What is the density of the oak board

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(25) - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) {}^{2} - log_{6}(5) [/tex]

[ property : x² = 2 log x ]

[tex]\qquad \tt \rightarrow \: 2 \: log_{6}(5) {}^{} - log_{6}(5) [/tex]

[tex]\qquad \tt \rightarrow \: log_{6}(5) [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

yes

Step-by-step explanation:

because bank

Answer:

Charles Babbage

Step-by-step explanation:

Answer: Hope this may help you

Charles Babbage, I think

Step-by-step explanation:

Charles Babbage is sometimes referred to as the father of computers.

Using the Empirical Rule, it is found that:

It states that, for a normally distributed random variable:

Considering the mean of 88% and the standard deviation of 4%, the scores that are within 2 standard deviations of the mean are:

68% are within 1 standard deviation of the mean, hence, out of 100:

0.68 x 100% = 68 scores.

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Answer: 10

Step-by-step explanation:

[tex]\frac{5}{x+5} (2x-5(2))\\\frac{5}{x+5} (2x-10)\\\frac{10x-50}{x+5}\\\frac{10(x+5)}{x+5} \\\frac{10}{1} \\10[/tex]

Answer:

y = 2/3x + 4/3

Step-by-step explanation:

Voy a suponer que necesitas resolver para y.

2x + 3y = 4

3y = -2x + 4

y = -2/3x + 4/3

Press the Linear Regression button to generate the regression line.

We have given that, regression line using a regression calculator

We have to determine how to graph a scatterplot and its regression line using a regression calculator.

Before entering data into the regression calculator, it is important to determine which variable should be associated with the x-axis and which with the y-axis.

Regression analysis is a set of statistical processes for estimating the relationships between a dependent variable and one or more independent variables.

Enter the data pairs.

Press the Linear Regression button to generate the regression line.

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Answer:

3x* 2x^2 +3x*5 -2 * 2x^2  -2 *5

Step-by-step explanation:

(3x-2)(2x^2+5)

We can FOIL to find the expansion

First 3x* 2x^2 = 6x^3

Outer 3x*5 = 15x

Inner -2 * 2x^2 = -4x^2

Last -2 *5 = -10

Add all the terms together

3x* 2x^2 +3x*5 -2 * 2x^2  -2 *5

Answer:

3x • 2x^2 + 3x • 5 + (–2) • 2x^2 + (–2) • 5

Step-by-step explanation:

other answer was right

The difference of two squares expression is (d) 25a^2-36b^6

The difference of two squares is represented as:

x^2 - y^2

Where x and y are perfect square expressions.

From the list of options, we have:

25a^2-36b^6

The terms of the above expression are perfect squares

i.e.

25a^2 = (5a)^2

36b^6 = (6b^3)^2

Hence, the difference of two squares expression is (d) 25a^2-36b^6

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(a) [tex]\frac{6-8}{-4-4}=\frac{-2}{-8}=\boxed{1/4}[/tex]

(b) Using the point (4,8), we get [tex]\boxed{y-8=\frac{1}{4}(x-4)}[/tex]

(c) Rearranging into slope-intercept form,

[tex]y-8=\frac{1}{4}(x-4)\\\\y-8=\frac{1}{4}x-1\\\\\boxed{y=\frac{1}{4}x+7}[/tex]

Answer:

f'(x) = 7x^4 (5 ln(x) + 1) + x^2

Explanation:

[tex]\sf Let \ f(x)=7x^5 ln(x) + \dfrac{1}{3} x^3[/tex]

Properties used while differentiating:

[tex]i) \quad \sf \dfrac{d}{dx} (ln(x)) = \dfrac{1}{x}[/tex]

[tex]ii) \quad \sf \dfrac{d}{dx} (x^n) = n(x)^{n-1}[/tex]

[tex]iii) \quad \sf \dfrac{d}{dx}(uv)=u \dfrac{dv}{dx}+v \dfrac{du}{dx}[/tex]

Begin solving:

f'(x) =

[tex]\Longrightarrow \sf \dfrac{d}{dx}\:\left(7x^5\:ln\left(x\right)\:+\:\dfrac{1}{3}\:\:x^3\right)[/tex]

[tex]\Longrightarrow \sf \dfrac{d}{dx}\:\left(7x^5\:ln\left(x\right)\right) + \dfrac{d}{dx}\left(\dfrac{1}{3}x^3\right)[/tex]

[tex]\Longrightarrow \sf \dfrac{d}{dx}(7x^5)\:\ \times ln\left(x\right) + \dfrac{d}{dx}(ln(x)) \times \ 7x^5 + \left(3\:\times \dfrac{1}{3}x^{3-1}\right)[/tex]

[tex]\Longrightarrow \sf 5(7x^{5-1})\:\times\ ln(x) + \dfrac{1}{x} \:\times\ 7x^5 \ + x^2[/tex]

[tex]\Longrightarrow \sf 35x^{4} ln(x) + \ 7x^4 \ + x^2[/tex]

[tex]\Longrightarrow \sf 7x^4(5 ln(x) + 1) \ + x^2[/tex]

Answer: [tex]x=5\sqrt{3}[/tex]

Step-by-step explanation:

As the triangle is equilateral, we know that all sides have a length of 10. Thus, if we consider either of the right triangles, we know they have legs of lengths 5 and x (since an altitude of an equilateral triangle bisects the side it is drawn to), and a hypotenuse of 10.

Thus, by the Pythagorean theorem,

[tex]5^{2}+x^{2}=10^{2}\\\\25+x^{2}=100\\\\x^{2}=75\\\\\boxed{x=5\sqrt{3}}[/tex]

The most appropriate Venn diagram is known to be option b in the image shown.

A Common multiples are known to be the multiples that are said to be common to two or that have more numbers in them.

The Least Common Multiple ( LCM ) is known to be a term that connote  the Lowest Common Multiple ( LCM ) and also that has the Least Common Divisor ( LCD).

From the image shown the lowest multiples are 5², 2⁶, 3 while the greatest common factor is 2⁶.

Option B is correct because the greatest common factor which is  2⁶ can only be found in the middle and this was gotten when you add:

2³ . 2³

Collect like terms

2 ³⁺³

2⁶

Therefore, the greatest common factor which is  2⁶

To get the  Least Common Multiple, one need to add all the factors in the Venn diagram which are therefore:

5², 2³ . 2³, 3

=5², 2 ³⁺³, 3

=5², 2⁶, 3

Therefore, The most appropriate Venn diagram is known to be option b in the image shown.

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Answer:

A or 19/5

Step-by-step explanation:

To solve first we isolate are variables so we distubte to get -2y-2+21=3y then we add 2y to the opposite side to get -2+21=5y. Then we add -2+21 to get 19 so are equation is 19=5y. Next we just divide 19 by 5 to get y=(19/5) or option A

The proportion that can be used to represent the given statement is [tex]\frac{3}{1} =\frac{12}{4}[/tex]

Given that there are 3 feet in 1 yard, which is equivalent to 12 feet in 4 yards.

In general, the term "proportion" refers to a part, share, or amount that is compared to a whole. According to the definition of proportion, two ratios are in proportion when they are equal.

We need to determine the proportion that can be used to represent this.

Now, 1 yard = 3 feet implies  4 yards = 12 feet.

The required proportion can be written as [tex]\frac{3}{1} =\frac{12}{4}[/tex].

Therefore, the proportion that can be used to represent the given statement is [tex]\frac{3}{1} =\frac{12}{4}[/tex].

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Answer:

So, the answer is 20

Step-by-step explanation:

[tex]f(x) = \frac{1}{2} x + 10 = = = > \\ f(x) - 10 = \frac{1}{2} x = = = > \\ 2f(x) - 20 = x = = = > \\ {f}^{ - 1} (y) = 2y - 20 = = = > {f}^{ - 1} (x) = 2x - 20[/tex]

The missing value of the inverse function is 20.

Option D is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto-one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

To find the inverse of a function, we usually replace f(x) with y, then solve for x in terms of y, and finally replace y with the inverse function notation h(x).

So let's do that with the given function:

f(x) = (1/2)x + 10

y = (1/2)x + 10

2y = x + 20 (multiply both sides by 2 to isolate x)

x = 2y - 20 (subtract 20 from both sides)

Now we can replace x with h(x) and y with x to get the inverse function:

h(x) = 2x - 20

Thus,

The missing value is 20.

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Answer:

L is not valid.

Step-by-step explanation:

For any triangle, the sum of the two legs must be greater than the hypotenuse. Otherwise the two legs would not be long enough to touch.

Answer:

L

Step-by-step explanation:

to add to the previous basically correct answer :

for a triangle the sum of any 2 sides must be greater than the third side (not just legs and Hypotenuse).

for all other options any combination of sum of 2 sides being bigger than the third side works.

but for L

2 + 5 = 7, which is smaller than the third side (8). so, this cannot be a triangle.

The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

[tex]\rm x^{2}+4y^{2}-2x+16y-19=0[/tex]

We can write the above equation as:

[tex]\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1[/tex]

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

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Answer:

It doesn't say anything about "Length" and "Width".

Step-by-step explanation:

Brainlest . Just press the .

Answer: We can take 2 common we could also write this as 2 times X plus y.

Step-by-step explanation:

The ordering-quantity that should be recommended will be 117 units.

The following can be deduced from the information given:

Demand = 679

Ordering cost = 7

Holding cost = 10%

Ordering quantity will be:

= ✓(2 × Demand × Ordering cost / Holding cost)

= ✓(2 × 679 × 7/0.1)

= ✓13580

= 116.53

= 117

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The equation in the vertex form of g(x) is:

[tex]g(x) = (x + 1)^2 - 38[/tex]

We know that g(x) is a translation of 2 units below and 3 units to the left of f(x).

So first, let's rewrite f(x) to its vertex form:

[tex]f(x) = x^2 - 4x - 32[/tex]

The vertex is at:

[tex]x = -(-4)/2*1 = 2[/tex]

The y-value of the vertex is:

[tex]f(2) = 2^2 - 4*2 - 32 = -36[/tex]

Then the vertex form of f(x) is:

[tex]f(x) = (x - 2)^2 - 36[/tex]

If we move this vertex 2 units below, and 3 units to the left, then we have:

[tex]g(x) = f(x +3) - 2\\\\g(x) = (x - 2 + 3)^2 - 36 - 2\\\\g(x) = (x + 1)^2 - 38[/tex]

That is the equation for g(x) in vertex form.

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Answer:

I believe you forgot to add a picture

The correct statement compares the means of the data in the dot plots is option C; the mode is greater for Mrs. Ramos’s class.

Median represents the middle value of the given data when arranged in a particular order.

Mode is that number that appears most frequently in the given set of data.

Given;

The Number of pets in Mr. McIntyre’s class ;

0,0,0,0,0,1, 1, 1, 1, 1, 4, 4, 4, 4, 1,

Median = 1

Mode = 0 and 1

The Number of pets in Mrs. Ramos’s Class;

0, 1, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 3, 3, 3

Median = 3

Mode = 4 and 5

Hence, C; The mode is greater for Mrs. Ramos’s class.

The remaining part of the question is

"Which statement correctly compares the measures of center of the data in the dot plots?

The median is greater for Mr. McIntyre’s class.

The median is the same for both classes.

The mode is greater for Mrs. Ramos’s class.

The mode is the same for both classes."

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Answer:

10k.

Step-by-step explanation:

1) if for the 1st position can be used 0-9 digits (10 digits), for the 2d - 0-9 digits, for the 3d - 0-9 digits and for the 4th - 0-9 digits, then

2) the required number of pwd is: 10*10*10*10=10⁴=10000.

The definition for the graphed function is the one shown in option d:

y = -x + 2   if x < 1

y = -2x + 1   if x  ≥ 1.

Here we have a piecewise function, where for the first part we have a linear equation with a negative slope (for x < 1, we know that the symbol "<" must be used because of the open dot at the end of the line).

Then, we have another linear equation with a negative (and steeper) slope. This time there is a closed dot, so the domain for this second part is x ≥ 1.

With that we can conclude that the correct option is:

d:

y = -x + 2   if x < 1

y = -2x + 1   if x  ≥ 1.

Where you can see that the second part has a larger (in module) slope, and the domains are defined as we saw above.

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Answer: 8

Step-by-step explanation:

As corresponding sides of similar triangles are proportional,

[tex]\frac{RX}{RB}=\frac{XE}{BO}\\\\\frac{6}{15}=\frac{a}{20}\\\\a=20\left(\frac{6}{15} \right)=\boxed{8}[/tex]

An equation is formed when two equal expressions are equated together. The value of x in the equation [√(x+7)]-11=2 is 162.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution for x in the equation [√(x+7)]-11=2 can be solved as,

[tex]\sqrt{x+7}-11=2\\[/tex]

Using the addition property of equality,

[tex]\sqrt{x+7} -11+11= 2+11\\\\\\\sqrt{x+7} = 13[/tex]

Squaring both the sides of the equation,

x + 7 = 169

Using the subtraction property of equality,

x + 7 - 7 = 169 - 7

x = 162

Hence, the value of x in the equation [√(x+7)]-11=2 is 162.

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Answer:

y - 5 = -2(x + 3)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

Given:

point: (-3, 5)

slope (m): -2

The standard point-slope equation is

y - y₁ = m(x - x₁)

Plug in what you know.

y - (5) = -2(x - (-3))

Simplify.

y - 5 = -2(x + 3)

This is your equation.

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