The scale on a map is 1 : 25000
How many kilometres on the ground is represented by 7 cm on the map?

Step-by-step explanation:

i hope this is helpful!........

Answer:

3t

Step-by-step explanation:

The algebraic expression to show the number of tomatoes Tye planted this year is 3t

From the first statement given in the question, we were told that:

From the above statement, we can write the algebraic expression to show the number of tomatoes Tye planted this year. This is shown below:

Number of tomatoes planted this year = 3 × Number of tomatoes planted last year

= 3t

Thus, from the above illustration we can say that the algebraic expression is 3t

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Answer:

  (b)  8.9 m

Step-by-step explanation:

The mirror ensures that angle 1 is congruent to angle 2, so the triangles in the diagram are similar. The ratios of height to mirror distance are proportional.

__

The height of the object is proportional to its distance from the mirror, so we have ...

  (tree height)/(tree-to-mirror) = (person height)/(person-to-mirror)

  (tree height)/(2.5 m) = (1.78 m)/(0.5 m)

Multiplying this proportion by 2.5 m, we find ...

  tree height = (2.5 m)(1.78/0.5) = 8.9 m

The height of the palm tree is 8.9 meters.

Answer:

d

By the alternate interior angles theorem,

By the reflexive property, AB is congruent to itself.

Thus, the triangles will be congruent by ASA.

The length of arc for the options 1,2,3 and 4 willl be 60.39,61.23,10.4 and 7.851 respectively.

An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).

As a result, when measuring angles in radians,

The length of the arc is:

[tex]\rm l = r \theta[/tex]

Unit conversions;

1 π = 180°

1° = 180/π

315°= 5.49 rad

270° = 4.71 rad

60° = 1.04 rad

150°=2.617 rad

The measure of the length of arc for the given radius;

[tex]\rm L_1 = R_1 \theta \\\\ L_1 = 1 \times 5.49 \\\\\ L_1 = 60.39 \\\\ L_2 = 13 \times 4.71 \\\\ L_2 = 61.23 \\\\ L_3 = 10 \times 1.04 \\\\ L_4 = 10.4 \\\\ L_4 = 3 \times 2.617 \\\\ L_4 = 7.851[/tex]

The length of arc for the options1,2,3 and  4 willl be  60.39,61.23,10.4 and 7.851 respectively.

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Answer:

[tex]3x^3 + 4x^2 -3x + 2[/tex]

Step-by-step explanation:

The area of the swimming pool will be equal to [tex]length * width[/tex].

We know that the length is [tex]3x^2-2x+1[/tex] and the width is [tex]x+2[/tex].

Therefore we can substitute those into the equation:

[tex](3x^2-2x+1)(x+2)\\[/tex]

Then, we expand the brackets using a grid (attached).

After this, we collect like terms to find the final answer:

[tex]3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2[/tex]

Our final answer is: [tex]3x^3 + 4x^2 -3x + 2[/tex]

Answer:

added in picture

Step-by-step explanation:

added in picture

Answer:

$71,744.53

Step-by-step explanation:

The earnings triple every day, so you can calculate them for the 15 days. For the total, you also have to add them up.

See the calculations in below picture.

A consistent and independent system of equations describes the given system of equations.

The consistent and independent system of equations are given below.

A consistent equation is a system of linear equations that is consistently unbiased when it has precisely one solution. While this is the case, the graphs of the lines within the system move at exactly one point. In inconsistent, a system of linear equations is inconsistent if it has no solutions.

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Solution: x=2 ✅

[tex]\searrow[/tex]

⚜Detailed explanation: ⚜

In this problem we need to solve for x, the unknown.

First, note that the terms 2x and 5x have an x in them, so why not add them and make life easier?

[tex]---\mapsto\boldsymbol{2x+5x=14}\\\\---\mapsto\boldsymbol{7x=14}[/tex]

We're getting closer! Now we know that if we multiply 7 times the unknown, we'll get 14. So let's divide both sides by 7! Then we will have the value of the unknown.

[tex]---\mapsto\boldsymbol{x=2}[/tex] is what we obtain upon dividing

Superb, it's ez as winking!

_________________________________________

Voila! There's our solution!

Hope I helped! Best wishes!

Reach far. Aim high. Dream big.

____________________________________________

Answer:

4x82x929wjdjdejdjekke

[tex] \frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9 } \\ \frac{(x + 3 ) + (x + 2)}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ \frac{2x + 5}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ 2( {x}^{2} + 5x + 6) = (x + 9)(2x + 5) \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 5x + 18x + 45 \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 23x + 45 \\ 2 {x}^{2} - 2 {x}^{2} + 10x - 23x + 12 - 45 = 0 \\ - 13x - 33 = 0 \\ - 13x = 33 \\ x = \frac{33}{ - 13} \\ x = - 2.54[/tex]

Hope it helps

Please give brainliest

Answer:

A

Step-by-step explanation:

64

The unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

The question is incomplete.

The complete question is:

The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown. What is the greatest possible whole-number value of the congruent side lengths?

9 cm

10 cm

14 cm

15 cm

We have:

The longest side of an isosceles obtuse triangle measures 20 centimeters.

Let's assume the unknown side length is x:

In the isosceles obtuse triangle, two sides are congruent.

As we know the sum of the two sides in a triangle is greater than the third side length:

x + x > 20

2x > 20

x > 10

a² + b² < c²

14 will satisfy the above two inequaility.

Thus, the unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.

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A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

Answer:

a = 2.36

Step-by-step explanation:

a-(-3.75)=6.11

The negative 3.75 is being subtracted from the 'a'. A negative number being subtracted from another number makes it positive. So, 3.75 is actually being added to 'a' which is equal to 6.11

I re-wrote the question as:

a + 3.75 = 6.11

Subtract 3.75 from both sides to leave 'a' by itself

a + 3.75 = 6.11

   -3.75    -3.75

a = 2.36

Answer:

Domain: All real numbers

Range: y≤4

Answer:

4/9 miles

Step-by-step explanation:

                 [tex]\sf Area = \dfrac{2}{3} \ square \ miles\\[/tex]

               [tex]\sf length = 1\dfrac{1}{2}=\dfrac{3}{2} \ miles[/tex]

[tex]\sf Width \ of \ rectangle = \dfrac{Area}{length}[/tex]

                             [tex]\sf = \dfrac{2}{3} \div \ \dfrac{3}{2}\\\\ =\dfrac{2}{3}*\dfrac{2}{3}\\\\ =\dfrac{4}{9} \ miles\\[/tex]

Use KCF method for faction division.

K- Keep the first fraction.

C - Change the division to multiplication.

F - Flip the second fraction.

The statements that would complete the proof where ∠2 ≅ ∠7 by the transitive property are:

∠2 ≅ ∠3

∠3 ≅ ∠7

The transitive property states that if x = y, and y = z, then x = z.

From the image given below, we have:

∠2 ≅ ∠3 because they are vertical angles which must be congruent.

∠3 ≅ ∠7 because corresponding angles are congruent.

Applying the transitive property, we can state that: ∠2 ≅ ∠7.

Therefore, the statements that would complete the proof are:

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The true statements are:

The lines are given as:

Lines mn, pq, mp, mn, nq and pq

From the question, the lines are either parallel lines or perpendicular lines

As a general rule,

Parallel lines have equal slope

This means that:

Lines mn and pq have the same slope

Assume two perpendicular lines have slopes m and n.

The relationship between their slopes is:

m * n = -1

This means that:

The product of the slopes of perpendicular lines mn and mp is -1

Hence, the true statements are (a) and (c)

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Complete question

Line mn is parallel to line pq, mp is perpendicular to mn, and nq is perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer.

Pptions:

A will have a value of 2. The value of A is found by the substitutional equation system.

A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.

The given equation in the problem is;

Equation 1: [tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24}[/tex]

Equation 2: [tex]x+7y=8[/tex]

Rearrange equation 2 as;

x=8-7y

Substitute the value of x;

[tex]\rm \frac{3}{8} + \frac{1}{3} y= \frac{17}{24} \\\\ \frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24} \\\\ \frac{-21}{8} y+\frac{1}{3} = \frac{17}{24}-3 \\\\ \frac{-63y+8y}{24}=\frac{17-72}{24}\\\\ \frac{-55 \ y}{24} = - \frac{55}{24}\\\\ y= 1[/tex]

Substitute the value of y in equation 2 as;

x+7y=8

x+7(1)+8

x=8-7

x=1

The system of equations by substitution obtained the value of A is;

x + y = A

1+1=A

A=2

Hence the value of A will be 2.

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C. y= |x-5|

you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.

Answer:

1/5

Step-by-step explanation:

2 units divided into 5 marks each = 10 marks

2/10 = 1/5 unit each mark

The y-intercept of the line is (0 -6). The given function has no vertical and horizontal asymptotes

A linear equation is an equation that has a leading degree of 1. Given the equation

g(x) = 4x - 6

The y-intercept occurs at a point where x = 0

g(0) = 4(0) - 6

g(0) = -6

Hence the y-intercept of the line is (0 -6)

The given function has no vertical and horizontal asymptotes

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Answer:

Step-by-step explanation:

Write 5.54 million in ordinary form

5.54 * [tex]10^{6}[/tex] =

5540000

or

5.54 * 1000000 =

5540000

Answer:

6

Step-by-step explanation:

Mean no. of runs per game =

= Total no. of runs/ total no. of games

= 9+8+4+0+7+6+4+5+9+8 / 10

= 60 / 10

= 6

Answer:

21.5

Step-by-step explanation:

break the shape down to make two shapes: a triangle and rectangle.
triangle = A=bxh/2

3x5=15/2=7.5

Rectangle = A=bxh

2x7=14

7.5+14= 21.5

Hope this helps :)

Answer:

21.5

Step-by-step explanation:

(all steps provided in image attached)

The function is shown to be positive throughout the whole range [-3, -2] in graph (B).

According to the question,

Looking at the graph, we can see that the graph B has positive y-values in the range [-3, -2].

Hence The function is shown to be positive throughout the whole range [-3, -2] in graph (B).

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Part 1

Using the distance formula,

[tex]AB=\sqrt{(-2-1)^{2}+(2-7)^{2}}=\sqrt{34}\\\\BC=\sqrt{(-2-4)^{2}+(2-2)^{2}}=6\\\\AC=\sqrt{(1-4)^{2}+(7-2)^{2}}=\sqrt{34}[/tex]

So, the measure of the longest side is 6 units.

Part 2

Triangle ABD will have vertices A(1,7), B(-2, 2), and D(1,2).

We already know that [tex]AB=\sqrt{34}[/tex]

Using the distance formula,

[tex]AD=\sqrt{(1-1)^{2}+(7-2)^{2}}=5\\\\BD=\sqrt{(-2-1)^{2}+(2-2)^{2}}=3[/tex]

So, ABD is a scalene triangle.

Part 3

From part 2, we know that the length of side AD is 5 units.

Placing the equations under the correct solution, we get

x = 3                                      x ≠ 3

-14x = -42                              -5 + x = -9

[tex]-\frac{3}{5} +x = \frac{12}{5}[/tex]                          [tex]\frac{x}{3} =9[/tex]

[tex]\frac{x}{4} =\frac{6}{8}[/tex]                                    

x -5 = -2            

From the question, we are to place the equations under the correct solution

To do this, we will solve the equations one after the other

x = -42/-14

x = 3

x = -9 + 5

x = -4

∴ x ≠ 3

[tex]x = \frac{12}{5} +\frac{3}{5}[/tex]

[tex]x = \frac{12+3}{5}[/tex]

[tex]x = \frac{15}{5}[/tex]

x = 3

[tex]x=\frac{6\times 4}{8}[/tex]

[tex]x=\frac{24}{8}[/tex]

x = 3

x = 3 × 9

x = 27

∴ x ≠ 3

x = -2 + 5

x = 3

Hence, placing the equations under the correct solution, we get

x = 3                                      x ≠ 3

-14x = -42                              -5 + x = -9

[tex]-\frac{3}{5} +x = \frac{12}{5}[/tex]                          [tex]\frac{x}{3} =9[/tex]

[tex]\frac{x}{4} =\frac{6}{8}[/tex]                                    

x -5 = -2            

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