What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)?

3x − 4y = −17
3x − 4y = −20
4x + 3y = −2
4x + 3y = −6

Based on the hints of distinguishing between radical and non-radical numbers, we have the following lists:

In this question we must order sets of numbers in ascending order. A hint consists in comparing non-radical numbers with the closest radical numbers whose results are integers.

In consequence, we obtain the following orders:

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Answer:

0.98994949366117

√0.98 = 0.98994949366117

Step 1:

Divide the number (0.98) by 2 to get the first guess for the square root.

First guess = 0.98/2 = 0.49.

Step 2:

Divide 0.98 by the previous result. d = 0.98/0.49 = 2.

Average this value (d) with that of step 1: (2 + 0.49)/2 = 1.245 (new guess).

Error = new guess - previous value = 0.49 - 1.245 = 0.755.

0.755 > 0.01. As error > accuracy, we repeat this step again.

Step 3:

Divide 0.98 by the previous result. d = 0.98/1.245 = 0.7871485944.

Average this value (d) with that of step 2: (0.7871485944 + 1.245)/2 = 1.0160742972 (new guess).

Error = new guess - previous value = 1.245 - 1.0160742972 = 0.2289257028.

0.2289257028 > 0.01. As error > accuracy, we repeat this step again.

Step 4:

Divide 0.98 by the previous result. d = 0.98/1.0160742972 = 0.9644963982.

Average this value (d) with that of step 3: (0.9644963982 + 1.0160742972)/2 = 0.9902853477 (new guess).

Error = new guess - previous value = 1.0160742972 - 0.9902853477 = 0.0257889495.

0.0257889495 > 0.01. As error > accuracy, we repeat this step again.

Step 5:

Divide 0.98 by the previous result. d = 0.98/0.9902853477 = 0.9896137535.

Average this value (d) with that of step 4: (0.9896137535 + 0.9902853477)/2 = 0.9899495506 (new guess).

Error = new guess - previous value = 0.9902853477 - 0.9899495506 = 0.0003357971.

0.0003357971 <= 0.01. As error <= accuracy, we stop the iterations and use 0.9899495506 as the square root.

So, we can say that the square root of 0.98 is 0.989 with an error smaller than 0.01 (in fact the error is 0.0003357971). this means that the first 3 decimal places are correct. Just to compare, the returned value by using the javascript function 'Math.sqrt(0.98)' is 0.9899494936611666.

Note: There are other ways to calculate square roots. This is only one of them.

To round it to the tenths, it's 1

To round to the hundredths, it's.99

Thousandth is.990

Answer: K

Step-by-step explanation:

The subtraction with the negatives can cancel out, resulting in a possible positive answer.

Answer:

k

Step-by-step explanation:

K      you CAN get a positive number....

        example  :

     -3   - (-5)   = -3 + 5 = + 2

Considering the given data-set, it's mean and the formula, the variance is of 870 lbs².

The variance of a data-set is given by the sum of the differences squared between each observation and the mean, divided by the number of values.

The mean is the sum of all observations divided by the number of observations, hence:

M = (145 + 175 + 180 + 205 + 120)/5 = 165.

And the variance, in lbs squared, is given by:

V = [(145-165)² + (175-165)² + (180-165)² + (205-165)² + (120-165)²]/5 = 870.

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Answer:

(2a-b)(3c-d)

Answer:

The answer is 1/42 as you take reciprocal of 6=(1/6) and reciprocal of 7=(1/7) and multiply.

Answer:

[tex]\boxed {\frac{1}{42}}[/tex]

Step-by-step explanation:

Reciprocal of 6 : 1/6

Reciprocal of 7 : 1/7

Their product :

Answer:

[tex] \cfrac{61}{24} [/tex]

Step-by-step explanation:

Given expression:

[tex] \cfrac{2}{3} + \bigg(\cfrac{5}{2} \bigg) {} ^{ 2} \times \cfrac{3}{10} [/tex]

Solution:

Simplify using PEMDAS.

[tex] = \sf \cfrac{2}{3} + \cfrac{25}{4} \times \cfrac{3}{10} \\ \\ = \cfrac{2}{3} + \cfrac{15}{8} \\ \\ = \cfrac{16 +45 }{24} \\ \\ = \boxed{\cfrac{61}{24} }[/tex]

Done!

Answer:

[tex]\frac{61}{24}[/tex]

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] + ( [tex]\frac{5}{2}[/tex] )² × [tex]\frac{3}{10}[/tex] ← evaluate exponent

= [tex]\frac{2}{3}[/tex] + [tex]\frac{25}{4}[/tex] × [tex]\frac{3}{10}[/tex] ← evaluate multiplication ( cancel 25 and 10 by 5 )

= [tex]\frac{2}{3}[/tex] + [tex]\frac{5}{4}[/tex] × [tex]\frac{3}{2}[/tex]

= [tex]\frac{2}{3}[/tex] + [tex]\frac{15}{8}[/tex] ← evaluate addition

= [tex]\frac{2(8)}{3(8)}[/tex] + [tex]\frac{15(3)}{8(3)}[/tex]

= [tex]\frac{16}{24}[/tex] + [tex]\frac{45}{24}[/tex]

= [tex]\frac{61}{24}[/tex]

The ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)

The given parameters are:

Initial height, h = 8 inches

Rate = 0.5 inches per hour

The height of the candle at x hour is:

y = Initial - rate * x

This gives

y = 8 - 0.5x

Set x  = 0 to 5

y = 8 - 0.5(0) = 8

y = 8 - 0.5(1) = 7.5

y = 8 - 0.5(2) = 7

y = 8 - 0.5(3) = 6.5

y = 8 - 0.5(4) = 6

y = 8 - 0.5(5) = 5.5

So, the ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)

In (a), we have:

y = 8 - 0.5x

The above is a linear relation.

All linear relations are functions

Hence, the relation is a function.

We have

Initial height, h = 8 inches

New rate = 0.4 inches per hour

The height of the candle at x hour is:

y = Initial - rate * x

This gives

y = 8 - 0.4x

The above is a linear relation.

All linear relations are functions

Hence, the new relation is also a function.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 6(3x - 7) = 2[/tex]

Step 1 -

[tex]\qquad \tt \rightarrow \: 18x - 42 = 2[/tex]

[ distributive property ]

Step 2 -

[tex]\qquad \tt \rightarrow \: 18x = 2 + 42[/tex]

[tex]\qquad \tt \rightarrow \: 18x = 44[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

d) Step 1: 18x - 42 = 2

Step 2: 18x = 44

Step-by-step explanation:

Given equation,

→ 6(3x - 7) = 2

Now the value of x will be,

→ 6(3x - 7) = 2

→ 6(3x) - 6(7) = 2

→ 18x - 42 = 2

→ 18x = 2 + 42

→ 18x = 44

→ x = 44/18

→ [ x = 22/9 ]

Hence, value of x is 22/9.

H0: µ1 = µ2; The exercise program do not have significant effect on physical fitness, H1: µ1 =/ µ2; the exercise program had a significant effect on physical fitness and the  Estimated Cohen's d is 0.82.

A. Significant effect

H0: µ1 = µ2

Based on the above hypothesis the exercise program does not have significant effect on physical fitness

H1: µ1 =/ µ2

Based on the above hypothesis the exercise program had a significant effect on physical fitness

Pooled variance: sp2 = (190 + 120.5/(15-1) + (10-1)

Pooled variance: sp2 = 310.5/23

Pooled variance: sp2 =13.5

Estimated standard error ( sM1-M2):

sM1-M2 =√13.5/15 +13.5/10

sM1-M2 =√2.25

sM1-M2 = 1.5

Tailed test (t)

t = (15.5 - 12)/1.5

t=3.5/1.5

t= 2.33

B. Estimated Cohen's d:

Estimated Cohen's d  = 3/√13.5

Estimated Cohen's d = 3/3.67

Estimated Cohen's d= 0.817

Estimated Cohen's d= 0.82 (Approximately); this is a large effect.

Conclusion demonstrating how the outcome of the hypothesis test would tend to appear in a research report is:  (Reject H0). Because the  group exercise program tend to have a significant effect on the physical fitness of elderly adults, t = 2.33, p <.05, d = 0.82.

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Step-by-step explanation:

hope you can understand

David will be 10 and John will be 9

Answer:

False, distributions having the same mean and standard deviation can have very different shape of distribution.

Answer: d = 40 - 5/2t; 1995

Hope it helps :)

Answer:

franchise fast-food restaurant located in the Northeast specializing in halfpound hamburgers, fish sandwiches, and chicken sandwiches. Soft drinks and French fries are

also available. The planning department of Bun-and-Run Inc. reports that the distribution of

daily sales for restaurants follows the normal distribution and that the population standard

deviation is $3,000. A sample of 40 showed the mean daily sales to be $20,000. Find the 95%

confidence interval for the population mean.

The cost per unit for each product is given as:
x ≈ 0.0067; and

y ≈ 0.0041. See explanation below.

Given that the current production:

Current cost of production is given as:

Current Total Cost = 150y + 245x where;

if doubling the batch sizes will reduce the cost per unit by 50% then the new cost equation will be:

Thus, New Total Cost of production = (150 x 2) (y/2) + (245 x 2) (x/2)

= (300)(y/2) + (490) (x/2)

Since we are looking for the cost per unit of each product:

f(x) = 300 * (x/2)..........Unit cost of Model Gold

If we make x subject of the formula, then we arrive at:
1/300 = x/2
x = (1/300) * 2

x = 0.00666666666

x ≈ 0.0067

f(x) = 490* (x/2)

If we make y subject of the formula, then we arrive at:

i/490 = y/2

y = (1/490) * 2

y = 0.00408163265306122448979591836735

y ≈ 0.0041

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The next step in the series is choice D.

Answer:

D

Step-by-step explanation:

if we define the diagrams in terms of their rows and columns, then

1st : 2 by 1

2nd : 3 by 2

3rd : 4 by 3

note that the rows and columns both increase by 1

then the next likely diagram is

5 by 4 , that is diagram D

The expression that represents this inequality must relate both temperatures, then it would look like this: -40°F < x < 140°F.

To express this situation in an inequality we must include the temperature values. Additionally, we must include the greater than (>) or less than (<) symbols to relate the values.

According to the above, the expression would look like this:

Note: This question is incomplete because some information is missing. Here is the information:

A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form.

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Answer:

3,n-1>9

3>n2+9

3>n11 is ans

Answer: 59

Step-by-step explanation:

The measure of an arc is equal to the measure of the central angle intercepted by it.

The packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

Trajectory is the path followed by a moving object when it is falling under gravitational force.

x = 90 t

y = -4.9 t²2 + 4500

t ≥ 0

y = 0

-4.9t² + 4500 = 0

4.9t²2 = 4500

[tex]\rm t = \sqrt {\dfrac{4500}{4.9}}[/tex]

t = 30.30 seconds

substituting the value to determine the horizontal distance

x = 120 * 30.30

x = 3636.55 meters

Therefore the packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

The complete question is

a drone traveling horizontally at 120m s over a flat ground at an elevation of 4500 meters must drop an emergency package on a target on the ground the trajectory of the package is given by x 120t y 4.9t 2 4500 where the origin is the point on the ground directly beneath the drone at the moment of release. How many horizontal meters before the target should the package be released in order to hit the target? Round to the nearest meter.

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Answer:

Step-by-step explanation:

Answer:

No, the total is 43.5 which is below 50.

Step-by-step explanation:

English: 25% × 48 = 12

Mathematics: 50% × 35 = 17.5

Typing: 5% × 80 = 4

Accounting 20% × 50 = 10

12 + 17.5 + 4 + 10 = 43.5

Total: 43.5

Passing: 50

Answer: No. The total is too low.

If we know that h(x) = (f ° g) (x) = √x + 5, then f(x) = x + 5 and g(x) = √x by applying the binary operation of composition between two functions.

Let be f and g two functions, h is a composition of f with respect to g when the input variable of f is equal to g.  The composed function is h(x) = √x + 5 and there may be more than a solution. One of these solutions are f(x) = x + 5 and g(x) = √x.

If we know that h(x) = (f ° g) (x) = √x + 5, then f(x) = x + 5 and g(x) = √x by applying the binary operation of composition between two functions.

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Answer:

6

Step-by-step explanation:

I presume you meant

[tex]g(x) = \sqrt{x + 32} \\ g(32) = \sqrt{32 + 4} \\ g(32) = \sqrt{36} \\ g(32) = 6[/tex]

Answer:

[tex]11 - 2 {}^{3} [/tex]

[tex]11 - 8[/tex]

[tex]3[/tex]

Answer:

Step-by-step explanation:The answer is 45

Answer:

24 square units

Step-by-step explanation:

1) the area can be calculated using the formula:

A=0.5*a*h, where a- base, h-height;

2) if a=8, h=6, then the required area is:

A=0.5*8*6=24 [units²].

Answer: 24 square units

Step-by-step explanation:

The base: 8

The height: 6

The area: 8 x 6 / 2 = 24

/ stands for divided by

Answer:

[tex]x^{2}-\frac{3}{2} x-\frac{7}{16} =0[/tex]

Step-by-step explanation:

[tex]\begin{cases}\alpha -\beta =2\\ \alpha^{2} -\beta^{2} =3\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}\alpha -\beta =2&\\ \left( \alpha +\beta \right) \left( \alpha -\beta \right) =3&\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}\alpha -\beta =2&\\ \alpha +\beta =\frac{3}{2} &\end{cases}[/tex]

Then

2α = 2 + 3/2 = 7/2

2β = (3/2) - 2 = -1/2

Then

Then

α = 7/4

β = -1/4

Then

a quadratic equation with root α and β can be :

[tex]\left( x+\frac{1}{4} \right) \left( x-\frac{7}{4} \right) =0[/tex]

[tex]\Longrightarrow x^{2}-\frac{3}{2} x-\frac{7}{16} =0[/tex]

The expression in factored form for the polynomial of least possible degree graphed will be y(x) = (x + 3)(x + 2 )(x - 1 )(x - 3 )

From the graph, the zeros of the polynomial of given graph are:

x = -3

x = -2

x = 1

x = 3

Equate the above equations to zero

x + 3 = 0

x + 2 = 0

x - 1 = 0

x - 3 = 0

Multiply the equations

(x + 3)(x + 2 )(x - 1 )(x - 3 ) = 0

Express as a function gives;

y = (x + 3)(x + 2 )(x - 1 )(x - 3 )

Hence, the factored form of the polynomial will be y = (x + 3)(x + 2 )(x - 1 )(x - 3 )

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