Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is a right triangle. Show all calculations for full credit.


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Answer:

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F(x) is in the format of a quadratic function:

Hence it is a parabola.

The table represents a relation with two x-intercepts and two y-intercepts (points with the coordinate of 0).

We know that parabola can have maximum of one y-intercept, hence G(x) is not a parabola.

The matching answer choice is the first one.

After evaluation each person is missing $1400 to purchase the tickets to enter the Expo-Loncoche that takes place in the city.

Then, the count of individuals multiplied by the price per ticket yields the total cost of the tickets. So we have to apply principles of algebraic expression.
Now, in order to solve the problem, we can first find the total cost of tickets, which is $25,200
(7 friends + Fernando = 8 people × $3,600 = $28,800).
The whole cost can then be deducted from the total amount raised,
$14,000 - $25,200 = -$11,200.

Therefore, they are short $11,200 in total.
Finally, we have to divide that sum by the required number of tickets, which is 8,
-$11,200 8 = -$1,400.
Hence,  each person needs an additional $1,400 to buy tickets.

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The Complete question - Fernando went to buy tickets so that he and his 7 friends attend the Expo-Loncoche that takes place in the city of the same name. Together they managed to raise $14,000, but each the entrance costs $3,600. How much money is missing each to buy tickets?

The height of a 16-year-old boy in the 96th percentile is approximately 73.375 inches. The z-score associated with the 96th percentile is 1.75.

To find the z-score associated with the 96th percentile, we can use the following steps:

1. Locate the percentile in a standard normal distribution table or use a calculator that can compute percentiles (e.g., a graphing calculator or an online calculator).

2. For the 96th percentile, we find the corresponding z-score. Using a standard normal distribution table or an online calculator, the z-score is approximately 1.75.

So, the z-score associated with the 96th percentile is 1.75.

To find the height of a 16-year-old boy in the 96th percentile, we can use the following formula:

Height = mean + (z-score × standard deviation)

Here, the mean height is 68.3 inches, the z-score is 1.75, and the standard deviation is 2.9 inches. Plugging these values into the formula:

Height = 68.3 + (1.75 × 2.9) ≈ 68.3 + 5.075 ≈ 73.375 inches

So, the height of a 16-year-old boy in the 96th percentile is approximately 73.375 inches.

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The length of AB is approximately 12.704 units.

To solve this problem, we can use trigonometry and the fact that the easel forms a 30° angle to find the length of AB.

We know that RC is 22, and that angle R is 30°. Let's use the trigonometric function tangent to find AB:

tan(30°) = AB / RC

We can rearrange this equation to solve for AB:

AB = tan(30°) * RC

Using a calculator or trigonometric table, we find that tan(30°) = 0.5774 (rounded to four decimal places). Therefore:

AB = 0.5774 * 22

AB ≈ 12.704

So the length of AB is approximately 12.704 units.

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Minimum

-11

Main concepts:

Concept 1: Identify the type of equation

Concept 2: Identify the concavity (opens up/down)

Concept 3: Finding a vertex of a parabola

Concept 1: Identify the type of equation

First, observe that the equation is a polynomial.  This is a type of equation where there may be multiple terms containing an x, where each term with an x is raised to a whole number power, and may be multiplied by a real number.  Additionally, there may be a constant term added (or subtracted).

For our equation, [tex]y=3x^2-12x+1[/tex], the first two terms contain an x, each raised to a whole number power, and are multiplied by a number.  Additionally, there is a constant added to the end of the equation.  Therefore, this is a polynomial.

The largest power of x in a polynomial is called the "degree" of the polynomial.  Since the largest power of x is 2, this is called a second degree polynomial.  Another common name for a second degree polynomial is a quadratic equation.

This quadratic equation is already in what is known as "Standard form" [tex]y=ax^2+bx+c[/tex]

Concept 2: Identify the concavity (opens up/down)

For quadratic equations, the graph of the equation will be a sort of "U" shape" called a parabola.  The parabola either opens up or down depending on the "leading coefficient" in the quadratic equation.

The "leading coefficient" of any polynomial is the constant number that is multiplied to x in the term with the highest power.  In this case, the leading coefficient is 3.

A parabola opens up or down in correspondence with the sign of the leading coefficient.  If the leading coefficient is positive, the parabola opens upward.  If the leading coefficient is negative, the parabola opens downward.

Since the leading coefficient is 3, the parabola for our example opens upward.  The branches of the "U" will go upward forever, without a maximum.  However, the bottom of the "U" will have a minimum value.  We are assigned to find this minimum value (how low it goes).

Concept 3: Finding a vertex of a parabola

To find the vertex of a parabola, with an equation in standard form, there are a few methods, but the most straightforward is to use the vertex formula:

[tex]h=\dfrac{-b}{2a}[/tex]

Where "h" is the x-coordinate of the vertex, and "a" and "b" are the coefficients from the quadratic equation: [tex]y=ax^2+bx+c[/tex]

[tex]h=\dfrac{-(-12)}{2(3)}[/tex]

[tex]h=\dfrac{12}{6}[/tex]

[tex]h=2[/tex]

So, the parabola will have a vertex with an x-coordinate of "2", meaning that the lowest point will be at a position that is 2 units to the right of the origin... however, we still don't know how high that minimum is.  Fortunately, the equation [tex]y=3x^2-12x+1[/tex] itself gives the relationship between any x-value and the y-value that is associated with it.

[tex]y=3x^2-12x+1[/tex]

[tex]y=3(2)^2-12(2)+1[/tex]

[tex]y=3*4+(-12)*2+1[/tex]

[tex]y=12+-24+1[/tex]

[tex]y=-11[/tex]

So, the vertex of the parabola is (2,-11).

The height of the vertex is -11, so the value of the minimum is -11.

Side note: "What is the value of the minimum" is a different question that "where is the minimum at".  The minimum is at 2.  The actual value of the minimum is -11.

Answer:

The answer to 1+1 is 2.

Answer:

2

Step-by-step explanation:

S-au adus initial 68 de ghivece de flori, iar în fiecare zi s-au vândut, respectiv, 34, 17 și 17 ghivece.

Initial, la florărie s-au adus x ghivece de flori. În prima zi s-au vândut 1/2 * x ghivece. A doua zi, din numărul rămas s-au vândut 1/4 * (x - 1/2 * x) ghivece, adică 1/4 * 1/2 * x.

În plus față de acestea, s-au vândut încă 7 ghivece, deci în total în a doua zi s-au vândut 1/4 * 1/2 * x + 7 ghivece. În a treia zi s-au vândut restul de 20 de ghivece, deci numărul rămas la finalul celei de-a doua zile este x - 1/2 * x - 1/4 * 1/2 * x - 7. Trebuie să fie egal cu 20, deci avem ecuația x - 1/2 * x - 1/4 * 1/2 * x - 7 = 20.

Rezolvând această ecuație, obținem x = 128. Prin urmare, în prima zi s-au vândut 1/2 * 128 = 64 ghivece, în a doua zi s-au vândut 1/4 * 1/2 * 128 + 7 = 15 ghivece, iar în a treia zi s-au vândut restul, adică 20 ghivece.

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The scope of both functions is all real numbers.

To compute the values of (f+g)(x) and (f-g)(x), we apply the addition and subtraction of two distinct functions, respectively:

(f+g)(x) = f(x) + g(x) = [tex](-2x + 4) + (3x^2) = 3x^2 - 2x + 4[/tex]

(f-g)(x) = f(x) - g(x) = [tex](-2x + 4) - (3x^2) = -3x^2 - 2x + 4[/tex]

The scope of both functions is all real numbers.

Subsequently, we evaluate the expressions for x = -3:

(f+g)(-3) = [tex]3(-3)^2 - 2(-3) + 4[/tex] = 3(9) + 6 + 4 = 27 +6 +4 = 37

(f-g)(-3) = [tex]-3(-3)^2 - 2(-3) + 4[/tex]= -3(9) + 6 + 4 = -27 + 6 + 4 = -17

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Answer:

m∠W = 45°

Step-by-step explanation:

When both legs of a right triangle are congruent, we know that it is an isosceles right triangle because of the isosceles triangle theorem.

Therefore, we can identify W as:

m∠W = (180 - 90)° / 2

m∠W = 45°

Note: We get the / 2 from the fact that both non-right angles are congruent; therefore, they are half of the remaining angle measures after subtracting the right angle (90°) from the total of a triangle (180°).

The net present value of this investment, assuming a required 8% return, is approximately $13,829.

To calculate the net present value (NPV) of this investment, we'll first find the present value of the net cash flows and the salvage value, then subtract the initial investment.

For the net cash flows, we'll use the Present Value of Annuity (PVA) formula:

PVA = Net Cash Flow * [(1 - (1 + r)^(-n)) / r]

Where:
- Net Cash Flow is $11,000
- r is the required return (0.08)
- n is the number of years (7)

PVA = 11,000 * [(1 - (1 + 0.08)^(-7)) / 0.08]
PVA = 11,000 * 4.99271
PVA ≈ $54,920

Next, we'll find the present value of the salvage value at the end of year 7:

PV_salvage = Salvage Value / (1 + r)^n
PV_salvage = 6,700 / (1 + 0.08)^7
PV_salvage ≈ $3,909

Now, we can calculate the NPV by adding the present values and subtracting the initial investment:

NPV = (PVA + PV_salvage) - Initial Investment
NPV = (54,920 + 3,909) - 45,000
NPV ≈ $13,829

The net present value of this investment, assuming a required 8% return, is approximately $13,829.

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Answer:

2.2

Step-by-step explanation:

To find your GPA, use the attached image:

After you've written down your numerical scores, divide it by the total classes you're taking, which is 7.

So, your GPA is 2.2

The function is increasing for all real values of x where x < –4.

The statement that is true about the function is: "The function is decreasing for all real values of x where x < -4."

In order to determine the behavior of the function, we look at the given options. Among the options, the only statement that aligns with the function being decreasing is the one that states the function is decreasing for all real values of x where x < -4.

If a function is decreasing, it means that as the value of x decreases, the value of the function also decreases. In this case, it indicates that as x becomes more negative, the function's values decrease.

Therefore, the statement that correctly describes the behavior of the function is that it is decreasing for all real values of x where x < -4.

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1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.

2) . The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.

3) The expanded equation is e² = x² -12x + 36 + h²
4) the expanded equation is a² = b²-x²+32

According to the Pythagorean theorem, the square of the hypotenuse (c) of a right triangle equals the sum of the squares of the other two sides  (a² + b²).

So

1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.

2) The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.

3) The equation is e² = (6 - x)² + h² when expanded

e² = 36 - 12x + x² + h²
or

e² = x² -12x + 36 + h²

4) Using this equation, we can solve for h² by subtracting (b-x)² from both sides:

a² - (b-x)² = h²

Now we can substitute this expression for h² into the equation given in step 3

2² = 6² - 2bx + (a² - (b-x)²)

Simplifying this equation, we get:

4 = 36 - 2bx + a² - (b-x)²

Expanding the square term, we get:

4 = 36 - 2bx + a² - (b² - 2bx + x²)

Simplifying further, we get:

4 = 36 - b² + x² + a²

Rearranging, we get:

a² = b² - x² + 32

So the equation expanded  is a² = b² - x² + 32.

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Full Question:

For 1 and 2, see attached image.
3)  The equation e²= (6 – x)² + h² is expanded y to become ?
4) Using the equation from step 1, the equation

2² = 6² - 2bx +32+ h becomes a = 62 - 2bx + 2

by substitution

22 = 62 - 2x + x2 +h?

The linear equation in slope intercept form is:

y = -0.1x + 9

The formula for finding the Linear Equation in slope intercept form is expressed in the form:

y = mx + c

where:

m refers to the slope

c refers to the y-intercept

Looking at the given graph, we can see that:

The y-intercept = 9

The y-intercept is the point where the line crosses the y-axis while x-intercept is the point where the line crosses the x-axis.

Taking the two coordinates:

(1970, 7) and (1990, 5)

Slope:

m = (5 - 7)/(1990 - 1970)

m = -2/20

m = -0.1

Thus, the Equation in slope intercept form is expressed in the form of:

y = -0.1x + 9

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The polynomial represented by the model is [tex]]x^2 - x + 2[/tex]

Based on the provided model, the polynomial represented is:

1 black square block: x^2
2 white thin blocks: -2x
1 black thin block: x
1 white small square block: -1
3 black small blocks: +3

The polynomial that the model represents is:
[tex]x^2 - 2x + x - 1 + 3[/tex]

Combining like terms, we get:
[tex]x^2 - x + 2[/tex]

So, the polynomial represented by the model is [tex]x^2 - x + 2[/tex].

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Since the function approaches the same value (0) along both paths, we can claim that the limit lim(x,y)→(0,0) f(x,y) exists and is equal to 0.

Your question is asking whether the limit of the function f(x,y) exists at the point (0,0). The function f(x,y) is defined as:
f(x,y) = x^2 + y if (x,y) ≠ (0,0)
f(x,y) = 0 if x = y = 0
To verify whether the limit exists, we need to check if the function approaches a unique value as (x,y) approaches (0,0). In other words, we need to determine if lim(x,y)→(0,0) f(x,y) exists.
To verify this claim, consider the function along different paths towards (0,0). Let's examine two paths:
1) x = 0: As x approaches 0, f(0,y) = y, and the limit becomes lim(y→0) y = 0.
2) y = x: As y approaches 0 along this path, f(x,x) = x^2 + x, and the limit becomes lim(x→0) (x^2 + x) = 0.

Since the function approaches the same value (0) along both paths, we can claim that the limit lim(x,y)→(0,0) f(x,y) exists and is equal to 0.

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The function is P(t) = 380 x [tex]1.0300^{t}[/tex], which is an exponential function, and the rate of change is 1.24% each hour.

The equation P(t) = 380 x [tex](1 + 0.03)^{t}[/tex] represents the population of bacteria after t days.

Rounding to four decimal digits and simplifying:

P(t) = 380 x [tex]0.0300^t[/tex]

We can use the following formula to determine the percentage rate of change each hour:

r = [tex]100 \times e^{(ln(1 + 0.03)/24) - 1)}[/tex]

where e is the Euler's number, ln is the natural logarithm, and r is the percentage rate of change per hour.

Rounding to the nearest tenth of a percent and simplifying:

r = 1.24%

This exponential function simulates the population of bacteria multiplying exponentially at a rate of 3% each day in a petri dish.

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The amount of water in the tank can be calculated by multiplying 3/4 to the volume of the tank: 3/4 x V = (3/4)L x W x H.

To calculate the amount of water in the aquarium's fish tank in the shape of a prism,

you would need to know the dimensions of the tank and then multiply the volume of the tank by 3/4.

Let's assume that the aquarium has a rectangular prism shape,

the amount of water in the tank would depend on the dimensions of the tank.

Let's assume the tank has a length of L, a width of W, and a height of H.

The volume of the tank can be calculated by multiplying the length, width, and height together: V = L x W x H.

If the tank is 3/4 full of water, the volume of water in the tank would be 3/4 of the total volume of the tank.

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a. The ratio of the perimeters of Figures A and B will also be (3)÷(4).

b. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.

c. The area of Figure B will be (9÷16)a.

Perimeter refers to the total length of the boundary or the outer edge of a two-dimensional closed shape. It is the sum of the lengths of all sides of the shape.

a. Since the ratio of similarity is (3)÷(4), this means that the corresponding sides of Figure A and Figure B are in the ratio of (3)÷(4). Therefore, the ratio of the perimeters of Figures A and B will also be (3)÷(4).

b. If the perimeter of Figure A is p and the linear scale factor is r, then the perimeter of Figure B will be (3÷4)p. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.

c. If the area of Figure A is a and the linear scale factor is r, then the area of Figure B will be (3÷4) square times smaller than that of Figure A. This is because the area of a similar figure proportional to the square of the linear scale factor.

Therefore, the area of Figure B will be (9÷16)a.

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Solving for dz/dt, we get:

dz/dt ≈ 11.650 ft/sec.

So, after another minute, the distance between Claire and Anna is changing at a rate of approximately 11.650 ft/sec.

Hi there! To answer this question, we can use the Pythagorean theorem and implicit differentiation. Let x be the distance Claire runs east and y be the distance Anna runs north. After 1 minute, Claire has already run 12 * 60 = 720 ft. After another minute, x = 720 + 12t, and y = 7t.

Now, we can set up the Pythagorean theorem: x^2 + y^2 = z^2, where z is the distance between them. Substituting the expressions for x and y, we get (720 + 12t)^2 + (7t)^2 = z^2.

To find the rate at which the distance between them is changing (dz/dt), we need to differentiate both sides of the equation with respect to time, t:

2(720 + 12t)(12) + 2(7t)(7) = 2z(dz/dt).

Now, we can plug in the values for t = 2 minutes:

2(720 + 24)(12) + 2(14)(7) = 2z(dz/dt).

Simplifying, we get:

34560 + 392 = 2z(dz/dt).

After 2 minutes, Claire has run 12(120) = 1440 ft, and Anna has run 7(60) = 420 ft. Using the Pythagorean theorem, we can find z:

z = √(1440^2 + 420^2) ≈ 1500 ft.

Now we can find dz/dt:

34952 = 2(1500)(dz/dt).

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The unit rate in chapters per hour is 21/16 hours

Greg read 7/8 hours in 2/3 chapter

The unit rate can be calculated as follows

7/8= 2/3

1= x

cross multiply both sides

2/3x= 7/8

x= 7/8 ÷ 2/3

x= 7/8 × 3/2

x= 21/16

Hence 21/16 chapters is read in one hour

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The domain of the function is 0 ≤ b ≤ 6, and the range of the function is 30 ≤ c ≤ 174.

The function that models the total weight of a crate with b boxes inside is given as:

c = 24b + 30

We know that each crate can hold a maximum of 6 boxes. Therefore, the number of boxes inside the crate can only take values from 0 to 6.

Domain:

The number of boxes b can take values from 0 to 6. Therefore, the domain of the function is:

0 ≤ b ≤ 6

Range:

To find the range of the function, we need to consider the maximum and minimum values that c can take when

0 ≤ b ≤ 6.

When b = 0, the crate is empty, and the total weight of the crate is:

c = 24(0) + 30 = 30.

When b = 6, the crate is full with 6 boxes, and the total weight of the crate is:

c = 24(6) + 30 = 174.

Therefore, the range of the function is:

30 ≤ c ≤ 174

We can then say the domain of the function is 0 ≤ b ≤ 6, and the range of the function is 30 ≤ c ≤ 174.

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If she sells 280 items and raises $540, then Susan raises $300 from selling lemonade.

To determine how much money Susan raises from selling lemonade, we'll set up a system of equations using the given information.

Let x be the number of lemonade cups and y be the number of brownies sold. We know:

1. x + y = 280 (total items sold)
2. 2.50x + 1.50y = 540 (total money raised)

First, we'll solve for x in equation 1:

x = 280 - y

Now, substitute this expression for x in equation 2:

2.50(280 - y) + 1.50y = 540

Simplify and solve for y:

700 - 2.50y + 1.50y = 540
-1.00y = -160
y = 160

Now that we have the number of brownies (y), we can find the number of lemonade cups (x):

x = 280 - 160
x = 120

Finally, calculate the money Susan raises from selling lemonade:

Money from lemonade = 120 * $2.50 = $300

So, Susan raises $300 from selling lemonade.

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The area of sector is 14π/3 square inches for a circle having a radius of 7 inches and measures an angle of 4π/15 radians.

Radius of circle =  7 inches

Angle of circle =  4π/15 radians

The area of a sector of a circle can be calculated by using the formula:

A = (θ/2) × [tex]r^2[/tex]

A =  The area of the sector

θ = central angle in radians

r = radius of the circle.

Substituting the given values in the formula:

Area = (θ/2) × [tex]r^2[/tex]

Area = (4π/15 × 1/2) × [tex]7^2[/tex]

Area= (2π/15) × 49

Area = 14π/3

Therefore, we can conclude that the area of the sector is 14π/3 square inches.

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Answer:the radius of the hemisphere with a volume of 324 ft³ is approximately 6.3 feet (to the nearest tenth).

Step-by-step explanation:

The formula for the volume of a hemisphere is:

V = (2/3) × π × r³, where V is the volume and r is the radius of the hemisphere.

We have been given the volume of the hemisphere as 324 ft³, so we can substitute this into the formula:324 = (2/3) × π × r³

To find the radius r, we need to solve for it. Dividing both sides by (2/3) × π gives:r³ = (324 / ((2/3) × π))r³ = (324 × 3) / (2 × π)r³ = 486 / π

Taking the cube root of both sides gives:r = (486 / π)^(1/3)

Using a calculator to evaluate this expression, we get:r ≈ 6.3

Answer:

Step-by-step explanation:

We can set up the proportion (20/40) = (x/220), where x is the number of students in the 7th grade class who prefer the zoo. Cross-multiplying this proportion gives us 40x = 20*220, which simplifies to x = 110.

Therefore, we can expect that 110 students in the 7th grade class prefer the zoo.

To explain this solution in more detail, we can use the concept of proportionality. In statistics, when we take a random sample from a larger population, we can use the proportion of the sample to estimate the proportion of the population.

If we assume that the sample is representative of the population, then the proportion of students who prefer the zoo in the sample should be similar to the proportion of students who prefer the zoo in the 7th grade class.

By setting up a proportion between the sample and the population, we can estimate the number of students in the 7th grade class who prefer the zoo. We know that 20 out of the 40 students in the sample from the 7th grade class prefer the zoo,

so we can use this proportion to estimate the number of students in the 7th grade class who prefer the zoo. Cross-multiplying the proportion gives us the equation 40x = 20*220, which we can solve for x to get x = 110.

It is important to note that this is just an estimate and that there is some degree of uncertainty involved in the estimation process. However, by using statistical methods such as proportionality, we can obtain a reasonable estimate that can help us make informed decisions.

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The test that should be run on the claim by Proctor & Gamble should be B. z-test of a proportion.

The alternative hypothesis indicates a c. left-tailed test.

The p - value is 0.2665. Unilever does not have sufficient evidence to reject Proctor & Gamble's claim, so A. no.

Conducting a z-test of a proportion is necessary in light of the proportion-based nature (at least half of the bars being 99.44% pure) of the inquiry, instead of means. Proctor & Gamble had asserted that over fifty percent of their bars exhibit 99.44% purity or better; Unilever wishes to investigate this assertion's accuracy.

Consequently, we run our test under null-hypothesis framework that considers fifty percent of bars possessing sufficient purity level and alternative hypothesis positing <50% do. The resultant course of action entails carrying out a left-tailed test.

The p - value. Find the test statistic:

z = ( 0. 4795 - 0.5) / √ ( ( 0.5 x (1 - 0.5) ) / 146)

z = - 0. 6236

z- table shows the p - value is 0. 2665 as a result.

With the p - value being higher than the normal significant level of 0. 05, Unilever should not reject Proctor & Gamble's claim.

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If after 2.00 minutes, Ethan is 195km away from his house towards west, Ethan's velocity is approximately 6393 km/h.

To find Ethan's velocity, we need to first determine the distance he traveled and the time he spent traveling.

Given:
1. Initial position: Ethan's house
2. Distance to park: 85 km south
3. Final position: 195 km west from house after 2 minutes

To find the total distance, we can use the Pythagorean theorem, as the path forms a right triangle:
Distance = √(85² + 195²) = √(7225 + 38025) = √(45250) ≈ 212.72 km

Now, let's convert the time from minutes to hours:
2 minutes = 2/60 hours ≈ 0.0333 hours

Finally, we can calculate Ethan's velocity:
Velocity = Distance / Time = 212.72 km / 0.0333 hours ≈ 6393 km/h

Ethan's velocity is approximately 6393 km/h.

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