What is the mole fraction of sodium chloride in solution that is 13. 0 y mass sodium chloride and that has a density of 1. 10 g/ml?

Answer:

0.53 (sig figs) or 0.525 original answer

Explanation:

If you use the formula (M1)(V2)=(M2)(V2) and plug in the values, you are solving for the missing X, which is the concentration.

The concentration of the 2.22 mL perchloric acid that was neutralized with barium hydroxide is 3.1 M.

The neutralization is given as the reaction of the acid and the base forming salt. The reaction of 1 mole of barium hydroxide requires 2 moles of perchloric acid to neutralize completely.

The volume of barium hydroxide given was 15.1 mL. The moles of barium hydroxide has been:

[tex]\rm 1000\;mL\; Ba(OH)_2 = 0.2288 \;mol Ba(OH)_2\\\\15.1\;mL\;Ba(OH)_2=0.0034\;mol[/tex]

The moles of perchloric neutralized by 0.0034 mol barium hydroxide will be:

[tex]\rm 1\;mol\;Ba(OH)_2=2\;mol\;HClO_4\\\\\rm 0.0034\;mol\;Ba(OH)_4=0.0069\;mol\;HClO_4[/tex]

The volume of perchloric has been 2.22 mL. The concentration of the acid is given as:

[tex]\rm Concentration=moles\;\times\dfrac{1000}{volume(mL)}\\\\Concentration=0.0069\;mol\;\times\dfrac{1000}{2.22}\\\\Concentration=3.1\;M[/tex]

The concentration of the perchloric acid aliquot is 3.1 M.

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The density in grams per milliliter  7.975.

Density is the mass of per unit volume. Density is equals to mass into volume.

D = M x V

The mass of a gem is given, M = 5.50

The volume is 10.45 - 9.00 = 1.45

Thus, the density is

D = 5.50 × 1.45 = 7.975

Thus, the density in grams per milliliter is 7.975.

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Answer:

H2O

H2O

Explanation:

because the are only two hydrogen that can react to Oxygen

Ionization reaction gives the ionization state of the chemical species. Its ionization will result in a conjugate base of the formic acid and release a hydrogen ion.

The acid dissociation constant is the concentration of the acid that has been dissociated into its constituents ions in the solution.

The ionization equation of the formic acid is:

[tex]\rm HCOOH \rightleftharpoons HCOO^{-} + H^{+}[/tex]

The acid dissociation constant (Ka) for formic acid is given as,

[tex]\rm Ka = \rm \dfrac {[H^{+}][HCOO^{-}]}{[HCOOH]}[/tex]

Anions are negatively charged ions and formate ions generated in the dissociation of the formic acid.

Therefore, the formate ion is an anion.

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Answer:

A

Explanation:

Banana ripening in air is an example of oxidation reaction.

Answer:

T = (Z x 10) + 50

Explanation:

The molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃ Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

AuCl₃(aq) ⇄ Au³⁺(aq) + 3Cl⁻(aq)

Let the solubility of the AuCl₃ in 0.013m solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ion and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 litre then the concentration of chloride ions in MgCl₂ is 2(0.010) = 0.020M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.020.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²⁵

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.020)³

Value of 3x is negligible as compared to the 0.020, so the equation becomes

3.2 × 10⁻²⁵ = (x)(0.020)³

x = 3.2×10⁻²⁵ / (0.020)³

x = 4 ×10⁻²⁰M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

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Answer:

Here is the solution....hope it helps :)

The number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

The number of moles of the given aluminum oxide is calculated as follows;

Al2O3 = 101.96 g/mol

moles = 285/101.96

moles = 2.795 moles

1 mole = 6.02 x 10²³ particles

2.795 moles = ?

= 2.795  x  6.02 x 10²³ particles

= 1.68 x 10²⁴ particles.

Thus, the number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

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Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

hope it helps :)

The total pressure of the gas is calculated as 849 mmHg.

The term partial pressure is the pressure that is exerted by an individual gas in a mixture of gases.

In this case, the partial pressures of hydrogen and water are 789 mmHg and  60 mmHg respectively.

Thus, the total pressure of the gas =  60 mmHg +  789 mmHg = 849 mmHg.

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Answer:

B. Helium

Explanation:

Correct me if I'm wrong

We can tell which acid which have the highest percent ionization on the basis of pH value.

The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.

If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.

Hence acids with high pH value will show highest percent ionization.

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The following is a classification of the compounds;

The term ionic substance refers to a substance that is composed of ions. It is a substance that can dissolve in water.

The following is a classification of the compounds;

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If there are equal moles of each gas, what is the partial pressure of H₂ is 0.362.

The pressure that one of the gases in a mixture would exert if it were in the same volume on its own.

According to the Dalton's law of partial pressure

The Partial pressure of a gas = (Total pressure × mole fraction of the particular gas)

Partial pressure of H₂ is

[tex]\dfrac{1.81}{5.00} = 0.362[/tex]

Thus, the partial pressure of H₂ is 0.362.

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Answer: When this atom loses an electron, the result is a positive ion.

Explanation:

The concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

Molarity is the measure of the concentration of any solute in per unit volume of the solution.

The reaction is [tex]\rm Pb^2^+(aq) + 2Cl^-(aq) \rightarrow PbCl_2(s).[/tex]

The molarity of lead is 0.025 M

The ksp is given 17×10⁻⁵

Now, calculating the concentration

[tex][Pb^2^+] = 0.025 M.\\Ksp = 1.17 \times 10^-^5\\Ksp = [Pb^2^+] \times [Cl^-]^2\\[Cl^-] = \dfrac{\sqrt{ Ksp}}{[Pb^2^+]} \\\\[Cl^-] = \dfrac{\sqrt{ 0.0000117}}{0.025} \\[Cl^-] = 2.16 \times 10^-^2M.[/tex]

Thus, the concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

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According to the research, scientific observations are important because every experiment begins with observations.

It consists of receiving knowledge of the outside world through our senses, it means that we naturally make observations about the world around us and the first step proposed by the scientific method.

Scientific observation, on the other hand, refers to the process of detailing any phenomenon of nature with analytical intent, usually later replicated in a laboratory (experimentation) or controlled environment.

Similarly, there are qualitative observations that are based on the senses, which are generally more subjective, while quantitative observations are more objective, focusing mainly on numbers, for example "the flower has five petals" is a quantitative observation.

Therefore, we can conclude that according to the context, scientific observations are important because every experiment begins with observations.

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Answer:

1. Every experiment begins with observations

2.In field investigations, it is much more difficult to separate your control and experimental groups.

3.based on your senses

4.The flower has five petals.

5.We naturally make observations about the world around us.

They are statements made based on something seen, noticed, or measured. (I think 5 is wrong, if it is then sorry guys dont report me, i tried my best.)

Explanation:

The nitrate reduction test with the uninoculated tube considers it a positive control.

The nitrate reduction assay is given as the assay with the ability of the bacteria or enzyme to reduce nitrate to nitrite.

The test is performed by considering the difference in the inoculated and the uninoculated tubes with bacteria. The tube with the bacteria and the nitrate is termed a test tube.

The tube with nitrate only without bacteria is termed as a negative control, as it will not have the results for the reduction and can be used to assess the test.

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Geometric progression is a sequence that can be found by multiplying the same value by the preceding number. The next term in the sequence is 8 / 81.

A geometric progression is a sequence of numbers other than 0 and can be estimated by multiplying a specific digit by the prior number. It is given as,

an = a₁rⁿ⁻¹

Where r is the common ratio or the number.

For the given sequence the common ratio (r) is 2/3.

Substituting values:

an = (1/2) ×  (2/3)ⁿ⁻¹

Applying r:

an=2ⁿ⁻¹ / 2 × 3ⁿ⁻¹

Substitute n to find the nth term as:

a₅=2⁽⁵⁾⁻²/ 3⁽⁵⁾⁻¹

a₅=8/ 3⁽⁵⁾⁻¹

a₅ = 8/ 81

Therefore, the next number on the sequence is 8/81.

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Between A and B

The highest probability is that A and B are solids and they are forming liquid or gases.

Between A and C

Highest probability is that A and C are gases and they are turning into liquid or solid

The mass of the formed precipitate of AgCl in the reaction is 1.29 grams.

Moles (n) of any substance from molarity (M) will be calculated by using the below equation:
M = n/V, where

V = volume in L

Given chemical reaction is:
2AgNO₃(aq) + CaCl₂(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)

From the stoichiometry of the reaction, mole ratio of AgNO₃ to CaCl₂ is 2:1.

0.0015 moles of AgNO₃ = reacts with 1/2×0.0045 = 0.00075 moles of CaCl₂

Here CaCl₂ is the limiting reagent, and formation of precipitate depends on this only.

Again from the stoichiometry of the reaction:

0.0045 moles of CaCl₂ = produces 2(0.0045) = 0.009 moles of AgCl

Mass of 0.009 moles AgCl will be calculated as:

n = W/M, where

W = (0.009)(143.45) = 1.29g

Hence required mass of precipitate is 1.29 grams.

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The Delta G for the autoionization of water can be calculated as [tex]\Delta G=-RTlnK[/tex].

The autoionization of water is given as the reaction of the two water molecules, resulting in the formation of the ions of hydronium and hydroxide ion.

It can be expressed as:

[tex]\rm 2\;H_2O\;\leftrightharpoons\;H_3O^+\;+\;OH^-[/tex]

The[tex]\Delta G[/tex] of the autoionization of water can be given as;

[tex]\Delta G=-RTlnK[/tex]

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