Viewing the moon on the 7th day of the lunar cycle, what percentage of the the lunar surface would be illuminated?



a. 17%


b. 35%


C. 45%

The standard enthalpy of formation of H₂O(l) is -63.2 kJ/mol.

To find the standard enthalpy of formation of H₂O(l) using the given information, follow these steps:

1. Write down the given standard enthalpy change for the reaction: -572.6 kJ.
2. Recall the equation for the standard enthalpy change of a reaction: ΔH° = Σ [n × ΔHf°(products)] - Σ [n × ΔHf°(reactants)], where n is the stoichiometric coefficient, and ΔHf° is the standard enthalpy of formation.
3. Apply the equation to the given reaction: -572.6 kJ = [ΔHf°(CO2) + ΔHf°(H₂O)] - [ΔHf°(H₂CO) + ΔHf°(O)].
4. Note that the standard enthalpy of formation for O₂(g) is zero since it is an elemental form.
5. Plug in the known values for the standard enthalpies of formation for CO₂(g) and H₂CO(g). The values are -393.5 kJ/mol for CO₂(g) and -115.9 kJ/mol for H₂CO(g).
6. Substitute the values into the equation: -572.6 kJ = [-393.5 kJ/mol + ΔHf°(H₂O)] - [-115.9 kJ/mol + 0].
7. Simplify and solve for ΔHf°(H₂O): ΔHf°(H₂O) = -572.6 kJ + 115.9 kJ + 393.5 kJ = -63.2 kJ/mol.

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H₂O(l) is -63.2 kJ/mol.

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The name of this branched alkene is 6- ethyl-8-methyl-5-propylnon-2-ene.

The longest carbon chain containing the carbon-carbon double bond is selected as the parent alkene.

The suffix ‘ane’ of the alkane is replaced by ‘ene’.

The position of double bonds or side chains indicated by numbers 1, 2, 3 etc.

The longest chain is numbered from that end, which gives the lowest number to the carbon atom of the double bond and written just before the suffix ‘ene’. If while numbering the chain the double bond gets the same number from either side the carbon chain is numbered in such a manner that the substituent gets the lowest number.

The name and position of other groups (substituents) is indicated by prefixes.

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The volume of 2. 30 moles of gas exerting a pressure of 2. 80 atm at 155°C is 84.7 L.

We can use the ideal gas law to solve for the volume:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature to Kelvin:

155°C + 273.15 = 428.15 K

Next, we can plug in the values and solve for V:

V = (nRT) / P

V = (2.30 mol * 0.08206 Latm/molK * 428.15 K) / 2.80 atm

V = 84.7 L

Therefore, the volume of 2.30 moles of gas exerting a pressure of 2.80 atm at 155°C is 84.7 L.

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Student 1 and Student 3 both provide incorrect explanations for the increase or decrease in entropy during dissolution reactions. Option A is correct.

Student 1 suggests that the entropy increased for ammonium nitrate but decreased for sodium hydroxide, based on the number of species introduced to water, which is not a valid explanation. Student 3 suggests that the entropy decreased for both ammonium nitrate and sodium hydroxide due to the salts becoming more ordered, which is also incorrect.

On the other hand, Student 2 provides the correct scientific reasoning. According to the second law of thermodynamics, dissolution reactions always result in an increase in entropy. As the solid dissolves, the molecules become more dispersed in the solvent, which increases the number of micro-states and hence the entropy. Option A is correct.

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Both mass and charge are conserved. Therefore, option (3) is correct.

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s) conserves mass and charge.

The rule of conservation of mass prohibits matter creation or destruction during chemical reactions. The reactants and products must have the same mass. The left and right sides of the reaction must have the same mass of iron (Fe) and copper sulfate (CuSO₄).

Redox processes also involve electron transfer. The law of charge conservation asserts that reactants and products must have equal charges. Iron loses electrons to generate Fe²⁺ ions, while copper ions receive electrons to form copper metal (Cu). The reaction is neutral.

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This type of reaction is classified as an endothermic reaction, as it absorbs energy in the form of heat from its surroundings.

The heat transfers between the cold pack and your skin by conduction, which is the transfer of heat energy from a warmer object to a cooler one. The law of conservation of energy states that energy cannot be created or destroyed, only transferred from one form to another.

In this case, the heat from your skin is transferred to the cold pack, and the cold pack absorbs the heat and converts it into a different form of energy, usually in the form of radiation or vibration.

This is the same process that occurs with an ice pack, where the heat in the skin is absorbed by the ice, and the ice radiates the heat away in the form of cold air.

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The mass of the silver sample is approximately 77.9 grams.

To solve this problem, we can utilize the equation for heat transfer:

q = m * c * ΔT

where q represents the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Initially, we calculate the heat transferred from the silver to the water:

q silver = m silver * c silver * ΔT silver

q water = m water * c water * ΔT water

For thermal equilibrium between the silver and water, we equate the two equations as they reach the same temperature:

q silver = q water

m silver * c silver * ΔT silver = m water * c water * ΔT water

Rearranging the equation allows us to solve for the mass of the silver:

m silver = (m water * c water * ΔT water) / (c silver * ΔT silver)

Substituting the given values:

m silver = (250g * 4.184 J/g°C * (23.35°C - 6.5°C)) / (0.235 J/g°C * (98.75°C - 23.35°C))

As a result:

m silver = 77.9 g

Thus, the mass of the silver sample is approximately 77.9 grams.

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We need a volume of 60.4 ml of 11.7 M HCl to make a 500.0 ml solution with a pH of 3.20.

To calculate the required volume of 11.7 M HCl to make a 500.0 ml solution with a pH of 3.20, we need to use the Henderson-Hasselbalch equation, which relates the pH of a solution to its pKa and the ratio of the concentrations of the conjugate base and acid.

Using the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻] ÷ [HA])

where [A-] / [HA] is the ratio of the concentration of the conjugate base (Cl⁻) to the concentration of the acid (H⁺).

Rearranging the equation, we can solve for [H⁺]:

[H⁺] = [tex]10^{(pH - pKa)}[/tex]

[H⁺] = [tex]10^{(3.20 - (-1))}[/tex]

= [tex]10^{-3.20} + mol/L[/tex]

Since the concentration of HCl is equal to the concentration of [H⁺] in solution, we can calculate the moles of HCl required to make the solution:

moles of HCl = concentration of HCl × volume of solution

moles of HCl = [tex](10^{-3.20})[/tex] × (0.5 L)

= 7.08 × 10⁻⁴ mol

Finally, we can calculate the required volume of 11.7 M HCl:

volume of HCl = moles of HCl ÷ concentration of HCl

volume of HCl = (7.08 × 10⁻⁴ mol) ÷ (11.7 mol/L)

= 0.0604 L

= 60.4 ml

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The process of carbon dioxide getting into the atmosphere primarily occurs through natural processes like respiration, volcanic eruptions, and decay of organic matter.

However, human activities like burning of fossil fuels and deforestation have significantly increased the levels of carbon dioxide in the atmosphere. When these fuels are burned, they release carbon dioxide into the air, which contributes to the greenhouse effect, trapping heat in the atmosphere and leading to global warming. Additionally, deforestation reduces the number of trees that absorb carbon dioxide through photosynthesis, further exacerbating the problem.

Overall, the process of carbon dioxide getting into the atmosphere is a complex interaction between natural and human-induced factors that have significant impacts on our planet.

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If the unknown solution reacts with potassium carbonate to form a white precipitate, then it contains strontium ions, indicating that the unknown solution is strontium nitrate.

On the other hand, if the unknown solution reacts with potassium sulfate to form a white precipitate, then it contains magnesium ions, indicating that the unknown solution is magnesium nitrate.

Therefore, based on the observations, if a white precipitate is observed when the unknown solution is mixed with potassium carbonate and no precipitate is observed when the unknown solution is mixed with potassium sulfate, the unknown solution is most likely strontium nitrate.

If no precipitate is observed when the unknown solution is mixed with both potassium carbonate and potassium sulfate, the unknown solution is most likely magnesium nitrate.

Therefore, we can determine the identity of the unknown solution by observing the reaction with potassium carbonate and potassium sulfate.

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The equation Q = mcΔT, where Q is the amount of heat absorbed, m is the mass of the object, c is the specific heat capacity of the object, and ΔT is the change in temperature.

In this case, we are given the mass of the wood (1500.0 grams) and its specific heat capacity (1.8 g/JxC), as well as the amount of heat absorbed (67,500 Joules) and the final temperature (57C). We want to find the initial temperature.

First, we can rearrange the equation to solve for ΔT: ΔT = Q/mc. Plugging in the values we know, we get:
ΔT = 67,500 J / (1500.0 g x 1.8 g/JxC) = 25C

This tells us that the temperature of the wood increased by 25C due to the heat absorbed. To find the initial temperature, we can subtract ΔT from the final temperature:

Initial temperature = final temperature - ΔT = 57C - 25C = 32C
Therefore, the initial temperature of the wood was 32C.

In summary, we used the equation Q = mcΔT and rearranged it to solve for ΔT. We then subtracted ΔT from the final temperature to find the initial temperature of the wood. The specific heat capacity tells us how much heat energy is needed to raise the temperature of a given mass of a substance by a certain amount.

In this case, the specific heat capacity of the wood (1.8 g/JxC) was used to calculate how much heat energy was absorbed by the wood. The mass of the wood was also important, as it determines how much heat energy is needed to raise its temperature. The final temperature of the wood and the amount of heat absorbed were given in the problem, and we used this information to solve for the initial temperature.

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The reaction is a double displacement reaction, in which two ions switch places in the reactants to form the products. The chemical equation for the reaction between Na2CO3 (aq) and NaCl2 (aq) is as follows:

2 Na2CO3 (aq) + NaCl2 (aq) → 2 NaCl (aq) + CO2 (g) + H2O (l).

In this reaction, sodium carbonate (Na2CO3) reacts with sodium chloride (NaCl2) to form sodium chloride (NaCl), carbon dioxide (CO2) and water (H2O). The reaction is a double displacement reaction, in which two ions switch places in the reactants to form the products. The sodium ions in the Na2CO3 react with the chloride ions in the NaCl2 to form the NaCl, while the carbonate ions in the Na2CO3 react with the sodium ions in the NaCl2 to form CO2 and H2O.

The reaction does not form a precipitate, so no solid product is formed. This is because both the reactants and products are soluble in water, and so no solid product is formed.

Overall, this reaction between Na2CO3 and NaCl2 results in the formation of NaCl, CO2 and H2O, and no solid precipitate is formed. This is because both the reactants and products are soluble in water, and so no solid product is formed.

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The pH of the solution is 1.77 which, contains 1.44% formic acid by mass.

The first step is to determine the molarity of the solution, which can be done using the percent composition by mass and the density of the solution;

mass of formic acid = 1.44% × 100 g = 1.44 g

volume of solution = 1.44 g ÷ 1.01 g/mL

= 1.43 mL

= 0.00143 L

molarity of formic acid=moles of formic acid ÷ volume of solution

moles of formic acid = mass ÷ molar mass = 1.44 g ÷ 46.03 g/mol

= 0.0313 mol

molarity of formic acid = 0.0313 mol ÷ 0.00143 L

= 21.9 M

Next, we can use the expression for the acid dissociation constant of formic acid to determine the pH;

Ka = [H⁺][HCOO⁻] / [HCOOH]

Let x be the concentration of [H⁺] and [HCOO⁻] at equilibrium. Then, the concentration of [HCOOH] at equilibrium is 0.047 - x.

Substituting these expressions into the Ka expression and solving for x, we get;

6.2 × 10⁻⁴ = x² / (0.047 - x)

Solving for x using quadratic formula, we get;

x = 0.017 M

Therefore, the pH of the solution is;

pH = -log[H⁺] = -log(0.017)

= 1.77

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The gas occupies a volume of 1.28 L in its final state, which is option (c).

We can solve this problem using the combined gas law:

(P1V1/T1) = (P2V2/T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Plugging in the given values, we have:

(3.0 atm)(2.0 L)/(300 K) = (5.0 atm)(V2)/(320 K)

Solving for V2, we get:

V2 = (3.0 atm)(2.0 L)(320 K)/(5.0 atm)(300 K) = 1.28 L

Therefore, the gas occupies a volume of 1.28 L in its final state, which is option (c).

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The best classification for the creation of a complex ion like Cu(NH3)4 2+ (aq) is a Lewis acid-base reaction. The NH3 molecules serve as Lewis bases in this process, while the Cu2+ ion functions as a Lewis acid by accepting a pair of electrons from them. As a result, a coordination complex is created that contains four NH3 ligands and a Cu2+ ion.

Covalent coordinate bonds are created when the NH3 molecules give the Cu2+ ion a pair of electrons from their lone pairs. As a result, a stable complex ion with a net charge of 2+ is created, with the Cu2+ ion at its centre and four NH3 ligands surrounding it.

Overall, the formation of complex ions involves the interaction of a Lewis acid (metal ion) and a Lewis base (ligand), resulting in the formation of a coordinate covalent bond.

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The formation of a complex ion such as Cu(NH3)4 2+ (aq) can be best categorized as a coordination complex.

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To produce exactly 3.50 g of NaCl, we need 5.00 g of NaHCO3 and 2.18 g of HCl.

To find how much of the reactant is needed we need to use stoichiometry for finding the solution.

The balanced equation is : [tex]NaHCO_3 + HCl \rightarrow NaCl + CO_2 + H_2O[/tex]

We need to produce exactly 3.50 g NaCl. Now from the balanced equation, we can see that the molar ratio of [tex]NaHCO_3[/tex] to NaCl is 1:1. Therefore, we can  use the molar mass of NaCl to find the moles of NaCl that correspond to 3.50 g:

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 3.5 / 58.44 = 0.0598 mol NaCl

As the molar ratio of [tex]NaHCO_3[/tex] to NaCl is 1:1, therefore we need 0.0598 mol of [tex]NaHCO_3[/tex]. Similarly, the molar ratio of HCl to [tex]NaHCO_3[/tex] is 1:1. Therefore, we need 0.0598 mol of HCl.

Now we can use the molar mass of each element to find the mass of each reactant required.

molar mass of [tex]NaHCO_3[/tex] = 84.01 g/mol

mass of [tex]NaHCO_3[/tex] = 0.0598 mol × 84.01 g/mol = 5.00 g

molar mass of HCl = 36.46 g/mol

mass of HCl = 0.0598 mol × 36.46 g/mol = 2.18 g

Therefore, to produce exactly 3.50 g of NaCl, we need 5.00 g of [tex]NaHCO_3[/tex] and 2.18 g of HCl.

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Answer and explanation:

Based on the temperature change, we can conclude that the reaction of baking soda and vinegar is exothermic. In an exothermic reaction, energy is released from the system to the surroundings in the form of heat, which causes an increase in the temperature of the surroundings.

In this case, the system consists of the baking soda and vinegar, which react to form carbon dioxide gas, water, and sodium acetate. As the reaction proceeds, energy is released from the system to the surroundings in the form of heat. This heat causes an increase in the temperature of the surroundings, which in this case is the surrounding air and any objects in the vicinity of the reaction.

The decrease in temperature from 25˚C to 19˚C indicates that the reaction released energy to the surroundings, and this energy was absorbed by the air and objects in the vicinity of the reaction. This is why the temperature of the surroundings decreases.

Overall, an exothermic reaction like this involves the conversion of potential energy stored in the reactants into kinetic energy in the form of heat, which is released to the surroundings.

Add approximately 10.9 grams of pentanol to 250 mL of water to make a 5% solution by volume.

To make a 5% solution by volume with pentanol and water, you'll need to determine the volume of pentanol to be added to the 250 mL of water.

First, find the total volume of the solution:

Total volume = (Volume of pentanol + 250 mL) * 100

Next, calculate the volume of pentanol needed for a 5% solution:

Volume of pentanol = (5% * Total volume) / 100

Since the desired solution is 5% pentanol by volume:

5% * (Volume of pentanol + 250 mL) = Volume of pentanol
0.05 * (Volume of pentanol + 250) = Volume of pentanol

Now, solve for the volume of pentanol:

0.05 * Volume of pentanol + 12.5 = Volume of pentanol
-0.05 * Volume of pentanol = -12.5
Volume of pentanol = 13.16 mL (rounded to 3 significant figures)

Now, use the density of pentanol to find the mass of pentanol to be added:

Mass of pentanol = Volume of pentanol * Density of pentanol
Mass of pentanol = 13.16 mL * 0.825 g/mL
Mass of pentanol ≈ 10.9 g (rounded to 3 significant figures)

Therefore, you should add approximately 10.9 grams of pentanol to 250 mL of water to make a 5% solution by volume.

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The molarity of the solution is 0.5 M.

To calculate the molarity of the solution, we need to first calculate the number of moles of NaF present in the solution. The molar mass of NaF is 41.99 g/mol (22.99 g/mol for Na and 19.00 g/mol for F).

Number of moles of NaF = mass of NaF / molar mass of NaF

= 15.1 g / 41.99 g/mol

= 0.359 mol

The volume of the solution is given as 550.0 mL, which needs to be converted to liters (L) as the unit of molarity is moles/L.

Volume of the solution = 550.0 mL = 0.5500 L

Molarity of the solution = number of moles of solute / volume of solution

= 0.359 mol / 0.5500 L

= 0.653 M

However, we need to consider that the NaF was diluted to a final volume of 550.0 mL, which means that the concentration of the solution has been decreased. Therefore, we need to divide the calculated molarity by 2.

Molarity of the solution after dilution = 0.653 M / 2

= 0.5 M

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NAD+ is the most common electron carrier needed for both glycolysis and the citric acid cycle. It is a coenzyme and is involved in redox reactions.

It is an oxidized form of NADH, which is the reduced form. During the oxidation of organic molecules, NAD+ will accept electrons and become NADH. During the reduction of organic molecules, NADH will give electrons and become NAD+.

During glycolysis, NAD+ is used to accept electrons from the oxidation of glucose, creating NADH and releasing energy for the ATP production. During the citric acid cycle, NAD+ accepts electrons from the oxidation of acetyl CoA, creating NADH and releasing energy for the ATP production. The NADH produced in both glycolysis and the citric acid cycle can be used in the electron transport chain to produce ATP.

In summary, NAD+ is an oxidized form of NADH and it is essential in both glycolysis and the citric acid cycle to produce energy in the form of ATP.

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The term that describes a pure substance that is composed of only one type of atom is an element.

An element is a substance that cannot be broken down into simpler substances by chemical reactions. Each element has a unique number of protons in the nucleus of its atoms, which gives it a specific atomic number. For example, the element carbon has an atomic number of 6, meaning that each carbon atom has 6 protons in its nucleus.

Elements are the building blocks of all matter, and there are currently 118 known elements, ranging from hydrogen (which has an atomic number of 1) to oganesson (which has an atomic number of 118). Elements can exist in various states of matter, including solids, liquids, and gases, depending on their temperature and pressure.

Pure substances, like elements, have uniform properties and composition throughout. This means that every particle of an element has the same chemical and physical properties, such as its melting point, boiling point, and density. In contrast, a mixture is composed of two or more substances that are physically combined but not chemically bonded.

Mixtures can be separated into their component parts by physical means, while pure substances cannot.

In summary, an element is a pure substance that is composed of only one type of atom. It cannot be broken down into simpler substances by chemical reactions and has uniform properties and composition throughout.

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The equilibrium concentration of Ag⁺ in the solution is 0.00200 M.

To solve this problem, we can use the equation for the reaction between silver nitrate (AgNO₃) and sodium iodate (NaIO₃), which is:

AgNO₃ + NaIO₃ -> AgIO₃ + NaNO₃

We know the initial concentrations of the two solutions: 0.00200 M for the AgNO₃ and 0.01 M for the NaIO₃. When they are mixed together, they will react to form a new equilibrium concentration of silver ions (Ag⁺).

To find the equilibrium concentration of Ag⁺, we need to use the stoichiometry of the reaction and the equilibrium constant (K) for the reaction. The balanced equation tells us that one mole of AgNO₃ reacts with one mole of NaIO₃ to form one mole of AgIO₃. Therefore, at equilibrium, the concentration of Ag⁺ will be equal to the initial concentration of AgNO₃ minus the amount that reacted to form AgIO₃:

[Ag⁺] = [AgNO₃] - [AgIO₃]

We can use the equilibrium constant expression for the reaction to find the concentration of AgIO₃:

K = [AgIO₃]/([AgNO₃][NaIO₃])

At equilibrium, this expression will equal the equilibrium constant for the reaction, which is given as 1.8 x 10^-12. We can rearrange this expression to solve for [AgIO₃]:

[AgIO₃] = K[AgNO₃][NaIO₃]

Substituting the initial concentrations and the value of K, we get:

[AgIO₃] = (1.8 x 10^-12)(0.00200 M)(0.01 M) = 3.6 x 10^-17 M

Now we can plug this value into the equation for [Ag⁺] to find the equilibrium concentration of silver ions:

[Ag⁺] = [AgNO₃] - [AgIO₃] = 0.00200 M - 3.6 x 10^-17 M = 0.00200 M (to three significant figures)

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The pH after the addition of 19.0 ml of 0.500 M HNO₃ to a 75.0 ml volume of 0.200 M NH₃ (Kb = 1.8 * 10⁻⁵) is 9.11.

1. Calculate moles of NH₃ and HNO₃: moles NH₃ = 75.0 ml * 0.200 mol/L = 15.0 mmol, moles HNO₃ = 19.0 ml * 0.500 mol/L = 9.5 mmol

2. Find moles of NH₃ remaining: 15.0 mmol - 9.5 mmol = 5.5 mmol

3. Calculate new concentrations: [NH₃] = 5.5 mmol / (75.0 ml + 19.0 ml) = 0.055 mol/L, [NH₄⁺] = 9.5 mmol / (75.0 ml + 19.0 ml) = 0.095 mol/L

4. Apply the Henderson-Hasselbalch equation: pH = pKa + log([NH₃]/[NH₄⁺])

5. Find pKa from Kb: pKa = 14 - log(Kb) = 14 - log(1.8 * 10⁻⁵) = 9.74

6. Calculate pH: pH = 9.74 + log(0.055/0.095) = 9.11

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Answer:

air is a solution because it is homogeneous, uniform throughout,and doesn't scatter light

In order to produce the impact of future droughts that may occur in the area, the scientist's plan would most likely include several key elements.

First and foremost, the plan would likely involve extensive research and data analysis to better understand the climate patterns and environmental factors that contribute to drought in the region.

This could involve collecting and analyzing data on rainfall, temperature, humidity, and other key indicators, as well as examining the impact of human activity on the local ecosystem.

Based on this research, the scientist may develop a range of strategies aimed at mitigating the effects of drought, such as water conservation measures, alternative irrigation techniques, and improved crop management practices.

Additionally, the plan may involve community outreach and education initiatives to raise awareness about the importance of water conservation and sustainable resource management.

Overall, the scientist's plan would likely be a comprehensive and multi-faceted approach aimed at preparing the city for future droughts and promoting long-term resilience and sustainability.

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Answer:

388.88 mmHg (2 d.p.)

Explanation:

To find the final pressure when the volume is kept constant, we can use Gay-Lussac's law.

[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]

where:

The values to substitute into the equation are:

Substitute the values into the equation and solve for P₂:

[tex]\implies \sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

[tex]\implies \sf \dfrac{745}{523 }=\dfrac{P_2}{273}[/tex]

[tex]\implies \sf P_2=\dfrac{745 \cdot 273}{523 }[/tex]

[tex]\implies \sf P_2=\dfrac{203385}{523 }[/tex]

[tex]\implies \sf P_2=388.88145315...[/tex]

[tex]\implies \sf P_2=388.88\;mmHg\;(2\;d.p.)[/tex]

Therefore, the final pressure would be 388.88 mmHg if a gas is cooled from 523 K to 273 K and the volume is kept constant, starting with an initial pressure of 745 mmHg.

By making a simple division of the Molar concentrations. The correct option is a.

The equilibrium constant Kc is a measure of the equilibrium between the forward and reverse reactions of a chemical reaction. It is a ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.

The equilibrium constant Kc:

Kc = [products]/[reactants]

here [products] is the concentration of the products at equilibrium and [reactants] is the concentration of the reactants at equilibrium.

If the concentrations of the products and reactants are given in molar concentrations (M), we can express the equilibrium constant as a ratio of Molar concentrations using the following equation:

Kc = [products]M / [reactants]M

Therefore, to find the equilibrium constant Kc, we simply need to divide the Molar concentrations of the products and reactants by their respective coefficients.

Therefore, the correct option is a) by making a simple division of the Molar concentrations.  

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Correct Question:

The equilibrium constant Kc is found:

a) by making a simple division of the Molar concentrations

b) with the quotient of the speed of the products over the reactants

c) dividing the speeds of the equations that form the chemical reaction

d) with the quotient of the concentrations of the substances present in the equation​

The student incorrectly calculated the mass of the sample of pyrite by assuming the density of pyrite to be 2 g/cm³, which is actually the density of water. The actual density of pyrite is about 5 g/cm³, so the actual mass of the 10 cm³ sample would be 50 g.

The student likely confused the concept of density, which is the mass per unit volume of a substance, with the specific gravity, which is the ratio of the density of a substance to the density of water.

Pyrite has a specific gravity of about 5, meaning that its density is about 5 times greater than that of water. Therefore, the mass of a 10 cm³ sample of pyrite would be 5 times greater than the mass of a 10 cm³ sample of water, or 50 g.

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Answer:1.8

Explanation:

=nrt/v

P=(3.15)(.0821)(472)/67

P=1.82atm

Answer:

One of two or more versions of a genetic sequence at a particular region of a chromosome.