The short leg of a triangle measures 17 and the long leg measures 32. What is the measure of the smaller acute angle of the triangle to the nearest tenth of a degree ? Draw a triangle to represent the problem. Be sure to show the trig equation you used when solving

To determine the range and sample standard deviation of tornadoes that touched down during each month of one year, we need to use the data in the table.

However, the table is not provided in the question.

Please provide the table with the number of tornadoes that touched down during each month of one year so I can help you with your question.
To determine the range and sample standard deviation of the number of tornadoes that touched down each month, you'll first need to provide the data in a table format.

Once you provide the data, I can help you calculate the range and sample standard deviation.

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Correct question:

Each​ year, tornadoes that touch down are recorded. The following table gives the number of tornadoes that touched down during each month of one year. Determine the range and sample standard deviation.

3 2 41 115 197 95

70 85 68 64 110 91

Range?

Sample Standard Deviation?

In Year 6 at Woodland Junior School, there are 90 children split into three classes of 14, 24, and 12 on the basis of there selection of sports. In 6M, 14 not chose hockey, and the rest of the class was split equally between football and netball. In 6P, 24 not chose netball, 16 chose football, and 8 choose hockey  In 6T, the ratio of football to netball to hockey was 1:2:3. The completed table is shown.

To complete the table, we need to distribute the remaining children who did not choose their sport in each class. Here's how we can calculate it

In 6M, the number of children who did not choose hockey is 27 - 13 = 14.

Since the rest of the class was split equally between football and netball, each of these two sports will have 14/2 = 7 children.

In 6P, the number of children who did not choose netball is 33 - 9 = 24.

Since twice as many children chose football as chose hockey, we can write the number of footballers as 2x, and the number of hockey players as x. Then we have 2x + x + 9 = 33, which gives x = 8. Therefore, we have 16 children who chose football, and 8 children who chose hockey. The number of children who did not choose any of these two sports is 33 - 16 - 8 - 9 = 0.

In 6T, the ratio of children who chose football to netball to hockey was 1:2:3. Let's call the number of children who chose netball as 2x, and the number of children who chose hockey as 3x. Then we have x + 2x + 3x = 30, which gives x = 6. Therefore, we have 6 children who chose football, 12 children who chose netball, and 18 children who chose hockey.

Thus, the completed table is shown.

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The landscaper needs to buy approximately 85.33 bags of topsoil to cover the whole garden.

The landscaper uses 4 bags of topsoil to cover 3/8 of the garden. To cover the whole garden, he would need:

First, we need to find how many bags of topsoil he needs per 1/8 of the garden:

4 bags / 3/8 of the garden = 32/3 bags of topsoil per 1 garden

Then, we can find the number of bags he needs for the whole garden:

32/3 bags * 8 = 256/3 bags or 85.33 bags (rounded to two decimal places)

Therefore, the landscaper needs to buy approximately 85.33 bags of topsoil to cover the whole garden.

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For the first question, to get the limit of the function lim (In V 4x2 + 6 - In x), we can use the property of logarithms that says ln(a) - ln(b) = ln(a/b). Applying this property to the given function, we get ln[(4x^2 + 6)/x]. Now we can simplify the expression by dividing both the numerator and the denominator by x. So we get ln(4x + 6/x), which can be rewritten as ln(4 + 6/x). Now we can take the limit as x approaches infinity. As x gets larger and larger, the 6/x term becomes smaller and smaller and approaches zero. So ln(4 + 6/x) approaches ln(4), and the final answer is A. In 2.

For the second question, to get the horizontal asymptote(s) of the function f(x) = 37€*, we can take the limit as x approaches infinity. As x gets larger and larger, the exponential term €* becomes larger and larger, approaching infinity. So the function approaches 37 times infinity, which is infinity. Therefore, there is no horizontal asymptote and the answer is D. none.
For the third question, the statement is false. The limit as x approaches infinity of 2^(ln(a)/ln(x)) is equal to infinity if a > 1 and is equal to zero if 0 < a < 1.

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Cos(165) in terms of sine and cosine of an acute angle is -1 + 2sin^2(7.5).

We can use the trigonometric identity cos(180 - x) = -cos(x) to find cos(165) in terms of cosine of an acute angle.

Since 165 = 180 - 15, we have:

cos(165) = cos(180 - 15) = -cos(15)

To express cos(15) in terms of sine and cosine of an acute angle, we can use the following trigonometric identities:

sin(2x) = 2sin(x)cos(x) and cos(2x) = cos^2(x) - sin^2(x)

Let's take x = 7.5, which is half of 15 (the acute angle):

sin(15) = 2sin(7.5)cos(7.5)

cos(15) = cos^2(7.5) - sin^2(7.5)

Now, we can solve for cos(15):

cos(15) = cos^2(7.5) - sin^2(7.5)

= (1 - sin^2(7.5)) - sin^2(7.5)

= 1 - 2sin^2(7.5)

Therefore, we have:

cos(165) = -cos(15)

= -[1 - 2sin^2(7.5)]

= -1 + 2sin^2(7.5)

So, cos(165) in terms of sine and cosine of an acute angle is -1 + 2sin^2(7.5).

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The equation given in the solution is X(t) = (cos(4t) + C2sin(4t)). This equation represents the position of the mass at time t after the spring has been released with an initial velocity of 0. The terms "spring" and "stretch" indicate that Hooke's Law is being used to determine the spring constant k.

The term "velocity" is used to describe the initial velocity of the mass, which is given as 0. The position of the mass at time t is determined by the value of X(t), which is a function of time. Therefore, the position of the mass at any given time can be found by plugging in the value of t into the equation X(t) = (cos(4t) + C2sin(4t)).
Hi! Based on the information provided, you have a spring with a mass of 6 kg and a natural length of 0.3 m. A force of 38.4 N is required to stretch it to 0.7 m. The spring constant, k, is determined to be 96. The spring is then stretched to 0.7 m and released with an initial velocity of 0. To find the position of the mass at time t, you can use the equation:
x(t) = C1 * cos(4t) + C2 * sin(4t)

Given the initial condition x(0) = 0.4, we find that C1 = 0.4. The initial velocity x'(0) is 0, leading to the conclusion that C2 = 0. Therefore, the equation for the position of the mass at time t is:
x(t) = 0.4 * cos(4t)

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So the value of the integral ∫ dx/√(1-2x^2) over the interval [-1/√2, 1/√2] is (1/√2)π.
The value of the integral ∫ dx/√(1-2x^2) is given by:
∫ (1/√(1-2x^2)) dx = (1/2) * arcsin(√2 * x) + C
where C is the constant of integration.

The value of the integral ∫ dx/√(1-2x^2) is equal to the integral of the function 1/√(1-2x^2) with respect to x. This is an example of an integral that requires a trigonometric substitution to evaluate. Specifically, we can let x = sin(θ)/√2 and dx = cos(θ)/√2 dθ. Substituting these expressions into the integral yields:

∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / √(1-2(sin(θ)/√2)^2) dθ

Simplifying the denominator gives:

√(1-2(sin(θ)/√2)^2) = √(1 - sin^2(θ)) = cos(θ)

Substituting this expression into the integral gives:

∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / cos(θ) dθ = ∫ dθ/√2 = (1/√2)θ + C

To find the value of the integral, we need to substitute back in for x and evaluate at the limits of integration. If we are integrating over the interval [-1/√2, 1/√2], then:

(1/√2)θ evaluated from -π/4 to π/4 gives:

(1/√2)(π/4 + π/4) - (1/√2)(-π/4 - π/4) = (1/√2)π

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The function g(x, y) is defined as 15x^2 + 2y^2. To compute g(3,3), g(0,-2), and g(a,b), we substitute the given values into the function.

To find g(3,3), we substitute x = 3 and y = 3 into the function g(x, y) = 15x^2 + 2y^2:

g(3,3) = 15(3)^2 + 2(3)^2

g(3,3) = 135 + 18

g(3,3) = 153

To find g(0,-2), we substitute x = 0 and y = -2 into the function g(x, y) = 15x^2 + 2y^2:

g(0,-2) = 15(0)^2 + 2(-2)^2

g(0,-2) = 0 + 8

g(0,-2) = 8

To find g(a,b), we substitute x = a and y = b into the function g(x, y) = 15x^2 + 2y^2:

g(a,b) = 15a^2 + 2b^2

Note: The function g(a,b) cannot be simplified further without knowing the values of a and b.

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The height of the cone in terms of y is h = y / 4.

The cylinder and the cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x.

Therefore,

volume of a cylinder = πr²h

where

Volume of a cone = 1 / 3 πr²h

where

Therefore,

πr²h = 1 / 3 πr²h

πx²y = 1 / 3 π (2x)²h

πx²y = 1 / 3 π 4x² h

multiply both sides by 3

πx²y = π 4x² h

divide both sides by  π 4x²

Hence,

h = πx²y  / π 4x²

h = y / 4

Therefore, the height of the cone is h = y / 4.

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Answer:

Who is the current world number one in men’s tennis?

What is the name of the sport that combines skiing and shooting?

How many countries are in the European Union?

What is the largest animal that ever lived on Earth?

What is the most spoken language in the world?

Step-by-step explanation:

is that ok?

A theater can make at least $675 from ticket sales by selling at least 100 adult tickets and up to 50 child tickets.

To solve this problem, we can use a system of equations. Let's define:

- x as the number of adult tickets sold
- y as the number of child tickets sold

We know that:

- x + y ≤ 150 (due to the limit on seating)
- 12x + 7.5y ≥ 675 (they want to make at least $675)

We can solve this system of equations using substitution or elimination. Let's use elimination:

- Multiply the second equation by 2 to get rid of the decimals: 24x + 15y ≥ 1350
- Multiply the first equation by 15: 15x + 15y ≤ 2250
- Subtract the second equation from the first: 9x ≥ 900
- Divide both sides by 9: x ≥ 100

So they need to sell at least 100 adult tickets to make at least $675. Let's see if that's possible:

- If they sell 100 adult tickets, that leaves 50 tickets for children
- 100 adult tickets * $12 = $1200
- 50 child tickets * $7.50 = $375
- Total ticket sales = $1575 (more than $675)

So they can make at least $675 from ticket sales by selling at least 100 adult tickets and up to 50 child tickets.

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The average monthly exchange rate between the us dollar and the Australian dollar for 2018

A. The components of a time series of average monthly exchange rates include trend, seasonality, cyclical fluctuations, and random noise. The trend represents the long-term movement of the exchange rate, seasonality represents repeating patterns within a fixed period, cyclical fluctuations are changes due to economic cycles, and random noise consists of unpredictable fluctuations.

B. To smooth out the patterns that include everything the model learned, you can apply an exponential smoothing method with a chosen smoothing coefficient (alpha). A suitable coefficient could be 0.2, representing a balance between giving weight to recent data and considering the historical pattern. The decision on the coefficient depends on the specific characteristics of the data and the desired degree of smoothing.

C. To forecast the monthly exchange rate for 2020, you can apply various techniques, such as moving average, exponential smoothing, autoregressive integrated moving average (ARIMA), and machine learning-based methods. Each method has its advantages and limitations, and it's important to analyze the performance of each technique on historical data to choose the most appropriate method for forecasting.

D. Comparing the forecasting results of different techniques applied in part (C) requires measuring their accuracy using metrics like mean absolute error (MAE), root mean square error (RMSE), and mean absolute percentage error (MAPE). The technique with the lowest error values would be considered more accurate in predicting the monthly exchange rates. It is crucial to consider the data characteristics and the goals of the forecast when deciding on the most suitable technique.

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lets assume.

Algebraic expression: c - 2.5. The variable is c, which represents Julie's initial weight in kilograms.

Algebraic equation: Jhon's height = 2m + 5. The variables are m, which represents Peter's height in centimeters, and the height of Jhon, which is represented by the equation.

Algebraic equation: Ador's age = 3(Emy's age - d). The variables are Ador's age and Emy's age, which is d years less than 9.

Algebraic expression: n + 7. The variable is n, which represents Jupiter's current age in years.

Algebraic equation: Anna's age = 3p + 4. The variables are p, which represents Anna's sister's age in years, and Anna's age, which is represented by the equation.

SO ANNA  current age is P=3+4

and p=7

Anna's age = 3p + 4, where p is the age of Anna's sister in years, and Anna is 4 years older than thrice the age of her sister.

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Let's assume that the number of shirts that must be sold to cover the costs is x.

The revenue from selling x shirts is 12x dollars, and the total cost is the sum of the setup fee and the cost per shirt multiplied by the number of shirts, which is 65 + 7x dollars.

To break even, the revenue must be equal to the cost:

12x = 65 + 7x

Subtracting 7x from both sides:

5x = 65

Dividing both sides by 5:

x = 13

Therefore, the student council must sell 13 shirts to break even.

To find the total costs, we can substitute x = 13 into the expression for the total cost:

65 + 7x = 65 + 7(13) = 156

So the total costs will be $156.

Answer:

The student council's costs will be $146 and they need to sell 13 shirts to cover their costs.

Step-by-step explanation:

Let's call the number of shirts sold "x".

The revenue from selling x shirts at $12 each is:

The total cost of making x shirts is:

In order to break even (i.e. cover their costs), the revenue must equal the total cost:

[tex]\sf:\implies 12x = 7x + 65[/tex]

Solving for x:

[tex]\sf:\implies 5x = 65[/tex]

[tex]\sf:\implies \boxed{\bold{\:\:x = 13\:\:}}\:\:\:\green{\checkmark} [/tex]

Therefore, the student council must sell 13 shirts to break even.

To find the total costs, we can substitute x = 13 into the total cost equation:

[tex]\sf:\implies Total\: Cost = 7(13) + 65 = \boxed{\bold{\:\:\$146\:\:}}\:\:\:\green{\checkmark} [/tex]

So the student council's costs will be $146 and they need to sell 13 shirts to cover their costs.

Word problem: The ratio of the number of people that attended Michael party to the number of people that attended Joshua's party is 5: 25

First, we need to know that equivalent ratios are those ratios that can usually be simplified to a similar value.

Also, algebraic expressions are defined as expressions that are composed of terms, variables, coefficients, terms, constants and factors.

These expressions are also made up of arithmetic operations such as addition, multiplication, subtraction, bracket, parentheses, etc

From the information given,

The word problem is;

The ratio of the number of people that attended Michael party to the number of people that attended Joshua's party is 5: 25

This is represented as;

5/25

Divide the values

1/5

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Using the combine clues method:

[tex]R_1=7\\\\R_2=9\\\\R_3=8\\\\S_1=2\\\\S_2=4\\\\S_3=5\\\\T_1=10\\\\T_2=14[/tex]

Certain items that must be worn, used, or accessed in order to access particular clues. The maximum skill level needed to solve each master clue is shown.

Clue 1: [tex]R_1 + R_2 + R_3 = 24[/tex]

Clue 2: [tex]R_1 + R_2 =16[/tex]

Since, [tex]R_1 + R_2 + R_3 = 24[/tex] (from clue 1)

[tex]R_1 + R_2 + R_3 = 24\\\\16 + R_3 = 24[/tex]

Subtract both the sides by 16,

[tex]R_3=8[/tex]

Clue 3:

We need to find the blank [tex]R_1 +[/tex] __ [tex]+S_2=20[/tex] and [tex]S_2=4[/tex]

Since, [tex]R_1 + R_2 = 16[/tex] (from clue 2)

So,

[tex]R_1 + R_2 + S_2 = 20\\\\16 + S_2 = 20[/tex]

Subtract 16 from both sides.

[tex]16 + S_2 - 16 = 20 -16\\\\S_2 = 4[/tex]

So,

[tex]R_1 + R_2 + S_2 = 20[/tex]

Clue 4:

We need to find the blank [tex]R_2[/tex] = __

[tex]S_2 + R_2 = 13[/tex]

Since, [tex]S_2 = 4[/tex]

[tex]S_2 + R_2 = 13\\\\4 + R_2 = 13[/tex]

Subtract 4 from both sides.

[tex]R_2 = 9[/tex]

So, [tex]R_2 = 9[/tex]

Clue 5:

We need to find the blank ___ [tex]+ T_2 = 22[/tex] and [tex]T_2=[/tex] ___

[tex]R_3 + T_2 = 22[/tex]

Since, [tex]R_3 =8[/tex] (from the Clue 2)

[tex]R_3 + T_2 = 22[/tex]

[tex]8 + T_2 = 22[/tex]

Subtract both the sides by 8,

[tex]T_2 = 14[/tex]

So, [tex]R_3 + T_2 = 22[/tex]

Clue 6:

We need to find the blank [tex]T_1 +[/tex] ___ = 24 and ___ = 10

Since, [tex]T_1 + T_2 = 24[/tex] (from the Clue 5)

[tex]T_1 + 14 = 24[/tex]

Subtract both the sides by 14,

[tex]T_1 = 10[/tex]

Clue 7:

We need to find the value of [tex]S_1[/tex],

Given [tex]T_1 + R_3 + S_1 =20[/tex]

Since, [tex]T_1=10[/tex] and [tex]R_3=8[/tex]

[tex]10+ 8 + S_1 = 20\\\\18 + S_1 = 20[/tex]

Subtract both the sides by 18,

so, [tex]S_1=2[/tex]

Combining this with what we learned from Clue 2 and Clue 6, we know

[tex]S_1=2[/tex]

Now, we need to find the blank, [tex]S_1 + S_2 +[/tex] ___ = 11

Combining this with what we learned from Clue 3 and Clue 7, we know:

___ = 5

[tex]S_1 + S_2 + S_3 = 11\\\\2 + 4 + S_3 = 11\\\\6 + S_3 = 11[/tex]

Subtract both the sides by 6,

[tex]S_3 = 5[/tex]

For [tex]R_1[/tex]

Since,

[tex]R_1 + R_2 + R_3 = 24\\\\R_1 + 9 + 8 = 24\\\\R_1 + 17 = 24[/tex]

Subtract both the sides by 17,

[tex]R_1 = 17[/tex]

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Answer: 64$

Step-by-step explanation:

Answer:

The answer to your problem is, 259,644

Step-by-step explanation:

an = 1880 ( it 25% [tex])^{t}[/tex]

= 1880 x (1.25[tex])^{t}[/tex]

ai = 1880, r will equal 1.25

Sn = [tex]\frac{aill-r^{4} }{l = r}[/tex]

[tex]S_{16}[/tex] = [tex]\frac{1880(l-1.25^{16}) }{l - 1.25}[/tex]

= 259,644

Thus the answer to your problem is, 259,644

Answer:

An integer to describe 6 meters above the sea level would be  meters.

As per the question statement, We are supposed to use an integer to describe the following situation "6 meters above sea level".

We assume that sea level is the datum line and anything above that would be positive and below that would be negative.

So 6 meters above the sea level can be described as .

Integers: Set of whole number containing both positive and negative values of it.

PLS MARK BRAINLIEST

Step-by-step explanation:

The ratio of the perimeters is 14/5, which simplifies to 70/25, which reduces to 14/5. So the answer is (d) 5/7.

Let's use the fact that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding side lengths. If we let the corresponding side lengths be a and b, then we have:

(area of first triangle)/(area of second triangle) = (a^2)/(b^2)

We are given that the areas of the two triangles are 50 cm^2 and 98 cm^2, respectively. Let's call the side lengths of the first triangle a1, a2, and a3, and the side lengths of the second triangle b1, b2, and b3. Then we have:

(50)/(98) = (a1a2)/(b1b2)

We don't know the actual values of a1, a2, b1, and b2, but we can find the ratio of their perimeters by adding up the side lengths of each triangle. Let's call the perimeters of the first and second triangles P1 and P2, respectively. Then we have:

P1 = a1 + a2 + a3

P2 = b1 + b2 + b3

Dividing P1 by P2, we get:

P1/P2 = (a1 + a2 + a3)/(b1 + b2 + b3)

We can rewrite the ratios of the side lengths using the equation we found earlier:

P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = [(a1a2)/(b1b2)]*1

P1/P2 = (a1a2)/(b1b2)

We still don't know the values of a1, a2, b1, and b2, but we can eliminate them by using the equation we found earlier:

(50)/(98) = (a1a2)/(b1b2)

Simplifying this expression, we get:

(a1/a2) = sqrt((98/50)*(b1/b2))

We can use this to substitute for one of the ratios of side lengths in the equation for P1/P2:

P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = [sqrt((98/50)(b1/b2))][(a1 + a2 + a3)/(a1 + a2 + a3)]

P1/P2 = sqrt((98/50)*(b1/b2))

Now we can substitute the given values to get:

P1/P2 = sqrt((98/50)(b1/b2)) = sqrt((98/50)(2/1)) = sqrt(196/50) = 14/5

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There may be a difference on speed based on various factors

Though it would be reasonable to conclude that if it takes less time for a car to move 50 centimeters than 150 centimeters, they must be traveling faster; we do not know exactly when they did this and whether their speed changed accordingly.

Furthermore, it could have taken the same time covering both distances; thus leaving unanswered questions regarding their relative speeds.

Due to variables affecting car speed such as changes in terrain or obstacles in its path, we cannot accurately predict its speed without more information regarding these two runs.

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we need to find two numbers whose product is 110. Possible combinations include L = 10 feet and W = 11 feet or L = 11 feet and W = 10 feet. Therefore, the dimensions of the brick wall can be either 10 feet by 11 feet or 11 feet by 10 feet.

A brick wall can be shaped like a rectangular prism, and in this case, the wall needs to be 3 feet tall. With the builder having enough bricks for the wall to have a volume of 330 cubic feet, we can calculate the area of the base of the wall.

To find the base area, we can use the formula for the volume of a rectangular prism: Volume = Base Area × Height. In this situation, we know the volume (330 cubic feet) and the height (3 feet), so we can solve for the base area.

330 cubic feet = Base Area × 3 feet
Dividing both sides of the equation by 3, we get:
Base Area = 110 square feet

So, the base area of the brick wall that is shaped like a rectangular prism with a height of 3 feet and a volume of 330 cubic feet will be 110 square feet.

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Answer:
-Reflection across line p followed by 240 clockwise rotation about point T.

-Reflection across line r.

-120 counterclockwise rotation about point T.

Step-by-step explanation:

All these transformations map the triangle onto itself.

The length of the hypotenuse of the right triangle is 15 cm.

The Pythagorean Theorem states that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the hypotenuse. Using this formula, we can calculate the length of the hypotenuse of a right triangle.

Given that the longer sides of the right triangle are 9 cm and 12 cm long, we can assume that one of these sides is the shorter side and the other is the longer side. Let's assume that the shorter side is 9 cm long and the longer side is 12 cm long.

Using the Pythagorean Theorem, we can calculate the length of the hypotenuse as follows:

Hypotenuse² = Shorter side² + Longer side²

Hypotenuse² = 9² + 12²

Hypotenuse² = 81 + 144

Hypotenuse² = 225

Taking the square root of both sides, we get:

Hypotenuse = √225

Hypotenuse = 15

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Answer:

Step-by-step explanation:

There are 12 possible cards you can choose.

There are 3 possible results for the spinner.

There are 2 possible results for the coin toss.

When doing all 3 events:

      Total possibilities [tex]=12\times 3 \times 2=72.[/tex]

SOLUTION:   72

Cloud storage is the storage option that has the ability to update itself regularly.

Unlike internal hard drives and flash drives, which require manual updates and data transfers, cloud storage services automatically synchronize and update your files across multiple devices. This feature ensures that you always have access to the most recent version of your data, without needing to perform manual updates.

Cloud storage services operate on remote servers managed by service providers, allowing users to store, share, and access their data from any device with internet access. This not only provides convenience but also offers enhanced data security and protection against data loss due to hardware failure or damage.

On the other hand, internal hard drives and flash drives are physical storage devices that store data locally. While they offer a certain level of convenience and portability, they lack the ability to automatically update or sync across multiple devices, making them less versatile compared to cloud storage.

In summary, cloud storage is the storage option with the ability to update itself regularly, providing users with convenience, enhanced security, and the ability to access their data from multiple devices. Meanwhile, internal hard drives and flash drives require manual updates and are limited in their capacity to sync data across devices.

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To find f-1(6), we need to find the value of x that gives f(x) = 6. However, we don't have enough information about the function f to do this. We need to know whether f is a linear function or not.

When the function and its inverse intersect, we have f(x) = f-1(x). Substituting y for both f(x) and f-1(x), we get y = f(y). To find the value of y when this is true, we need to solve for y:
y = f(y)
y = f-1(y)
Substituting y = f(x), we get:
f(x) = f-1(f(x))
f(x) = x

So the function and its inverse intersect when y = x.
If a = 0, then the linear function is f(x) = b, which is a constant function. Constant functions do not have inverses, so the inverse of f(x) = b does not exist.

If a ≠ 0, then the inverse of f(x) = ax + b is given by:
f-'(x) = (x - b) / a
This is also a linear function, so the inverse of a linear function is always a linear function when a ≠ 0.
(a) To find the inverse of a linear function, you need to swap the x and y values. Given that f(4) = 6, the inverse function f^(-1)(6) would yield the value of x when y = 6. Since we know that f(4) = 6, it implies that f^(-1)(6) = 4.
A function and its inverse intersect when the input value (x) is equal to the output value (y). In other words, they intersect when y = x.

(c) Yes, the inverse of a linear function is always a linear function. If f(x) = ax + b, where a ≠ 0, then the inverse function, f^(-1)(x), can be found by swapping x and y values and solving for y. In this case, x = ay + b. Solving for y, we get y = (x - b) / a, which is also a linear function.

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The Surface Area of the sphere is approximately 339.79 square inches.

The surface area of a sphere is given by the formula:

surface area= [tex]4\pi r^{2}[/tex]

where r is the radius of the sphere.

The diameter of the sphere measures 10.4 inches, hence the radius can be calculated as:

r=10.4/2=5.2inches

Hence, the surface area can be calculated as by substituting r=5.2 inches

Therefore, surface area of the sphere is:

Surface Area = [tex]4\pi (5.2)^{2}[/tex]=[tex]4\pi (27.04)[/tex]= 108.16[tex]\pi[/tex] square inches.

So, the Surface Area of the sphere is approximately 339.79 square inches(if we use [tex]\pi[/tex]=3.14 as an approximation)

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Note that where the above statistics are give, the p-value is 0.04.

1st , we calculate the differences between the number of citations given in the day shift and afternoon shift for each day

Differences -  0, 6, 4, 6

The mean difference is  (m)  = (0 + 6 + 4 + 6) / 4 = 4

The sample standard deviation of the differences is    s = √ ([((0-4)² + (6-4)² + (4-4)² + (6-4)²)/3]) = 2.31

The standard error of the mean difference is  SE(m) = s / √(n) = 2.31 / √(4) = 1.155

The t-statistic is  t = (m - 0) / SE(m) = 4 / 1.155 = 3.4632034632

The paired t-test has n-1=3 degrees of freedom. We calcu0late the p-value associated with a t-statistic of 3.46 using a t-table or a t-distribution calculator with three degrees of freedom.

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The length of CB is 3 unit.

In the given figure ;

By SAS property of similar of triangles,

ΔCED and ΔCAB are similar.

Therefore,

CE/CB = DE/AB = DC/AC

⇒ CE/CB = DC/AC

⇒ 2/CB = 2.4/3.6

⇒ CB = (3.6/2.4)X2 = 3

Hence CB = 3

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