glucose
So, we make 0,8328 moles of Carbon Dioxide
Explanation:
Question 2
The volume of a gas-filled balloon is 20.0 L at 60 atm pressure. What volume in liters will the balloon have at 30 atm?
Question 3
8.00 L of gas at standard temperature and pressure (STP) is compressed to 3 L. What is the new pressure of the gas in atm?
Question 4
If a tennis ball has a pressure of 200 atm at a temperature of 27oC, what pressure in atm will the tennis ball have if the temperature of the gas increased to 77oC?
Question 5
Exactly 5.00 L of air at -23oC is warmed to 27o What is the new volume in liters if the pressure remains constant?
Question 6
The temperature inside my refrigerator is about 40 If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon in liters when it is fully cooled by my refrigerator?
Question 7
Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas in liters?
Question 8
Today, I forgot my soda in the trunk of my car. The initial pressure is 3 atm and it was a cool morning, at 15o By the afternoon, however, the temperature rose to 25oC. What is the pressure in atm inside the can?
please help me, im failing all my classes and really need some help with this. if i could give more than 100 i would
These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:
PV = nRT
where R is the universal gas constant.
The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.
Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.
Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.
Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.
Depending on what we're given and instructed to find in each question, we can figure out which law to use.
---
Question 2:
We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.
V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.
So, at 30 atm, the balloon will have a volume of 40.0 L.
---
Question 3:
This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.
P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.
So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).
---
Question 4:
Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.
P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.
So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.
---
Question 5:
This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.
---
Question 6:
Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.
V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.
So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.
---
Question 7:
This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.
The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).
---
Question 8:
We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.
P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.
So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.
1) If a gas occupies 2.60 liters at a pressure of 1.00 atm, what will be its volume at a
pressure of 3.50 atm?
Use Boyle's Law: P₁V₁ = P₂V₂. Since pressure and volume are inversely related and we're increasing the pressure, we should expect the new volume to be less than 2.60 liters.
Here, P₁ = 1.00 atm, V₁ = 2.60 liters, and P₂ = 3.50 atm; we want to find the new volume, V₂, at P₂. We can modify the equation to solve for V₂:
V₂ = P₁V₁/P₂ = (1.00 atm)(2.60 L)/(3.50 L) = 0.714 L
So the volume of the gas at a pressure of 3.50 atm will be 0.743 L.
a solution of KCl in water has a concentration of 0.243 M. The solution has a volume of 0.580 L. How many grams of KCl are present in the solution?
Answer:
10.5 g
Explanation:
Step 1: Given data
Molar concentration of the solution (C): 0.243 MVolume of solution (V): 0.580 LStep 2: Calculate the moles of solute (n)
Molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
n = M × V
n = 0.243 mol/L × 0.580 L = 0.141 mol
Step 3: Calculate the mass corresponding to 0.141 moles of KCl
The molar mass of KCl is 74.55 g/mol.
0.141 mol × 74.55 g/mol = 10.5 g
The volume of a gas-filled balloon is 20.0 L at 60 atm pressure. What volume in liters will the balloon have at 30 atm?
Answer:
40 litres
Explanation:
using Boyle's law V1P1=V2P2
V1=20 l
P1= 60atm
P2= 30 atm V2=?
substituting we will have that
20×60=V2×30
V2={20×60}/30
V2=40 l
What volume would 75.0g of oxygen gas occupy
Answer:
Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.
HELP PLZ
Carbon readily makes these bonds with other elements, primarily..?
Explanation:
Carbon has the ability to form long chains of carbon atoms as well as ringed compounds by continuously bonding to itself. This covalent bonds may be single, double, or triple. Carbon forms covalent bonds easily with other elements, especially hydrogen, oxygen, nitrogen, halogens, and a variety of nonmetals.
6. A box measures 11.25 inches in length, 8.1 inches in width and 6.85 inches in height. What is the
volume of the box?
Answer:
I'd say 624.2^3 inches.
Explanation:
Quinine in a 1.664-g antimalarial tablet was dissolved in sufficient 0.10 M to give 500 mL of solution. A 15.00-mL aliquot was then diluted to 100.0 mL with the acid. The fluorescence intensity for the diluted sample at 347.5 nm provided a reading of 327 on an arbitrary scale. A standard 100 ppm quinine solution registered 180 when measured under conditions identical to those for the diluted sample. Calculate the mass of quinine in milligrams in the tablet.
Answer:
605.6mg of quinine
Explanation:
Based on Lambert-Beer's law, the intensity of an optical measurement is directely proportional to its concentration.
Unknown concentration gives a reading of 327
100 ppm gives 180 of intensity
The concentration of the diluted quinine tablet is:
327 * (100ppm / 180) = 181.67 ppm. The final dilution
The concentration of the first diluted solution is:
181.67 ppm * (100.0mL / 15mL) = 1211ppm
ppm could be defined as mass of solute (In this case of quinine) in mg per liter of solution. That is:
1211mg / L
As the tablet was diluted to 500mL = 0.5L, the mass of the quinine is:
0.5L * (1211mg / L) =
605.6mg of quinine
Can someone help me with this
Answer: A
Explanation:
Answer:
B
Explanation:
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB I LIKE B it's B though gl on the rest.
sketch the electrolytic cell for converting alumina to aluminum
Calculate the number of total atoms in 195 grams of Ni(OH)2.
1.267 x 10 ^ 24 is the total number of atoms
Five identical test tubes are each filled from the following five copper (11) sulfate stock solutions. Which of the following test tubes would appear the lightest blue?
a) Stock solution made form 0.200 moles of CuSO4 dissolved to a total volume of 400 ml
b) Stock solution made form 0.150 moles of CuSO4 dissolved to a total volume of 300 mL
C)Stock solution made form 0.250 moles of CuSO4 dissolved to a total volume of 500 ml
d) Stock solution made form 0.175 moles of CuSO4 dissolved to a total volume of 400 ml
e) Stock solution made form 0.125 moles of CuSO4 dissolved to a total volume of 300 ml
Answer:
deez cutz
Explanation:
did i get it right
Which of the following molecules has a bent shape?
O A. CO2
O B. H20
O C. BeCl2
O D. NH3
help me, please - i will make you brainliest
Answer:the correct answer is a.
100.00 mL of 0.15 M nitrous acid (HNO2) are titrated with a 0.15 M NaOH solution. (a) Calculate the pH for the initial solution. (b) Calculate the pH for the point at which 80.0 mL of the base has been added. (c) Calculate the pH for the equivalence point. (d) Calculate the pH for the point at which 105 mL of the base has been added.
Answer:
a. pH = 2.04
b. pH = 3.85
c. pH = 8.06
d. pH = 11.56
Explanation:
The nitrous acid is a weak acid (Ka = 5.6x10⁻⁴) that reacts with NaOH as follows:
HNO₂ + NaOH → NaNO₂(aq) + H₂O(l)
a. At the beginning there is just a solution of 0.12M HNO₂. As Ka is:
Ka = [H⁺] [NO₂⁻] / [HNO₂]
Where [H⁺] and [NO₂⁻] ions comes from the same equilibrium ([H⁺] = [NO₂⁻] = X):
5.6x10⁻⁴ = X² / 0.15M
8.4x10⁻⁵ = X²
X = [H⁺] = 9.165x10⁻³M
As pH = -log [H⁺]
pH = 2.04b. At this point we have HNO₂ and NaNO₂ (The weak acid and the conjugate base), a buffer. The pH of a buffer is obtained using H-H equation:
pH = pKa + log [NaNO₂] / [HNO₂]
Where pH is the pH of the buffer,
pKa is -log Ka = 3.25
And [NaNO₂] [HNO₂] could be taken as the moles of each compound.
The initial moles of HNO₂ are:
0.100L * (0.15mol / L) = 0.015moles
The moles of base added are:
0.0800L * (0.15mol / L) = 0.012moles
The moles of base added = Moles of NaNO₂ produced = 0.012moles.
And the moles of HNO₂ that remains are:
0.015moles - 0.012moles = 0.003moles
Replacing in H-H equation:
pH = 3.25 + log [0.012moles] / [0.003moles]
pH = 3.85c. At equivalence point all HNO2 reacts producing NaNO₂. The volume added of NaOH must be 100mL. That means the concentration of the NaNO₂ is:
0.15M / 2 = 0.075M
The NaNO₂ is in equilibrium with water as follows:
NaNO₂(aq) + H₂O(l) ⇄ HNO₂(aq) + OH⁻(aq) + Na⁺
The equilibrium constant, kb, is:
Kb = Kw/Ka = 1x10⁻¹⁴ / 5.6x10⁻⁴ = 1.79x10⁻¹¹ = [OH⁻] [HNO₂] / [NaNO₂]
Where [OH⁻] = [HNO₂] = x
[NaNO₂] = 0.075M
1.79x10⁻¹¹ = [X] [X] / [0.075M]
1.34x10⁻¹² = X²
X = 1.16x10⁻⁶M = [OH⁻]
pOH = -log [OH-] = 5.94
pH = 14-pOH
pH = 8.06d. At this point, 5mL of NaOH are added in excess, the moles are:
5mL = 5x10⁻³L * (0.15mol / L) =7.5x10⁻⁴moles NaOH
In 100mL + 105mL = 205mL = 0.205L. [NaOH] = 7.5x10⁻⁴moles NaOH / 0.205L =
3.66x10⁻³M = [OH⁻]
pOH = 2.44
pH = 14 - pOH
pH = 11.56I need help
Balance the chemical equation
Answer:
Iwill add 2 for Na and 2 for NaCl so the answer is "C"
Calculate the enthalpy change for the photosynthesis of gluclose
Answer:
jhdgafhgafhagfhafg
Explanation:
during evaporation, the volume of the liquid decreases and the liquid becomes what???
Answer:
Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds
a shape with five sides is called a?
Answer:
A five-sided shape is called a pentagon.
Explanation:
Answered by NONE other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO!!!
Hope this helped!!!
Answer:
a pentagon
Explanation:
I remember that a pentagon has 5 sides
What is the minimum temperature
needed to dissolve 35 grams of KCl in 100 grams of water?
Answer:
[tex]30^{\circ}\text{C}[/tex]
Explanation:
To know the temperature at which KCl dissolves in water we need to refer to the general solubility curves.
In the case of [tex]KCl[/tex], [tex]35\ \text{g}[/tex] of it will dissolve in [tex]100\ \text{g}[/tex] of water at a minimum temperature of [tex]30^{\circ}\text{C}[/tex].
So, the the minimum temperature needed to dissolve 35 grams of KCl in 100 grams of water is [tex]30^{\circ}\text{C}[/tex].
How many molecules of methane gas (CH4) are in 32.1 grams of methane
Answer:
There are 1.8021⋅1024 molecules of CH4 in 48 grams of CH4 .
Explanation:
hope it helps you
follow me for more
I'm willing to help
Which of the following statements is true????
Sedimentary rock is usually found in areas which have, or once had, water.
According to the theory of continental drift, the continents are formed from small islands which drifted together.
Seasons happen because the Earth is farther away from the sun during the winter than during the summer.
Metamorphic rock is formed from small rock fragments cemented by water.
Answer:
I believe it is C?
Sorry fi it doesn't help!
3.org bookmarks
B Classes
Next.
Reaction Rates and Chemical Equilibrium: Mastery Test
Select the correct answer from each drop-down menu.
What effect does a decrease in temperature have on the overall rate of a chemical reaction?
The reaction rate will
A decrease in temperature decreases(blank)
The reaction rate will (blank)
Answer:
A decrease in temperature decreases the number of collisions between molecules . The reaction rate will decrease
Explanation:
Given the following balanced chemical equation:
2C2H10 + 902 +4CO2 + 10H2O
How many moles of C2H10 are needed to completely react with 6.15
moles of oxygen?
O 1.37 mol
2 mol
0277 mol
Explanation:
[tex]6.15 \: mol \: oxygen \: \times \frac{2 \: mol \: c2h10}{9 \: mol \: oxygen} = 1.37 \: moles \: of \: c2h10 \: needed [/tex]
If it was helpfull, please select as brainliest answer. thanks;)
Can someone please help with this !!!!
is pyramidal molecular geometry?
A. N2
B. H2O
C. NH3
D. CCL4
Answer:
[tex]\color{Blue}\huge\boxed{Question} [/tex]
Is pyramidal molecular geometry?[tex]\color{Blue}\huge\boxed{Answer} [/tex]
B.H2OWhich type of substances do you separate into ions when writing the complete ionic equation?
a. Aqueous
b. Liquid
c. Gas
d. Solid
Answer:
a. Aqueous
Explanation:
Took the test
List 4 significant problems with nuclear power plants.xx
Answer:
Cost.
Weapons Proliferation Risk.
Meltdown Risk.
Mining Lung Cancer Risk.
Explanation:
Hope this helped!!!
Question 13 of 25
A scientist measures how quickly bamboo plants grow after receiving
different amounts of water. She gives each plant a different amount of water
and measures the plant's growth. What is the manipulated variable in this
experiment?
A. The total number of bamboo plants
B. The number of days of the experiment
C. The size of the bamboo plant
D. The amount of water given
