Variations in the resistivity of blood can give valuable clues to changes in the blood's viscosity and other properties. The resistivity is measured by applying a small potential difference and measuring the current. Suppose a medical device attaches electrodes into a 1.5-mm-diameter vein at two points 5.0 cm apart.

Required:
What s the blood resistivity if a 9.0 V potential difference causes a 230μA current through the blood in the vein?

Answers

Answer 1

Answer:

 ρ= 1.378 10⁴ Ω / m

Explanation:

Let's use ohm's law

          V = i R

           R = V / i

let's calculate

           R = 9.0 / 230 10⁻⁶

           R = 3.9 10⁴ Ω

now we can use the definite of resistance

           R = ρ [tex]\frac{L}{A}[/tex]

the area of ​​a circle is

           A = π r² = π (d/2)²

           ρ = R A / L

           ρ = π R [tex]\frac{d^2}{4L}[/tex]

let's calculate

          ρ = π 3.9 10⁴  [tex]\frac{(1.5 \ 10^{-3}^2 }{4 \ 5 \ 10^{-2}}[/tex]

          ρ= 1.378 10⁴ Ω / m


Related Questions

what is a resultant vector​

Answers

Answer:

A resultant vector is a combination or, in simpler words, can be defined as the sum of two or more vectors which has its own magnitude and direction.

You are conducting an experiment inside an elevator that can move in a vertical shaft. A load is hung vertically from the ceiling on a string, and is stationary with respect to you. The tension in the string is measured to be exactly equal to the force due to gravity on the load. No other forces are acting on the load. Which of the following statements about the elevator are correct?
A. The elevator is an inertial frame of reference.
B. The elevator is not an inertial frame of reference.
C. The elevator may be at rest for the duration of the entire experiment.
D. The elevator may be moving at a constant velocity upward.
E. The elevator may be moving at a constant velocity downward.
F. The elevator must be accelerating

Answers

Answer: B. The elevator is not an inertial frame of reference.

F. The elevator must be accelerating.

Explanation:

Since we've been given the information that the tension in the string is measured to be exactly equal to the force due to gravity on the load and that no other forces are acting on the load, the statements about the elevator that are correct include:

• The elevator is not an inertial frame of reference.

• The elevator must be accelerating.

If the elevator isn't accelerating, the tension in the string can't be equal to the force of gravity.

Metals are amazing, and they are all around us. You can probably easily identify them by their shiny surfaces and tinny sound when you tap them.

a. True
b. False

Answers

Answer:

a. True

Explanation:

Metals are amazing, and they are all around us. You can probably easily identify them by their shiny surfaces and tinny sound when you tap them.

Generally, metals are mainly hard, shiny, and can be hammered into thin sheets. Also, another property of a metal is that, it is a good conductor of heat and even electricity because there valence (outer) electrons are delocalized. Some examples of chemical elements that are metals are iron, gold, sodium, silver, copper etc.



The lever shown above can be used to move the
bowling ball off the shelf. Pushing down at what
point on the lever would require you to apply the
least amount of force to move the ball?
A. 1
B. 2
C. 3
D. 4

Answers

Answer:

C your answer would be C

Explanation:

It should be right

PLEASE HELP IS URGENT


A current of 2A flows through a resistor for 30s.
(a) How many Coulombs of charge pass through in that time?
(b) Ifa total of 300J of energy are produced in that time, how many joules will be
produced when just 1C of charge passes?
(c) By referring to the definition of a volt, how great will be the p.d. in volts across the
resistor?​

Answers

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What is the largest source of
thermal energy in our Solar System? Does this energy
reach us through conduction, convection, or radiation?
please help me

Answers

Answer:

sun itself is the main source of thermal energy.radiation

The sun
radiation
explanation: the sun is the source of heat and it heats the solar system through radiation

Are Saturated fats healthy?

Answers

Answer:

Its not as harmful as trans fat, saturated fat can raise bad LDL cholesterol and too much can negatively impact heart health, so it's best consumed in moderation. While there's no need to cut out all saturated fat from your diet, most nutrition experts recommend limiting it to about 10% of your daily calories.

Explanation:

(LDL stands for low-density lipoproteins. It is sometimes called the "bad" cholesterol because a high LDL level leads to a buildup of cholesterol in your arteries.)




Hot water is poured into a mug and the mug gets hot. This is an example of which type of energy transfer?

A) radiation

B) conduction

C) convection

D) This s not an energy transfer

PLEASE HELP ME

Answers

The answer is B: Conduction

The Willis Tower in Chicago has an observation deck 412 m above ground.

How far can you see out over Lake Michigan from the observation deck?

Answers

Answer:

Check Newton's Rings:

d = height of air film

s = distance from center to ring being considered

R = radius of circle considered

The approximate formula is:

d = s^2 / (2 R)   or s = (2 R d)^1/2

If we just use 4000 mi for R and 1/4 mi for d the height

we get s = (2 * 4000 * 1/4)^1/2 = 2000^1/2 mi = 45 mi

The mass of a ship before launch is 55,000 metric tons. The ship is launched down a ramp and drops a total of 10 vertical meters before coming to rest in a lock containing 75,000 cubic meters of fresh water. The specific heat of water is 4200 joules per kilogram degree Celsius. Assume all energy is transferred from the ship to the water. Determine the change in temperature of the water in degrees Celsius .

Answers

Answer:

ΔT = 17.11 °C

Explanation:

In this case, we have a ship standing on a place with a given mass and it's about to be launched to a lock containing water.

At first, before launch, the ship has a potential energy, and when the ship hits the water after being launched, this potential energy is transformed into kinetic energy.

So, let's calculate first the potential energy of the ship:

E = mgh   (1)

We have the mass, gravity and height, so we need to replace the given data here. Before we do that, let's remember to use the correct units. A ton is 1000 kg, so replacing and converting we have:

E = (55000 ton * 1000 kg/ton) * (9.8 m/s²) * 10 m

E = 5.39x10⁹ J

Now this energy will be the same when the ship hits the water, only that is kinetic energy that will result in the rise of temperature. To get this rise we use the following expression:

E = m * C * ΔT   (2)

We have the energy, the mass of water (assuming density of water as 1 kg/m³) and the specific heat, so, replacing in (2) and solving for ΔT we have:

ΔT = E / m * C    (3)

ΔT = 5.39x10⁹ / 4200 * 75000

ΔT = 17.11 °C

Hope this helps

A 6 kg box with initial speed 8 m/s slides across the floor and comes to a stop after 2.4 s. A) What is the coefficient of kinetic friction?B) How far does the box move? C) You put a 5 kg block in the box, so the total mass is now 11 kg, and you launch this heavier box with an initial speed of 7 m/s. How long does it take to stop?

Answers

Answer:

A. Coefficient of kinetic friction, μ = 0.34

B. The box moves a distance of 9.64 m before coming to a stop

C. The heavier box will stop after 2.1 seconds

Explanation:

a. The coefficient of kinetic or sliding friction is given as: μ = F/R

where applied force, F = m × (∆v)/t

∆v = v - u

∆v = 0 - 8 m/s = -8 m/s; t = 2.4 s

R = normal reaction = m×g

where g = 9.8 m/s²

Substituting in the kinetic friction formula; μ = m∆v/t ÷ 1/m×g

μ = ∆v/g×t

μ = 8 / 9.8 × 2.4

μ = 0.34

b. Using the equation v² = u² + 2as to calculate the distance travelled by the box

where v = 0 m/s; u = 8.0 m/s; a = ? s = ?

From F = ma = μR

a = μR/m = (μ × m × g)/m

a = μg

a = 0.34 × 9.8

a = 3.32 m/s²

This is negative acceleration or deceleration

Substituting in the equation of motion

8² + 2 × -3.32 × s = 0

-6.64s = -64

s = 9.64 m

Therefore, the box moves a distance of 9.64 m before coming to a stop

c. The coefficient of friction is independent of mass.

Using the formula in (a): μ = ∆v/g×t

t = ∆v/μg

t = 7/0.34 × 9.8

t = 2.10 s

Therefore, the heavier box will stop after 2.1 seconds

The  coefficient of kinetic friction of the box is 0.34.

The distance traveled by the box is 9.6 m.

The time taken for the heavier box to stop is 2.1 s.

The coefficient of kinetic friction

The  coefficient of kinetic friction of the box is calculated as follows;

[tex]\mu mg = ma\\\\\mu g = a\\\\\mu g = \frac{v}{t} \\\\\mu = \frac{v}{gt} \\\\\mu = \frac{8}{9.8 \times 2.4} \\\\\mu = 0.34[/tex]

The distance traveled by the box

The distance traveled by the box is calculated as follows;

[tex]v^2 = u^2 + 2as\\\\2as = -u^2\\\\s = \frac{-u^2}{2a} \\\\s = \frac{-u^2}{2\mu g} \\\\s = \frac{-(8)^2}{2\times 0.34 \times 9.8} \\\\s = -9.6 \ m\\\\|s| = 9.6 \ m[/tex]

The time taken for the heavier box to stop is calculated as;

[tex]\mu = \frac{v}{gt} \\\\t = \frac{v}{\mu g} \\\\t = \frac{7}{0.34 \times 9.8}\\\\ t = 2.1 \ s[/tex]

Learn more about coefficient of kinetic friction here: https://brainly.com/question/20241845

Work is done on an object when
A) The displacement is not zero
B) The force and the displacement are perpendicular
C) The displacement is zero
D) The force is zero

Answers

Answer:

Incomplete question but the closest ans is

A) The displacement is not zero

Explanation:

For work to be done, the direction of force has to be parallel to or in the same direction as the displacement, this can then be calculated by

[tex]W=Fs \ cos[/tex]θ

Where θ is the angle between direction of force and direction of displacement

By this equation,

if Force is zero, W is zero

if displacement is zero, W is zero

if force and displacement are perpendicular θ=90, cosθ = 0

So A is the cloest choices

A fan has four identical, symmetrically placed blades. The blades are rotating clockwise at twenty revolutions per second.


A) What is the smallest time interval between stroboscope flashes that will make the fan blades appear motionless?


B) What is the highest frequency (in flashes per second) at which a stroboscope will make the

fan blades appear to stand still? Show your calculation.


C) The same questions as (a) and (b), but someone has put a yellow dot on one blade, and now you want the yellow dot to appear to be standing still. Explain, and show your calculation.


D) Now the stroboscope is set for nineteen flashes per second, and the yellow dot appears to be slowly rotating. Which direction does it appear to rotate, clockwise or counterclockwise? Explain, and show your calculation.


E) The same as (d), but the stroboscope is set for twenty-one flashes per second. Explain, and show your calculation.

Answers

Answer:

A) t = 1.249 10⁻² s, B)  f = 80 Hz, C) f = 20 Hz,

D)  slowly advancing an angle of approximately    Δθ = 0.05 rad each flash

E) In each flash it seems to go backward an angle of Δθ = -0.05 rad

Explanation:

A) To make it appear that the blades are immobile, it implies that every time the light turns on, a blade should be in the same position, therefore, as we have 4 blades, they must rotate an angle of 2π/4,  

         θ = π / 2  

         θ = 1.57 rad  

taking the angle let's use the endowment kinematics relations  

          θ = w₀ t + ½ α t²  

in general the fans rotate at constant speed α= 0  

         θ = w₀ t  

         t = θ / w₀  

let's reduce the magnitudes to the SI system  

        w₀ = 20 rev / s (2π rad / 1rev) = 125.66 rad / s  

let's calculate  

        t = 1.57 / 125.66  

        t = 1.249 10⁻² s  

B) the fastest speed for the blades to rotate is when one blade of a complete turn , we use the relationship between the fecuance and the period  

        f = 1 / T  

        f = 1 / 1.25 10⁻²  

       f = 80 Hz

C) we have two possibilities:  

* a yellow dot is placed on each sheet  

In this case the angular velocity of the blade is the same at all points, therefore the results obtained should not change

* a yellow dot is placed on a single sheet.  

Here for the point to remain fixed the angle of rotation must be

       θ= 2π rad  

the time is  

       t = 2π / 125.66  

       t = 5 10⁻² s  

the maximum frequency is  

      f = 1/5 10⁻²  

      f = 20 Hz

D) The copy strobe rotates at f = 19 Hz, the time between each flash is  

      t = 1/19  

      t = 5.26 10⁻² s  

this time is higher, so the angle turned is large  

       θ = w t  

       θ = 125.66 5.26 10⁻²  

       θ = 6.61 rad  

the relationship between this angle and the angle of a circle is  

θ = 1,052

We can see that it is this time the blade rotates 1 complete turns, for this the position of the blade changes us, for the other 0.052 rad the blade rotates a little more than the circumference therefore it seems that it is slowly advancing an angle of approximately  

         Δθ = 0.05 rad each flash  

E) in this case changes the flash speed  

       t = 1/21  

       t = 4.76 10⁻² s  

the angle rotated is  

      θ = 125.66 4.76 10⁻²  

      θ = 5.984 rad  

      θ / 2π = 0.95  

in that case, the blade did not complete the turn, therefore in each flash it seems to go backward an angle

Δθ = -0.05 rad

The time required for one complete cycle of a mass oscillating at the end of a spring is 0.40 s. What is the frequency of oscillation?

Answers

Answer:

the  frequency of the oscillation is 2.5 Hz.

Explanation:

Given;

time to complete the oscillation, t = 0.4 s

number of oscillations, n = 1

The frequency of the oscillation is calculated as;

[tex]F = \frac{n}{t} \\\\F = \frac{1}{0.4} \\\\F = 2.5 \ Hz[/tex]

Therefore, the  frequency of the oscillation is 2.5 Hz.

1.A boy runs at a speed of 3.3 m/s straight off the end of a diving board that is 3 meters above the water

2.What is the horizontal distance the boy in # 1 travels while in the air ? ​

Answers

I think that it is 3 for the distance

If a boy runs at a speed of 3.3 m/s straight off the end of a diving board that is 3 meters above the water, then the horizontal distance traveled by the boy would be 2.58 meters.

What are the three equations of motion?

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem if a boy runs at a speed of 3.3 m/s straight off the end of a diving board that is 3 meters above the water,

3 = ut + 1/2 × a × t²

3 = 0 + 0.5 × 9.8 × t²

t = 3 / 4.9

t = 0.7824

The horizontal distance traveled by the boy = 3.3 ×  0.7824

                                                                         = 2.58 meters

Thus, the horizontal distance traveled by the boy would be 2.58 meters.

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List down the types of centripetal force?

Answers

Answer: Just a few examples are the tension in the rope on a tether ball, the force of Earth's gravity on the Moon, friction between roller skates and a rink floor, a banked roadway's force on a car, and forces on the tube of a spinning centrifuge. Any net force causing uniform circular motion is called a centripetal force.

Answer:

roller skates and a rink floor, a banked roadway's force on a car, and forces on the tube of a spinning centrifuge

Explanation:

A high-voltage transmission line carries 1,000A at 700,000 V. What is the power carried by the line?
If the resistance in the wire is 1ohm/mile and the line is 110 miles long, what is the power loss due to resistive losses in this wire?
a. 11kW
b. 110kW
c. 11 MW
d. 110 MW

Answers

Answer:

d. 110 MW

Explanation:

The computation of the power loss is given below:

= I^2 × R

= 1000^2 × 110

= 110 × 10^6 W

= 110 MW

Here I represent the current through the resistance

ANd, R represent the resistance

So, the correct option is d

A spring with a constant of 76 N/m is extended by 0.9 m. How much energy is stored in the extended spring?

Answers

Answer:

[tex]E=30.78\ J[/tex]

Explanation:

The force constant of the spring, k = 76 N/m

The extension in the spring, x = 0.9 m

We need to find the energy is stored in the extended spring. The energy stored in the spring is given by :

[tex]E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 76\times (0.9)^2\\\\E=30.78\ J[/tex]

So, 30.78 J of energy is stored in the spring.

This is a problem about a child pushing a stack of two blocks along a horizontal floor. The masses of the blocks, and the coefficients of friction between the two blocks and between the lower block and the floor will be given. In order to do the pushing, the child will only be touching one of the two blocks. The mass of the upper block in the stack is 0.760 kg . The mass of the lower block in the stack is 1.630 kg . The coefficients of friction between the two blocks are: static 0.790, and kinetic 0.660. The child's mother, who likes to encourage his experiments, has oiled a small strip of the horizontal floor so that it is very slick; the coefficient of kinetic friction between the oiled section of floor and the lower block is only 0.080 and the coefficient of static friction is insignificantly different. Before the pushing starts, here is a question about the vertical forces acting on the two blocks.

Required:
What is the vertical component of the contact force on the lower block by the floor?

Answers

Answer:

 N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

            N - w₁ -w₂ =

            N = m₁ g + m₂ g

            N = g (m₁ + m₂)

let's calculate

            N = 9.8 (0.760 + 1.630)

            N = 23.4 N

This is the force of the support of the two blocks on the surface.

Calculate the amount of heat given off by 640 g of water cooling from 76 °C to 28° C. Specific heat of water = 4.816 J/g C. Show your step by step process on how you have arrived at your answer. *

Answers

Answer:

47947.52 J.

Explanation:

From the question,

Amount of heat given of (Q) = mc(t₁–t₂).................... Equation 1

Where m = mass of water, c = specific heat capacity of water, t₁ = initial temperature, t₂ = final temperature.

Given, m = 640 g = 640 g, c = 4.816 J/g°C, t₁ = 76 °C, t₂ = 28 °c.

Substitute these values into equation 1 above

Q = 640×4.816(48)

Q = 147947.52 J.

Hence the amount of heat given off is 47947.52 J.

A bar magnet is attached solidly to a frictionless surface and its length is aligned with the x axis.To the right of the first magnet a short distance away is a second bar magnet with its center placed on the x axis and its length perpendicular to the x axis.The second magnet is free to move.Once placed in position at rest,which best describes the initial motion of the second magnet?

a. The magnet will move away from the fixed magnet.
b. The magnet will not move.
c. The magnet will move toward the fixed magnet.
d. The magnet will start to rotate.

Answers

Answer:

the correct answer is D

Explanation:

For this exercise we must remember that the poles of the same if not repel each other and the poles of different signs attract.

With this, let's analyze the situation presented.

The two magnets are perpendicular, with the second magnet to the right of the first.

We have two cases:

* first magnet with the north pole to the right

  If the north of the second magnet is upwards there is a repulsion and the south pole of the second magnet there is an attraction with the north pole of the first magnet, so it would have a force that has to rotate the second magnet.

The force with the south pole of the first magnet that is at a greater distance is less, so the resultant of force is determined by the nearest poles.

If the poles of the second magnet are reversed, that is, the South pole up and the North pole down, the same result is obtained, but with a twist in the opposite direction.

* first magnet with the south pole to the right

    Repels with the south pole of the second magnet and attracts with the north of the second magnet

therefore in both possibilities the second magnet acquires a rotational movement

Consequently the correct answer is D

A 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s2. What is the tension in the string (in N)?

Answers

Answer:

36N

Explanation:

First draw a diagram so you can see which forces act in which direction.

Then define which is your positive direction. I chose the direction of accelleration (downward) to be positive. This means that the weight of the object is also acting in the positive direction but Tension is acting in the negative direction.

If the elevator which contains the object within is accellerating at 2.6 ms^-2 then the object and string system is also accellerating at the same rate.

F = ma where F is the resultant force.

Resultant for is Weight + Tension but tension is in the negative direction so

F = mg -T

F = 5g - T

F = ma so F = 5 x 2.6

13 = 5g-T

T = 5g - 13

T = 36N

(I've taken g = 9.8ms^-2 but if this is for a physics class I'd take it to be 9.81ms^-2)

We have that For a 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s2 he tension in the string (in N) is

T=62N

From the question we are told

A 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s2. What is the tension in the string (in N)

Generally the equation for the Tension  is mathematically given as[tex]T=mg+ma\\\\T=5*(9.8+2.6)\\\\T=62N[/tex]

Therefore

For a 5.0-kg object is suspended by a string from the ceiling of an elevator that is accelerating downward at a rate of 2.6 m/s2 he tension in the string (in N) is

T=62N

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QUCIK!! SOMEONE PLEASE HELP! I’LL MARK BRAINLIEST!!

Answers

Answer:

A. v = √2gh

B. No! The final velocity does not depend on the mass of the car.

C. Yes! the final velocity depends on the steepness of the hill

D. 3.28 m/s

Explanation:

A. Determination of the final velocity.

½mv² = mgh

Cancel out m

½v² = gh

Cross multiply

v² = 2gh

Take the square root of both side

v = √2gh

B. Considering the formula obtained for the final velocity i.e

v = √2gh

We can see that there is no mass (m) in the formula.

Thus, the final velocity does not depend on the mass of the car.

C. Considering the formula obtained for the final velocity i.e

v = √2gh

We can see that there is height (h) in the formula.

Thus, the final velocity depends on the steepness of the hill

D. Determination of the final velocity.

Height (h) = 0.55 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity (v) =?

v = √2gh

v = √(2 × 9.8 × 0.55)

v = √10.78

v = 3.28 m/s

- Thermal Energy Test
The front door of a home is made of steel. When it is warm outside, the door sticks and is difficult to open or close. When the weather is cool, the door
does not stick. Which statement best explains the difference in the behavior of the door when the weather is warm compared to when it is cool?
A. When a material contracts, it increases in volume due to an increase in kinetic energy.
a
B. Different materials expand and contract at the same rates due to the kinetic energy being the same.
C. Thermal expansion makes the door fit better when it is cooler due to a decrease in kinetic energy.
D. The metal in the door expands when it becomes warm due to an increase in kinetic energy, and contracts when it's cooler.

Answers

Answer:D. The metal in the door expands when it becomes warm due to an increase in kinetic energy, and contracts when it's cooler.

Explanation:

because the metal in the door expands due to warm to an increase in kinetic energy and contracts.

When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making the crossing. Using the principles of Kinetic Molecular Theory (KMT), explain why it is a good idea to follow this recommendation.

Answers

According to the ideal gas law, pressure will rise as a gas's temperature rises. There is a limit to how much the tire can expand before the rubber gives in to the pressure build-up.

What the principles of Kinetic Molecular Theory?

For every 10 degrees that the temperature drops, the inflation pressure in tires typically decreases by 1 to 2 psi. Moreover, as the tire pressure heats up during the first 15 to 20 minutes of driving, it will increase by one psi every five minutes.      

The ideal gas law states that pressure will increase as a gas's temperature increases. Before the rubber gives in to the pressure build up, the tire can only expand so far.

Therefore, The pressure in your tires will increase due to the increased particle movement in hot air, which will cause the centre of the tread to bow out and wear out first. Increasing the demand for new tires.

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Explain how a common housecat gets “worms.”explain(science)

Answers

Answer:

Ingenstion

Explanation:

The most common tapeworms that infect cats worldwide are Dipylidium caninum and Taenia taeniaeformis. Dipylidium caninum is transmitted to cats by fleas. The immature fleas larvae ingest the eggs of the worm, but infection is then passed on to a cat when it swallows an infected flea during grooming.

Answer:

The most common worms that housecats get are tapeworms. The housecats always lick their fur to clean them. The tapeworms love where it is damp. After the housecats clean their fur, they will play in the house sometimes they will roll on the floor. Then they get tapeworm eggs, after the eggs hatch the tapeworm will live on the fur of the cats.

Explanation:

A garbage truck and a minivan are moving at the same velocity.


Which automobile will have greater momentum and why? Explain your response using Newton’s second law of motion specifically.


If the garbage truck and minivan in Part A get into an accident with each other, how can safety restraints in a car can save a life? Explain your response using one of Newton’s laws.


Which of Newton’s laws of motion act upon the vehicles at the point of impact? Explain your answer.

Answers

Answer:

Part A

Newton's second law of motion states that the force applied to an object is directly proportional to the rate of change of momentum that is produced

Mathematically, we have;

F = m·v - m·u/Δt

Where;

m = The mass of the object

v = The final velocity of the object

u = The initial velocity of the object

Δt = The duration of motion of the object during change in velocity

Therefore, given that the mass, 'M', of the truck is larger than the mass, 'm', of the minivan, where the time of change in velocity Δt, and the initial and final velocities of both automobiles are the same such as in a sudden stop, the garbage ruck will exert more force than the minivan, and therefore, the garbage truck has a greater initial momentum before the automobiles are brought to a stop

Part B;

According to Newton's first law of motion, we have;

The use of a seat belt (and airbag for front seated passengers) will prevent dashboard or windscreen for the front passengers or the front seat for the passengers in the back, from being the item that stops the continued forward motion of the passengers in the car, which can lead to injury

Part C; The Newton's law of motion that act on a body at the point of impact is Newton's third law of motion, which states that the action and reaction are equal and opposite

Therefore, the action of the garbage truck on the minivan upon impact is equal to the reaction of the minivan to the force the garbage truck exerts on the minivan

Explanation:

A student is conducting an experiment to compare the resistivity of two unknown materials by using two wires, each made of one of the materials and each connected in a circuit. The student measures the potential difference across and current in the wires. What must be the same to be able to compare the resistivities using just the potential difference and current measurements?

Answers

Answer:

is there a. b.  c  or d?

Explanation:

What formula could be used to find distance if you know the speed an the time

Answers

Answer: d = st

Explanation:

We know that the distance is equal to the rate (speed) times the time

d = st

[GT.01]The diagram below shows a portion of the geologic time scale.



Based on the time scale, it can be concluded that

flowering plants appeared on Earth before animals.
animals appeared on Earth before flowering plants.
flowering plants created the first oxygen molecules.
land animals created the first oxygen molecules.

Answers

Answer:diagram....???

geologic time scale what evolve

Answer:

If below is the same diagram:

B. animals appeared on Earth before flowering plants.

good luck, i hope this helps :)

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