To which part of the system does the actuator connect to in an automobile cruise control system?

A. Piston
B. Wheel
C. Throttle
D. Gearbox

Answer:

Yes

Explanation:

In such a case, one way to check the credit charge is to contact your bank, doing so would allow the bank to check your account properly to determine where the transaction was originated from.

Another way you could check is to contact the online merchant where such a transaction was initiated.

Answer:

shear strength = 2682.31 Ib/ft^2

Explanation:

major principal stress = 100 Ib / in2

minor principal stress = 20 Ib/in2

Normal stress = 3000 Ib/ft2

Determine the shear strength when direct shear test is performed

To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a

for direct shear test

use Mohr Coulomb criteria relation between normal stress and shear stress

Shear strength when normal strength is 3000 Ib/ft  = 2682.31 Ib/ft^2

attached below is the detailed solution

Answer:

[tex]T_{2}[/tex] = -9.24 °C

x = 0.1057

Explanation:

The tables used in this answer and explanation come from Fundamentals of Engineering Thermodynamics 9th Edition.

Using Table A-14: Properties of Saturated Ammonia (Liquid-Vapor): Pressure Table and the given [tex]P_{2}[/tex], [tex]T_{2}[/tex] can be determined by finding the temperature that corresponds with [tex]P_{2}[/tex] on the table. In this case, [tex]T_{2}[/tex] = -9.24 °C.

The quality of the refrigerant can be determined by using data from the same table and [tex]h_{2} =274.26[/tex] kJ/kg.

Necessary data (P=3bar):

[tex]h_{f}=137.42[/tex] kJ/kg

[tex]h_{g}=1431.47[/tex] kJ/kg

The formula to calculate quality is [tex]h_{2} =h_{f}+x(h_{g}-h_{f})[/tex].

Rearranging for x:

[tex]x=\frac{h_{2}-h_{f} }{h_{g}-h_{f} }= \frac{274.26-137.42}{1431.47-137.42}=0.1057[/tex]

Answer:

Hello your question has some missing information below are the missing information

The refrigerant enters the compressor as saturated vapor at 140kPa Determine The coefficient of performance of this heat pump

answer : 2.49

Explanation:

For  vapor-compression refrigeration cycle

P1 = P4  ; P1 = 140 kPa

P2( pressure at inlet ) = P3 ( pressure at outlet ) ; P2 = 800 kPa

From pressure table of R 134a refrigerant

h1 ( enthalpy of saturated vapor at 140kPa ) = 239.16 kJ/kg

h2 ( enthalpy of saturated liquid at P2 = 800 kPa and t = 60°C )

= 296.8kJ/kg

h3 ( enthalpy of saturated liquid at P3 = 800 kPa ) = 95.47 kJ/kg

also h4 = 95.47 kJ/kg

To determine the coefficient of performance  

Cop = ( h1 - h4 ) / ( h2 - h1 )

∴ Cop = 2.49

Answer: It is  a nominal rate per year

Answer:

In C++:

#include <iostream>

#include <cmath>

using namespace std;

int main(){

 double total = 0;

 for(int i = -170; i<=-130;i++){

     if(i%2 == 0 && i%7==0){

         double angle = i*3.14159/180;

         total+=sin(angle);      }  }

 cout<<"Total: "<<total;

 return 0; }

Explanation:

This initializes the total to 0

 double total = 0;

This iterates from -170 to - 130

 for(int i = -170; i<=-130;i++){

This checks if the current number is even and is divided by 7

     if(i%2 == 0 && i%7==0){

This converts the number from degrees to radians

         double angle = i*3.14159/180;

This adds the sine of the number

         total+=sin(angle);      }  }

This prints the calculated total

 cout<<"Total: "<<total;

Answer:

thank you

Explanation:

have a nice day

Answer:

thankd

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Answer:

≈ 53 seconds

Explanation:

calculate Time required for the product to begin the falling-rate drying period

Initial moisture content =  0.77 kg water /kg of product

                                               = 3.35 kg water /kg solids

Critical moisture content = 0.3 kg water / kg product

                                         = 0.43 kg water / kg solids

∴ amount of water to be removed = 3.35 - 0.43 = 2.95kg water /kg solids

next: calculate surface are a of product during drying

= (0.05 * 0.05 ) * 6

= 0.015 m^3

Drying rate = 0.1 kg water m^2.s^-1 * 0.015 m^3 = 1.5 * 10^-3 kg water s^-1

applying product density

initial product mass = 0.11875 * 0.23 = 0.0273kg solid

hence total amount of water to removed = 2.92 * 0.0273 = 0.07972 kg

therefore : Time required for the product to begin the falling-rate drying period

= 0.07972 / 1.5 * 10^-3

= 53 seconds

Answer:

A

Explanation:

Actually I don't know anything about American history, I chose it because South Africa is not in the least

Explanation:

When a problem is discovered in the system design or manufacturing process, it generally gets reported to all concerned (if the company has an appropriate culture). Depending on the nature of the problem, a "quick fix" may be found by the discoverer, or by someone to whom the discovery is reported. In some situations, what seems a simple problem requires a rethinking of the entire manufacturing process, possible product recalls, possible plant retrofits, and even larger ramifications. This can happen regardless of where along the line the problem is discovered.

__

Hypothetical example:

A test technician determines that a lithium battery charger sometimes gets confused and doesn't shut down properly--continuing to charge the battery when it should not. If the proximate cause is a wire harness routing or a component improperly installed, a manufacturing engineer may be called in to address the issue. The manufacturing engineer's investigation may determine that a number of battery chargers have been delivered with the problem. Further investigation may reveal a potential for fire in situations where injury or loss of life are possible outcomes.

Assessment of the design by manufacturing, process, and design engineers may reveal more than one potential cause of the shutdown/fire-hazard issue, and that the location and nature of any fire may release toxins or cause damage to systems and equipment beyond those in the immediate vicinity of the defective battery and/or charger.

Such ramifications may require the attention of one or more systems engineers and/or a rethinking of system failure modes and effects, including fire detection and suppression, throughout the product. The product may be effectively "grounded" (taken out of service), with possible customer revenue implications, until such time as the issues can be satisfactorily resolved.

(Note: 787 Dreamliner battery problems were caused by the physics of the battery construction, not the charger. The rest of the scenario above is not a bad match.)

Answer:

Profit from stock price gains with limited risk and lower cost than buying the stock outright.

Profit from stock price drops with limited risk and lower cost than shorting the stock.

Profit from sideways markets by selling options and generating income.

Get paid to buy stock.

Explanation:

I don’t know if you meant option but I hope this helps.

Answer:

a) the power loss due to irreversible head loss is 4.57 kW

b) the efficiency of the piping is 95%

c) the electric power output is 72.9918 kW

Explanation:

Given the data in the question below;

Irreversible loses [tex]h_L[/tex] = 7m

Total head, H = 140 m

flow rate Q = 4000 L/min = 0.0666 m³/s

Generator efficiency n₀ = 84% = 0.84

we know that density of water is 1000 kg/m³

g = 9.81 m/s²

a) power loss due to irreversible head loss [tex]P_L[/tex] is;    

[tex]P_L[/tex] = p × Q × g × [tex]h_L[/tex]

we substitute

[tex]P_L[/tex] = 1000 × 0.0666 × 9.81 × 7

[tex]P_L[/tex] = 4573.422 W

[tex]P_L[/tex] = 4573.422 / 1000

[tex]P_L[/tex] = 4.57 kW

Therefore, the power loss due to irreversible head loss is 4.57 kW

b) the efficiency of the piping n is;

n = (Actual head / maximum head) × 100

n = (( H - [tex]h_L[/tex] ) / H) × 100

so we substitute

n = (( 140 - 7 ) / 140) × 100

n = (133/140) × 100

n = 0.95 × 100

n = 95%

Therefore, the efficiency of the piping is 95%

c) the electric power output if the turbine-generator efficiency is 84 percent;

n₀ = [tex]Power_{outpu[/tex] / [tex]power_{inpu[/tex]

[tex]Power_{outpu[/tex] = n₀ × [tex]power_{inpu[/tex]

[tex]Power_{outpu[/tex] = n₀ × ( pQg( H - [tex]h_L[/tex] ))

so we substitute

[tex]Power_{outpu[/tex] = 0.84 × ( 1000 × 0.0666 × 9.81( 140 - 7 ))

[tex]Power_{outpu[/tex] = 0.84 × 653.346( 133)

[tex]Power_{outpu[/tex] = 0.84 × 86895.018

[tex]Power_{outpu[/tex] = 72991.815 W

[tex]Power_{outpu[/tex] = 72991.815 / 1000

[tex]Power_{outpu[/tex] = 72.9918 kW

Therefore, the electric power output is 72.9918 kW

Answer: Advanced technologixal machines

Explanation: such as big cranes, multiple workers helping creat said structure, and big bull dozers

Answer:

BFS uses Queue to find the shortest path. DFS uses Stack to find the shortest path. ... Time Complexity of BFS = O(V+E) where V is vertices and E is edges. Time Complexity of DFS is also O(V+E) where V is vertices and E is edges.

Explanation:

Answer:

a) Decrease

b) Decrease

c) Decrease

d) Decrease

Explanation:

Ti= 200°F ,

Te =  170°F

Area of heat exchanger = [tex]\pi *(2 )* 10[/tex]  = 20π

A) when The flow rate of the cooling fluid is increased

Temperature of process stream will decrease  and this is because the tube side heat transfer coefficient will increase and this will increase the rate of heat transfer thereby decreasing the temperature of the process stream.

B) when There are 200 tubes that are 1.0-in. OD and 20.0ft long

The temperature of the process stream will decrease and this is because the heat transfer coefficient will increase likewise the heat transfer rate

C) When The number of shell passes is doubled

This will cause an increase in the overall length of the shell, an increase in velocity of constant volumetric flowrate, hence the Temperature of the process steam will decrease as well

D) When The tube material is changed to copper.

Due to the high thermal conductivity of copper when compared to steel , switching to copper will cause a decrease in the temperature of the process steam

Answer:

what?????

Explanation: