What decides the amount of delay between shots on a digital camera?

In python:

i = 1

lst1 = ([])

lst2 = ([])

while i <= 5:

   person1 = int(input("Enter the salary individual 1 got in year {}".format(i)))

   person2 = int(input("Enter the salary individual 1 got in year {}".format(i)))

   lst1.append(person1)

   lst2.append(person2)

   i += 1

if sum(lst1) > sum(lst2):

   print("Individual 1 has the highest salary")

else:

   print("Individual 2 has the highest salary")

This works correctly if the two individuals do not end up with the same salary overall.

Answer:

All functions were written in python

addUpSquaresAndCubes Function

def addUpSquaresAndCubes(N):

    squares = 0

    cubes = 0

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

    return(squares, cubes)

sumOfSquares Function

def sumOfSquares(N):

    squares = 0

    for i in range(1, N+1):

         squares = squares + i**2

    return squares

sumOfCubes Function

def sumOfCubes(N):

    cubes = 0

    for i in range(1, N+1):

         cubes = cubes + i**3

    return cubes

Explanation:

Explaining the addUpSquaresAndCubes Function

This line defines the function

def addUpSquaresAndCubes(N):

The next two lines initializes squares and cubes to 0

    squares = 0

    cubes = 0

The following iteration adds up the squares and cubes from 1 to user input

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

This line returns the calculated squares and cubes

    return(squares, cubes)

The functions sumOfSquares and sumOfCubes are extract of the addUpSquaresAndCubes.

Hence, the same explanation (above) applies to both functions

Answer:

c. StringBuilder

Explanation:

An alternative to the String class would be the StringBuilder Class. This class uses Strings as objects and allows you to mix and match different strings as well as adding, removing, implementing,  and modifying strings themselves as though they were similar to an array. Unlike the string class StringBuilder allows you to modify and work with a combination of strings in the same piece of data as opposed to having various objects and copying pieces which would take up more memory.

Answer:

Here is the Python program:

def MyersTriangle(a, b, c):  #method to test triangles

    if not(isinstance(a, int) and isinstance(b, int) and isinstance(c, int)):  #checks if values are of type int

         return 'Enter integer values'  

    elif a==0 or b==0 or c==0: #checks if any value is equal to 0

         return 'Enter integer values greater than 0'

    elif a<0 or b<0 or c <0:  #checks if any value is less than 0

         return 'All values must be positive'

    elif not (a+b>=c and b+c>=a and c+a>=b):  #checks if triangle is valid

         return 'Not a valid triangle'

    elif a == b == c:  #checks if triangle is equilateral

         return 'triangle is equilateral'

    elif a == b or b == c:  #checks if triangle is isoceles

         return 'triangle is isoceles'

    elif a != b and a != c and b != c:  #checks if triangle is scalene

         return 'triangle is scalene'        

#test cases

print(MyersTriangle(2.4,7.5,8.7))  

print(MyersTriangle(0,0,0))

print(MyersTriangle(-1,5,4))

print(MyersTriangle(10,10,25))

print(MyersTriangle(5,5,5))

print(MyersTriangle(3,3,4))

print(MyersTriangle(3,4,5))

Explanation:

The program uses if elif conditions to check:

if the values are integers: this is checked by using isinstance method that checks if values belongs to a particular int. If this returns true then values are integers otherwise not

if values are not 0: this is checked by using logical operator or between each variable which checks if any of the values is 0

if values are not negative: This is checked by using relational operator < which means the values are less than 0

if values make a valid triangle: this is checked by the rule that the sum of two sided of the triangle is greater than or equal to the third side.

and then checks if the triangle is scalene, isosceles, or equilateral: This is checked by the following rules:

For scalene all three sides are unequal in length

For isosceles any of the two sides are equal in length

For equilateral all sides should be equal in length.

The screenshot of the program along with the output is attached.

Answer:

names, email addresses, subjects of e-mails

Explanation:

Answer:

names

e-mail addresses

physical addresses

fax numbers

Explanation:

correct answers

Answer:

c.a system that start with a process, them output resources in the input

Answer:

me

Explanation:

yea not me

Explanation:

Answer:

Slower

Explanation:

Answer:

Written in Python:

import re

name = input("Name: ")

print(re.sub("[ ]", ", ", name))

Explanation:

This line imports the regular expression library

import re

This line prompts user for input

name = input("Name: ")

This line replace the space with comma and prints the output

print(re.sub("[ ]", ", ", name))

Answer:

text box

Explanation:

on edge 2020

Answer:

A- text box

Explanation: ;)

Answer: Did you ever think of a mirror?

Explanation: Not trying to be rude about it.

Answer:

Written in Python

num = int(input("Items: "))

myitems = []

total = 0

for i in range(0, num):

     item = int(input("Number: "))

     myitems.append(item)

     total = total + item

average = total/num

print("Average: "+str(average))

count = 0

for i in range(0,num):

     if myitems[i] > average:

           count = count+1

print("There are "+str(count)+" items greater than average")

Explanation:

This prompts user for number of items

num = int(input("Items: "))

This creates an empty list

myitems = []

This initializes total to 0

total = 0

The following iteration gets user input for each item and also calculates the total

for i in range(0, num):

     item = int(input("Number: "))

     myitems.append(item)

     total = total + item

This calculates the average

average = total/num

This prints the average

print("Average: "+str(average))

This initializes count to 0

count = 0

The following iteration counts items greater than average

for i in range(0,num):

     if myitems[i] > average:

           count = count+1

This prints the count of items greater than average

print("There are "+str(count)+" items greater than average")

Answer:

logging off one of the computers, and then logging back on

Answer:

the last one:

logging off one of the computers, and then logging back on

Explanation:

if something goes wrong on an electronic device you can reboot it and it should eventually work.

have a nice day

Answer:

Earned value is a measure which is used on projects to determine the value of work which has been completed to date, in order to understand how the project is performing on a cost and schedule basis. At the beginning of a project, a project manager or company will determine their budget at completion (BAC) or planned value (PV).

Explanation:

the answer is:

c. which methods of solving problems and interacting with others he favors.

Answer:

C

Explanation:

Answer:

Single use i think

Explanation:

Answer: im pretty sure on a network.

Explanation:

Answer:

Webmail

Explanation:

Got it right on a test

Answer:

a

Explanation:

Yes, true.

Shortest Remaining Time First, also popularly referred to by the acronym SRTF, is a type of scheduling algorithm, used in operating systems. Other times it's not called by its name nor its acronym, it is called the preemptive version of SJF scheduling algorithm. The SJF scheduling algorithm is another type of scheduling algorithm.

The Shortest Remaining Time First has been touted by many to be faster than the SJF

The answer to the question which asks if the Shortest Remaining Time First is the best preemptive scheduling algorithm that can be implemented in an Operating System is:

This refers to the type of scheduling algorithm which is used to schedule tasks that would be executed in the processing unit in an Operating System based on the shortest time taken to execute the task.

With this in mind, we can see that this is the best preemptive scheduling algorithm that can be implemented in an Operating System because it makes task execution faster.

Read more about scheduling algorithm here:
https://brainly.com/question/15191620

Answer:

Here is the function:

def NumberOfSongs(word):  # function definition    

   count=0  #count the occurrence of word in song

   for song in lyrics['Lyrics']:  #iterates through song lyrics

       if word in str(song):  #if word is in the song

           count=count+1  #adds 1 to the count

   if count!=0:  #if word occurs in the songs

       return f'{str(count)} songs were found to contain {word} in this dataset'  #display the count of the word in the song

   else:  #if word does not appear in any song

       return f'No songs were found to contain the words:{word}'  #returns this message if no songs were found with given word

print(NumberOfSongs('like')) #calls method with the word like given as parameter to it

Explanation:

You can add the csv file this way:

import pandas as pd

lyrics = pd.read_csv("lyrics.csv", encoding="cp1252")

Now you can use the NumberOfSongs method which iterates through the Lyrics of lyrics.csv and find if any of the songs in the file contains the specified word.

The screenshot of program along with its output is attached. Since the file was not provided i have created a csv file. You can add your own file instead of lyrics.csv

When you check to see how much RAM, or temporary storage you have available, you are checking your primary memory.

The correct option is first.

Drive provides a storage space and speed for processing the data in the drive on the personal computers or laptops at low cost.

RAM, also known as Random Access Memory, is storage drive which is temporary but primary.

So, RAM is considered as primary memory.

Thus, when you check to see how much RAM, or temporary storage you have available, you are checking your primary memory.

Learn more about drive.

https://brainly.com/question/10677358

#SPJ2

Answer:

The function in Python is as follows:

def match(f1,f2):

    f3 = []

    for i in range(0,len(f1)):

         if f1[i] == f2[i]:

              f3.append("True")

         else:

         f3.append("False")

    print(f3)

Explanation:

This line defines the function

def match(f1,f2):

This line creates an empty list

    f3 = []

This line is a loop that iterates through the lists f1 and f2

    for i in range(0,len(f1)):

The following if statement checks if corresponding elements of both lists are the same

         if f1[i] == f2[i]:

              f3.append("True")

If otherwise, this is executed

         else:

         f3.append("False")

This prints the newly generated list

    print(f3)

Answer:

What?

Explanation:

Answer:

Procter and Gamble is an organization that uses supercomputing.

Explanation:

Supercomputing refers to the use of high-performance computers in the development and production of items. Procter and Gamble is a company known for the production of many household items and personal care products. Uses and advantages of supercomputing to this company include;

1. Testing virtual prototypes of substances used in production: This is a faster way of developing products that are sustainable because many prototypes can be examined with the help of computers and the best chosen for production.

2. Developing unique designs of products: Supercomputers allow for the development of high-quality designs which include the internal and external designs of products.

3. Simulation of many molecules: Molecules such as those involved in the production of surfactants can be analyzed to understand how they work with the aid of supercomputers.

4. Computational fluid dynamics: This helps the scientists to understand how fluid works using numerical analysis and the structure of compounds.

The designs and products obtained through supercomputing are a source of competitive advantage because the company can make high-quality and unique products that appeal to customers and meet the latest trends. This would increase their marketability and give them an advantage over companies that do not have access to these computers.

Reference:   The Department of Energy. (2009) High-Performance Computing Case Study. Procter & Gamble's Story of Suds, Soaps, Simulations, and Supercomputers

Answer:

#include <iostream>

#iclude <iomanip>

#include <algorithm>

using namespace std;

int main(){

int num1, num2, num3,

int sum, maxDrop, minDrop = 0;

float avg;

string end = "\n";

cout << " Enter the leaf drop for September: ";

cin >> num1 >> endl = end;

cout << "Enter the leaf drop for October: ";

cin >> num2 >> endl = end;

cout << "Enter the leaf drop for November: ";

cin >> num3 >> endl = end;

int numbers[3] = {num1, num2, num3} ;

string month[3] = { "September", "October", "November"}

for ( int i =0; i < 3; i++) {

 if (numbers[i] < 0) {

   cout << "Error: all leaf counts must be at least zero\n";

   cout << "End of Maple Marvels\n";

   cout << "Welcome to Maple Marvels";

   break;

 } else if (number[i] >= 0 ) {

     sum += number[i] ;

   }

}

for (int i = 0; i < 3; i++){

 cout << month[i] << " leaf drop: " << numbers[i] << endl = end;

}

cout << "Total drop: " << sum << endl = end;

cout << setprecision(3) << fixed;

cout << "Average drop: " << sum / 3<< endl = end;

maxDrop = max( num1, num2, num3);

minDrop = min(num1, num2, num3);

int n = sizeof(numbers)/sizeof(numbers[0]);

auto itr = find(number, number + n, maxDrop);

cout << "Highest drop: "<< month[ distance(numbers, itr) ] << endl = end;

auto itr1 = find(number, number + n, minDrop);

cout << "Lowest drop: " << month[ distance(numbers, itr1) ] << endl = end;

cout << "End of Maple Marvels";

Explanation:

The C++ soucre code above receives three integer user input and calculates the total number, average, minimum and maximum number of leaf drop per month, if the input isn't less than zero.

Answer:

Written in C++

int sum(int arr[], int size) {

 int total = 0;      

 if(size>=3)  {

  for (int i = 0; i < size; ++i) {

     if(i%3 == 0)      {

     total += arr[i];    

     }

  }

 }

  return total;

}

Explanation:

This line defines the function

int sum(int arr[], int size) {

This line initializes sum to 0

 int total = 0;      

This line checks if size is at least 3

 if(size>=3)  {

This loop iterates through the array

  for (int i = 0; i < size; ++i) {

The following adds multiples of 3

     if(i%3 == 0)      {

     total += arr[i];    

     }

  }

 }

This returns the calculated sum

  return total;

}

See attachment for full program

Answer:

Answers are given by the users, so reliable information varies. Usually, you can find if it is reliable by checking other websites to see if the information matches up with other reliable websites.

Explanation:

Answer:

zip_codes = ["11111", "22222", "33333", "44444", "55555", "66666", "77777", "88888", "99999", "00000"]

charges = [3.2, 4, 1.95, 5.7, 4.3, 2.5, 3.8, 5.1, 6.6, 7.3]

deliver = False

index = -1

zip_code = input("Enter the zip code: ")

for i in range(len(zip_codes)):

   if zip_code == zip_codes[i]:

       deliver = True

       index = i

       break

if deliver:

       print("The charge of delivery to " + zip_codes[index] + " is $" + str(charges[index]))

else:

   print("There is no delivery to " + zip_code)

Explanation:

*The code is in Python.

Initialize the zip_codes array with 10 zip codes

Initialize the charges array with 10 corresponding values

Initialize the deliver as False, this will be used to check if the zip code is in the zip_codes

Initialize the index, this will be used if the zip code is a valid one, we will store its index

Ask the user to enter the zip_code

Create a for loop that iterates the length of the zip_codes array. Inside the loop:

Check if the zip_code is equal to the any of the items in the zip_codes. If it is, set the deliver as True, set the index as i, and break

When the loop is done, check the deliver. If it is True, then print the charge of the delivery. Otherwise, print that there is no delivery to that zip code