The weight of oranges growing in an orchard is normally distributed with a mean weight of 6 oz. and a standard deviation of 0.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 95% of all oranges from this orchard.

Answer:

Yes

Step-by-step explanation:

Simplify the following:

1×7×6×7×89×7×33×188 + 4444 - 82×77×9999

1×7 = 7:

7×6×7×89×7×33×188 + 4444 - 82×77×9999

7×6 = 42:

42×7×89×7×33×188 + 4444 - 82×77×9999

42×7 = 294:

294×89×7×33×188 + 4444 - 82×77×9999

| | 2 | 9 | 4

× | | | 8 | 9

| 2 | 6 | 4 | 6

2 | 3 | 5 | 2 | 0

2 | 6 | 1 | 6 | 6:

26166×7×33×188 + 4444 - 82×77×9999

26166×7 = 183162:

183162×33×188 + 4444 - 82×77×9999

| 1 | 8 | 3 | 1 | 6 | 2

× | | | | | 3 | 3

| 5 | 4 | 9 | 4 | 8 | 6

5 | 4 | 9 | 4 | 8 | 6 | 0

6 | 0 | 4 | 4 | 3 | 4 | 6:

6044346×188 + 4444 - 82×77×9999

| | | 6 | 0 | 4 | 4 | 3 | 4 | 6

× | | | | | | | 1 | 8 | 8

| | 4 | 8 | 3 | 5 | 4 | 7 | 6 | 8

| 4 | 8 | 3 | 5 | 4 | 7 | 6 | 8 | 0

| 6 | 0 | 4 | 4 | 3 | 4 | 6 | 0 | 0

1 | 1 | 3 | 6 | 3 | 3 | 7 | 0 | 4 | 8:

1136337048 + 4444 - 82×77×9999

| | 8 | 2

× | | 7 | 7

| 5 | 7 | 4

5 | 7 | 4 | 0

6 | 3 | 1 | 4:

1136337048 + 4444 + -6314×9999

| | | | 9 | 9 | 9 | 9

× | | | | 6 | 3 | 1 | 4

| | | 3 | 9 | 9 | 9 | 6

| | | 9 | 9 | 9 | 9 | 0

| 2 | 9 | 9 | 9 | 7 | 0 | 0

5 | 9 | 9 | 9 | 4 | 0 | 0 | 0

6 | 3 | 1 | 3 | 3 | 6 | 8 | 6:

1136337048 + 4444 + -63133686

| | | | | | 1 | | | 1 |  

| 1 | 1 | 3 | 6 | 3 | 3 | 7 | 0 | 4 | 8

+ | | | | | | | 4 | 4 | 4 | 4

| 1 | 1 | 3 | 6 | 3 | 4 | 1 | 4 | 9 | 2:

1136341492 - 63133686

| | | | | | | 10 | | |  

| | 0 | 13 | | | 3 | 0 | 14 | 8 | 12

| 1 | 1 | 3 | 6 | 3 | 4 | 1 | 4 | 9 | 2

- | | | 6 | 3 | 1 | 3 | 3 | 6 | 8 | 6

| 1 | 0 | 7 | 3 | 2 | 0 | 7 | 8 | 0 | 6:

Answer: 1,073,207,806

Answer:

4.6570394e+12

Step-by-step explanation:

1. 1x7=7

2. 7x6=42

3. 42x7=294

4. 294x89=26166

5. 26166x7=183162

6. 183162x33=6044346

7. 6044346+4444=6048790

8. 6048790-82=6048708

9. 6048708x77=465750516

10. 465750516x9999=4.6570394e+12

Answer:

Hello There Again. The correct answer is D.

Explanation: Because it shows that you need to subtract 2.75 - 3.50 which that will be 75. So the correct answer will be D.

Hope It Helps! :)

Sixth graders paid a total of $508.50 for all their meals on Monday.

Answer:

8(3)=24

3(8) =24

Step-by-step explanation:

Step-by-step explanation:

i want brainliest please

Answer:

8 sets of 3 positive tiles.

Which of the following multiplication expressions can be modeled by the tiles shown? Check all that apply.

yes 8(3) = 24

no 6(4) = 24

no (3)(12) = 36

no 24(3) = 72

yes 3(8) = 24

no 2(12) = 24

yah welcome

Answer:

43.96

Step-by-step explanation:

you do 6 divided by 2 to find the radius

then u find the volume

v= [tex]\pi[/tex]r^2h/3

v=3.14(3 to the power of 2)7/3

hope this helps

correct me if this is wrong

Answer:

b=3.54

Step-by-step explanation:

9.89-6.35=3.54

Answer: b=3.54

Step-by-step explanation:

Subtract 6.35 from both sides and you will get that b=9.89-6.35 solve that and you will get that b= 3.54.

Answer:

the answer for the question is 25 and 26

Answer:

H(24) = 70,000

Step-by-step explanation:

If the growth equation is

H(35020) = 12

Then we are told to find H(70,000)

35020 = 12

70,000 = x

35020x = 12 × 70,000

x = 12 × 70,000/35020

= 23.99

≈ 24.

H(24) = 70,000

Answer:

[tex] y = -\dfrac{1}{28}x + 15 [/tex]

Step-by-step explanation:

The car uses 15 gallons of gasoline to drive 420 miles.

(15 gal)/(420 mi) = 1/28 gal/mi

The car uses 1/28 gallon of gasoline per mile.

y = mx + b

When x = 0, at the start of the drive, the car has 15 gallons of gasoline.

y = mx + 15

Then for every mile it travels, the amount  of gasoline goes down by 1/28 gal. For x miles of travel, it uses 1/28 * x gallons of gasoline.

[tex] y = -\dfrac{1}{28}x + 15 [/tex]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

[tex]a(t) = 24t + 2[/tex]

Velocity:

[tex]v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K[/tex]

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

[tex]v(t) = 12t^{2} + 2t + 13[/tex]

Position:

[tex]s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K[/tex]

Since s(0) = 3

[tex]s(t) = 4t^{3} + t^{2} + 13t + 3[/tex]

What is its position at time t=5?

This is s(5).

[tex]s(t) = 4t^{3} + t^{2} + 13t + 3[/tex]

[tex]s(5) = 4*5^{3} + 5^{2} + 13*5 + 3[/tex]

[tex]s(5) = 593[/tex]

It's position at time t = 5 is 593.

From the side/angle inequality, we see that the smallest angle of a triangle must be opposite its shortest side. In this case, that angle is opposite the shortest side [tex]\overline{AC},[/tex] so our answer is [tex]\boxed{\angle B}.[/tex]

As for finding its measure (which I'm aware the question probably didn't ask for), we can use the law of cosines:

[tex]5^2=6^2+7^2-2(6)(7)\cos B[/tex]

[tex]\cos B=\frac{5}{7}\implies\angle B\approx\boxed{44.4^\circ}.[/tex]

Answer:

Smallest Angle in the triangle is angle c.

Answer:

-15

Step-by-step explanation:

g(x) = -4x + 5, find g(5)

Let x = 5

g(5) = -4*5 +5

      = -20 +5

     = -15

Answer: Option C: 44

Step-by-step explanation:

so, here we have the equation:

H(a,b) = 2a + 4b

"evaluate" means change the values of the variables for specific values, here we must replace the "a" for 10, and the "b" for a 6.

So we have:

H(10, 6) = 2*10 + 4*6 = 20 + 24 = 44

Answer:

  4.1 cm

Step-by-step explanation:

The segment marked x bisects the chord, so the triangle shown has legs x and 7.8, and hypotenuse 8.8.

The Pythagorean theorem can be used to find x:

  8.8² = x² +7.8²

  x² = 8.8² -7.8² = 77.44 -60.84 = 16.60

  x = √16.6

  x ≈ 4.1 . . . cm

Answer:

Step-by-step explanation:

x + 3y = 1

-3x - 3y = -15

-2x = -14

x = 7

7 + 3y = 1

3y = -6

y = -2

(7, -2)

Answer:

x =7 , y= -2

Step-by-step explanation:

x + 3y = 1

-3x - 3y = -15

Add the equations together to eliminate y

x + 3y = 1

-3x - 3y = -15

-------------------------

-2x = -14

Divide by -2

-2x/-2 = -14/-2

x = 7

Now we can find y

x+3y = 1

7 + 3y = 1

Subtract 7 from each side

7+3y-7 = 1-7

3y = -6

Divide by 3

3y/3 = -6/3

y = -2

Answer:

b. less than evens

Step-by-step explanation:

the probability that the next roll is 6 is

[tex] \frac{1}{6} [/tex]

B. less than evens should be the answer

Answer:

23/26 = 0.8846=0.88 [ to the nearest hundredth]

Step-by-step explanation:

4 sec a-5 = 0; seca=1/cos a

Therefore;

4 sec a-5 = 0=>4/cos a - 5 = 0

Multiplying through by cos a, we have;

4-5cosa= 0=>4= 5cosa

4/5 = cosa

a = cos^{-1}0.8

=36.88

Alternatively Cos a =4/5

Sina = 3/5; {note Cos a = adjacent / hypothesis and from Pythagoras rule we can derive the value of the opposite side which is;

5^2 -4^2 = 25-16 = 9; hence the opposite side is √9 = 3;sin a = opposite/ hypothenus = 3/5}

Substituting the value of Cosa and Sina into the expression below;

2 cos a + 5 sin a ÷ 2 sin a + 5 cos a​

We have ;

[2×4/5 + 5× 3/5 ]/ [2 × 3/5 + 5× 4/5]

[8/5 + 15/5 ]/ [6/5 + 20/5]

[23/5]/[26/5] = 23/5 × 5/26 = 23/26

=

Answer:

y = 1/x+2 + 3

Step-by-step explanation:

x = -2

y = 3

Answer:

[tex]A=1500-1450e^{-\dfrac{t}{250}}[/tex]

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

[tex]R_{in}[/tex] =(concentration of salt in inflow)(input rate of brine)

[tex]=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}[/tex]

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, [tex]C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}[/tex]

[tex]R_{out}[/tex]=(concentration of salt in outflow)(output rate of brine)

[tex]=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}[/tex]

Now, the rate of change of the amount of salt in the tank

[tex]\dfrac{dA}{dt}=R_{in}-R_{out}[/tex]

[tex]\dfrac{dA}{dt}=6-\dfrac{A}{250}[/tex]

We solve the resulting differential equation by separation of variables.  

[tex]\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}[/tex]

Taking the integral of both sides

[tex]\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}[/tex]

Recall that when t=0, A(t)=50 (our initial condition)

[tex]50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}[/tex]

Answer:

C. 0.1515

Step-by-step explanation:

The main objective here is to find the P-value for the test of [tex]H_0[/tex]

Given that ;

the mean value = 2.2

the standard deviation = 1.4

number of recorded accident per week = 52

The null  hypothesis is : [tex]H_o: \mu =2[/tex]

The alternative hypothesis is : [tex]H_A = \mu < 2[/tex]

The Z- value can be calculated as:

[tex]z = \dfrac{x- \mu}{\dfrac{\sigma }{\sqrt{n}}}[/tex]

[tex]z = \dfrac{2- 2.2}{\dfrac{1.4 }{\sqrt{52}}}[/tex]

[tex]z = \dfrac{- 0.2}{\dfrac{1.4 }{7.211}}[/tex]

z = -1.03

From the normal distribution table for probability;

P(z< -1.03 ) = 0.1515

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean score of in-state applicants

x2 = sample mean score of out -of-state applicants

s1 = sample standard deviation for in-state applicants

s2 = sample standard deviation for out-of-state applicants

n1 = number of in-state applicants

n1 = number of out-of-state applicants

For a 90% confidence interval, we would determine the z score from the t distribution table because the number of samples are small

Degree of freedom =

(n1 - 1) + (n2 - 1) = (17 - 1) + (10 - 1) = 25

z = 1.708

x1 - x2 = 1046 - 1118 = - 72

Margin of error = z√(s1²/n1 + s2²/n2) = 1.708√(37²/17 + 50²/10) = 31.052239

Confidence interval is - 72 ± 31.052239

Answer:

40*40 =1600

Step-by-step explanation:

Answer:

D. Logical Fallacies

Step-by-step explanation:

Let's break this down:

fallacy: A false or mistaken idea.

By this definition, we can see that "false" would go with the word "faulty". A logical Fallacy is is a false or mistaken idea that's intended to sound logical. I hope this helps you!!

Answer:

5 dimes and 18 nickels

Step-by-step explanation:

5D + 18 N =

5 x 10 + 18 x 5 =

5 x.10 + 18 x 0.05=

.50 + .90=

$1.40

Answer:

3/20

Question:

A farmer plants corn in 1/4 of his field. He plants white corn in 3/5 of the corn

section of his field. This situation is shown in the model. What fraction of the whole field is planted with white corn

Step-by-step explanation:

Portion of the field planted with corn = 1/4

Total corn planted = 1/4 of field

Portion of the corn section planted with white corn = 3/5

Total white corn planted = 3/5 of corn section

We need to find the portion of the total field planted with white corn

The fraction of the whole field planted with white corn would be the product of the fraction of Total corn planted and fraction of Total white corn planted

= 1/4 × 3/5

= 3/20

The fraction of the whole field planted with white corn = 3/20

Answer:

6/8

Step-by-step explanation:

6/8

Answer:

a) 240 ways

b) 12 ways

c) 108 ways

d) 132 ways

e) i) 0.55

ii) 0.4125

Step-by-step explanation:

Given the components:

Receiver, compound disk player, speakers, turntable.

Then a purcahser is offered a choice of manufacturer for each component:

Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood => 5 offers

Compact disc player: Onkyo, Pioneer, Sony, Technics => 4 offers

Speakers: Boston, Infinity, Polk => 3 offers

Turntable: Onkyo, Sony, Teac, Technics => 4 offers

a) The number of ways one component of each type can be selected =

[tex] \left(\begin{array}{ccc}5\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right) [/tex]

[tex] = 5 * 4 * 3 * 4 = 240 ways [/tex]

b) If both the receiver and compact disk are to be sony.

In the receiver, the purchaser was offered 1 Sony, also in the CD(compact disk) player the purchaser was offered 1 Sony.

Thus, the number of ways components can be selected if both receiver and player are to be Sony is:

[tex] \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right) [/tex]

[tex] = 1 * 1 * 3 * 4 = 12 ways [/tex]

c) If none is to be Sony.

Let's exclude Sony from each component.

Receiver has 1 sony = 5 - 1 = 4

CD player has 1 Sony = 4 - 1 = 3

Speakers had 0 sony = 3 - 0 = 3

Turntable has 1 sony = 4 - 1 = 3

Therefore, the number of ways can be selected if none is to be sony:

[tex] \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) [/tex]

[tex] = 4 * 3 * 3 * 3 = 108 ways [/tex]

d) If at least one sony is to be included.

Number of ways can a selection be made if at least one Sony component is to be included =

Total possible selections - possible selections without Sony

= 240 - 108

= 132 ways

e) If someone flips switches on the selection in a completely random fashion.

i) Probability of selecting at least one Sony component=

Possible selections with at least one sony / Total number of possible selections

[tex] \frac{132}{240} = 0.55 [/tex]

ii) Probability of selecting exactly one sony component =

Possible selections with exactly one sony / Total number of possible selections.

[tex] \frac{\left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right)}{240} [/tex]

[tex] = \frac{(1*3*3*3)+(4*1*3*3)+(4*3*3*1)}{240} [/tex]

[tex] \frac{27 + 36 + 36}{240} = \frac{99}{240} = 0.4125 [/tex]

Answer:

A, B, D and E.

Step-by-step explanation:

From the diagram

[tex]ED \cong DB\\FA \cong AC[/tex]

The correct options are A, B, D and E.

Answer:

1, 2, 4, 5

Step-by-step explanation:

Line segment E B  is bisected by Line segment D F .

A is the midpoint of Line segment F C .

Line segment E B  is a segment bisector.

FA = One-halfFC.

Answer:

The park owners should take into account the population of children in the community, if there are a good number of kids living in that area and the towns nearby - there would be a great demand for another roller coaster. They should consider the safety measures on the particular roller coaster they intend to add and check for the available space where they plan to fit the ride in the park.

Hope that answers the question, have a great day!

Answer:

4x^2 +5x -21

Step-by-step explanation:

(x+3) * (4x-7)

FOIL

first : x*4x = 4x^2

outer: -7x

inner: 3*4x =12x

last: -7*3 = -21

Add them together : 4x^2 -7x+12x -21

Combine like terms : 4x^2 +5x -21

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let [tex]\bar X[/tex] = sample mean diameter

The z score probability distribution for sample mean is given by;

                            Z  =  [tex]\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean diameter = 141 millimetres

           [tex]\sigma[/tex] = standard deviation = 7 millimetres

           n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P([tex]\bar X[/tex] > 141.4 millimetres)

      P([tex]\bar X[/tex] > 141.4) = P( [tex]\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }[/tex] > [tex]\frac{141.4-141}{\frac{7}{\sqrt{39} } } }[/tex] ) = P(Z > 0.36) = 1 - P(Z [tex]\leq[/tex] 0.36)

                                                            = 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.