Answer:
(1) 2 ohms
(2) 12 Volts Across each resistor
(3) I₁ = 3 A, I₂ = 2 A, I₃ = 1 A
Explanation:
From the question,
(1) Equilvalent Resistance (Rt) for parallel connection is
1/Rt =(1/R₁)+ (1/R₂) + (1/R₃)
Where R₁ = 4 ohms, R₂ = 6 ohms, R₃ = 12 ohms
1/Rt = 1/4 +1/6 +1/12
1/Rt = (3+2+1)/12
1/Rt = 6/12
1/Rt = 1/2
Rt = 2 ohms.
(2) Since the resistors are connected in parallel, They will have the same potential difference across them,
Hence the P.d across each resistor = 12 Volts.
(3) For R₁,
I₁ = V/R₁ = 12/4
I₁ = 3 A.
For R₂,
I₂ = V/R₂
I₂ = 12/6
I₂ = 2 A
For R₃,
I₃ = V/R₃
I₃ = 12/12
I₃ = 1 A
A marble was sent down a ramp into a solo cup. The first time the solo cup moved 20 cm. The second time the solo cup moved 24 cm. The third time the cup moved 16 cm. What is the average movement of the cup?
Answer:
20
Explanation:
The average of the movement is 20+24+16/2 = 20cm
Answer:
.................................................................................................... .................
Explanation:
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When the Asthenosphere transfers heat, what happens?
Convection Currents, Earthquakes, volcanic eruptions, or weathering?
Who is better Godzilla or King Kong
Answer:
nun
Explanation:
Answer:
Godzilla
Explanation:
The Earth's atmosphere is opaque to the
part of the electromagnetic
spectrum
a)
b)
c)
-)
)
0
Visible
Infrared
X-Ray
All of the above
A and Care correct
Band C are correct
Help pweaseeee ill give u a brainlest
Answer:
Mass of the larger object
Decribe what must happen inside of an aluminum can in order for it to be attracted to a positively-charged and to a negatively-charged object
Answer:
The PROTONS in the can attract to the negatively charged object, so then the can becomes polarized and the ELECTRONS in the can attract the positively charged object.
Explanation:
The PROTONS inside the can entice to the negatively charged object, so then the can will become polarized and the ELECTRONS in the can appeal to the undoubtedly charged item.
How are proton and electron associated?The number of protons within the nucleus of the atom is identical to the atomic range. The variety of electrons in an impartial atom is identical to the number of protons. The mass range of the atom (M) is equal to the sum of the wide variety of protons and neutrons inside the nucleus.
Protons definitely charged subatomic particles that live in the nucleus. Neutrons: Neutrally charged subatomic particles that are living in the nucleus. Electrons: Negatively charged subatomic debris found inside the electron shells surrounding the nucleus.
An electron is a negatively charged factor of an atom while the proton is an undoubtedly charged frame. The electrons are present out of doors the nucleus inside the orbiting shells. But the protons alongside neutrons shape the nucleus of the atom and are gifted in the middle of the atomic nuclei.
Learn more about electron and proton here: https://brainly.com/question/4894505
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The national government would like to start a program that would give states money for flood relief. Which of the following states could most likely benefit from a program like this?
Answer:
When a disaster is declared, the Federal government, led by the Federal Emergency Management Agency (FEMA), responds at the request of, and in support of, States, Tribes, Territories, and Insular Areas and local jurisdictions impacted by a disaster.
Explanation:
Which of the following explanations is correct about the wave that travels through the medium?
A. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
B. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
C. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
D. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
A negative 6 mC charge enters a region of 45 T magnetic field that is directed up. If the charge is moving toward the south with a speed of 400 m/s
Question: A negative 6 mC charge enters a region of 45 T magnetic field that is directed up. If the charge is moving toward the south with a speed of 400 m/s. determine the magnitude and direction of the force
Answer:
Magitude of F = 108 N
Direction: Perpendicular to the plane containing v and B.
Explanation:
From the question,
Since the velocity of the charge(v), is parallel to the field(B).
Therefore, We apply
F = qvB..................Equation 1
Where F = Force, B = magnetic field, v = velocity, q = Charge.
Given: q = 6 mC = 0.006 C, v = 400 m/s, B = 45 T
Substitute these values into equation 1
F = 0.006×400×45
F = 108 N.
The direction of the force is always perpendicular to the plane containing v and B.
plz answer fast need your help plz plz plz
Answer:
the vertical component of the force is 43.30 N.
Explanation:
Given;
angle of inclination of the force, θ = 60⁰
magnitude of the force, F = 50 N
The vertical component of the force is calculated as follows;
[tex]F_y = F \times sin(\theta}\\\\F_y = 50 N \times sin(60)\\\\F_y = 50 N \times \frac{\sqrt{3} }{2} \\\\F_y = 25\sqrt{3} \ N\\\\F_y = 43.30 \ N[/tex]
Therefore, the vertical component of the force is 43.30 N.
a hot iron bar is placed 100ml 22C water. the water temperature rises to 32C. how much heat did the water gain and how much heat did the iron bar lose? Q=change T x C x M
Answer:
Water gained: 10Iron lost: -10Explanation:
Given: Hot iron bar is placed 100ml 22C water, the water temperature rises to 32C
To find: How much heat the water gain, how much heat did the iron bar lost
Formula:Q = change T x C x M
Solve:
How much heat water gained
Initial heat = 22, then rose to 32. To find how much heat the water gained, simply subtract the current heat by the initial heat.
32 - 22 = 10
The water gained 10 amounts of heat.
How much heat Iron lost
Current heat = 32, then dropped to 22. To find how much heat the Iron lost, simply subtract the initial heat by the current heat.
22 - 32 = -10
The Iron lost -10 amounts of water.
NEPTUNE
•Number of days to orbit the sun:
•Distance around the sun:
Answer:
1. 165 years
2. 2.781 billion mi
Explanation:
i need help asap !
Work output has a force of 5 N and distance of 5 m. Work input has a force of 10 N and distance of 10 m. What is the efficiency?
100%
25%
125%
0.25%
Answer:
the answer is 100%!
your welcome
A swimmer swims the 500 yd freestyle race in 13 minutes. What is his speed in yd/min? (Round to the nearest tenth). *
Answer:
0.026 yards per minute because 13/500=0.26 which would find what fraction of a minute it would take to swim 1 yard
T/F The outer planets have solid surfaces that are very rocky and dense
Answer:
False
Explanation:
the inner planets have solid rocky dense surfaces
a current of 3 amps flows through a lamp which is connected to a 24 volt battery calculate the lamps resistance
Answer:
8
Explanation:
V = voltage
I = current
R = resistance
V = IR is the equation to find out the Voltage of an item so if we move around the equation so we are trying to resistance it would become R = V/I. So....
V = IR
R = V/I
R = 24/3
R = 8
8. A man takes one minute to lift 4 bags of sugar each of weight 50N
through a height of 1.5m. Calculate the power expanded
A. 1.25W
B. 5.00W
C. 75.00W
D. 300.00W
Lunite of measurements are
Answer:
D
Explanation:
the formula is F=mgh
so now you can write it like
m= 4×50=200
200×1.5×10=30000
The mass of an object is 84 kg. Find its weight on the Earth and the Moon.
Answer:
We would take the mass given, 80 kg, and multiply it times the acceleration of Earth's downward pull on that mass, 9.8 m/s/s. So the weight on Earth is 784 newtons. So the weight of the same 80 kg mass on the moon is 133.28 N.
hi
mass is express in Newtons.
On Earth gravity is 9.807 so wieght would be : 9.807 * 84= 823.79
On the Moon garvity is 1.62 so weight would be : 84 *1.62 = 136.08
3. A warehouse employee is pushing a 30.0 kg desk across a floor at a
constant speed of 0.50 m/s. How much work must the employee do on
the desk to change the speed to 1.00 m/s?
Answer: The employee must do 11.2308 Joules of work
Explanation:
Work done = force × distance
But
Force = ma(mass x acceleration due to gravity)
F = 30×9.8
F = 294N
Also distance moved can be found using the equation
v² = u² +2gS
1.00 ² = 0.50²+2(9.8)S
1 =0.25+19.6S
1-0.25 =19.6S
0.75=19.6S
S=0.75/19.6
S = 0.0382m
Work done = force × distance = FS
Work done = 294 N X 0.0382m
Workdone =11.2308Nm = 11.2308 Joules
Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
What is work done?Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,
[tex]W=Fd[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,
[tex]W=(ma)d[/tex]
For the gravitational acceleration, it can be written as,
[tex]W=(mg)d\\W=mgd[/tex]
The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.
Thus, the distance traveled by it can be find out using the third law of motion as,
[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]
As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,
[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]
Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
Learn more about the work done here;
https://brainly.com/question/25573309
Describe the movement of air masses and the weather conditions at front 3. What type of front is it?
Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).
Warm Front. ...
Stationary Front. ...
Occluded Front.
Answer:
Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.
Explanation:PLATO
what must happen in order for a metaphoric rock to be transformed into a igneous rock
Answer:
If the newly formed metamorphic rock continues to heat, it can eventually melt and become molten (magma). When the molten rock cools it forms an igneous rock.
Explanation:
what two types of energy does a rock have as it rolls down a hill
When the rock or soil of Earth’s surface is moved to another location by water, ice, or wind
A. Deposition.
B. Weathering
C. Erosion
D. Abiotic
Ayala is making salad dressing. She mixes oil and vinegar in a blender until a smooth consistency is formed. Explain whether this is a heterogeneous or a homogeneous mixture and why
Answer:Hetero
Explanation: Honestly, same as the last guy said
someone please help I have no idea what to do
Answer:
10⁶ or 1000000
Explanation:
formula: frequency = velocity/wavelength = [tex]\frac{3.0x10^{8} }{3.0x10^{2}}[/tex]i'm not sure because the teacher probably wrote the question wrong.A - 28.4-μC charge is placed 16.4 cm from a charge q, the force between the two charges is 1240 N. What is the value of q?
Answer:
1.31×10⁻⁴ C or 131 μC
Explanation:
From the question,
Applying Coulomb's Law,
F = kqq'/r²..................... Equation 1
Where F = Force between the charges, q = first charge, q' = second charge, r = distance between the charges, k = coulomb's constant.
make q' the subject of the equation
q' = F×r²/(kq)
q' = Fr²/kq................ Equation 2
Given: F = 1240 N, r = 16.4 cm = 0.164 m, q = 28.4 μC = 2.84×10⁻⁵ C,
Constant: k = 8.98×10⁹ Nm/C²
Substitute these values into equation 2
q' = (1240×0.164²)/[(2.84×10⁻⁵)×(8.98×10⁹)
q' = (33.35104)/(25.5032×10⁴)
q' = 1.31×10⁻⁴ C
q' = 131 μC
A 1.3 kg book has 11.7 joules of potential energy relative to the floor when it's sitting on top of
Brenda's dresser. Calculate how tall Brenda's dresser is?
what is the name often given to the force exerted by the first object on a second object
A 1,100kg car is going at 22 m/s. What force is needed to stop it in 20
seconds?
A 1,100 kg car is going at 22 m/s. Force is needed to stop it in 20
seconds is 1210 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Using equation of motion,
v = u + at
0 = 22 + a.20
a = 1.1 m/sec²
force = mass.acceleration
force = 1100.(1.1)
force = 1210 N.
A 1,100 kg car is going at 22 m/s. Force is needed to stop it in 20
seconds is 1210 N.
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A 5kg book is slid across the floor with an initial velocity of 3m/s. It slows and stops due to the friction with the floor. How man joules of work did friction do?
Answer:
SUP DAD i love cookies
Explanation:
yuh
