What is the measure of an angle if it is 120 less
than four times its own supplement?

Answer:

equate two simultaneous equations for r and solve

Transformation involves changing the position and size of a shape.

The true statements are:

The complete question is as follows:-

The composition do,0.75(x,y) ∘ do,2(x,y) is applied to △lmn to create △l''m''n''. which statements must be true regarding the two triangles? check all that apply. ∠m ≅ ∠m'' △lmn ~ △l''m''n'' △lmn ≅ △l''m''n'' the coordinates of vertex l'' are (-3, 1.5). the coordinates of vertex n'' are (3, -1.5). the coordinates of vertex m'' are (1.5, -1.5).

The process of changing the location of the image on the coordinate system will be known as the translation.

The coordinates of the triangle are:

L =(-1,2)

M = (-1,-1)

N = ( 2,-1)

The transformation rule is given as:

do 0.75 (x,y) 2 (x,y)

The transformation rule is a dilation by a factor of 0.75, and then a factor of 2.

Uniform dilation changes the size of a shape, but the angles remain unchanged. This means that:

∠l≅∠l''

∠m≅∠m''

∠n≅∠n''

Δlmn⇒Δl'm'n'

The above highlights mean that:

The angles of both triangles are congruent

The triangles are similar

Next, we apply the rule on the coordinates of the triangle

L'' = 0.75 x 2 x (-1,2)

L'' = ( -1.5,3)

M'' = 0.75 x 2 x (-1,-1)

M'' = ( -1.5 , -1.5)

N'' = 0.75 x 2 x (2,-1)

N'' = (3 , -1.5)

Hence, the true statements are: The coordinates of n" are.

Read more about transformations at:

brainly.com/question/11709244

#SPJ1

If quadrilateral JKLM were in third quadrant then the coordinates will be (-1,0),(-4,-1),(-4,-2)(-1,-2)

Given Quadrilateral JKLM is in fourth quadrant and coordinates (1,0),(4,-1),(4,-2)(1,-2)

We know that the coordinates of x used to negative in third quadrant and positive in fourth quadrant. Coordinates of y used to negative in third and fourth quadrant.

So in order to change the coordinates from fourth to third we need to change the coordinates of x axis to negative and the coordinates will be :

Coordinates of J will change from (1,0) to (-1,0)

Coordinates of  K will change from(4,-1) to (-4,-1)

Coordinates of L will change from (4,-2) to (-4,-2)

Coordinates of M will change from (1,-2) to (-1,-2).

Learn more about coordinates at https://brainly.com/question/17206319

#SPJ10

The height of the shorter cone is 6.81cm

A cone is hollow three-dimensional shape with side lengths that tappers from the base to a point at the vertex.

Analysis:

Let the radius of the first cone be = r

radius of shorter cone = R

height of first cone = h

height of shorter cone = H

if volume of the two cones are same

1/3π[tex]r^{2}[/tex]h = 1/3π[tex]R^{2}[/tex]H

[tex]r^{2}[/tex]h = [tex]R^{2}[/tex]H

H =  [tex]r^{2}[/tex]h /  [tex]R^{2}[/tex]

H = [tex](8.5)^{2}[/tex]x 10 / [tex](10.3)^{2}[/tex] = 6.81cm

In conclusion, the height of the shorter cone is 6.81cm

Learn more about cones: brainly.com/question/1082469

#SPJ1

Answer:

No, the solution is -3.

Step-by-step explanation:

3y+10=-5y-14

We move all terms to the left:

3y+10-(-5y-14)=0

We get rid of parentheses

3y+5y+14+10=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

Answer:

y = - 3

Step-by-step explanation:

3y + 10 = - 5y - 14 ( add 5y to both sides )

8y + 10 = - 14 ( subtract 10 from both sides )

8y = - 24 ( divide both sides by 8 )

y = - 3

The expression -4 (-11 + 4n) – 3(- 2n + 9) is equivalent to the expression 17 — 10n.

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ -4 (-11 + 4n) – 3(- 2n + 9)

On simplifying, we have

⇒ 44 – 16n + 6n – 27

⇒ 17 — 10n

More about the equivalent link is given below.

https://brainly.com/question/889935

#SPJ1

Answer:

y = -x

Step-by-step explanation:

Breaking down the equation

[tex]y=e^x-x[/tex] can be written as [tex]y=e^x + (-x)[/tex], making it more clear that this function is composed of two functions:

asymptotes of the parts

The regular exponential function normally has an asymptote at y=0, a horizontal line because as "x" gets more and more negative, e^(x) gets closer and closer to zero (see blue graph).  This asymptotic behavior perhaps can be more easily understood by recognizing that [tex]e^{-x}[/tex] is equivalent to [tex]\dfrac{1}{e^x}[/tex], so that as the x values get more and more negative, it is effectively dividing 1 by a larger and larger number, thus getting closer and closer to zero.

In this situation, that exponential function is added to "-x", which is a linear function with a slope of negative 1.

As the left end of the exponential function gets closer and closer to zero, the exponential part contributes almost nothing to the sum, whereas as the "x" gets more and more negative, the linear function "-x" gets more and more positive (linearly).  Since the exponential piece adds almost nothing to it (when moving to the left), the combined function is essentially "-x" (although it is ever so slightly greater than it, just as it was ever so slightly greater than zero) (see pink graph, with dashed asymptote).

Clarifications

To be clear, on the right side of the graph, the exponential part of the function completely overwhelms the linear piece, and the function behaves much more like an exponential function, nearly completely masking the behavior of the linear piece.  Since an exponential function is unbounded, and the domain of both the exponential and linear functions are all real numbers, on the right side of the graph, there is no asymptotic behavior.

a)QM and PM

b)QMN and NMQ

c)M

Answer:

perpendicular

Step-by-step explanation:

For every meter there are 3.281 feet. The perimeter of the yard is 188ft. Divide 188 by 3.281 and you get 57.3 (rounded to 1dp). Round that up to the nearest meter and you get 58. So, Mr Smith needs 58 meters of fencing for his yard.

Answer:

30

Step-by-step explanation:

Area of a triangle = (base length × height)/2

Given base length = 5 and given height = 12

So area = (5×12)/2

==> multiply 12 and 5

Area = (60)/2

==> divide 60 by 2

Area = 30

Step-by-step explanation:

please mark me as brainlest

The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.

The complete options are given below.

1. (-11/2) -(11/2)

2.(-5/2)-(3/2)

3.(-5/2-(11/2)

4. (-11/2) -(-3/2)

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The end points are given below.

(-3, -7) and (-8, 4)

We have

(x₁, y₁) = (-3, -7)

(x₂, y₂) = (-8, 4)

Then the mid-point will be

x = (- 3 - 8) / 2

x = -11 / 2

y = (-7 + 4) / 2

y = -3/2

Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).

Then the correct option is D.

More about the midpoint of line segment AB link is given below.

https://brainly.com/question/17410964

#SPJ1

Answer:

 [tex]\frac{18}{5}[/tex] (11)

Step-by-step explanation:

If it varies directly, you need to find k, the constant of proportionality.

This is done by plugging the values in for x & y that are known.

y = kx

18 = k(5)

[tex]\frac{18}{5}[/tex] = k

Now solve for y  when x is 11.

y = [tex]\frac{18}{5}[/tex] (11)

y = 39.6

Step-by-step explanation:

multiply 2×3 to get 6 and then multiply 6×4

or

multiply 3×4 to get 12 and then multiply 12×2

The value of [tex]a_{5}[/tex] is 2500, when [tex]a_{1}=4[/tex] and [tex]5a_{n-1}[/tex].

Given that, [tex]a_{1}=4[/tex] and [tex]5a_{n-1}[/tex].

We need to find the value of [tex]a_{5}[/tex].

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of [tex]a_{5}[/tex] :

[tex]a_{2} =5a_{2-1}=5a_{1}=5 \times4=20[/tex]

[tex]a_{3} =5a_{3-1}=5a_{2}=5 \times20=100[/tex]

[tex]a_{4} =5a_{4-1}=5a_{3}=5 \times100=500[/tex]

[tex]a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500[/tex]

Therefore, the value of [tex]a_{5}[/tex] is 2500.

To learn more about arithmetic sequence visit:

https://brainly.com/question/15412619.

#SPJ1

Answer: 3

Step-by-step explanation:

Answer:

The answer should be 3.3/4

Step-by-step explanation:

The function would become an exponential decay function.

Step-by-step explanation:

the circumference of a whole circle is

2×pi×r

with r being the radius. which is in our case a.

so,

2×pi×a

the part arc of just a sector of the circle is just the angle/360 part (as the whole circle is 360°).

we therefore know

27×pi = 2×pi×a × 60/360 = 2×pi×a × 1/6 = pi×a × 1/3

3×27×pi = pi×a

81×pi = pi×a

a = 81

The IQR for male data is 10, the estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

From the box plot:

Part A:

IQR for males data:

IQR = Q3 - Q1

The estimated value of Q3 is 15 (between 10 and 20)

The estimated value of Q1 is 5 (between 0 and 10)

IQR = 15 -5 = 10

Part B:

= Median(male) - Median(femal)

= 10 - 8

= 2

Part C:

The box plot for males is symmetric and for females, the box plot is left side skewed.

Part D:

There can be holidays for the outliers

Thus, the IQR for male data is 10, estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

Learn more about the box and whisker plot here:

brainly.com/question/3209282

#SPJ1

Answer:

D.All of the choice

Step-by-step explanation:

D.All of the choice

Answer:

x: 98 y: 112

Step-by-step explanation:

Supplementary angles add up to 180 so:

x + 82 = 180

x = 98

And:

y + 68 = 180

y = 112

Answer:

supplementary, 98°, 112°

Step-by-step explanation:

Opposite angles of a quadrilateral inscribed in a circle are supplementary, i.e., they add up to 180°.

∴ x° + 82° = 180°

  x = 180° - 82°

       x = 98°

y° + 68° = 180°

y = 180° - 68°

    y = 112°

Answer:

A

Step-by-step explanation:

First, simplify the numerator:

[tex]\frac{3 }{\sqrt{3} + \sqrt{x} } \\[/tex]

Next, multiply the numerator and denominator by the opposite of the denominator to rationalize the expression.

[tex]\frac{3}{\sqrt{3}+\sqrt{x} }*\frac{\sqrt{3}-\sqrt{x} }{\sqrt{3}-\sqrt{x}}[/tex]

Finally, evaluate the denominator by multiplying them together.

[tex]\frac{3(\sqrt{3}-\sqrt{x})} {(\sqrt{3}+\sqrt{x})(\sqrt{3}-\sqrt{x})}[/tex]

Simplify:

[tex]\frac{3(\sqrt{3}-\sqrt{x})} {3-x}[/tex]

And done! :)

5.12 minutes ≈ 5 minutes 7.2 seconds

Distance. The length along a line or line segment between two points on the line or line segment.

Here, The flight path of the airplane is along the line ...

y = -125/135x = -25/27x

The perpendicular line through Mt. Rainier's location is ...

 y = 27/25(x -56) -40

In standard form, these two equations are ...

25x +27y = 0

27x -25y = 2512

The point of closest approach has the coordinates that are the solution to these two equations:

(x, y) = (33912/677, 31400/677)

The distance d from the origin to this point is given by the Pythagorean theorem (distance formula) as ...

d = 1256√(2/677) . . . . . km

This distance can be converted to time using the speed of the airplane:

1256√(2/677) X 60/800 =  94.2√(2/677) ≈ 5.120019 mins

Thus, 5.12 minutes after departing JBLM you will be closest to Mt. Rainier.

The attached graph shows the geometry of the problem.

Learn more about Distance from:

https://brainly.com/question/15172156

#SPJ1

Answer:

The answer is tanx

Step-by-step explanation:

This is because, when you graph the trigonometric functions, which can be reresented as: a*(trig sign)*bx + K, the period of the function for sin, cos, csc, and sec are all 2pi divided by "b". However, the formula to find the function of tan or cot graphs is pi divided by b. And, since we don't see any values being multilied to the x in the choices, and we calculate the period for each of them, it concludes that tanx, has a period of pi