Suppose you use bottles and balloons to run an experiment to measure the amount of metabolism by yeast. One of your bottles has black coffee and yeast, with a balloon sealing the top of the bottle. After 3 hours, you note that the balloon has not inflated at all. What is the most likely reason that it did not inflate
The yeast was not able to metabolize the sugar in black coffee and so, no carbon dioxide was produced.
What is the product of the action of glucose on yeast?Yeast metabolizes sugar or glucose to produce alcohol and carbon dioxide.
The carbon dioxide produced is responsible for the raising action of yeast on dough and for the inflation of the balloon.
In the experiment, the possible reason why the balloon did not inflate is that the yeast was not able to metabolize the sugar in black coffee and so, no carbon dioxide was produced.
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When hydrated copper(II) sulfate crystals are heated, anhydrous copper(II) sulfate forms. A mass of 12.5 g of hydrated copper(II) sulfate crystals is heated in a crucible until all the water of crystallisation is removed.
A mass of 8.0 g of anhydrous copper(II) sulfate forms.
Calculate the formula of hydrated copper(II) sulfate CuSO4.nH2O
Show your working.
[Mr of CuSO4 = 159.5 Mr of H2O = 18]
Mass of water = g
Water of crystallization (n) =
Formula of hydrated copper(II) sulfate =
The formula of hydrated copper(II) sulfate is CuSO4.10H2O
What is the formula of the hydrated copper (ii) sulfate salt?The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
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(a) write the net acid-base reaction that occurs when hi is added to water. (use the lowest possible coefficients. omit states-of-matter in your answer.)
The net acid-base reaction that occurs when HI is added to water is HI(aq) + H2O(l) ⇄ H3O^+(aq) + I^-(aq).
What is an acid base reaction?A acid base reaction involves the transfer of a proton in the Bronsted- Lowry sense. In this case, the acid is the lone pair donor while the base is the lone pair acceptor.
Thus;
HI(aq) + H2O(l) ⇄ H3O^+(aq) + I^-(aq). This the net acid-base reaction that occurs when HI is added to water.
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The net acid-base reaction that takes place when HI is added to water is HI(aq) + H2O(l) ⇄ H3O^+(aq) + I^-(aq).
What is an acid-base reaction?
An acid-base reaction involves the shift of a proton in the Bronsted Lowry sense. The acid is the lone pair giver while the base is the lone pair acceptor(takes the lone pair). The acid and base reaction will rely upon the strength of the acid and base. This eventually means if the reaction is between a strong acid and a weak base then its result will differ from the reaction between a strong acid and a strong base or a weak acid and a weak base.
Therefore; HI(aq) + H2O(l) ⇄ H3O^+(aq) + I^-(aq).
The above-mentioned equation is the net acid-base reaction that occurs when HI is added to water.
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A 250.ml sample of water was
boiled to 97.0°C then placed on
the counter to cool. If the water
cooled to11.0°C, how much heat
did it lose? Remember the
specific heat of water is 4.184
J/g°C.
Answer: The solubility of this gaseous solute will be,
Explanation :
First, we have to calculate the concentration of solute.
Now we have to calculate Henry's law constant.
Using Henry's law :
where,
C = concentration of solute =
p = partial pressure = 27.59 kPa
= Henry's law constant =?
Now put all the given values in the above formula, and we get:
Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.
Therefore, the solubility of this gaseous solute will be,
Instructions: In this virtual lab, you will use a virtual spectrometer to analyze astronomical bodies in space. Record your hypothesis and spectrometric results in the lab report below. You will submit your completed report to your instructor.
The main function of using a virtual spectrometer in order to analyze astronomical bodies in space is to find the chemical composition of planets and stars.
What is a Virtual Spectrometer?This refers to the instrument that is used to observe the color separation of light in a controlled experiment.
Hence, we can see that another reason for the use of a virtual spectrometer to make an analysis of astronomical bodies is to indicate the speed and direction of a star or galaxy as it spreads incoming beams of light into different spectrums.
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Solve the given division and express the answer in terms of scientific notation. 4.8
x 104 by 1.6 × 10³ =
Whose view that matter is infinitely divisible was considered correct for most of the last two millennia?.
Aristotle and Democritus (to some extent) view that matter is infinitely divisible was considered correct for most of the last two millennia
What is Matter ?Anything that occupies space and have some mass is known as matter.
Aristotle believed that everything was comprised of earth, air, water, and fire, which were infinitely divisible.
Democritus stated that matter was subdivided into indivisible and immutable particles that created the appearance of change when they joined and separated from others.
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A, B, C, or D, thanks for the help
According to the label the true statement about the following substance is option c. It does not pose a health risk
What are lab labels ?
Specially designed labels with particularly specialised adhesive qualities are called "lab labels." In the pharmaceutical or medical industry, as well as in laboratories, they are used for labelling. For the labelling of tubes, test tubes, blood bags, and other types of vessels, special laboratory labels are created.
Labels on chemicals
The identify of the hazardous chemical(s) in the container (for example, chemical name) and the dangers present must both be listed on this label. This warning about hazards can be distributed in a variety of ways. Employers want to choose a solution that will function in each place.
The following label indicates that the chemical does not pose a health risk.
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a serving of a particular fruit dessert contains 20.0 g of sugar. if all the sugar is sucrose, c12h22o11, how many molecules of sugar are present in this serving?
Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Avogadro's NumberAvogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Molecules of sugar in this caseIn first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?
[tex]amount of moles=\frac{20 gramsx1 mole}{342 grams}[/tex]
amount of moles= 0.058 moles
Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?
amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole
amount of molecules= 3.49334×10²² molecules
Finally, 3.49334×10²² molecules of sucrose are present.
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All of the following are physical properties except a. density b. colour c. reaction with oxygen d. melting point
Answer:
C
Explanation:
a, b and d are physical properties ..... the compound or element in question has not changed its identity
c when combined with oxygen, it has changed to a different compound via CHEMICAL property.
You are trying to determine the
mass of sodium chloride required to
create a 0.875 m solution in 534 g of
water. How many moles of NaCl are
required?
Answer:
Answer:
Mass = 27.291 g
Explanation:
Given data:
Mass of sodium chloride = ?
Mass of water = 534 g
Molality = 0.875 m
Solution:
Molality:
It is the number of moles of solute into kilogram of solvent.
Formula:
Molality = number of moles of solute / kilogram solvent
Mathematical expression:
m = n/kg
Now we will convert the g into kg.
Mass of water = 534 g× 1kg/1000 g = 0.534 kg
Now we will put the values in formula.
0.875 m = n / 0.534 kg
n = 0.467 mol
Now we will calculate the mass of sodium chloride:
Mass = number of moles × molar mass
Mass = 0.467 mol × 58.44 g/mol
Mass = 27.291 g
Which statement best describes a physical change?
Explanation:
A physical change is one which can be reversed.it also does not produce any new substance.
changes in state such as the melting of a solid, the freezing and vaporization of a liquid as well as changes In shape are examples of physical changes
Hello can someone help me please and thanksss
the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]. D
How to find the parabolaGiven the focus(6,2) and the directrix, y = 0
Use the formula
[tex]\sqrt{(x-6)^{2} + (y-2)^{2} } }[/tex] = (y - 0)
Find the square of both sides, square root is removed from the side with it and square added on the other side
[tex](x-6)^2 + (y-2)^2 = (y- 0)^{2}[/tex]
Expand the expression and bring all terms to one side
[tex]x^{2} - 6x - 6x + 36 +y^{2} -2y- 2y +4[/tex] = [tex]y^{2} - 0[/tex]
Collect like terms
[tex]x^{2} - 12x -4y + 40 = 0[/tex]
Make 'y' the subject of the formula
[tex]4y = x^{2} - 12x + 40[/tex]
Divide through by 4 and substrate 4 from 40 to give a perfect quadratic equation
[tex]y = 1/4( x^{2} - 12x + 36) + 4[/tex]
1/4 is dividing the quadratic equation [tex]x^2 - 12x +36[/tex]
Then divide factor by 4 to give 1, this is so because of the nature of the options given
[tex]y = 1/4( x^{2} -6x -6x +36) + 1[/tex]
Simplify the expanded quadratic equation
[tex]y = x (x -6) - 6 (x- 6)[/tex], we have [tex](x - 6) ^2[/tex]
Then insert in place into previous equation
[tex]y = 1/4 (x-6)^2 + 1[/tex]
Thus, the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]
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Calculate the root mean square velocity of I2(g) at 373 K.
From the calculations, the root mean square speed is 6.1 m/s.
What is the root mean square speed?The root mean square speed of a gas is obtained by the use of the formula;
V rms = √3RT/M
Where;
R = gas constant
T = temperature
M = molar mass
V rms =√3 * 8.314 * 373/254
V rms =6.1 m/s
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Which of the following reactions would result in decreased entropy?
Q A. CO,(s) → CO2(g)
OB. H₂O(g) → H₂O()
OC. 203(g) → 30₂(g)
D. N₂204(g) → 2NO₂(g)
The reaction that would result in decreased entropy is : ( A ) CO(s) → CO2(g)
What are Endothermic reactionsReactions that absorb heat from its surroundings are known as endothermic reactions, Endothermic reactions result in a decreased entropy as the temperature of the surrounding becomes lower than the temperature of the container where the reaction occurs.
Examples of endothermic reactions are : melting and evaporation which results in the change of state from solid to liquid or from solid to gaseous state.
Hence we can conclude that The reaction that would result in decreased entropy is : ( A ) CO(s) → CO2(g)
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anyone? got an answer
6. How many grams are present in 13.2 moles of O₂?
Answer:
422.3868 Grams
Explanation:
13.2 (MOLES) * 31.999 (Dioxygen's Molar Mass) = 422.3868 (Grams Present)
Using a ph meter, you find the ph of an unknown solution to be 8. 0. How would you describe this solution?.
Answer:
Just Barely Base/Neutral
Explanation:
a pH of 8.0 is greater than Neutral (7.0) but is still neutral due to it being more neutral than a base
how is uranus and saturn similar
Answer:
Like Saturn, Uranus has rings and moons. But unlike Saturn — and indeed every other planet in the solar system — the ice giant is tipped on its side. In other words, rather than spinning like a top as it circles the sun, Uranus rolls around on its side.
Explanation:
What is the simplest method of determining the composition of a compound?
Answer:
Chemical formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound. If a compound's chemical formula cannot be reduced anymore, then the empirical formula is the same as the chemical formula.
please give me brainliest
Brainliest to first decent answer
What is the chemical formula for the molecule represented by the model?
CHO
C4H9O2
C4H8O
C3H8O2
The correct formula of the molecule is C4H9O2.
What is a model?The model of a compound is a representation of the molecule. It gives us an idea of what the molecule looks like as well as its molecular formula.
Looking at the structure of the compound as shown in the model in the question, the correct formula of the molecule is C4H9O2.
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Answer:C4H9O2.
Explanation:
For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entropy of the reactants is 0.2 kJ/K. The entropy of the products is 0.3 kJ/K. The temperature of the reaction is 25 degrees Celsius. What can you conclude about this reaction
Answer:
For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entropy of the reactants is 0.2 kJ/K. The entropy of the products is 0.3 kJ/K. The temperature of the reaction is 25oC. What can you conclude about this reaction?
It is exergonic
It is endergonic
it is a redox reaction
It is being catalyzed by an enzyme
The ideal gas law only approximates the behaviour of real gases. The conditions
under which the ideal gas law is MOST accurate are
a. Low pressure and high temperature
b. Low pressure and low temperature
c. High pressure and high temperature
d. High pressure and low temperature
Select the correct answer.
Which substance in this redox reaction is the oxidizing agent?
Cu + 2AgNO3 → 2Ag + Cu(NO3)2
A.
N
B.
AgNO3
C.
Cu
D.
NO3−
E.
Cu(NO3)2
Reset Next
Post Test: Chemical Reactions
© 2022 Edmentum. All rights reserved.
Answer:
CU
Explanation:
Cu is the correct answer if I'm correct
How many moles of na2so4 are present in 284.078 grams of na2so4?
a. 2
b. 3
c. 5
d. 6
Changes in which measurements do not shift the equilibrium of a chemical system
Any Change in the amount of an inert gas into a gas-phase equilibrium at constant volume does not result in a shift of the equilibrium of a chemical system. This follows the equilibrium law.
What is Equilibrium law ?According to this principle, Adding an inert gas into a gas-phase equilibrium at constant volume does not result in a shift.
This is because the addition of a non-reactive gas does not change the partial pressures of the other gases in the container.
While the total pressure of the system increases, the total pressure does not have any effect on the equilibrium constant.
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Please Answer!!!!
Which equation is balanced?
A) H₂+ O2 → H₂O + O2
B) 4H2₂+ O2 → H₂O + O
C) 2H₂ + O2 → 2H₂O
D) H₂ + O2 → H₂O
Option C is the correct answer
2H₂ + O2 → 2H₂OIn LHSNo. of hydrogen atoms is 4No. of oxygen atoms is 2In RHS No. of hydrogen atoms is 4No. of oxygen atoms is 2Hence , LHS = RHS
A balanced equation obey the law of conservation of mass. According to this law mass can neither be created nor be destroyed. Among the given options, the balanced equation is 2H₂ + O₂ → 2H₂O. The correct option is C.
What is a balanced equation?A chemical equation in which the number of atoms of reactants and products are equal on both sides of the equation is defined as the balanced chemical equation. The numbers which are used to balance the equation are called the coefficients.
The coefficients are generally placed in front of the formulas. The substances on the left hand side are called the reactants and the substances on the right hand side are called the products.
Here the balanced equation is:
2H₂ + O₂ → 2H₂O
The number of 'H' and 'O' atoms are equal on both sides.
Thus the correct option is C.
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How many grams Fe2O3 would be
required to make 187 g Fe?
Fe₂O3 + 3CO → 2Fe + 3CO₂
266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
How to calculate mass?The mass of a product or reactant can be calculated using stoichiometry as follows:
According to this question, iron oxide reacts with carbon monoxide as follows:
Fe₂O3 + 3CO → 2Fe + 3CO₂
1 mole of Fe2O3 produces 2 moles of Fe
Moles of Fe = 187/56 = 3.34mol
3.34/2 = 1.67 moles of Fe2O3 will be required to produce 3.34 moles of Fe.
mass of Fe2O3 = 1.67 mol × 159.69 g/mol = 266.63g
Therefore, 266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.
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An electron on an energy level has an energy of 16.32 x 10−19 J. It moves to another level by absorbing 5.4 x 10−19 J of energy. Which of the following descriptions most likely explains what occurred?
The electron moved down to an energy level and has an energy of 10.92 x 10−19 J.
The electron moved down to an energy level and has an energy of 21.72 x 10−19 J.
The electron moved up to an energy level and has an energy of 10.92 x 10−19 J.
The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Answer:
The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Explanation:
i know
Answer:
D) The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
Explanation:
I took the test and got it right.
Task 2. Protecting Your Model Village from Tsunamis In this task, you will design a model village to withstand the effects of a tsunami. Estimated time to complete: 1 hour You will need the following materials: 2 pieces of printer paper, 8 inches × 11 inches 2 pieces of card stock, 8 inches × 11 inches 1 piece of cardboard, 8 inches × 11 inches a long, shallow plastic container, around 30 inches long, 15 inches wide, and 5 inches deep tape or glue a small plate or tray water a ruler a small bag of sand, about 2 pounds Hypothesis and Data Collection
Part A Before you design your model village, write down the problems you observed in task 1. What were the largest risks to the community? What happened to the homes?
Part B Design a model village that addresses the problems you identified. Consider the following questions: Does elevation play a factor? If so, can the elevation be changed to protect the homes? Could the residents build a structure that would prevent a tsunami from reaching the community? What would this structure look like? How would the residents build it? What could limit the erosion of the beach?
Part C After you design your model, build your homes and place them in the same positions as they were in task 1. Build any additional structures you think will help protect these homes. Repeat the tsunami experiment from task 1, pushing the waves three to four times.
Analyze and Extend Part A Did your results match your predictions about the additional structure protecting the homes?
Part B To prevent damage from natural hazards, scientists must consider the best ways to keep people safe while also considering practicality in terms of cost, interference of new structures in day-to-day life, and other such factors. If your plan worked, was it a practical solution for the community? Can you think of any downsides to your plan? If it didn’t work, how would you improve your plan? Can you foresee any problems with executing your plan?
Part C. Tsunami evacuation plans often consider the elevation of the community and its distance from the shoreline when deciding which towns to evacuate. How could this data help in building new homes and communities along coastal areas that are prone to tsunamis?
Part D
The home in the picture below is from a tsunami-prone area. Based on the results of your experiment, do you think the structure of this home would protect against tsunamis? I'LL GIVE BRAINLIEST TOO.
The structure of this home would protect against tsunamis due to its height and hard structure.
Does the structure of this home would protect against tsunamis?Yes, in my opinion, the structure of this home would protect against tsunamis because of 8 foot tall wall that is present around the house. This wall is enough to protect the house from tsunamis due to its long height and hard composition.
So we can conclude that the structure of this home would protect against tsunamis due to its height and hard structure.
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