urgent help with a geometry assignment!!

Answer:

D. 159

Step-by-step explanation:

The volume of the right pyramid with the given properties is 80√3 cubic volume

The given parameters are:

Start by calculating the base area using:

Base area = 6 * Area of equilateral triangle

So, we have:

Base area = 6 * 4√3

Evaluate

Base area = 24√3

The volume of the pyramid is:

Volume = 1/3 * Base area * Height

So, we have:

Volume = 1/3 * 24√3 * 10

Evaluate

Volume = 80√3

Hence, the volume of the right pyramid is 80√3 cubic volume

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Answer:

WY represents the height.

If the area of an equilateral triangle with sides of 4 ft is 4StartRoot 3 EndRoot square feet, then the area of the regular hexagon base is 24 StartRoot 3 EndRoot square feet.

The volume is 80 StartRoot 3 cubic feet. :D

Answer: 5/24

Step-by-step explanation:

7/8 = 21/24      2/3= 16/24

21/24 - 16/24 = 5/24

Answer:

[tex]1.47 \times {10}^{4} [/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

That means the chance of getting blue = 12/20

12/20 = 6/10

6/10 = 3/5

also, 3/5 = 60%, or .60

The quadratic function that models the data given in the table is 203.8x² - 26.6x + 8.6

A quadratic function is an equation that usually has a single variable and it is raised to the power of 2.

A quadratic function has the form : ax² + bx + c = 0

Where: a, b,c are known numbers and x is unknown

Given the quadratic function: 185x²+ 1.

Given the quadratic function: 203.8x² - 26.6x + 8.6

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1) Diagonals of a rectangle bisect each other, so AW=13.

2) Since diagonals of a rectangle are congruent, AC=BD. Then, since diagonals of a rectangle bisect each other, DW=13.

3) Diagonals of a rectangle are congruent, so BD=26.

4) Opposite sides of a rectangle are congruent, so AD=10.

5) Using the Pythagorean theorem, BA=24.

Answer:

x = -2, -8.

Step-by-step explanation:

x =[(-b +/- √(b^2 - 4ac)] / 2a

x^2 + 10x + 16 = 0

Here a = 1, b = 10 and c = 16, so substituting in the formula:

x = [-10 +/- √(10^2 - 4*1*16)] / 2

= (-10 +/- √36)/2

= (-10 +/- 6)/2

= -4/2, -16/2

= -2, -8.

Answer:

x = - 8 , x = - 2

Step-by-step explanation:

x² + 10x + 16 = 0

with a = 1, b = 10 , c = 16

then using the given quadratic formula

x = [tex]\frac{-10+/-\sqrt{10^2-(4(1)(16)} }{2}[/tex]

  = [tex]\frac{-10+/-\sqrt{100-64} }{2}[/tex]

  = [tex]\frac{-10+/-\sqrt{36} }{2}[/tex]

  = [tex]\frac{-10+/- 6}{2}[/tex]

then

x = [tex]\frac{-10-6}{2}[/tex] = [tex]\frac{-16}{2}[/tex] = - 8

x = [tex]\frac{-10+6}{2}[/tex] = [tex]\frac{-4}{2}[/tex] = - 2

Step-by-step explanation:

that's it b is for brings

b compliment is for doesn't bring

Answer:

x = 50° y = 130°

Step-by-step explanation:

x and 50° are vertically opposite angles and are congruent , then

x = 50°

y and 50° are adjacent angles and sum to 180° , then

y + 50° = 180° ( subtract 50° from both sides )

y = 130°

Answer:

A(-2,2),. B(−1, −2), and C(-6, 1). Graph the triangle. Then graph the triangle after a translation 7 units right and. 3 units up.

Step-by-step explanation:

After translation 7units left and 17unit up ΔXYZ become ΔX'Y'Z' with new coordinates X'(-14,4) , Y'(-10,8) an Z'(-14,12).

" Translation is defined as the moving a geometrical shape by certain distance."

According to the question,

In ΔXYZ,

Coordinates of X =(-7,-13)

Coordinates of Y = (-3 ,-9)

Coordinates of Z = ( -7, -5)

After translation 7units left and 17units up and rotation 270° counterclockwise around the origin

New coordinates as shown in the drawn graph of ΔX'Y'Z'

Coordinates of X' = (-14, 4)

Coordinates of Y' = (-10, 8)

Coordinates of Z' = (-14,12)

Hence, translation 7units left and 17unit up ΔXYZ gives ΔX'Y'Z' with new coordinates X'(-14,4) , Y'(-10,8) an Z'(-14,12).

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Answer:

It's 44 in²

Remember the diagonal formula, whereas there is p and q for the diagonals.

[tex]A = \frac{pq}{2} = \frac{11*8}{2} = 44~in.[/tex]

Answer:

Area of rhombus  = 44 square inches

Step-by-step explanation:

[tex]\sf \boxed{Area \ of \ rhombus = \dfrac{d_1*d_2}{2}}[/tex]

[tex]\sf \text{Here, $d_1$ and $d_2$ are the diagonals}[/tex]

                             [tex]\sf = \dfrac{11 *8}{2}\\\\ = 11*4\\\\ = 44 \ in^{2}[/tex]

Answer:

10 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (8, 5 ) and (x₂, y₂ ) = (- 2, 5 )

d = [tex]\sqrt{(-2-8)^2+(5-5)^2}[/tex]

   = [tex]\sqrt{(-10)^2+0^2}[/tex]

   = [tex]\sqrt{100}[/tex]

   = 10

Answer:

length=0.65 mi

length in yr= 0.65x1760=1144

The length of the jogging track is 0.65 miles.

To convert the length of the jogging track from yards (yd) to miles (mi), use the ratio between yards and miles.

1 mile = 1760 yards

Now, set up the equation to convert the length:

Length in miles (mi) = Length in yards (yd) / Conversion ratio

Length in miles (mi) = 1144 yd / 1760 yd/mi

Now, perform the calculation:

Length in miles (mi) = 1144 / 1760 ≈ 0.65 miles (rounded to the nearest hundredth)

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The different mathematical operations that have as a result 54 are 9x6,  8x9 - 18, 5x5 + 29, and 27x2.

This refers to calculating values using addition, multiplication, division, etc.

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Answer:

y = 1.25r

Step-by-step explanation:

1.25 x r(the pounds brought) = y(the money spent)

Answer:

1.5

Step-by-step explanation:

Answer:

Each sandwich costs $5.12

Step-by-step explanation:

Six sandwiches is $30.72

Divide 30.72 by 6 and you get 5.12

That means that each sandwich costs $5.12

Problem 1

--------------------

Explanation:

Arc BC is 58 degrees. The arc AB combines with it to form semicircle ABC, which is basically arc ABC with measure 180

This must mean arc AB is 180-58 = 122 degrees

When in doubt, chances are the number 180 might be involved (in some way) when it comes to geometry problems. Of course, this isn't always a guarantee. The number does show up a lot though.

Once we determine what arc AB is equal to, we cut it in half to get the inscribed angle ADB. Refer to the inscribed angle theorem. Notice how angle ADB subtends the arc AB.

==========================================================

Problem 2

--------------------

Explanation:

x = length of AE

Since AC = 13, this makes EC = 13-x

We'll use the intersecting chords theorem to find x.

(AE)*(EC) = (BE)*(DE)

x*(13-x) = 6*6

13x-x^2 = 36

-x^2 + 13x - 36 = 0

x^2 - 13x + 36 = 0

(x-9)(x-4) = 0

x-9 = 0 or x-4 = 0

x = 9 or x = 4

This means AE could be 9 units long or 4 units long.

Usually the diagram isn't drawn to scale so we don't really use it all too much (other than initial set up). However, if the diagram was drawn to scale, then notice that AE is over the halfway point of AC. This means we would be able to rule out x = 4 since 4 is not over the halfway point of 13. I have a feeling this is what your teacher might be going for.

In short, only AE = 9 is possible.

Answer:

There are now 6.5 ounces in the new bag.

Step-by-step explanation:

To solve this question, take 30% of 5 and add it to the original amount of 5

30% = 0.30

5 * 0.30 = 1.5

5 + 1.5 = 6.5 ounces of candy.

Hope this helps!

Answer:

See below

Step-by-step explanation:

For a circle:

   Area = pi r^2   =   3.14 * 1.6^2 = 8.04 units^2

   Circumf = pi * d   = pi * 2r = 3.14 * (2 * 1.6) = 10.05 units

Answer:

[tex]a{}^{2} - {b}^{2} = {c}^{2} [/tex]

[tex]12 {}^{2} - (3 \sqrt{7})^{2} [/tex]

[tex]144 - 63 = 81[/tex]

[tex] \sqrt{80 } = 9[/tex]

Answer:

sorry for dirty handwriting

The composite function for the price a loyalty member would pay based on the original price x is  C(L(x)) = 0.7803x.

We have been given that

Sales price: S(x) = 0.85%

Loyalty member discount L(S) = 0.85S

Final cost: C(L) = 1.08L

Find out- which is the composite function for the price a loyalty

member would pay based on the original price x?

Sales price: S(x) = 0.85%

Loyalty member discount L(S) = 0.85S

Put the value of S then -

L(S) = 0.85× 0.85x

L(S) = 0.7225x

Final cost: C(L) = 1.08L

Now put the value of L

C(L) = 1.08L

C(L) = 1.08 × 0.7225x

C(L(x)) = 0.7803x

Hence , C(L(x)) = 0.7803x is the composite function for the price a loyalty member will pay given the initial price x.

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