What is the hydrogen ion concentration in molarity if the hydroxide ion concentration is 7.609 10-13 ?

[H+][OH-] = 10-14
pH = -log[H+]
[H] = 10pH

Answer: [tex]5.15\times 10^5kg[/tex]

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

Putting in the values we get:

[tex]\text{Number of moles}=\frac{1.00\times 10^{31}}{6.023\times 10^{23}}=0.166\times 10^{8}moles[/tex]

1 mole of phosphorous [tex]P[/tex] weighs = 31 g

Thus [tex]0.166\times 10^8[/tex] moles of phosphorous [tex]P[/tex] weigh=[tex]\frac{31}{1}\times 0.166\times 10^8=5.15\times 10^8g=5.15\times 10^5kg[/tex]

Answer:

Hyba odpowiedzi c. Hyba

Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.

The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:

[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]

Substituting the mass of each atom to identify the molar mass of ammonium chromate:

[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]

The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:

[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]

The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.

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Answer:

i dont kno

Explanation:

Explanation:

As temperature increases, fermentation rate accelerates. With increased fermentation rate, more aromatic compounds are produced because the metabolic intermediates are excreted from the yeast cells just like people getting sweaty and stinky during vigorous exercise.

Red: weak

Orange: Strong

Answer:

a

Explanation:

Answer:

c

Explanation:

edge

Answer:

−26.4 kcal

Explanation:

According to Hess's law, the total heat changes occuring during a chemical reaction are independent of path.

2CO(g)+O

2

(g)⟶2CO

2

(g)N ,

ΔH=−135.2 kcal

The above reaction is reversed and halved, we get-

CO

2

(g)⟶CO+

2

1

O

2

(g)

ΔH=

2

135.2

kcal ....(i)

C+O

2

(g)⟶CO

2

(g)

ΔH= -94 kcal ...(ii)

Required equation

C(s)+

2

1

O

2

(g)⟶CO(g);

Adding Eqs. (i) and (ii), we get

C(s)+

2

1

O

2

(g)⟶CO(g),

ΔH =

2

135.2

−94=−26.4 kcal

Answer:

First, third, and sixth

Explanation:

Answer:we see 1 side because the other side is not visible

Explanation:

Answer:

13 branches/tree

Explanation:

Step 1: Given data

Step 2: Calculate the total number of branches (b)

We will use the following expression.

b = l × b/l

b = 19565 leaves × 1 branch/35 leaves = 559 branch

Step 3: Calculate the number of branches per tree (b/t)

We will divide the total number of branches by the total number of trees.

559 branches/43 trees = 13 branches/tree

Answer:

3

m/s2

0.2

m/s2

Explanation:

if F=ma, then a = F/m. The unit to measure acceleration is typically m/s2.

Answer:

2M

Explanation:

M=mol/L

1. Find moles of CoCl2

mass of substance/molar mass = 130/129.833 = 1.001 mol

3. Substitute in molarity equation

M=(1.001/0.5)

M= around 2M

The molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M

HOW TO CALCULATE MOLARITY:

Therefore, the molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M.

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Answer: 75.7 % yield

Explanation:

The balanced chemical equation is:

[tex]2H_2S+SO_2\rightarrow 3S+2H_2O[/tex]  

According to stoichiometry :

68.2 g of [tex]H_2S[/tex] will require = 64 g of [tex]SO_2[/tex]

Thus 7.5 g of [tex]H_2S[/tex] will require = [tex]\frac{64}{68.2}\times 7.5=7.0g[/tex] of [tex]SO_2[/tex]

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 68.2 g of give = 96 g of

Thus 7.5 g of [tex]H_2S[/tex] give =[tex]\frac{96}{68.2}\times 7.5=10.5g[/tex]  of [tex]S[/tex]

% yield=[tex]\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%[/tex]

Thus 75.7 % yield is there.

Answer:

By using reference point (starting point) to measure the change in boat's position over time. Not 100% sure

Explanation:

Pls mark brainliest

Answer:

Ethylene glycol is a syrupy liquid at room temperature whereas polyethylene glycol is a solid material. The main difference between ethylene glycol and polyethylene glycol is that ethylene glycol has a fixed value for molecular weight whereas polyethylene glycol has no fixed value for molecular weight.

Answer:

22

Explanation:

5.5 mol C3H8 • (4 mol H2O / 1 mol C3H8 ) = 22 mol H2O

Answer:

D

Explanation:

Most likely, the pollutant that is most associated with high-tech gadgets in landfills would be heavy metals like lead, cadmium and mercury since they are being used in most of the electronic devices. Usually these metals can be found in the batteries of these gadgets.

High-tech gadgets in landfills would be heavy metals like lead, cadmium and mercury since they are being used in most of the electronic devices. Usually these metals can be found in the batteries of these gadgets. Hence, option D is correct.

Modern landfills are well-engineered and managed facilities for the disposal of solid waste.

Landfills are located, designed, operated and monitored to ensure compliance with federal regulations.

For instance, television and computer monitors normally contain hazardous materials such as lead, mercury, and cadmium, while nickel, beryllium, and zinc can often be found in circuit boards.

Due to the presence of these substances, recycling and disposal of e-waste becomes an important issue.

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Answer:

Cold front

Explanation:

Answer:

B- The polarity of the molecules and hydrogen bonding between molecules.

Explanation:

Hope this helps:)

Answer:

.4 moles

Explanation:

this is if it's 35 grams

Answer:

B. summer

Explanation:

The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.

Answer:

CH4

Explanation:

Tetra is the prefix for four. Hence the H4

Mono is the prefix for one, Hence the C

Methane (aka Tetrahydrogen monocarbide) written as CH4

The caliper is a component which is used by a disc brake system for performing its function.

The disc braking system consist of components such as disc/rotor, a brake calliper and brake pads. When the brake pedal is pushed, brake fluid creates pressure that produces friction.

So we can conclude that the caliper is a component which is used by a disc brake system for performing its function.

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Answer:

c. core, mantle and atmosphere

Answer:

Correct answer is letter A

Because Lithosphere includes the crust and the uppermost mantle.

Answer:

all soil are also different due to how they were form

Answer:

2 NH3(g) + 3 O2(g) + 2 CH4(g) = 2 HCN(aq) + 6 H2O(l)

Explanation:

Reaction stoichiometry Limiting reagent

Compound Coefficient Molar Mass Moles Weight

NH3(g) 2 17.03052  

O2(g) 3 31.9988  

CH4(g) 2 16.04246  

HCN(aq) 2 27.02534  

H2O(l) 6 18.01528

Instructions on balancing chemical equations:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.     Compare: Co - cobalt and CO - carbon monoxide

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.

Example: Fe{3+} + I{-} = Fe{2+} + I2

Substitute immutable groups in chemical compounds to avoid ambiguity.

For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,

but PhC2H5 + O2 = PhOH + CO2 + H2O will

Compound states [like (s) (aq) or (g)] are not required.

If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

Reaction stoichiometry could be computed for a balanced equation. Enter either the number of moles or weight for one of the compounds to compute the rest.

Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents.

The given chemical equation is already balanced and does not require any further balancing.

The chemical equation NH₃(g) + O₂(g) + CH₄(g) → HCN(aq) + H₂O(l) is already balanced because the number of atoms of each element is the same on both sides of the equation.

On the left side of the equation, there is 1 nitrogen (N) atom in NH₃ and 1 nitrogen (N) atom in HCN.

On the right side of the equation, there are 3 hydrogen (H) atoms in NH₃, 2 hydrogen (H) atoms in HCN, and 2 hydrogen (H) atoms in H₂O.

There are 3 oxygen (O) atoms in O₂ on the left side of the equation and 1 oxygen (O) atom in H₂O on the right side of the equation.

Finally, there is 1 carbon (C) atom in CH₄ on the left side of the equation.

Since the number of atoms of each element is balanced on both sides of the equation, we can conclude that the given equation is already balanced and does not require any further adjustments or coefficients.

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The complete question is:

How can I balance NH₃(g) + O₂ (g) + CH₄ (g) -> HCN (aq) + H₂O (l)?

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

Answer:

20g

Explanation:

First of all, you have got your formula wrong. It should be [tex]H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O[/tex].

Start by finding the Relative Formula Mass for sulfuric acid. [tex]H_{2}SO_{4}[/tex] is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing [tex]Mols=\frac{Mass}{Relative Formula Mass}[/tex]. So, [tex]\frac{24.5}{98} = 0.25[/tex], so the Mols of Sulfuric Acid is 0.25.

The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.

Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or [tex]NaOH[/tex]. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.

Answer:

292.4 g

Explanation:

First we convert 53.7 g of Al into moles, using its molar mass:

Then we convert Al moles into H₂SO₄ moles, using the stoichiometric coefficients:

Finally we convert 2.98 moles of sulfuric acid into grams, using its molar mass:

Answer:

1.784 g

Explanation:

The equation of the reaction is;

NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)

Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M

Number of moles of NaOH reacted =8.735 * 10^-3 moles

From the reaction equation;

1 mole of NaOH reacted with 1 mole of KHC8H4O4

Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.

So,

Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g