There are different types of contact forces like normal Force, spring force, applied force and tension force.
A man stands by a railway track.
A train travelling at 40 m/s takes 2.0 s to pass the man.
What is the length of the train?
40 m
D
80m
A 20m
B 38 m
Answer:
length of train is 80m
Explanation:
40*2
Why is it that when riding in a car, you don't feel like you're moving?
This may shock you:
We NEVER feel speed, velocity, or motion, as long as it's constant.
We only feel CHANGES in speed, velocity, or motion.
That means speeding up, slowing down, or changing direction.
As long as we're moving in a straight line at a constant speed, we don't feel anything.
In Figure (a), both batteries have em - 1.20 V and the external resistance R is a variable resistor. Figure (6) gives the electric potentials V between the terminals of each battery as functions of
Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by R, -0.500 . What is the internal resistance of (a) battery 1 and (b) battery 2?
0.60
V(V)
0
-0.350
(
R(0)
(6)
Answer:
i know da way ese'
Explanation:
If someone replenishes the tree population in a forest ecosystem, how
might this affect the producers already living there?*
Answer: Increase in competition for abiotic factors.
Explanation: Resource availability is one of the main factors determining the ecological dynamics of populations or species. Fluctuations in resource availability can increase or decrease the intensity of resource competition. Resource availability and competition can also cause evolutionary changes in life-history traits
What is the similarity between pushing and lifting? What is the difference?
Answer:
the similarity is that hands are applied and force
PLEASE HELPPPPPP <333
Answer:
Explanation:
The answer is c. I am very sure
Answer:
i think its b
Explanation:
im not very sure
A 10.0 N package of whole wheat flour is suddenly placed on the pan of a scale such as you find in grocery stores. The pan is supported from below by a vertical spring of force constant 395 N/m. If the pan has negligible weight, find the maximum distance the spring will be compressed if no energy is dissipated by friction.
Answer:
0.025 m
Explanation:
From the question,
Applying Hook's law
F = ke................... Equation 1
Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.
make e the subject of the equation
e = F/k....................... Equation 2
Given: F = 10 N, e = 395 N/m
Substitute these values into equation 2
e = 10/395
e = 0.025 m
Which sentence best explains the law of conservation of mass as applied to
chemical reactions?
A. The amount of mass changes only slightly during a chemical
reaction.
B. The volumes of the reactants and products are equal during a
chemical reaction.
C. The types of atoms can change during a chemical reaction, but
their masses cannot.
D. In a chemical reaction, the total mass of the reactants equals the
total mass of the products.
Answer:
A. The amount of mass changes only slightly during a chemical
reaction.
Positioning a iron core in the middle of a current carrying solenoid creates:
a. A dipole
b. An electromagnet
c. Induced current
d. Mutual inductance
e. A natural magnet
Answer:
d
Explanation:
middle of a current carrying solenoid creates Mutual inductance
Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from the slit. The distance, on the screen, between the dark spots to either side of the central maximum in the pattern is 25 mm. (a) What is the distance between the same dark spots when the screen is moved so it is only 1.5 m from the slit
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
L = 2.5 my = .0125λ = 600 nmAs we know, the equation
⇒ [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]
On substituting the values, we get
⇒ [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]
On applying cross multiplication, we get
⇒ [tex].0125a=2.5 (600\times 10^{-9})[/tex]
⇒ [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]
⇒ [tex]=1.2\times 10^{-4} \ m[/tex]
For new distance, we have to put this value of "a" in the above equation,
⇒ [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]
⇒ [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex]=3.22\times 10^{-3} \ m[/tex]
The total distance will be twice the value of "y", we get
= [tex]6.67\times 10^{-3} \ m[/tex]
or,
= [tex]6.67 \ mm[/tex]
Help answer question in picture
When putting the ball on the tee you want half of the golf ball to be above the club be below the club be in front of the club be behind the club
will put brainlest
A golf ball is a unique ball made specifically for the game of golf.
What is Gulf ball?A golf ball must adhere to specific velocity, distance, and symmetry requirements as well as have a mass of no more than 1.620 oz (45.9 g), a diameter of no less than 1.680 inches (42.7 mm), and no more than 1.620 oz (45.9 g) in total.
Similar to golf clubs, golf balls must pass testing and approval by The R&A and the United States Golf Association before they can be used in competitions.
Early in the 20th century, it was discovered that dotting the ball gave the player even more control over the trajectory, flight, and spin of the ball.
Therefore, A golf ball is a unique ball made specifically for the game of golf.
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5. What is the period of a vertical mass-spring system that has an amplitude of
71.3 cm and maximum speed of 7.02 m/s? The spring constant is 12.07 N/m.
The period of the vertical mass-spring is 0.64 s.
The given parameters:Amplitude of the spring, A = 71.3 cm Maximum speed of the spring, V = 7.02 m/sSpring constant, k = 12.07 N/mThe angular speed of the vertical mass-spring is calculated as follows;
[tex]V_{max} = A \omega\\\\\omega = \frac{V_{max}}{A} \\\\\omega = \frac{7.02}{0.713} \\\\\omega = 9.85 \ rad/s[/tex]
The period of the vertical mass-spring is calculated as follows;
[tex]f = \frac{\omega }{2\pi} \\\\T = \frac{1}{f} \\\\T = \frac{2 \pi}{\omega } \\\\T = \frac{2\pi }{9.85} \\\\T = 0.64 \ s[/tex]
Thus, the period of the vertical mass-spring is 0.64 s.
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A girl of weight 500 N climbs on top of a 2.0 m high wall. By how much does her g.p.a increase?
Answer:
By 1000 joules
Explanation:
Given
[tex]Weight = 500N[/tex]
[tex]Height = 2.0m[/tex]
Required
By how much does her GPA increases
To do this, we simply calculate the potential energy.
[tex]GPE = mgh[/tex]
Where
[tex]mg = Weight = 500N[/tex]
At the ground level, the height is 0
i.e. [tex]h = 0[/tex]
So:
[tex]GPE = 500N * 0 = 0[/tex]
At:
[tex]h = Height = 2.0m[/tex]
So, we have:
[tex]GPE = mgh[/tex]
[tex]GPE = 500N * 2.0m[/tex]
[tex]GPE = 1000J[/tex]
Calculate the difference
[tex]\triangle GPE = 1000J - 0J[/tex]
[tex]\triangle GPE = 1000J[/tex]
Hence, it increases by 1000 joules
If a force of 20kN acts on a circular rod of diameter 10mm, calculate the stress in the
rod.
The stress in the rod is equal to [tex]2.55 \times 10^8\;N/m[/tex]
Given the following data:
Force = 20 kN = 20,000 NewtonDiameter = 10 mm to m = 0.01 meterTo calculate the stress in the rod:
First of all, we would determine the area of the rod by using this formula:
[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{3.142 \times 0.01^2}{4}[/tex]
Area = 0.00007855 meter.
Mathematically, stress is given by this formula:
[tex]Stress = \frac{Force}{Area}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Stress = \frac{20000}{0.00007855} \\\\Stress = 2.55 \times 10^8\;N/m[/tex]
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Please help me with 1&2
Answer:
1: A
Explanation:
Question /
Which object is shown below?
A. Convex mirror
B. Convex lens
C. Concave lens
D. Concave mirror
SLIDNAT
3. Jose and Luke raced as they climbed to the top of the bleachers. Jose reached the top in 12.6 s and
Luke reached the top in 13.3 s. Jose and Luke have the same mass,
Who did more work?
How do you know?
Who had more power?
How do you know?
Answer:
jose
Explanation:
Jose run faster and did more work
because the time Jose took to accomplish the activity is less than Luke
both
both have same mass
The work done by both Jose and Luke is same because the change in potential energy is same.
The power of Jose is greater than than of Luke because Jose takes less time to do the same work.
What is power?Power is defined in physics as the amount of energy transferred or converted per unit time. The watt is the unit of power in the International System of Units, equal to one joule per second. Power is sometimes referred to as activity in older works. A scalar quantity is power.
Let the mass of each of them is m.
Hence, work done by each of them = mgh ( same for both of them)
As Jose reached the top in 12.6 s and Luke reached the top in 13.3 s.
Power of Jose = mgh/12.6
Power of Luck = mgh/13.3
Hence, Power of Jose is greater than Power of Luck.
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In 1960, the US Navy sent the submersible Trieste to the bottom of the Marianas Trench 11,000m deep. What was the force on the small 15cm diameter circular viewing window?
Answer:
P = d g h pressure = density * g * depth
P = 1000 kg/m^3 * 9.8 m / s^2 * 1.1 * 10E4 m = 1.1 * 10E8 N/m^2
F = P * A = 1.1 * 10E8 N/m^2 * pi * .075^2 / m^2 = 1.9 * 10E6 N/m^2
8.
A
2.0 m
A 1.0 kg box slides without friction around the
loop-the-loop apparatus as shown in the
diagram. If the object starts from rest at point A,
and the radius of the loop is 0.75 m, what is the
speed of the box at point B?
Answer:
6.26 m/s
Explanation:
From the given information:
Using the conservation of Energy;
M.E at A =M.E at B
[tex]\dfrac{1}{2}mv_A^2 + mgh _A = \dfrac{1}{2}mv_B^2 + mgh_B[/tex]
Replacing the values given in the equation:
[tex](1) (9.8) (2 \ m) +\dfrac{1}{2}(0)^2 = 1 \times 9.8 \times 0 + \dfrac{1}{2}(1) \times v_B^2 \\\\ 19.6 + 0 = 0 + 0.5v_B^2\\ \\ v_B^2 = \dfrac{19.6}{0.5} \\ \\ v_B^2 = 39,2 \\ \\ v_B = \sqrt{39.2} \\ \\ \mathbf{v_B = 6.26 \ m/s}[/tex]
A gun whose mass is 0.8 kg fires a bullet
whose mass is 0.016 kg with a velocity of
700 ms Calculate the velocity of the gun's
recoil
Answer:
14m/s
Explanation:
As per Newton's third law, the momentum of the bullet firing will equal the momentum of the guns recoil:
[tex]m_{g}v_{g} = m_{b}v_{b}[/tex]
(.8)v=(.016)(700)
v=11.2/0.8
v=14m/s
how is the medium of a wave and transmit of a wave similar and different?
plssss I really need helpppp
Answer:
Sound and light are similar in that both are forms of energy that travel in waves. They both have properties of wavelength, freqency and amplitude. Here are some differences: Sound can only travel through a medium (substance) while light can travel through empty space.
Please answer all three answers
Answer:
I. The rock that has the most kinetic energy is rock 3.
II. Rock 3 has the most kinetic energy because it weighs the highest among the rocks i.e it has the highest amount of mass. Also, the mass of an object is directly proportional to the kinetic energy possessed by the object; the higher the mass, the higher the kinetic energy.
III. Kinetic energy is taking place rather than potential energy because the rocks are in motion i.e rolling down a hill.
Explanation:
Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;
a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.
b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
From the above, we can deduce the following;
I. The rock that has the most kinetic energy is rock 3.
II. Rock 3 has the most kinetic energy because it weighs the highest among the rocks i.e it has the highest amount of mass. Also, the mass of an object is directly proportional to the kinetic energy possessed by the object; the higher the mass, the higher the kinetic energy.
III. Kinetic energy is taking place rather than potential energy because the rocks are in motion i.e rolling down a hill.
An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on the freeway. Bumper to bumper they go with the same speed vo. The centripetal acceleration of the compact car is ao and the centripetal force acting is Fo. The centripetal acceleration of the SUV is _____ ao of the compact car.
Answer:
Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.
Explanation:
FOR SUV:
[tex]ac_{suv} = \frac{mv^2}{r}\\[/tex]
where,
ac_suv = centripetal acceleration of the SUV = ?
m = mass of SUV = 6000 kg
v = speed of SUV = vo
r = radius of path
Therefore,
[tex]ac_{suv} = \frac{6000\ vo^2}{r}\\[/tex]---------------- equation (1)
FOR CAR:
[tex]ao = \frac{mv^2}{r}\\[/tex]
where,
ao = centripetal acceleration of the car = ?
m = mass of car = 2000 kg
v = speed of car = vo
r = radius of path
Therefore,
[tex]ao = \frac{2000\ vo^2}{r}\\[/tex]--------------------- equation (2)
Dividing equation (1) by eq(2):
[tex]\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao[/tex]
Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.
Ac soucre change it polarity how many time
The diagram represents two charges, q1 and q2 separated by a distanced "d" which change would produce the greatest increase in the electrical force between the two charges?
between the two charges?
Answer:
The diagram represents two charges, q1 and q2, separated by a distance d. Which change would produce the greatest increase in the electrical force between the two charges? *
Explanation:
doubling charge q1, only
Doubling the charge q would produce the greatest increase in the electrical force between the two charges.
The value of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the charges and inversely proportional to the square of the distance between them.
How would you define an Electrical force?
The repulsive or attractive interaction between any two charged bodies is called as an electric force. Similar to any force, its impact and effects on the given body are described by Newton’s laws of motion. The electric force is among the list of other forces that exert over objects.
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Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed
A 1,571 kilogram car travelling at 129 kilometers per hour is driving down a highway. The driver suddenly realizes a large animal is standing stationary on the highway in the way of the car. The driver manages to release their foot off the accelerator peddle, but does not have time to hit the brake peddle. The car strikes the animal which gets stuck to the car hood. Immediately after the collision the car slows to 59 kilometers per hour. Given this information, accident investigators are able to determine the mass of the animal as what
Answer:
[tex]1863.9\ \text{kg}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of car = 1571 kg
[tex]u_1[/tex] = Initial velocity of car = 129 km/h
[tex]u_2[/tex] = Initial velocity of the animal = 0
[tex]v[/tex] = Velocity of combined mass = 59 km/h
[tex]m_2[/tex] = Mass of the animal
As the momentum of the system is conserved we have
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow \dfrac{m_1u_1+m_2u_2}{v}-m_1=m_2\\\Rightarrow m_2=\dfrac{1571\times 129+0}{59}-1571\\\Rightarrow m_2=1863.9\ \text{kg}[/tex]
The mass of the animal is [tex]1863.9\ \text{kg}[/tex].
Particles q1 = +8.0 UC, 92 = +3.5 uc, and
q3 = -2.5 uC are in a line. Particles qi and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q2?
Answer:
-22.3
Explanation:
Acellus
The net force on particle q2 is 21.7 N.
The given parameters:
Charge on particle 1, q1 = 8 μCCharge on particle 2, q2 = 3.5 μCCharge on particle 3, q3 = -2.5 μCDistance between particle 1 and particle 2 = 0.1 mDistance between particle 2 and particle 3, = 0.15 mThe net force on particle q2 is calculated as follows;
[tex]Q_2_{net} = q_{12} \ + \ q_{23}\\\\Q_2_{net} = \frac{kq_1q_2}{r_{12} ^2} \ + \ \frac{kq_2q_3}{r_{23}^2} \\\\Q_2_{net} = \frac{9\times 10^9 \times 8 \times 10^{-6} \times 3.5 \times 10^{-6} }{0.1^2} \ + \ \frac{9 \times 10^9 b\times 3.5 \times 10^{-6} \times (-2.5) \times 10^{-6} }{0.15^2} \\\\Q_2_{net} = 25.2 \ N \ - \ 3.5 \ N\\\\Q_2_{net} = 21.7 \ N[/tex]
Thus, the net force on particle q2 is 21.7 N.
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4. Which of the following accurately pairs the part of an atom to its charge?
O A. Neutron-positive charge
O B. Electron-negative charge
O C. Proton-no charge
O D. Electron-no charge
Answer:
B Electrons are negatively charged while protons are positively charged
