the roots of the equation, px^2 - 6qx - (9p - 10q) = 0 are 2 ⴛ - 3 and 2β – 3, find the equation whose roots are ⴛ and β​

Answers

Answer 1

Step-by-step explanation:

Solution :-

Given quadratic equation is

px²-6qx-(9p-10q) = 0

On comparing with the standard quadratic equation ax²+bx+c = 0

a = p

b = -6q

c = -(9p-10q) = -9p+10q

Given roots of the equation = 2 Ⴛ - 3 and

2 Ⴛ - 3 and 2β – 3

We know that

Sum of the roots = -b/a

=> 2 Ⴛ - 3 + 2β – 3 = -(-6q)/p

=> 2 Ⴛ + 2β - 6 = 6q/p

=> 2 Ⴛ + 2β = (6q/p)-6

=> 2 Ⴛ + 2β = (6q-6p)/p

=> 2(Ⴛ + β) = (6q-6p)/p

=> Ⴛ + β = (6q-6p)/(2p)

=> Ⴛ + β = 2(3q-3p)/(2p)

=> Ⴛ + β = (3q-3p)/p ---------(1)

Product of the roots = c/a

=> (2 Ⴛ - 3 )( 2β – 3) = (-9p+10q)/p

=> 4Ⴛ β-6Ⴛ - 6β+9 = (-9p+10q)/p

=> 4Ⴛ β-6(Ⴛ +β)+9 = (-9p+10q)/p

=> 4Ⴛ β-6[(3q-3p)/p]+9 = (-9p+10q)/p

=> 4Ⴛ β-6[(3q-3p)/p] =[ (-9p+10q)/p]-9

=> 4Ⴛ β-6[(3q-3p)/p] = (-9p+10q-9p)/p

=> 4Ⴛ β-6[(3q-3p)/p] = (-18p+10q)/p

=> 4Ⴛ β =[(-18p+10q)/p]+6[(3q-3p)/p]

=> 4Ⴛ β =[(-18p+10q)/p]+[(18q-18p)/p]

=> 4Ⴛ β =[(-18p+10q)+18q-18p)]/p

=> 4Ⴛ β = (-36p+28q)/p

=> 4Ⴛ β = 4(-9p+7q)/p

=> Ⴛ β = 4(-9p+7q)/4p

=> Ⴛ β = (-9p+7q)/p

=> Ⴛ β = (7q-9p)/p ----------(2)

We know that

The quadratic equation whose roots are Ⴛ and β is x²-(Ⴛ+ β)x +Ⴛ β = 0

=> x²- [ (3q-3p)/p]x + [ (7q-9p)/p] = 0

=> [px²-(3q-3p)x+(7q-9p)]/p = 0

=> [px²-(3q-3p)x+(7q-9p)] = 0×p

=> px²-(3q-3p)x+(7q-9p) = 0

Answer :-

The required quadratic equation is

px²-(3q-3p)x+(7q-9p) = 0

Used Formulae:-The standard quadratic equation is ax²+bx+c = 0The quadratic equation whose roots are Ⴛ and β is x²-(Ⴛ+ β)x +Ⴛ β = 0Sum of the roots = -b/aProduct of the roots = c/a

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Answer:

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Answer:

0.3333

Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Step-by-step explanation:

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Answer:

See below ~

Step-by-step explanation:

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Answer:

Step-by-step explanation:

(0,2), (2,3), (4,4), (6,5), (8,6), (10,7) are the coordinates.

25+(-14)-18 ____ 25+(-14) -(-18) (Fill the blank with > or <)

Answers

Answer:

<

Step-by-step explanation:

25+(-14)-18 --->   25-32=-7
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Which expressions are equivalent to -6+4q+(-6q)−6+4q+(−6q)minus, 6, plus, 4, q, plus, left parenthesis, minus, 6, q, right parenthesis ?

Choose all answers that apply:


(Choice A)


-6(q+1)-4q−6(q+1)−4qminus, 6, left parenthesis, q, plus, 1, right parenthesis, minus, 4, q


(Choice B)


2(q-3)2(q−3)2, left parenthesis, q, minus, 3, right parenthesis


(Choice C)


None of the above

Answers

The expressions equivalent to  -6 + 4q + (-6q) is C. None of the above

Which expressions are equivalent

The expression -6 + 4q + (-6q) can be simplified to -2q - 6,

Evaluating the given options, we have

Option (b); 2(q - 3) = 2q - 6

Option (c): -6(q + 1) - 4q = -10q - 6

Therefore, None of the above expressions are equivalent

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Subtracting Fractions with an unlike Denominator?

5/8 - 2/32 =

Answers

1) Let us simplify the subtrahend of the expression.

Subtrahend: 2/32

[tex]\implies \dfrac{2}{32} \implies \dfrac{1 \times 2}{16 \times 2} \implies \underlin\dfrac{1}{16}[/tex]

2) Determine the LCM of the denominators.

The LCM of the denominators in the subtraction problem (5/8 - 2/32) can be determined by writing the multiples of 16 (Simplified denominator) and 8.

Writing the multiples of the denominators (16 and 8):

Multiples of 16 ⇔ 16, 32, 48, 64, 80...Multiples of 8 ⇔ 8, 16, 24, 32, 40...

Since we can see that 16 is a common multiple and is has the least value in both multiples, 16 is the common multiple of 8 and 16.

3) Solving the subtraction problem.

Multiply such number to the denominators such that the denominators are equivalent to the LCM. Keep in mind that the number we multiply in the denominator must be multiplied to the numerator.

    [tex]\implies \dfrac{5}{8} - \dfrac{1}{16}[/tex]

    [tex]\implies \dfrac{5 \times x}{8 \times x} - \dfrac{1}{16} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [8x = \text{LCM}][/tex]

    [tex]\implies \dfrac{5 \times 2}{8 \times 2} - \dfrac{1}{16} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [8 \times x = \text{LCM} \implies 8 \times x = 16 \implies x = 2][/tex]

    [tex]\implies \dfrac{10}{16} - \dfrac{1}{16}[/tex]

    [tex]\implies \dfrac{10}{16} - \dfrac{x}{16x} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [16x = \text{LCM}][/tex]

    [tex]\implies \dfrac{10}{16} - \dfrac{1 \times 1}{16 \times 1} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [16 \times x = \text{LCM} \implies 16 \times x = 16 \implies x = 1][/tex]

    [tex]\implies \dfrac{10}{16} - \dfrac{1}{16}[/tex]

Finally, let's subtract the fractions as the fractions have like denominators.

[tex]\implies \dfrac{9}{16}[/tex]

Therefore, the simplified fraction is 9/16.

Notes:

Parts of a subtraction problem:

Subtrahend: The number, variable, or expression being subtracted from the minuend of the expression. Minuend: The starting value of the expression. Difference: The solution to a subtraction problem.

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Find four numbers that are evenly divisible by both 2 and 9

Answers

Answer:

18

36

72

144

Step-by-step explanation:

For numbers to be divisible by 2 they must end in an even number

For numbers to be divisible by 9 the sum of the digits must be divisible by 9

Giving brainlyest to the person with the correct answer :)

Answers

Answer:

13.44 meters ahead

Step-by-step explanation:

phil distance = 6.59 m/s *12 sec     meters

Mary dist = 5.47 *12     meters  

difference :

6.59 *12   - 5.47 *12  = 13.44 meters

someone please help me what is (m - 5) divided by 4 where 5 = 17

Answers

If you mean where m=17 then the answer is 3 because 17-5 is 12 and 12/4 is 3.
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