This rectangle and right triangle have the same perimeter.


What is the difference in their areas?


0 square cm

0 square cm

2.0 square cm

2.0 square cm

3.6 square cm

3.6 square cm

4.8 square cm

4.8 square cm

Answer:

0.18 cm²

Step-by-step explanation:

Given that a rectangle and a triangle have same perimeter . The sides of them are ,

[tex]\begin{cases} Square = 4cm , 4cm , 3cm \ and \ 3cm .\\ Triangle = 4cm , 5.8cm \ and \ 4.2cm \end{cases}[/tex]

We know that area of rectangle is product of length and breadth.

[tex]\implies Area = length \times breadth \\\\\implies Area = 4cm \times 3cm\\\\\implies \red{ Area = 12cm^2}[/tex]

Also we know that the area of triange is half the product of base and height . So that ,

[tex]\implies Area = \dfrac{1}{2}\times 5.8cm \times 4.2 cm \\\\\implies \red{ Area = 12.18 cm^2 }[/tex]

Therefore the difference between them is ,

[tex]\implies D = A_1 - A_1 \\\\\implies D = 12.18cm^2-12cm^2 \\\\\implies \red{D = 0.18 cm^2}[/tex]

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