The short-term effects of marijuana can include __________.

Answer:

W = 6000 Joule

Explanation:

Work is defined as force times distance

W = F * d

We know that F = 15N, we just need the distance (d)

Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.

The width of the mower is only 50 cm = 0.5 m.

This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,

d = 10 (meter) * 40 (times) = 400 meter

Therefore:

W = (15) * (400) = 6000 J

Answer:

1.77 cm

Explanation:

The electric field strength produced by a point charge can be calculated using the equation:

E = k * Q / r^2

where E is the electric field strength, k is Coulomb's constant (k = 8.99 x 10^9 N m^2 / C^2), Q is the charge, and r is the distance between the charge and the point where the field is being measured.

Rearranging this equation to solve for r, we get:

r = sqrt(k * Q / E)

Substituting the given values, we get:

r = sqrt((8.99 x 10^9 N m^2 / C^2) * (4.82 x 10^-11 C) / (2250 N/C))

r = 0.0177 m or 1.77 cm

Therefore, the distance to the charge is 1.77 cm for this electric field strength.

The Kinetic energy of the car with a mass of 80 grams is 0.40 joules

From the graph given, we can see that the as the mass increase, the kinetic energy also increase. Thus, we can say that the kinetic energy and mass of the car are in direct proportionality.

Now, we shall obtain the velocity of the car. Details below:

KE = ½mv²

0.1 = ½ × 0.02 × v²

0.1 = 0.01 × v²

Divide both side by 0.01

v² = 0.1 / 0.01

Take the square root of both side

v = √(0.1 / 0.01)

v = 3.16 m/s

Finally, we shall determine the kinetic energy of the car of mass 80 grams. Details below:

KE = ½mv²

KE = ½ × 0.08 × 3.16²

Kinetic energy = 0.40 joules

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A chemical process known as hydrogen displacement occurs when hydrogen gas is replaced or displaced by another element or molecule.

It results from a number of reactions, most of which involve a reactive metal or substance. A metal reacting with an acid can displace hydrogen atoms of the acid, resulting in the formation of a salt and the release of hydrogen gas as an example.

Another example is the interaction of a metal with water molecules, which displaces hydrogen atoms and results in the formation of metal hydroxide and hydrogen gas. Chemistry studies hydrogen displacement reactions in great detail because they are important for understanding the reactivity of various compounds. They shed light on the behavior of elements, how well they can replace hydrogen, and how new compounds are formed.

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The orbital speed of the satellite orbiting around a planet of radius 34 Km is found to be 2.59 km/s.

To find the orbital speed (v) of the satellite, we can use the formula,

v = √(GM/r), gravitational constant (6.674 x 10⁻¹¹ N(m/kg)²) is G, mass of the planet is M, and orbital radius of the satellite is r. To calculate M, we can use the formula,

g = GM/r², rearranging this formula, we get,

M = gr²/G

Substituting the values, we get,

M = 3.3(34,000)²/(6.674 x 10⁻¹¹)

M = 6.06 x 10²⁰ kg

Now, substituting the values of G, M, and r into the formula for orbital speed, we get,

v = √((6.674 x 10⁻¹¹)(6.06 x 10²⁰)/(34,000))

v = 2.59 x 10³ m/s

Therefore, the satellite's orbital speed is approximately 2.59 km/s.

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Answer:

Explanation:

The total initial momentum of the system is zero since the boy and girl are at rest initially. According to the law of conservation of momentum, the total final momentum of the system must also be zero.

If the girl moves in a negative direction with a speed of 3 m/s, then she gains a momentum of -3 x 40 = -120 kgm/s in the negative direction. To conserve momentum, the boy must gain a momentum of +120 kgm/s in the positive direction, so that the total momentum of the system remains zero.

Therefore, the total final momentum of the boy and girl combined is 120 kgm/s in the positive direction. The answer is C. 120 kgm/s.

Answer:

The girl acquires a velocity of -3 x 40 = -120 kgm/s in the negative direction if she goes with a speed of 3 m/s in the opposite direction. The boy must acquire a momentum of +120 kgm/s in the positive direction to preserve and keep the system's overall momentum at zero.

Explanation:

The answer is option D

Brainliest please :)

The steps assume that the mirrors and boxes are arranged in a simple, two-dimensional configuration.

The steps to be followed are;

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The proportionality constant of the moving object experiencing a drag force is 0.01875 Ns²/m².

The work-energy principle states that the work done on an object is equal to its change in kinetic energy. So, the work done by the drag force can be found as follows:

W = (1/8)mv² - (1/2)mv₀²

where m = mass of the object, v = final speed, and v₀ = initial speed.

The work done by the drag force is also given by the formula:

W = ∫F(x)dx

where F(x) = force function and x = position of the object.

In this case, the force function is F(x) = -Cv², since the drag force is in the opposite direction of motion. So:

W = ∫-Cv²dx

Since the force is proportional to v², rewrite this as:

W = -C∫v²dx

Integrating both sides with respect to x:

W = -(1/3)Cv³

So, equating the two expressions for W:

(1/8)mv² - (1/2)mv₀² = -(1/3)Cv³

Substituting m = 0.01 kg, v₀ = 10 m/s, and solving for C:

C = -(3/8) × (m/v₀³) × (v² - v₀²) = -(3/8) × (0.01/10³) × (1/8 × 10² - 10²) = 0.01875 Ns²/m²

Therefore, the proportionality constant is C = 0.01875 Ns²/m².

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Answer:

To calculate the minimum total speed required for the projectile to escape the Earth's gravitational pull, we can use the equation for escape velocity:

v_escape = sqrt(2GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.

Plugging in the given values, we get:

v_escape = sqrt(26.67e-115.98e24/6370000)

v_escape = 11186.4 m/s

This is the minimum total speed required for the projectile to escape the Earth's gravitational pull. In order to achieve this speed, the projectile would need to be launched with a velocity of 11186.4 m/s relative to the Earth.

Explanation:

The time takes  is 1.19 ms for the sound waves to travel the length of the aluminum rod between the two houses.

The speed of sound in aluminum can be determined utilizing the condition

v = sqrt(Y/ρ),

where Y is the Youthful's modulus and ρ is the thickness of the material. Connecting the qualities for aluminum, we get

v = [tex]sqrt(6.9x10^10 N/m^2/2700 kg/m^3) = 5110 m/s[/tex].

The time it takes for the sound waves to venture to every part of the length of the aluminum pole can be determined utilizing the condition

t = d/v,

where d is the distance and v is the speed of sound. Connecting the qualities, we get

t = 6.1 m/5110 m/s = 0.00119 s or 1.19 ms.

Subsequently, it takes 1.19 ms for the sound waves to venture to every part of the length of the aluminum bar between the two houses.

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The general strengths of epidemiology for providing an answer to Mary Beth’s question.

The general  weaknesses of epidemiology for providing an answer to Mary Beth’s question:

The Specific strengths of a study:

The specific weaknesses of a study are :

Epidemiology is described as  the study and analysis of the distribution, patterns and determinants of health and disease conditions in a defined population.

The main objective of epidemiology has been said is to find  out what causes different health outcomes in different groups of people.

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The change in momentum of the object in terms of its mass, initial velocity, and final velocity is 5 kg m/s.

The change in momentum of an object can be calculated using the formula:

Δp = m * (v - u)

In this case, the mass of the object is 0.5 kg, the initial velocity (u) is 0 m/s, and the final velocity (v) is 10 m/s after 3 seconds of uniform acceleration.

Substituting these values into the formula gives:

Δp = 0.5 kg * (10 m/s - 0 m/s)

Δp = 5 kg m/s

Therefore, the change in momentum of the object in terms of its mass, initial velocity, and final velocity is 5 kg m/s.

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--The complete Question is, A 0.5 kg object is initially at rest. It then accelerates uniformly for 3 seconds and reaches a velocity of 10 m/s. Calculate the change in momentum of the object in terms of its mass (m), initial velocity (u), and final velocity (v).--

The 2001 World Trade Center attacks fall under which category of terrorism (a).foreign-sponsored terrorism on U.S. soil is correct option.

The 2001 World Trade Center attacks are generally considered to be an example of foreign-sponsored terrorism on U.S. soil. The attacks were carried out by a terrorist organization based in Afghanistan called Al-Qaeda, which was led by Osama bin Laden. The attackers were primarily from Saudi Arabia, but they received training and support from Al-Qaeda operatives based in Afghanistan.

Therefore, the correct option is (a).

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Answer :

Step-by-step explanation:

We are given with 4 resistors which are connected in parallel.

Let

R_1 =10Ω

R_2 = 12Ω

R_3 = 15Ω

R_4 = 20 Ω

First let's calculate the total resistance.

Since the resistors are connected in parallel, Total resistance will be,

[tex]{\boxed{ \implies {\sf {\dfrac{1}{R_{(total)} }= \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + \dfrac{1}{R_4}}}}} \\ [/tex]

Plugging in the required values,

[tex]\implies \sf \dfrac{1}{R_{(total)}} = \dfrac{1}{10} + \dfrac{1}{12} + \dfrac{1}{15} + \dfrac{1}{20} \\ \\\implies \sf \dfrac{1}{R_{(total)}} = \dfrac{6 + 5 + 4 + 3}{60} \\ \\ \implies \sf \dfrac{1}{R_{(total)}} = \frac{18}{60} \\ \\ \implies \sf R_{(total)} = \frac{60}{18} \\ \\ \implies \sf R_{(total)} = 3.33 [/tex]

Hence, The total resistance is 3.33 Ω

Now,

[tex] \implies \sf I = \dfrac{V}{R}[/tex]

Where,

Plugging the required values

[tex] \implies[/tex] I = 25/3.33

[tex] \implies[/tex] I = 7.5 A

Therefore, The total current in the circuit is 7.5 A

Answer:10.2

Explanation:

The fulcrum to balance the meter stick should be placed 8.33 cm to the left of the center of mass of the meter stick, under the condition that the mass of the meter stick is 0.2 kg and its center of mass is located at its geometric center.

In order to balance the meter stick with the 1.3 kg mass placed to the left end, we have to evaluate the distance ‘d' from the center of mass of the meter stick to the fulcrum.

The given center of mass of the meter stick is found at its geometric center which is at 50 cm from either end of the stick. Then the mass of the meter stick is 0.2 kg.

We can apply the principle of moments to evaluate this problem. The principle of moments says that for an object in equilibrium, the summation of the clockwise moments about any point must be equivalent to the sum of the anticlockwise moments about that point.

Let us consider that moments about the fulcrum. The clockwise moment because of the weight of the 1.3 kg mass and is stated by (1.3 kg) x (d cm). The anticlockwise moment is because of the weight of the meter stick and is given by (0.2 kg) x (50 - d cm). Since the meter stick is balanced, these two moments should be equal.

(1.3 kg) x (d cm)

= (0.2 kg) x (50 - d cm)

Evaluating for‘d’,

d = 8.33 cm

Hence, the fulcrum should be placed 8.33 cm to the left of the center of mass of the meter stick.

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In Experiment 6.1, two entangled atoms are delivered to several Stern-Gerlach analyzers where the spins are detected in various orientations. Each atom's measurement result is probabilistic and arbitrary. Because there is no way to influence how the measurement on the distant atom turns out, it is impossible to use this process to convey a message instantly.

A fundamental area of physics called quantum mechanics examines how matter and energy behave at the atomic and subatomic scales. The behavior of particles like electrons, protons, and photons as well as their interactions are understood and described mathematically.

The idea of entanglement, which describes how two or more particles can come to be connected in such a way that their states are correlated even though they are separated by a considerable distance, is also introduced by quantum mechanics.

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When the ball hits the racquet, it gets squished, and it gains elastic energy, since it is compressed.

Answer:

C. 110 kgm/s

Explanation:

Law of Conservation of Momentum states that total momentum before the collision must equal total momentum after the collision.

Momentum = p = mv

x = final velocity of the blue train

(50 kg)(4 m/s) + (30 kg)(0 m/s) = (50 kg)(x) + (30 kg)( 3 m/s)

200 kg·m/s + 0 = (50 kg)(x) + 90 kg·m/s

50 kg(x) = 110 kg·m/s

x = (110 kg·m/s)/(50 kg) = 2.2 m/s

p-final (blue train) = (50 kg)(2.2 m/s) = 110 kg·m/s

Answer:

According to the law of conservation of momentum, the total momentum of the system before and after the interaction must be equal.

The total initial momentum of the system is:

P_initial = 50 * 4 + 30* 0 = 200kgm/s

The total final momentum of the system

let the velocity of the blue train is=v

P_final = 30* 3 + 50* v = 200

after solving v=2.2m/sec

the momentum of blue train will be= 50* 2.2=110kgm/s

To convert one system of unit to another  of derived quantities is not a use of dimensional analysis.

Checking for consistency in the dimensions on both sides of an equation entails looking at the dimensions of the physical quantities involved in a problem, such as length, mass, time, electric charge, and temperature.

The core tenet of dimensional analysis is that physical quantities, such as length, mass, and time, may be described in terms of their basic dimensions.

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All of the options listed are included in the uses of dimensional analysis.

Dimensional analysis is a powerful tool used in physics to:

The dimensional analysis involves analyzing the dimensions of physical quantities and using them to establish relationships between them.

By using the principles of dimensional analysis, we can simplify complex physical problems and gain insights into the behavior of physical systems.

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The use of the wheel barrow in this case makes it a simple machine

A wheelbarrow is an illustration of a straightforward device that can simplify labour by lowering the force needed to move a large load. The wheel and axle and the lever are two basic machines that are used.

The wheelbarrow's wheel is made of an axle and wheel. The friction between the wheel and the ground is decreased by the wheel's rotation around the axle. It can also be seen as one of the classes of the lever.

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Answer: 3 meters from the ground

Explanation:

gravitational potential energy= mass*height*acceleration of free fall(g)

150=5*h*10

h=150/50

h= 3 m

The pressure exerted on the fluid by the force applied on the small piston can be calculated using the formula:

P = F/A

where P is the pressure, F is the force, and A is the area on which the force is applied. Since the force is applied on the smaller piston, we need to use its area:

A_small = πr_small^2

where r_small is the radius of the smaller piston. Thus,

A_small = π(0.02 m)^2 = 1.2566 x 10^-3 m^2

The force applied on the small piston is 250 N. Thus,

P = F/A_small = 250 N / 1.2566 x 10^-3 m^2 = 1.989 x 10^5 Pa

Therefore, the increase in pressure caused by the 250 N force on the small piston is 1.989 x 10^5 Pa, which is approximately equal to 2 x 10^5 Pa (to two significant figures).

b) We can use the principle of conservation of volume to determine how far the smaller piston moves when the larger piston moves 5 cm. The volume of the fluid in the hydraulic lift remains constant, so we have:

A_small × h_small = A_large × h_large

where h_small and h_large are the heights of the fluid columns above the smaller and larger pistons, respectively. Since the lift is filled with an incompressible fluid, the pressure is the same throughout the fluid. Thus,

P = F/A_small = F/A_large

Multiplying both sides of this equation by the areas of the pistons, we get:

F × A_small = F × A_large

Substituting the given values, we get:

250 N × (π(0.02 m)^2) = F × (π(0.20 m)^2)

Solving for F, we get:

F = 250 N × (0.02 m/0.20 m)^2 = 25 N

Now, we can use the force applied on the larger piston and the area of the smaller piston to calculate the force on the smaller piston:

F_small = F × (A_small/A_large) = 25 N × (1.2566 x 10^-3 m^2 / (π(0.20 m)^2)) = 0.1989 N

Using the formula for pressure, we can calculate the height of the fluid column above the smaller piston:

P = F_small/A_small = h_small × ρ × g

where ρ is the density of the fluid and g is the acceleration due to gravity. Since the density of the fluid and the acceleration due to gravity are constants, we can simplify this equation to:

h_small = F_small/(A_small × ρ × g)

Substituting the given values, we get:

h_small = 0.1989 N / (1.2566 x 10^-3 m^2 × 1000 kg/m^3 × 9.81 m/s^2) = 0.0159 m

Therefore, the smaller piston moves 0.0159 m (or approximately 1.6 cm) when the larger piston moves 5 cm.

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Answer:

The light spectrum measured for a nearby star can be used as a benchmark for more distant stars because two stars with identical spectra have the same intrinsic luminosity. Spectroscopy can be applied to light from a distant galaxy, but the dark lines in the solar spectrum give a unique pattern that can be used to identify the elements present in the star. The light spectrum of a distant galaxy that is moving rapidly away from the observer will be shifted towards the red end of the spectrum due to the Doppler effect, which causes the wavelengths of light to stretch out as the object moves away from the observer.

Engineers use electrical insulators to prevent electricity from flowing to the wrong place.

Insulators are materials that do not conduct electricity easily and are used to separate electrical conductors to prevent current leakage or short circuits. Common insulating materials include rubber, plastic, glass, and ceramic. By using insulators, engineers can ensure that electrical energy is directed along the intended path and that electrical equipment operates safely and efficiently.

. Insulators are commonly used in a variety of applications, including electrical wiring, power transmission and distribution systems, electronic devices, and high-voltage equipment. Common insulating materials include rubber, plastic, glass, ceramic, and air. The choice of insulating material depends on various factors such as the required level of insulation, the operating temperature, and the environment in which the insulator will be used.

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Answer:

Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.

To solve this problem, you can use the formula for sound intensity:

I = P/A

where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).

You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:

P = AI

where A is the area of the eardrum in square meters.

Substituting the given values, you get:

P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))

Simplifying this expression, you get:

P = 1.8 x 10^-3 W

Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.

Answer:

To meet the requirements of running for at least 30 minutes and developing a steady power of 500W, the flywheel engine needs to have sufficient energy storage capacity and be capable of delivering a steady power output.

Assuming that the flywheel engine is 100% efficient (i.e., no energy losses due to friction, air resistance, or other factors), the energy storage capacity required can be calculated as follows:

Energy storage capacity = Power x Time

= 500W x 30min

= 15,000 watt-minutes or 250 watt-hours

This means that the flywheel engine needs to be capable of storing at least 250 watt-hours of mechanical energy.

Answer:

5866.9 kg

Explanation:

We can use the conservation of momentum to solve this problem. The momentum of the rocket and fuel system is conserved, so:

Initial momentum = Final momentum

The initial momentum of the system is zero since the rocket is at rest initially. The final momentum is the momentum of the rocket after burning the fuel. We can find the final momentum using the rocket equation:

Δv = ve * ln(m0 / mf)

where Δv is the change in velocity (100 m/s), ve is the exhaust speed (1500 m/s), m0 is the initial mass of the rocket and fuel system (what we want to find), and mf is the final mass of the rocket and fuel system (m0 - 100 kg).

Solving for m0, we get:

m0 = mf * exp(Δv / ve) = (m0 - 100 kg) * exp(100 / 1500)

Simplifying this equation, we get:

m0 = 100 kg / (1 - exp(100 / 1500))

m0 = 5866.9 kg (rounded to four significant figures)

Therefore, the initial mass of the rocket and fuel system was approximately 5866.9 kg.

The electric current in the circuit below is 3 A And the right option is C. 3A.

Electric current is the rate of flow of charge in a circuit.

To calculate the electric current in the circuit below, we use the formula:

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is C. 3A

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What is common among all the graphs is that they all show an object that is moving.

In the distance time graph, we have the distance on the vertical axis and we have the time on the horizontal axis and the shape of the plots may differ depending on the nature of the motion of the objects.

Graphs of distance vs time help us to examine motion by showing how an object has moved over time. All objects shown on a distance vs. time graph are shifting positions over time, regardless of the graph's specific shape or slope, and the graph reveals information about the direction and speed of their motion.

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The mass to be hung at a point 40cm to the right of the pivot point such that the stick hangs level is 15 g.

To solve this problem, use the principle of moments which states that the sum of the clockwise moments about a pivot point is equal to the sum of the counterclockwise moments about the same pivot point. In this case, take the pivot point to be the suspension point of the meter stick.

Let x be the mass that needs to hang at a point 40cm to the right of the pivot point. Then, set up the following equation:

(clockwise moment) = (counterclockwise moment)

(0.2 kg) × (0.3 m) × (9.81 m/s²) = (x kg) × (0.4 m) × (9.81 m/s²) + (0.1 kg) × (0.1 m) × (9.81 m/s²)

Simplifying this equation:

0.05886 = 3.924x

x = 0.015 kg or 15 g

Therefore, we need to hang a 15 g mass at a point 40 cm to the right of the pivot point such that the stick hangs level.

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