Answer:
rotation
Explanation:
The seasons of the year result from Earths movement, or rotation around the sun. The answer for the blanks is rotation .
What is the earth's orbit?The Earth orbits the Sun in a counterclockwise pattern above the Northern Hemisphere at an average distance of 149.60 million km.
The Earth revolves around its axis once every 24 hours and orbits the sun once every 365 days. The Earth's rotation on its axis, not its orbit around the sun, causes day and night.
The term 'one day' refers to the time it takes the Earth to rotate once on its axis, which includes both day and night.
A season is a division of the year that is based on variations in weather, ecology, and the number of daylight hours in a certain place.
Seasons on Earth are caused by Earth's orbit around the Sun and its axial tilt relative to the ecliptic plane.
The seasons of the year result from Earths movement, or rotation around the sun.
Hence, the answer for the blanks is rotation .
To learn more about the earth's orbit, refer to the link;
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Which of the following is a form of kinetic energy?
A. Electrical energy
B. Potential energy
C. Sound energy
D. Nuclear energy
HELP URGENT
Answer:
Electrical energy ⚡ Hope this helps you Stay happy and safe Do mark as brainliest ✌️Answer:
Potential Energy. It's wrong but it was worth a try
An 10.2-kg stone at the end of a steel (Young's modulus 2.0 x 10^11 N/m2) wire is being whirled in a circle at a constant tangential
speed of 11.6 m/s. The stone is moving on the surface of a frictionless horizontal table. The wire is 3.62 m long and has a radius of
4.10 x 10^-3m. Find the strain in the wire.
Answer:
[tex]3.6\times 10^{-5}[/tex]
Explanation:
m = Mass of stone = 10.2 kg
v = Tangential velocity = 11.6 m/s
l = Length of wire = 3.62 m
r = Radius of wire = [tex]4.1\times 10^{-3}\ \text{m}[/tex]
A = Area of wire = [tex]\pi r^2[/tex]
Y = Young's modulus of steel = [tex]2\times 10^{11}\ \text{N/m}^2[/tex]
[tex]\varepsillon[/tex] = Strain
The force acting on the stone will be centripetal
[tex]F=\dfrac{mv^2}{l}\\\Rightarrow F=\dfrac{10.2\times 11.6^2}{3.62}\\\Rightarrow F=379.15\ \text{N}[/tex]
Stress is given by
[tex]\sigma=\dfrac{F}{A}\\\Rightarrow \sigma=\dfrac{379.15}{\pi (4.1\times 10^{-3})^2}\\\Rightarrow \sigma=7179488\ \text{N/m}^2[/tex]
Young's modulus is given by
[tex]Y=\dfrac{\sigma}{\varepsilon}\\\Rightarrow \varepsilon=\dfrac{\sigma}{Y}\\\Rightarrow \varepsilon=\dfrac{7179488}{2\times 10^{11}}\\\Rightarrow \varepsilon=3.6\times 10^{-5}[/tex]
Strain in the wire is [tex]3.6\times 10^{-5}[/tex].
What is the direction of the magnetic field if an electron moving in the positive x direction experiences a magnetic force in the positive z direction
Given :
An electron moving in the positive x direction experiences a magnetic force in the positive z direction.
To Find :
The direction of the magnetic field.
Solution :
We know, force is given by :
[tex]\vec{F}=q(\vec{v}\times \vec{B)}[/tex]
Here, q = -e.
[tex]\vec{F}=(-e)(\vec{v}\times \vec{B)}\\\\\hat{k}=(-e)(\hat{i}\times \vec{B})[/tex]
Now, for above condition to satisfy :
[tex]\hat{i}\times \vec{B}=-\hat{k}[/tex]
So, [tex]\vec{B}=-\hat{j}[/tex]
Therefore, direction of magnetic field is negative y direction.
Hence, this is the required solution.
A trebuchet launches a pumpkin at an angle of 63 degrees at an initial velocity of 51 m/ s from the ground. What is the range of the pumpkin?
Answer:
214.72m
Explanation:
The range (R) of a projectile can be calculated using the formula:
R = u²sin2θ/g
Where R = Horizontal range
u = initial velocity
θ = angle of initial velocity
g = acceleration due to gravity (9.8m/s²)
According to the provided information in this question, R= ?, u= 51m/s, θ = 63°, g = 9.8m/s².
Hence, R = u²sin2θ/g
R = 51² × sin 2×63/ 9.8
R = 2601 × sin 126/9.8
R = 2601 × 0.809/9.8
R = 2104.25/9.8
R = 214.72m
"NEED HELP FAST" Which of the following is a vector quantity?
A. Time
B. Velocity
C. Temperature
D. Distance
Answer:
the answer is b. b velocity. remember v=v
Given a force of 10 N and an acceleration of 5 m/s2, what is the mass?
Answer:
2kg
Explanation:
i think i found it yous welcom
Help please it’s urgent
Answer:
Q. No 1, true
Explanation:
Direct current is flow of current
Not sure about it
Sorry if it's wrong
PLS ANSWER WILL MARK BRANLIEST!!!!!!!!!!!!
Describe the life cycle of a star before it collapses into a black hole.
Describe the life cycle of a star before it becomes a black dwarf.
What is the likely outcome of our sun? *
The sun will supernova and become a black hole.
The sun will swell, encompassing the inner planets and collapses into a dwarf star.
The sun will become a pulsar.
How Do You Know?
P.S. the how do you know is only for the last question
1) describe the life cycle of a star before it collapses into a black hole.
1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.
2) describe the life cycle of a star before it becomes a dwarf.
ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.
3) what is the likely outcome of our sun?
ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.
Omar observes that many buildings in his city were built using limestone. He has read that acid rain can damage limestone. He also knows that limestone reacts with acids and that chemical reactions are affected by temperature. With this in mind, he conducts an investigation to see how the amount of damage to the limestone is affected by the amount of acid on the stone.
Which statement describes the correct plan for his procedure?Rhonda watched a video taken by a camera that was lifted into the upper atmosphere by a weather balloon. She saw the balloon pop when it reached a certain height. Afterward, Rhonda wondered what effect the air pressure at high altitudes has on the volume of gas in balloons.
What scientific practice is Rhonda performing
Answer:he conducts the investigation to see the effect acidic water has on limestone
Explanation:
For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same. Describe how they are different.
Answer:
he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
Explanation:
In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values where some natural frequency of the system coincides with the excitation frequency.
In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.
From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
It takes 525 J of work to compress a spring 25 cm. What is the force constant of the spring (in kN/m)?
Answer:
1.680kN/m
Explanation:
Work done by the spring is expressed as shown:
[tex]W = \frac{1}{2}ke^2[/tex] where:
k is the spring constant
e is the extension
Given
W = 525Joules
extension = 25cm = 0.25m
Substitute into the formula:
[tex]525 = \frac{1}{2}k(0.25)^{2} \\525 = \frac{0.0625k}{2}\\ 525 = 0.03125k\\k = \frac{525}{0.3125}\\k = 1680N/m\\k = 1.680kN/m[/tex]
Hence the force constant of the spring is 1.680kN/m
Are any of the forces acting on the freezer
unbalanced?
Answer: put them in the microwave
Explanation:
Using component notation, enter the vector B⃗ B→B_vec in the answer box. Enter your answer as a pair of vector components, separated by a comma. You should not enter any parentheses.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]\vec B = 2, -3[/tex]
Explanation:
Looking at the graph in the diagram we see each unit is equal to 1 both in the x axis and in the y- axis
Now the value of B along the x axis is
[tex]B_x = 2[/tex]
and along the y axis the value is
[tex]B_y = -3[/tex]
Hence the vector B is
[tex]\vec B =(B_x , B_y)= ( 2, -3)[/tex]
Sheldon and Penny are sitting in the back seat of a car that is moving in the x-direction with avelocity of 20 m/s. Sheldon makes a snide remark and Penny responds by throwing the cap ofher soda bottle at him with a velocity of 11 m/s (in what we'll call the y-direction) in theirreference frame. From the point of view of someone standing alongside the road, the speed ofthat cap would be closest to:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is E
Explanation:
From the question we are told that
The velocity in the x direction is [tex]v_x = 20 \ m/s[/tex]
The velocity of the cap of the soda bottle in the y direction is [tex]v_y = 11 \ m/s[/tex]
Gnerally the speed of the cap as seen by the observer is mathematically represented as
[tex]v_c = \sqrt{v_x^2 + v_y^2}[/tex]
=> [tex]v_c = \sqrt{ 20^2 + 11^2}[/tex]
=> [tex]v_c = 22.83 \ m/s [/tex]
=> [tex]v_c = 23 \ m/s [/tex]
what is the force produced on a body of 30kg mass when a body moving with the velocity of 26km/hr is acceleted to gain the velocity of 54 km/hr in 4 sec
Answer:
F = 58.35 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration. But first we must use the following equation of kinematics.
We have to convert speeds from kilometers per hour to meters per second
[tex]\frac{26km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=\frac{7.22m}{s} \\\frac{54km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=15\frac{m}{s}[/tex]
[tex]v_{f}=v_{o}+(a*t) \\[/tex]
where:
Vf = final velocity = 15 [m/s]
Vi = initial velocity = 7.22 [m/s]
a = acceleration [m/s^2]
t = time = 4 [s]
Note: the positive sign of the above equation is because the car increases its speed
15 = 7.22 + (a*4)
a = 1.945 [m/s^2]
Now we can use the Newton's second law:
F = m*a
F = 30*1.945
F = 58.35 [N]
I need help with this answer
decomposition
A decomposition reaction is just the opposite of combination reaction
When making a budget, you should prioritize ___________ before "__________." A. Needs/wants B. Wants/needs C. Electricity/Water D. Healthcare/Housing
Answer A
Explanation: because u need to make sure you know the difference between a need and a want
Answer:
a
Explanation:
PLEASE PROVIDE EXPLANATIONS.
THANK YOU!!!
Answer:
3.27 m
3.23 rad/s
Explanation:
There are external forces on the sphere, so momentum is not conserved, but energy is conserved.
Initial KE + Initial RE = Final PE
½ Mv² + ½ Iω² = Mgh
½ Mv² + ½ (⅖ MR²) ω² = Mgh
½ Mv² + ⅕ MR²ω² = Mgh
5v² + 2R²ω² = 10gh
For rolling without slipping, ωR = v.
5v² + 2v² = 10gh
7v² = 10gh
h = 0.7 v² / g
h = 0.7 (3.90 m/s)² / (10 m/s²)
h = 1.0647 m
Use trig to find the distance along the ramp:
sin 19.0° = h / d
d = h / sin 19.0°
d = 3.27 m
The clay sticks to the turntable, so this is an inelastic collision. Kinetic energy is not conserved, but angular momentum is conserved.
L₀ = L
I₀ ω₀ = I ω
(½ MR²) ω₀ = (½ MR² + mr²) ω
MR²ω₀ = (MR² + 2mr²) ω
ω = MR²ω₀ / (MR² + 2mr²)
ω = (0.190) (0.200)² (4.00) / (0.190 (0.200)² + 2 (0.040) (0.150)²)
ω = 3.23 rad/s
A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted:
Complete Question
A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted,
A :
a force repels the glass out of the capacitor.
B :
a force attracts the glass into the capacitor.
C :
no force acts on the glass.
D :
a net charge appears on the glass.
E :
the glass makes the plates repel each other.
Answer:
The correct option is B
Explanation:
Generally when the glass dielectric is slowly inserted between the plated,
The positive plate of the capacitor will induce a negative charge on the glass while the negative plate of the capacitor will induce a positive charge on glass which a electric field that posses an electric force that will attract the glass
B: a force attracts the glass into the capacitor.
A parallel-plate capacitor, with the air dielectric, is charged from a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates.
How is a dielectric slab inserted in a capacitor?
The dielectric slab is slowly inserted between the plates to a parallel plate capacitor while the capacitor is connected with a battery. As it is being inserted: 57. A parallel-plate capacitor, with air dielectric, is charged by the battery, after which the battery is the disconnected. A slab of glass dielectric is then slowly inserted between the plates. A parallel-plate capacitor, with the air dielectric, is charged from a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates.
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Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that of B is:_______
a. 1:9
b. 1:3
c. 1:1
d. 3:1
e. 9:1
2. A boy walks 3 miles north then turns around and walks on the same path
south for 2.1 miles. What is the boy's displacement?
Answer:
.9
Explanation:
3-2.1=.9
Determine the accelerations that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object.
ans: 4m/s²
and 2m/s²
step:
f=m.a
in first condition
f=12N , M=3kg
so,
12=3.a
a=12/3
a=4m/s².
similarly
in second condition
f=12N ,M=6Kg
so,
12=a.6
a=12/6
a=2m/s²
What are the four basics for knowledge called "innate knowledge"?
Answer: The four basics of innate knowledge are as follows:
Explanation:
1. This knowledge is learned from birth and it is inborn knowledge. It is allows the organism to act naturally. For example, a dog is not taught to pant, but it pants to reduce heat from the body.
2. It is inherent.
3. It is essential for survival.
4. It arises from intellectual knowledge rather than being learned via experiences.
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting, the current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V. When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V.
A. Find the battery's EMF.
B. What is its internal resistance?
Answer:
EMF = 11.35 V
R = 0.031Ω
Explanation:
To find the battery's EMF and the internal resistance we need to use Ohm's law:
[tex] V = IR [/tex]
Where:
V: is the voltage
I: is the current
R is the resistance
We have:
The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:
[tex] \epsilon = V + IR [/tex]
[tex] \epsilon = 9.36 V + 64.2A*R [/tex] (1)
When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:
[tex] \epsilon = 11.3 V + 1.96A*R [/tex] (2)
By solving equation (1) and (2) for R we have:
[tex] 9.36 V + 64.2A*R = 11.3 V + 1.96A*R [/tex]
[tex]R = \frac{1.94 V}{62.24A} = 0.031 \Omega[/tex]
Hence, the internal resistance is 0.031 Ω.
Now, by entering R into equation (1) we can find the battery's EMF:
[tex]\epsilon = 9.36 V + 64.2A*0.031 \Omega[/tex]
[tex] \epsilon = 11.35 V [/tex]
Therefore, the battery's EMF is 11.35 V.
I hope it helps you!
1. A 5.00 kg box is being pulled at constant speed up a 30o incline by a force of 45.0 N parallel to the incline. Determine the coefficient of kinetic friction between the box and the plane.
Answer:
μ = 0.48
Explanation:
To solve this problem we must make a free body diagram locating each of the respective forces on the boxes.
We must pay special attention that the body is moving at a constant speed, therefore there is no acceleration, and the sum of forces is equal to zero.
Attached is an image with the sum of forces and the equations of the sum of forces on the x & y axes.
The solution of all equations can be seen, in the attached image.
When a stretched rubber band snaps back it has increase
thermal energy.
potential energy.
kinetic energy.
elastic energy.
Answer:
Kinetic
Explanation:
Because it has a force pushing on it
There are two unitless vectors:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
A third vector is added to them such that they add up to to the null vector:
F1 + F2 + F3 = 0
What is the angle of the third vector with respect to the +x-axis?
Answer:
[tex]200.38^0[/tex]
Explanation:
Given the forces:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0
then to get F3:
F3 = -F2-F1
F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )
F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j
F3 = -8.31i-8.92i+10.97j-17.37j
F3 = -17.23i-6.4j
from the vector:
x = -17.23 and y = -6.4
angle of the third vector with respect to the +x-axis is expressed as:
[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]
Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]
An electric bulb rated 100 W, 100 V has to be
operated aross 141.4 V, 50 Hz A.C. supply. The
capacitance of the capacitor which has to be
connected in series with bulb so that bulb will
glow with full intensity is [NCERT Pg. 251]
Answer:
The capacitance of the capacitor is 31.84 μF.
Explanation:
Given;
power rating of the bulb, P = 100 W
voltage rating of the bulb, Vr = 100 V
operating voltage of the bulb, V= 141.4 V
frequency of the AC = 50 Hz
P = IV = 100 W
V = 100 V
I =
Ic = 1 A
The voltage across the capacitor is given by;
[tex]V_c = \sqrt{V^2 - V_R^2} \\\\V_c = \sqrt{141.4^2 - 100^2} \\\\V_c =99.97 \ V[/tex]
[tex]V_c = I_cX_c\\\\V_c = I_C* \frac{1}{2\pi fC}\\\\ 99.97 = 1 * \frac{1}{2\pi *50 *C}\\\\ C=\frac{1}{2\pi *50*99.97}\\\\ C = 31.84*10^{-6} \ F\\\\C = 31.84 \ \mu F[/tex]
Therefore, the capacitance of the capacitor is 31.84 μF.
If the shoe has less mass, it will experience _______________ (more, less, the same) friction as it would with more mass.
According to the nebular theory of solar system formation, what key difference in their early formation explains why the jovian planets ended up so different from the terrestrial planets
Answer:
The Jovian planets formed beyond the Frostline while the terrestrial planets formed in the Frostline in the solar nebular
Explanation:
The Jovian planets are the large planets namely Saturn, Jupiter, Uranus, and Neptune. The terrestrial planets include the Earth, Mercury, Mars, and Venus. According to the nebular theory of solar system formation, the terrestrial planets were formed from silicates and metals. They also had high boiling points which made it possible for them to be located very close to the sun.
The Jovian planets formed beyond the Frostline. This is an area that can support the planets that were made up of icy elements. The large size of the Jovian planets is as a result of the fact that the icy elements were more in number than the metal components of the terrestrial planets.
