What are some of the skills required to play floor hockey?​

hope this helps you !

Answer:

It is called reverberation.

Explanation:

The phenomenon of prolongation of sound is the process in which sound produced is reflected from plane surfaces in a continuous manner, which leads to reverberation of sound waves. It can also be referred to as a condition of continuous echo production.

It occurs when sound produced get reflected from a hard plane surface, and in the process hits another surface and another reflection occurs. This continuous reflection leads to prolongation of sound.

The sound produced is heard for some specific period of time before it dies down or get absorbed finally.

Answer:

7.14285714286

Explanation:

Answer: True

Explanation: Hope this helps :)

Answer:

Force = 125 Newton

Explanation:

Given the following data;

Pressure = 50 pa

Area = 2.5 m²

To find the force applied;

Force = pressure * area

Substituting into the formula, we have;

Force = 50 * 2.5

Force = 125 Newton

Answer:

5. 343j

Explanation:

Answer:

fiction

Explanation:

When two opposite forces act perpendicular to an axis, it causes rotational motion or torque.

Torque and couple are both related to rotational motion and are often used interchangeably, but they refer to slightly different concepts.

Torque is a measure of the force that causes an object to rotate around an axis or pivot point.

It is equal to the force applied multiplied by the perpendicular distance between the axis and the line of action of the force. Torque is a vector quantity, meaning it has both magnitude and direction. Its unit of measurement is Newton-meters (Nm) or foot-pounds (ft-lbs) in the English system.

A couple, on the other hand, is a pair of equal and opposite forces that act on a body but do not cause it to translate. Instead, they create a pure rotational motion.

A couple generates torque, but unlike a single force, it doesn't have a line of action or a specific point of application. Instead, a couple is characterized by its magnitude and the distance between the forces. Couples are often used in mechanics to model rotational systems and analyze the behavior of rotating bodies.

Torque is the measure of the force that causes rotational motion, while a couple is a pair of forces that create pure rotational motion without causing any translation.

Therefore, If two opposite forces act perpendicular to an axis, it causes rotational motion or torque.

To learn more about torque click:

https://brainly.com/question/17816858

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Thus Kinetic energy of the object is 200J when mass is 25 kg and velocity is 4 m/s.

Answer:

same

step by step explanation:

Answer:

noice.

Explanation:

thanks for points.... idrk what im supposed to do

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yeah same.

Answer:

0.8sec

Explanation:

Σf= 7.5-5= 2.5 N to the left

Σf=m*a=>2.5=2a=>a=1.25 m/s²

Lets say that the speed is 1m/s

a=speed-0/x=>x=1/1.25=>x=0.8

Hence the time will be 0.8sec

Answer: Heat transfer due to emission of electromagnetic waves is known as thermal radiation.

Explanation: Heat transfer through radiation takes place in form of electromagnetic waves mainly in the infrared region. Radiation emitted by a body is a consequence of thermal agitation of its composing molecules.

Answer: Thermal Radiation is the right answer.

Explanation:

Answer:

ghj

Explanation:

Answer:

bottle opener and door knob

Explanation:

Answer:

bottle opener

door handle

Answer:

500 Joules

Explanation:

W(work)= force * distance

w = 100*5

W= 500

Answer:

Explanation:

one and three seem right soo  answer C  

Answer:

The weight of the object X is approximately 3.262 N (Acting downwards)

The weight of the object Y is approximately 8.733 N (Acting downwards)

Explanation:

The question can be answered based on the principle of equilibrium of forces  

The given parameters are;

The weight of Z = 12 N (Acting downwards)

The weight of the pulleys = Negligible

From the diagram;

The tension in the in the string attached to object Z = The weight of object Z = 12 N

The tension in the in the string attached to object X = The weight of the object X  

The tension in the in the string attached to object Y = The weight of the object Y

Given that the forces are in equilibrium, we have;

The sum of vertical forces acting at a point, [tex]\Sigma F_y[/tex] = 0

Therefore;

[tex]T_{1y} + T_{2y} + T_{3y} = 0[/tex]

[tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex]

Where;

[tex]T_{1y}[/tex]  = The weight of object Z = 12 N

[tex]T_{1y}[/tex]  = 12 N

[tex]T_{2y}[/tex] = The vertical component of tension, T₂ = T₂ × sin(24°)

∴  [tex]T_{2y}[/tex] = T₂ × sin(156°)

Similarly;

[tex]T_{3y}[/tex] = T₃ × sin(50°)

From [tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex], and [tex]T_{1y}[/tex]  = 12 N, we have;

12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)

Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0

Therefore at point B, we have;

T₁ₓ + T₂ₓ + T₃ₓ = 0

The tension force, T₁, only has a vertical component, therefore;

∴ T₁ₓ = 0

∴ T₂ₓ + T₃ₓ = 0

T₂ₓ = -T₃ₓ

T₂ₓ =  T₂ × cos(156°)

T₃ₓ = T₃ × cos(50°)

From T₂ₓ = -T₃ₓ, we have;

T₂ × cos(156°) = - T₃ × cos(50°)...(2)

Making T₃ the subject of equation (1) and (2) gives;

Making T₃ the subject of equation in equation (1), we get;

12 = -(T₂ × sin(156°) + T₃ × sin(50°))

∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))

Making T₃ the subject of equation in equation (2), we get;

T₂ × cos(156°) = - T₃ × cos(50°)

∴ T₃ = T₂ × cos(156°)/(-cos(50°))

Equating both values of T₃ gives;

(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))

-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))

∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283

∴ T₂ ≈ -8.02 N

From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;

T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717

∴ T₃ ≈ -11.4 N

The weight of the object X = -T₂ × sin(156°)

∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N

The weight of the object X ≈ 3.262 N (Acting downwards)

The weight of the object Y = -(T₃ × sin(50°))

∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N

The weight of the object Y ≈ 8.733 N (Acting downwards)

Answer:

before this type of attack, high acceleration is the most important thing.

Explanation:

As the zebra is ambushed by the crocodile the most important thing is a quick reaction, in this attack the most likely is that the crocodile is in the water so it cannot run after the zebra.

Consequently, before this type of attack, high acceleration is the most important thing.

Answer:

The answer is "Option D"

Explanation:

Please find the graph file in the attached file.

Using formula:

[tex]\to v= \rho \lambda \\\\\ \to \lambda= 130 \cm \\\\ \to v= 335 \frac{cm}{s}\\\\ \to \rho= \frac{v}{\lambda} \\\\[/tex]

      [tex]=\frac{335}{130} \\\\ = 2.57 \approx 2.50 \ Hz[/tex]

Answer:

Eastward, at 11 m/s^2

Explanation:

64N-31N=unbalanced force of 33N

F=ma

33N=(3kg)a

a=11m/s^2 to the East

Answer:

B: Relay

Explanation:

Out of all the options, the only device that relies upon the magnetic field of an electric current.

The principle relies upon the principle of electro magnetic attraction whereby when the circuit detects a faulty current, it makes the electromagnetic field to become energized which in turn produces the temporary magnetic field. This magnetic field then moves the relay armature which is used in opening or closing the connections.

Carbon is the element modeled

Answer:

Option C. The force between them would be 4 times larger than with the

initial masses.

Explanation:

To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:

From:

F = GMₐM₆/ r²

Keeping G/r² constant, we have

F₁ = MₐM₆

Let the initial mass of both objects to be m

F₁ = MₐM₆

F₁ = m × m

F₁ = m²

Next, let the masses of both objects doubles i.e 2m

F₂ = MₐM₆

F₂ = 2m × 2m

F₂ = 4m²

Compare the initial and final force

Initial force (F₁) = m²

Final (F₂) = 4m²

F₂ / F₁ = 4m² / m²

F₂ / F₁ = 4

F₂ = 4F₁ = 4m²

From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the

initial masses.

Thus, option C gives the correct answer to the question.

Answer:

B

Explanation: