This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint.

f(x, y, z) = x2 + y2 + z2; x4 + y4 + z4 = 7

Answers

Answer 1

Answer:

The maximum value is +√21 and the minimum value is -√21

Step-by-step explanation:

f(x,y,z) = x² + y² + z². Let g(x,y,z) = x⁴ + y⁴ + z⁴ - 7 = 0

Using Lagrange multipliers,

df/dx = λg/dx, df/dy = λg/dy. and df/dz = λg/dz

df/dx = 2x, df/dy = 2y, df/dz = 2z

dg/dx = 4x³, dg/dy = 4y³, dg/dz = 4z³

So, df/dx = λg/dx ⇒ 2x = 4λx³     (1)

df/dy = λg/dy ⇒ 2y = 4λy³           (2)

df/dz = λg/dz ⇒ 2z = 4λz³           (3)

From (1) 4λx³ - 2x = 0

2λx³ - x = 0

x(2λx² - 1) = 0

solving, x = 0 or (2λx² - 1) = 0 ⇒ 2λx² = 1 ⇒ x = ±1/√(2λ) since x ≠ 0

From (2) 4λy³ - 2y = 0

2λy³ - y = 0

y(2λy² - 1) = 0

solving, y = 0 or (2λy² - 1) = 0 ⇒ 2λy² = 1 ⇒ y = ±1/√(2λ) since y ≠ 0

From (3) 4λz³ - 2z = 0

2λz³ - z = 0

z(2λz² - 1) = 0

solving, z = 0 or (2λz² - 1) = 0 ⇒ 2λz² = 1 ⇒ z = ±1/√(2λ) since z ≠ 0

g(x,y,z) = x⁴ + y⁴ + z⁴ - 7 = 0

(1/√(2λ))⁴ + (1/√(2λ))⁴ + (1/√(2λ))⁴ - 7 = 0

3 (1/√(2λ))⁴ = 7

(1/√(2λ))⁴ = 7/3

1/√(2λ) = ⁴√7/3

√(2λ) = ⁴√3/7

2λ = √3/7

λ = 1/2(√3/7)

Since x = 1/√(2λ) = 1/√(2 [1/2(√3/7)]) = 1/⁴√3/7 = ±⁴√7/3

Also y = 1/√(2λ) = 1/√(2 [1/2(√3/7)]) = 1/⁴√3/7 = ±⁴√7/3

and z = 1/√(2λ) = 1/√(2 [1/2(√3/7)]) = 1/⁴√3/7 = ±⁴√7/3

Substituting x,y and z into f(x,y,z) we have

f(x,y,z) = (⁴√7/3)² + (⁴√7/3)² + (⁴√7/3)² = 3(⁴√7/3)² = 3(√7/3) = √(7 × 3) = ±√21

The maximum value is +√21 and the minimum value is -√21


Related Questions

what are the solutions to the following system -2x^2+y= -5 y= -3x^2+5

Answers

[tex](x1,y1)= (- \frac{\sqrt{15} }{2} , \frac{5}{4} )\\(x2,y2)= (\frac{\sqrt{15} }{2} ,\frac{5}{4} )[/tex]

Answer:

Answer C.

Step-by-step explanation:

hope this helps <3

Can someone help me with this is the hardest one by far

Answers

Answer:

10 units

Explanation:

Create a right triangle, determine the a and b side lengths of the triangle by looking at the graph. (See image)

Then use the Pythagorean theorem to find c.

a² + b² = c²

(8)² + (6)² = c²

64 + 36 = c²

100 = c²

Square root both sides to get c.

[tex]\sqrt{100}[/tex] = c

10 = c

Use the horizontal number line to find the distance between -5 and 0.
1
-5 -4 -3 -2 -1 0
1
2 3 4
5
The distance between -5 and O is
<
The absolute value of -5 is

Answers

Answer:

I think +5 or 5

Answer:

there both 5

Step-by-step explanation: did the question on edg

(AAAA HELP PLS XD WILL MARK BRAINLIEST) Nhia is setting up a marble tournament for the kids in her
apartment complex. So far, 47 kids have signed up to play. Each
player needs 10 marbles. Nhia found a discount store that sells
bags of 24 marbles. Round each amount to the nearest ten to find
a reasonable estimate for the number of bags of marbles Nhia will
have to buy to be sure to have enough marbles.
A) 18
B) 25
C) 32
D) 39

Answers

Given that we have 47 kids and each kid needs 10 marbles, find out how many bags of 24 marbles will we need.

First, we will multiply 47 by 10 to get the amount of marbles needed.

47 x 10 = 470

So, that means we need 470 marbles in total.

Then, we divide 470 by 24 to see how many bags of 24 marbles 470 marbles is.

470 / 24 = 19.5833

Since, we can't have 19.5833 bags, we have to check what it would be if we only used 19.

19 x 24 = 456

470 - 456 = 14

Since, 18 is the closest number of bags but it has less than 470 it would not be correct.

Therefore, the best answer would be B. 25 since it is better to have extra marbles but not a very wide margin.

There are 560 third- and fourth-grade students in King Elementary School. If there are 80 more third-graders than fourth-graders, how many third-graders are there in the school? work has to be shown

Answers

Answer:

There are 200 4th grades and 360 third graders

Step-by-step explanation:

560/2=280-80=200 280+80=360

In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard deviation of the monthly incomes of non-technology workers is different. 71 non-technology workers are randomly selected and it is determined that these selected workers have a standard deviation of $950. Test the claim that the non-technology workers have a different standard deviation (so different from $650). Use a 0.10 significance level.

Answers

Answer:

There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

[tex]\chi ^{2} = \dfrac{\left (n-1 \right )s^{2}}{\sigma ^{2}}[/tex]

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,  

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

[tex]\chi ^{2} = \dfrac{\left (23-1 \right )950^{2}}{650 ^{2}} = 49.994[/tex]

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown. Which best describes the range of possible values for the third side of the triangle? A x 18.9 B 12.5 26 D 6 < x < 26

Answers

Solution:

12.5 < x < 18.9

Reason:

To solve this problem, we can apply Pythagorean's theorem.

To find the upper bound:

We can set the two given legs as the 2 legs of a right triangle. This allows us to keep the angle under 90 degrees. So if we set the legs to be 10 and 16, then the third side must be:

10^2 + 16^2 = x^2

x^2 = 356

x is roughly equal to 18.9

For the lower bound, this time, we set x as one of the legs, and 10 as the other let. Since we know that the longest side is 16, we can set up an equation again:

x^2 + 10^2 = 16^2

x^2 = 16^2 - 10^2

x^2 = 156

x is roughly equal to 12.5

So we have found the bounds to be 12.5 < x < 18.9

Answer:

its B

Step-by-step explanation:

12. Jeremy got quote from iVan to move him into his new home. One quote was for a weekday move which is

for 8 hours of loading/unloading and 6 hours of packing/unpacking for $890. The other quote was for a

weekend move which is for 5 hours of loading/unloading and 3 hours of packing/unpacking for $515. If

iVan has set hourly rates for loading/unloading and packing/unpacking, what are these hourly rates?

Answers

Answer:

Loading/unloading hourly rate: $70

Packing/unpacking hourly rate: $55

Step-by-step explanation:

We can write this as a system of linear equations.

We define L as the loading/unloading hourly rate, and P as the packing/unpacking hourly rate.

"One quote was for a weekday move which is  for 8 hours of loading/unloading and 6 hours of packing/unpacking for $890":

[tex]8L+6P=890[/tex]

"The other quote was for a  weekend move which is for 5 hours of loading/unloading and 3 hours of packing/unpacking for $515":

[tex]5L+3P=515[/tex]

If we express L in function of P in the first equation, and then replace this value in the second equation, we have:

[tex]8L+6P=890\\\\8L=890-6P\\\\L=\dfrac{890-6P}{8}[/tex]

[tex]5L+3P=515\\\\5\cdot \dfrac{890-6P}{8}+3P=515\\\\556.25-3.75P+3P=515\\\\-0.75P=515-556.25=-41.25\\\\P=41.25/0.75=55[/tex]

Then, L is:

[tex]L=\dfrac{890-6P}{8}=\dfrac{890-6(55)}{8}=\dfrac{890-330}{8}=\dfrac{560}{8}=70[/tex]

Eric’s average income for the first 4 months of the year is $1,450.25, what must be his
average income for the remaining 8 months so that his average income for the year is
$1,780.75?

Answers

Answer:

$1946

Step-by-step explanation:

Eric’s average income for the first 4 months of the year is $1,450.25

Therefore, his total earning in the first four months

= 4 X $1,450.25

=$5,801

Let the average income for the remaining 8 months= x

Then:

[tex]\text{Eric's Yearly Average Income}=\dfrac{5801+8x}{12} \\1,780.75=\dfrac{5801+8x}{12} \\$Cross multiply\\12*1,780.75=5801+8x\\21369=5801+8x\\8x=21369-5801\\8x=15568\\Divide both sides by 8\\x=\$1946[/tex]

Therefore, to get an average income for the year of $1,780.75, Eric must earn an average income of $1946 for the remaining 8 months.

What is the range of the function f(x) = -2(64) + 3?

Answers

Answer:

Step-by-step explanation:

f(x) = -2(64) + 3 is not a function of x; it's a constant with the single value -125.

Ensure that you have copied down this problem correctly.

Answer: -2 multiply 64 add 3 equals -125

Step-by-step explanation:

-2 multiply 64 add 3

then multiply 2 and 64 which is 128

then add/subtract: -128 add 3 which is -125

Then final answer -2 multiply 64 add 3 equals -125

2. A 175g sample of radioactive kryptonite-344 has a half-life of 122 days.

a) Write the exponential equation that gives the amount of kryptonite that remains after t days.

Write equation in the form M(t)= ab* where x=

elapsed time

half-life time

Answers

Answer:

[tex]M(t) = 175(0.9943)^{t}[/tex]

Step-by-step explanation:

The amount of kryptonite-344 after t days is given by the following equation:

[tex]M(t) = ab^{t}[/tex]

In which a is the initial amount.

175g sample:

This means that [tex]a = 175[/tex]

So

[tex]M(t) = 175b^{t}[/tex]

Half-life of 122 days.

This means that [tex]M(122) = 0.5*175 = 87.5[/tex]

So

[tex]M(t) = 175b^{t}[/tex]

[tex]87.5 = 175b^{122}[/tex]

[tex]b^{122} = 0.5[/tex]

[tex]\sqrt[122]{b^{122}} = \sqrt[122]{0.5}[/tex]

[tex]b = 0.9943[/tex]

So

[tex]M(t) = 175(0.9943)^{t}[/tex]

Find the value of x in the triangle shown below.
8
3

Answers

Answer:

[tex] \sqrt{55}[/tex]

Step-by-step explanation:

Given is a right angled triangle.

Therefore, by Pythagoras theorem:

[tex] {x}^{2} = {8}^{2} - {3}^{2} \\ = 64 - 9 \\ = 55 \\ x = \sqrt{55} [/tex]

Hal has 24 video games 6 if his games are sports related and the rest are role playing games which ratio represent the number of his role playing games

Answers

Answer:

It would be 18;24 or simplified it would be 3;4

Step-by-step explanation:

24-6=18 so there are 18 role playing games. So the ratio could be 18;24 but if it needs to be simplified you can divide both numbers by 6. 18/6=3 and 24/6=4

A rectangle has a base length of 12 inches and an unknown height, h. The area of the rectangle is less than 60 square inches. Which inequality can be used to model the problem?

12h < 60

12h > 60

12 + h < 60

12 + h > 60

Answers

Answer:

12h < 60

Step-by-step explanation:

A rectangle, with height h and base length l, has the following area.

[tex]A = l*h[/tex]

In this question:

[tex]l = 12, A < 60[/tex]

So

[tex]A < 60[/tex]

[tex]l*h < 60[/tex]

[tex]12h < 60[/tex]

So the correct answer is:

12h < 60

Answer:

12h < 60

hope this helps, its right because i took the test and it shows

Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu > 2.1 are tested. Assuming the commercial time is normally distributed, give the appropriate rejection region when there is a random sample of size 20 from the population and we would like to test at the level of significance 0.01. Let T be the appropriate test statistic.
A, T > 2.539
B. > 2.845
C. T> .528D. T >2.861

Answers

Answer:

A. T > 2.539

Step-by-step explanation:

We have a hypothesis test of the mean, with unknown population standard deviation.

The hypothesis are:

[tex]H_0: \mu = 2.1 \\\\H_a: \mu > 2.1[/tex]

From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.

The degrees of freedom can be calculated as:

[tex]df=n-1=20-1=19[/tex]

The significance level is 0.01, so the critical value tc should be the one that satisfies:

[tex]P(t>t_c)=0.01[/tex]

Looking up in a t-table, for 19 degrees of freedom, this critical value is tc=2.539.

Simplify (20!+21!+22!)/44

Answers

Answer:

11*20!

Step-by-step explanation:

(20!+21!+22!)/44=

20!(1+21+21*22)/44=

20!(22+22*21)/44=

20!*22*22/44= 11*20!

The simplified expression of (20!+21!+22!)/44 is 20! * 11

How to simplify the expression?

The expression is given as:

(20!+21!+22!)/44

The factorial of a number n is:

n! = n * (n - 1)!

So, we start by expanding 22!

(20!+21!+22!)/44 = (20!+21!+22 * 21 * 20!)/44

Next, we expand 21!

(20!+21!+22!)/44 = (20!+21 * 20!+22 * 21 * 20!)/44

Factor out 20!

(20!+21!+22!)/44 = 20! * (1 + 21 + 22 * 21)/44

Evaluate the expression in the bracket

(20!+21!+22!)/44 = 20! * 484/44

Divide

(20!+21!+22!)/44 = 20! * 11

Hence, the simplified expression of (20!+21!+22!)/44 is 20! * 11

Read more about simplified expression at:

https://brainly.com/question/723406

#SPJ6

What’s the correct answer for this?

Answers

。☆✼★ ━━━━━━━━━━━━━━  ☾  

A tangent to a circle forms a right angle with the radius

As it is a right angled triangle, we can use Pythagoras' theorem

a^2 + b^2 = c^2

Rearrange this for a side length:

a^2 = c^2 - b^2

Sub the values in:

a^2 = 6.5^2 - 6^2

a^2 = 6.25

Square root this for the answer

a = 2.5

Thus, your answer is option D

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

Answer:

2.5 ft

Step-by-step explanation:

As radius is perpendicular to tangent ,

LT [tex]\perp[/tex]KT

By pythagoras theorem:

LT² = LK² - KT²

LT² = (6.5)² - 6²

LT² = 42.25 - 36

LT² = 6.25

LT = 2.5 ft

LT = radius = 2.5 ft

Old McDonald has a farm with 36 cows and goats the number of cars he has 10 more than the number of coats how many of each animal does old McDonald have right to equations you think you solve the problem you see to represent the number of cars in on

Answers

Answer:

13 goats and 23 cows

Step-by-step explanation:

Use x to solve :) it's a hint

Answer:

g=goats

c=cows

a=cars

g + c = 36

10 + g = a

Step-by-step explanation:

the number of cows and goats together are equal to 36, so for the first equation you can write g + c = 36.

For the second equation, the number of cars he has is equal to the number of goats he has plus 10, so you can express that as 10 + g = a. (I used a since I already used c for the cows)

I think this is what you need if you need 2 equations to represent how many cars he has.

I'm not entirely sure what its asking you can comment if you need more or something else.

Solve for x.

Solve for x.

Answers

Answer:

20

Step-by-step explanation:

x is the radius of the circle.  The tangent line is perpendicular to the radius line at that point.  Using Pythagorean theorem:

x² + 15² = (x + 5)²

x² + 225 = x² + 10x + 25

225 = 10x + 25

200 = 10x

x = 20

Answer is:

x = 20. hope this helps

What is the sum 2/x^2 + 4/x^2

Answers

the answer is 6/x^2

hope that helped!

Joe says, "I have found an interesting fact! Twenty-five percent of thirty dollars is
the same as thirty percent of twenty-five dollars." Is Joe correct? Please explain
your thinking to show that Joe is right or wrong.

Answers

Answer:

Joe Is Right

Step-by-step explanation:

Twenty-five percent of thirty dollars is $7.50

(30 x 25)/100 = $7.50

Thirty percent of twenty-five dollars is $7.50

(25 x 30)/100 = $7.50

Therefore he is right

I hope this helps

The ratio between the exterior and interior angle of a regular polygon is 1:5, find
a. the measure of each exterior angle.
b. the measure of each interior angle.
c. the number of sides of the polygon.

Answers

Answer:

Exterior and interior angles are supplementary, meaning they sum to 180 degrees. If the exterior and interior angles are x and 5x respectively, we can write x + 5x = 180, and solving for x we get x = 30°. This means that the answer to a) is 30° and the answer to b) is 30 * 5 = 150°.

For c), to find the number of sides we can do:

180 - 150 = 30

180 / 30 = 6 so the answer to c) is 6.

samantha is making punch for a class picnic. there are 25 students in her class. Samantha uses 1 gallon 2 quarts of orange juice, 3 quarts of lemonade, and 1 gallon 3 quarts of sparkling water. How much punch did samantha make? will there be enough for each student to make two 1 cup servings of punch?

Answers

Answer:

4 gallonsyes

Step-by-step explanation:

A quart is 1/4 gallon, so the total of liquid ingredients for the punch is ...

  (1 2/4 gal) +(3/4 gal) +(1 3/4 gal) = 2 8/4 gal = 4 gal

Samantha made 4 gallons of punch.

__

1 cup is 1/16 gallon, so 2 cups each for 25 students requires ...

  (1/16 gal)(2)(25) = 50/16 gal = 3 1/8 gal

Samantha made more punch than that, so there will be enough for 2 1-cup servings for each student.

A can of StarKist tuna has a volume LaTeX: 18\pi\:cm^318 π c m 3 and a height of 2 cm. Find the area of the StarKist label below the wraps around the entire can and does not overlap. Write your answers in terms of LaTeX: \piπ.

Answers

Answer:

Area of the StarKist label around the can in terms of π = 12π cm²

Step-by-step explanation:

Given;

the volume of a can of StarKist tuna, V = 18 π cm³

height of the can of StarKist tuna, h =  2 cm

To determine the area of the StarKist label that wraps around the entire can and does not overlap, we assume the can to have a shape of a cylinder.

Volume of the can = πr²h

where;

r is radius of the can

h is height of the can

πr² x 2 = 18 π

2r² = 18

r² = 18/2

r² = 9

r = 3

Area around the can = curved surface area of the can (cylinder)

Curved surface area of the can = 2πr × h = 2πrh

Curved surface area of the can = 2πrh = 2π x 3 x 2 = 12π cm²

Area of the StarKist label around the can in terms of π = 12π cm²

What is the insignificant digit in 0.09040?

Answers

Answer:

0

Step-by-step explanation:

The 0, or the last digit is the insignificant digit because it serves no purpose.

Answer:

The last zero in the number is insignificant.

Step-by-step explanation:

The 0 at the extreme right indicates that the number is accurate to the fifth decimal place, that is, one in ten thousandths.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69. Group of answer choices Men aged 20-29: 4.8% Men aged 60-69: 10.6% There is substantially more variation in blood pressures of the men aged 60-69. Men aged 20-29: 4.4% Men aged 60-69: 8.3% There is substantially more variation in blood pressures of the men aged 60-69. Men aged 20-29: 4.6% Men aged 60-69: 10.2 % There is substantially more variation in blood pressures of the men aged 60-69. Men aged 20-29: 7.6% Men aged 60-69: 4.7% There is more variation in blood pressures of the men aged 20-29.

Answers

Here is  the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29:      117      122     129      118     131      123

Men aged 60-69:      130     153      141      125    164     139

Group of answer choices

a)

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

[tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = [tex]\dfrac{\sum \limits^{n}_{i-1}x_i}{n}[/tex]

Mean = [tex]\frac{117+122+129+118+131+123}{6}[/tex]

Mean = [tex]\dfrac{740}{6}[/tex]

Mean = 123.33

Standard deviation  [tex]= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }[/tex]

Standard deviation =[tex]\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }[/tex]

Standard deviation  = [tex]\sqrt{\dfrac{161.3334}{5}}[/tex]

Standard deviation = [tex]\sqrt{32.2667}[/tex]

Standard deviation = 5.68

The [tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]

[tex]coefficient \ of \ variation = \dfrac{5.68}{123.33}*100[/tex]

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = [tex]\dfrac{\sum \limits^{n}_{i-1}x_i}{n}[/tex]

Mean = [tex]\frac{ 130 + 153 + 141 + 125 + 164 + 139}{6}[/tex]

Mean = [tex]\dfrac{852}{6}[/tex]

Mean = 142

Standard deviation  [tex]= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }[/tex]

Standard deviation =[tex]\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }[/tex]

Standard deviation  = [tex]\sqrt{\dfrac{1048}{5}}[/tex]

Standard deviation = [tex]\sqrt{209.6}[/tex]

Standard deviation = 14.48

The [tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]

[tex]coefficient \ of \ variation = \dfrac{14.48}{142}*100[/tex]

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Some smells are perceived as being more feminine or more masculine. Researchers asked a random sample of 300 American adults to score quantitatively the perceived gender-orientation of lavender. Smaller scores indicate a more feminine scent and larger scores a more masculine scent. In this design, a gender-neutral scent would have a perceived gender-orientation score of 12. The participants gave the scent of lavender an average score of 10.28

a. Is this evidence that the scent of lavender is not gender-neutral, on average? State H0cap h sub zero and Hacap h sub a in the corresponding test, indicating what the parameter in your hypotheses is.

b.The researchers report that "p<.01p less than full stop 01 (2-tail)" for this test. Explain the meaning of "p<.01p less than full stop 01" and "2-tail."

c.Assuming that the conditions for inference were met, conclude in the context of this study.

Answers

Answer:

a) We are told smaller scores indicate a more feminine scent and larger scores a more masculine scent, also a score of 12 represents a gender-neutral scent.

Here the average from the sample for lavender is 10.28

To test for the evidence that lavender is not gender neutral on average, the null hypothesis H0 would take that lavender is gender-neutral, while the alternative hypothesis would take that the score of lavender is not gender neutral. We now have the null and alternative hypotheses as:

H0 : u = 12

H1 : u ≠ 12

Here, u represents the mean gender-orientation score for lavender. The alternative is two sided because we want to test if lavender is not gender neutral. Which means lavender might be more masculine of more feminine.

b) Given: p < 0.01 (2 tailed)

This means the p-value is less than level of significance 0.01.

Since the pvalue is less than the level of significance, we reject null hypothesis H0. This means there is sufficient evidence to conclude that the smell is not gender-neutral.

There is no reason to prefer a particular gender, that's why this is a two tailed hypothesis.

c) c.Assuming that the conditions for inference were met, which means the p-value is less than 0.01 so the null hypothesis H0 is rejected.

The conlusion would be that there is enough evidence to conclude that lavender is not gender-neutral

PLEASE HELP I DON'T UNDERSTAND THE QUESTION. THANK YOU :)

Answers

ABC and DEC are similar, since the line segments AB and DE are parallel.

This means corresponding sides of these triangles occur in a fixed ratio with one another.

In particular, this tells us

DE/AB = DC/AC

or

7/11 = 15/(15 + x)

Solve for x:

11/7 = (15 + x)/15

11/7 = 1 + x/15

4/7 = x/15

x = 60/7

Dan earns £388 over the course of a five-day week. How much is that per day?

Answers

Answer:

£77.6 per day

Step-by-step explanation:

388/5 = 77.6

Answer:

£77.60

Step-by-step explanation:

388/5=77.6

but remember that this is money so add the 0.

The table shows input and output values of the function y = x2 + 12x – 2. What is an approximate solution of the equation x2 + 12x – 2 = 0?

Answers

Answer:

The solutions for the equations are x = 0.1644 and x = -12.1644

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

In this question:

[tex]x^{2} + 12x - 2 = 0[/tex]

So

[tex]a = 1, b = 12, c = -2[/tex]

[tex]\bigtriangleup = 12^{2} - 4*1*(-2) = 152[/tex]

[tex]x_{1} = \frac{-12 + \sqrt{152}}{2} = 0.1644[/tex]

[tex]x_{2} = \frac{-12 - \sqrt{152}}{2} = -12.1644[/tex]

The solutions for the equations are x = 0.1644 and x = -12.1644

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