The number of moles of O2 in 10.6 grams of Na2CO3:

A. 0.1 moles
B. 0.3 moles
C. 0.2 moles
D. None of these

Explain please​

Answer:

Explanation:

For adiabatic change the expression is  

= [tex]PV^\gamma=constant[/tex]

[tex]=(\frac{RT}{V})V^\gamma = constant[/tex]

[tex]=TV^{\gamma-1} = constant[/tex]

[tex]=T_1V_1^{\gamma-1} =[/tex][tex]=T_2V_2^{\gamma-1}[/tex]

for Argon γ = 1.67

273.15 x 1 = T₂ x [tex]3^{1.67-1}[/tex]

T₂ = 273.15 / [tex]3^{0.67}[/tex]

= 273.15/ 2.0877

= 130.83 K.

Answer:

Electrostatic Force of Attraction

Hope this helps ;)

Explanation:

Answer:

The correct answer is Density

Explanation:

Hope this helps you

Answer:density

Explanation:

Answer:

Option C. Ionic

Explanation:

Ionic bond is formed between a metal and a non metal.

Ionic bond occurs when there is a transfer of electron(s) from a metallic atom to a non metallic atom.

The hydrometer is an instrument used to determine the density of liquids, and looks like a large glass float filled at the bottom with grains of lead or mercury.

Because the mass of the hydrometer is known and thus the mass of the displaced liquid, the density can be determined using the volume.

There is a scale on the handle, the density can be read here. The deeper the hydrometer sinks, the lower its density.

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Answers:

(a) The explanatory variable is the change in the temperature .

The response variable is the coral survivance.

(b) The explanatory variable is quantitative.

The response variable is categorical.

Explanation:

A quantitative variable is those that can take a range of values. In this case, the temperature may vary across a range of values associated with the survival of coral reefs.  

A categorical (also known as qualitative) variable is characterized to present finite states. In this case, the coral reefs can survive or not depending on their responses to changes in the temperature.

Response and explanatory variables are used in experimental procedure ; the explanatory and response variables are :

Explanatory variables are independent variables which causes changes to the measured variable.

Measured variable is the variable we intend to measure in an experiment. They are called dependent variables.

Quantitative variables are numerical values, weight is measured as a number. Hence, it is quantitative.

Categorical variables are labels and are used to group objects into classes. They are Non-numeric. Levels of temperature could be (high, medium, low). Hence, temperature is categorical in the experiment.

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Answer:

THE STANDARD HEAT OF SOLUTION OF SODIUM HYDROXIDE IN WATER IS -7.68 KJ PER MOLE.

Explanation:

Variables:

Mass of NaOH = 3.25 g

Mass of water = 50 g

Initial temperature of water = 22°C = 22 + 273 K = 295 K

Final temperature of the reaction mixture = 24.8 °C = 24.8 + 273 K = 297.8 K

Assuming that:

1. specific heat of water = 4.184 J/g °C

2. total mass of the reaction mixture = 50 g + 3.25 g = 53.25 g

3. the rise in temperature = (297.8 K - 295 K ) = 2.8 K

4. Molar mass of sodium hydroxide = ( 23 + 16 + 1) = 40 g/mol

5. number of mole of sodium hydroxide = mass / molar mass

n = 3.25 g / 40 g/mol

n = 0.08125 moles

The rise in temperature for the reaction mixture produces how much of heat:

Heat = mass * specific heat * change in temperature

Heat = 53.25 * 4.184  * 2.8

Heat = 623.8344 J of heat.

Equation of reaction:

NaOH + H2O -------> NaOH + H2O + Heat

This is not a reaction but a dissolution as sodium hydroxide is very soluble in water and this reaction is exothermic where heat is given off.

So since 3.25 g having 0.08125 moles produces 623.8344 J of heat, 1 mole of the sodium hydroxide used will produce:

0.08125 mole of sodium hydroxide = 623.8344 J of heat

1 mole of sodium hydroxide = ( 623.8344 / 0.08125 J of heat

= 7677.96 J of heat per mole of sodium hydroxide.

= 7.68 kJ of heat

So therefore, the standard heat of solution of sodium hydroxide in water is -7.68 kJ of heat since its an exothermic reaction.

Answer:

The correct answer is 1.5 balloons.

Explanation:

Based on the given question, the radius of the spherical balloons is 170 cm. Therefore, the volume of each balloon will be,  

= 4/3 × π × (170)³ cm³

= 20.5176 × 10⁶ cm³  

= 20.5176 m³

The density of air at 100 degree C s 0.946 Kg m⁻³

The mass of air in each balloon can be calculated by using the formula,  

Mass = density × volume

Mass = 0.946 Kg m⁻³ × 20.5176 m³

Mass = 19.410 Kg

The heat energy, that is, required to bring the air from 25 degree C to 100 degree C will be,  

= 19.410 × 10³ g × (100 -25) degree C × 1.009 J/g degree C

= 14.68 × 10⁵ J

The concentration of butane given is 1.00 Kg or 1000 g

The molecular weight of butane is 58.12 g per mole

The moles or n can be calculated by using the formula,  

n = mass / mol.wt

n = 1000 g/58.12 g/mol = 17.20 mol

The formation of enthalpy of butane at 25 degree C is 125.7 × 10³ J/mol. The evolution of heat energy that take place at the time of burning 17.20 moles of butane is,  

= 125.7 × 10³ J/mol × 17.20 mol

= 2.16 × 10⁶ J

The number of balloons that can be inflated with hot air is,  

= 2.16 × 10⁶ J / 14.68 × 10⁵ J per each balloon

= 1.5 balloons

Hence, maximum of 1.5 balloons can be inflated.  

Answer:

the pressure (torr) of theH₂ gas is 736.2 torr

Explanation:

Given that

The H₂ gas  produced in a chemical reaction is collected through water in a eudiometer; during this process, the gas collected contains some droplets of water vapor along with these gas.

So; the total pressure in the eudiometer = Pressure in the H₂ gas  - Pressure of the water vapor

Where;

[tex]P_{Totsl}[/tex] =  total pressure in the eudiometer = 760.0 torr

[tex]P_{H_2}[/tex] = Pressure in the H₂ gas  = ???

[tex]P_{H_2O}[/tex] = Pressure in the water vapor  = 23.8 torr

Now:

[tex]P_{Totsl}[/tex] = [tex]P_{H_2}[/tex] + [tex]P_{H_2O}[/tex]

- [tex]P_{H_2}[/tex] = + [tex]P_{H_2O}[/tex] - [tex]P_{Totsl}[/tex]

[tex]P_{H_2}[/tex]  = - [tex]P_{H_2O}[/tex] + [tex]P_{Totsl}[/tex]

[tex]P_{H_2}[/tex]  =  (- 23.8 + 760) torr

[tex]P_{H_2}[/tex]  = 736.2 torr

Thus; the pressure (torr) of theH₂ gas is 736.2 torr

If the pressure in a eudiometer is 760.0 torr and the vapor pressure of water is 23.8 torr, the pressure of the H₂ gas is 736.2 torr.

A eudiometer is a laboratory device that measures the change in volume of a gas mixture following a physical or chemical change. Usually, the gas is collected over water.

According to Dalton's law of partial pressures, the sum of the sum partial pressure of the hydrogen and the partial pressure of the water is equal to the total pressure in the eudiometer.

[tex]P = pH_2 + pH_2O\\\\pH_2 = P - pH_2O = 760.0 torr - 23.8 torr = 736.2 torr[/tex]

If the pressure in a eudiometer is 760.0 torr and the vapor pressure of water is 23.8 torr, the pressure of the H₂ gas is 736.2 torr.

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Answer:

lube

Explanation:

Answer:

12.54mL

Explanation:

Step 1:

Data obtained from the question:

Mass of Zn = 2.95g

Density of Zn = 7.14 g/mL

Volume of water = 12.13mL

Final volume reading of cylinder =..?

Step 2:

Determination of the volume of Zn. The volume of Zn can be obtained as follow:

Density = Mass /volume

7.14 = 2.95/volume

Cross multiply

7.14 x Volume = 2.95

Divide both side by 7.14

Volume = 2.95/7.14

Volume of Zn = 0.41mL

Step 3:

Determination of the final volume reading of the cylinder.

The final reading of the cylinder will be the addition of the volume of water and the volume of Zn as shown below:

Final volume of cylinder = volume of water + volume of Zn.

Volume of water = 12.13mL

Volume of Zn = 0.41mL

Final volume =..?

Final volume of cylinder = 12.13 + 0.41

Final volume of cylinder = 12.54mL

Therefore, the final volume reading of the cylinder is 12.54mL

The final volume reading of the graduated cylinder is 12.54 mL.

A 2.95 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder. The volume of the piece of zinc is:

[tex]2.95 g \times \frac{1mL}{7.14 g} = 0.413 mL[/tex]

The final volume reading of the graduated cylinder will be equal to the sum of the volumes of the piece of zinc and the water.

[tex]V = V(H_2O)+V(Zn) = 12.13 mL + 0.413 mL = 12.54 mL[/tex]

The final volume reading of the graduated cylinder is 12.54 mL.

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Answer:

Explanation:

Si tomamos en cuenta el peso molecular del agua, que es equivalente a:

1 Átomo de H₂O

O = 16 gr/mol

H = 1 gr/mol

H₂O = 18 gr/mol

Teóricamente sabemos que en 1 mol de H2O habrá 18 gr.

Para obtener los moles presentes en 1 mg de H₂O, (como 1 gr = 1000 mg), decimos:

1 mol H2O …………………………..  18000 mg

       X          ……………………………   1 mg

X = 1 / 18000 = 5,56 X 10⁻⁵ moles de H20

Y para obtener la cantidad de moléculas presentes, de acuerdo a los moles, multiplicamos por el número de Avogadro (6,023 X 10²³ moléculas /mol)

Moléculas de H₂O = 5,56x 10⁻⁵ mol x 6,023 x 10²³

Moléculas de H₂O = 3,34488 x10¹⁹ moléculas de H₂O

En el copo de nieve habrá 3,34488 x 10¹⁹ moléculas de H₂O.

Espero que te sirva =)

5,43 X 10²² particles of water (H20) are in a collection of snowflakes with a mass of 0.005 g.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.

The mole concept can be used to convert between mass and number of particles.

1 atom of H₂O

O = 16 g/mol

H = 1 gr/mol

H₂O = 18 gr/mol

1 mol H₂O …………………………..  18000 mg

?      X          ……………………………   1 mg

X = 1 / 18000

= 5,43 X 10²² moles de H20

Thus, 5,43 X 10²² particles of water (H20) are in a collection of snowflakes with a mass of 0.005 g.

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Answer:

  1000 grams

Explanation:

Kilo- is the SI prefix meaning 1000. So, 1 kilogram is the same as 1000 grams.

Answer:

How do you think these devices work?

Both devices follows the principle and endothermic and exothermic reactions.The cold pack is made up of two bags. The first bag contains water.And it is placed inside the second bag which contains NH4NO3 , and urea. Therefore, when the water bag is squeezed, the bag busted releasing the water  which dissolves  the surrounding  solid compounds. These compounds absolved heat energy in an endothermic reaction.

The components of hand warmers are  activated carbon, salt iron, water,,and cellulose.The Oxidation of iron when exposed to the air (oxygen)generated heat in an exothermic reaction to keep the hand warm.

Thus the cold results from the endothermic reaction as the solid compounds in cold packs absorbed water to break bonds to melts,and the hotness comes  from formation of new bonds(exothermic) as oxidation of Fe to form new compounds with other chemical occurs.

Explanation:

Answer: 45. 78 g  is formed in 16 minutes.

Explanation:

Let [tex]A_{o} =40 g[/tex] and [tex]B_{o} =50 g[/tex]

we know that [tex]\alpha =A_{o}\frac{M+N}{M}\, and \, \beta =B_{o}\frac{M+N}{N}[/tex]

According to the question to create [tex]x[/tex] part of the chemical C we will need 2 part of A and one part of B.

Therefore, M = 2 and N = 1.

Now, we can easily solve  for the value of α and β.

[tex]\alpha =40\frac{2+1}{2}=60\\\\\, and \, \beta =50\frac{2+1}{1}=150[/tex]

Now, the differential equation must be: [tex]\frac{dX}{dt}=k\left ( \alpha -X \right )\left ( \beta -X \right )[/tex]

I separate the variable and solve the equation

[tex]\int \frac{dx}{\left ( 60-x \right )\left ( 150-x \right )}=\int k\, dt[/tex]

[tex]ln\frac{150-x}{60-x}=90kt+C_{1}[/tex]

By using [tex]X(0) =0[/tex],

[tex]\frac{150-x}{60-x}=Ce^{90k_{o}},C=\frac{5}{2}[/tex]

and using [tex]X (8)=25[/tex] and solving for the value of 'k'

[tex]\Rightarrow \frac{150-25}{60-25}=\frac{5}{2}e^{450k}\\\\\Rightarrow 3.6\times \frac{2}{5}=e^{450k}\\\\\Rightarrow 1.4=e^{450k}[/tex]

Taking 'ln' both side, we get

[tex]\Rightarrow k=7.4716\times 10^{-4}[/tex]

We obtain:[tex]X(t)=\frac{60Ce^{90kt}-150}{Ce^{90kt}-1}[/tex]

Now, for the 16 min

[tex]\Rightarrow X(16)=\frac{150e^{1.07559}-150}{2.5e^{1.0759}-1}[/tex]

[tex]\Rightarrow X(16)=\frac{439.7583-150}{7.3293-1}\\\\\Rightarrow X(16)=\frac{289.7583}{6.3293}[/tex]

[tex]\Rightarrow X(16)=45.78 g[/tex]

Answer:

Carbon cycle is also important for the survival of life on earth.

Explanation:

In carbon cycle, carbondioxide gas is present in the atmosphere. This carbondioxide gas is taken inside by the plant body through stomata and made food from it. When this food is eaten by animals, this carbon is transferred to their bodies. During breathing, carbondioxide gas is removed from animal body and the carbondioxide gas again goes to the atmosphere.

Answer:

2nd option

Explanation:

Molarity is the number of moles of the solute (NaCl) in 1 litre of the solution (NaCl solution).

Given: concentration= 232g/ L

what we are trying to achieve is __mol/ L.

So in 1 litre, we have 232g of NaCl.

To convert mass to mole, we divide it by the Mr.

Given that the Mr is 58g/mol,

number of moles

= 232 ÷58

= 4

Thus, 1 litre has 4 moles of NaCl.

Therefore, the molarity is 4.0 mol/L.

Answer:

(a) Hypoeutectic

(b) Alpha solid, aluminium

(c) 70% α , 30% β

(d) 97.6% α, 2.4% β

(e) 97.6% α, 2.4% β

(f) 97% α, 3% β

Explanation:

(a) The eutectic composition for Al Si alloy is 11.7 wt% silicon, therefore, an Al-4% Si alloy is hypoeutectic

(b) For the hypoeutectic alloy, aluminium, Al, is expected to form first, such that the aluminium content is reduced till the point it gets to the eutectic proportion of 11.7 wt% silicon

(c) At  578°C we have

% α:  Al      (11 - 4)/(11 - 1) = 70% α

% L:  Si      100 - 70 = 30% β

(d) At  576°C we have

α: 99.83% Si    (99.83 - 4)/(99.83- 1.65) = 97.6% α

β: 1.65% Si (4 - 1.65)/(99.83- 1.65) = 2.4% β

(e) Primary α: 1.65% α (99.83 - 4)/(99.83 - 1.65) = 97.6% α

Eutectic 4% Si  = 100 - 97.6 = 2.4% β

(f) At 25°C we have;

α%: (99.83 - 4)/(99.83 - 1) = 97% α

β%:   100 - 97 = 3% β.

Explanation:

small amount of solute is dissolved in a large amount of solvent. it would not make sense to have more solute and solvent. you can think of it like this, you can dissolve a teaspoon of salt in a litre water but you can't resolve 1 kg of salt in a teaspoon of water.

also, the solute is what is begin dissolved and the solvent is what dissolving the solute so the one day the solvent is dissolved in the solute does not make complete sense.

Answer: The concentration of [tex]CH_3NC[/tex] will be [tex]1.56\times 10^{-2}M[/tex] after 416 seconds have passed.

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant = [tex]3.00\times 10^{-3}s^{-1}[/tex]

t = age of sample = ?

a = let initial amount of the reactant = [tex]5.45\times 10^{-2}M[/tex]

a - x = amount left after decay process = [tex]1.56\times 10^{-2}M[/tex]

[tex]t=\frac{2.303}{3.00\times 10^{-3}}\log\frac{5.45\times 10^{-2}}{1.56\times 10^{-2}}[/tex]

[tex]t=416s[/tex]

The concentration of [tex]CH_3NC[/tex] will be [tex]1.56\times 10^{-2}M[/tex] after 416 seconds have passed.

Answer:

In the given case, SiO2 is the limiting reactant, 71.72 Kg is the theoretical yield, and 90.8 percent is the experimental yield.

Explanation:

A reactant that completely gets used up in a chemical reaction, and it limits the concentration of product, which can be produced is termed as a limiting reactant. The maximum concentration of product that can get generated from the limiting reactant is termed as the theoretical yield.  

Based on the given question, the balanced chemical reaction is:  

SiO₂ + 2C ⇒ Si + 2CO

Now the mole ratio of SiO₂: C = 1: 2

Based on the given information, the mass of SiO₂ is 155.8 Kg. The no. of moles can be calculated by using the formula, n = weight/molecular mass.  

The molecular mass of SiO₂ is 60.08 gram per mole. By putting the values we get,  

n = 155.8 × 10³ grams / 60.08 grams/mol

n = 2.59 × 10³ moles

The weight of Carbon given is 78.3 Kg or 78.3 × 10³ grams, the molecular mass of C is 12 gram per mole. Similarly, the moles of C will be,  

n = 78.3 × 10³ grams / 12 g/mol

n = 6.52 × 10³ moles

The experimental molar ratio of SiO₂: C is,  

= 2.59 × 10³: 6.52 × 10³

= 2.59: 6.52 = 1: 2.5

Hence, it is clear that carbon in the given case is present in excess amount, therefore, SiO₂ is a limiting reactant.  

With the help of the balanced equation, the molar ratio of SiO₂: Si is 1: 1. As SiO₂ is the limiting reactant, therefore, theoretical yield of the reaction will be determined by SiO₂.  

As calculated, the moles of SiO₂ used is 2.59 × 10³

Hence, the moles of Si produced in the given reaction is 2.59 × 10³.  

Now the mass of Si produced theoretically can be determined by using the formula, moles = weight/molar mass. The molar mass of Si is 28.08 gram per mole. Now putting the values we get,  

Weight = 2.59 × 10³ moles × 28.08 gram per mole

Weight = 72.72 × 10³ grams or 72.72 Kg

The theoretical yield of Si is 72.72 Kg, however, the experimental yield is 66.1 Kg. Therefore, the percent yield for the reaction will be,  

= Experimental yield / Theoretical yield × 100 %

= 66.1 Kg / 72.72 Kg × 100%

= 90.8 %

Answer: The final temperature of both the weight and the water at thermal equilibrium is [tex]50.26^{o}C[/tex].

Explanation:

The given data is as follows.

mass = 7.62 g,           [tex]T_{2} = 10.8^{o}C[/tex]

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = [tex]mC \times \Delta T[/tex]    

          = [tex]7.62 g \times 4.184 J/^{o}C \times (52.3 - T)[/tex]

Now, heat gained by lead will be calculated as follows.

       q = [tex]mC \times \text{Temperature change of lead}[/tex]  

           = [tex]2.04 \times 0.128 \times (T - 11.0)[/tex]

According to the given situation,

     Heat lost = Heat gained

[tex]7.62 g \times 4.184 J/^{o}C \times (52.3 - T)[/tex] = [tex]2.04 \times 0.128 \times (T - 11.0)[/tex]

        T = [tex]50.26^{o}C[/tex]

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is [tex]50.26^{o}C[/tex].

Answer:

D. exosphere is the outer layer of the thermosphere

Answer:

Left, Left, Right, Left, Right, Right

Explanation:

Follow that order!

Answer:

[tex]=1.02x10^{23} atoms\ H[/tex]

Explanation:

Hello,

In this case, for water, whose molar mass is 18 g/mol, we can find two moles of hydrogen in one mole of water, therefore, for us compute the atoms, we should also use the Avogadro's number as shown below:

[tex]=1.53gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} *\frac{6.022x10^{23}atoms\ H}{1molH} \\\\=1.02x10^{23} atoms\ H[/tex]

Regards.

Answer:

The volume will increase by a factor of 8.5

Explanation:

In an ideal gas, the volume is inversely proportional to the pressure. This means that the volume will decrease when the pressure increases and vice versa.

Let  the initial volume be v1, and the initial pressure p1.

the final pressure is decreased by a factor of 8.5, i.e

p2 = p1/8.5 = 0.12p1

using p1v1 = p2v2

v2 = (p1/p2)v1

v2 = (p1/0.12p1)v1

v2 = 8.5v1

This means that the final pressure increases by a factor of 8.5

Answer:

Increases by a factor of 8.5

Explanation:

Hello,

In this case, with the given data, we can apply the Boyle's law in order to understand the pressure-volume behavior as an inversely proportional relationship:

[tex]P_1V_1=P_2V_2[/tex]

Thus, for the given pressure decrease we have:

[tex]P_2=\frac{P_1}{8.5}[/tex]

So the volume changes by:

[tex]V_2=\frac{P_1V_1}{\frac{P_1}{8.5} } \\\\V_2=8.5V_1[/tex]

Therefore, it increases by a factor of 8.5.

Regards.

Answer:

3mol/0.5liters or 6 M

Explanation:

The molarity of a solution of 3 moles (mol) of FeBr₃ in 1/2 L water is 6 Molar Solution.

Molarity (M) is the amount of a substance in a certain volume of solution.

Molarity is defined as the number of moles of a solute per liters of a solution.

Molarity is also known as the molar concentration of a solution.

Molarity is number of moles of solute in 1 litre of solution.

Therefore,

If 0.5 ltr of solution consisting of 3 moles of FeBr₃

Thus,

1 ltr of solution consisting of 6 moles of  FeBr₃.

6 moles of solute in 1 ltr of solution means 6 Molar solution.

Hence, The molarity of a given solution of 3 moles (mol) of FeBr₃ in 1/2 L water is 6 Molar Solution.

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Answer:

Explanation:

Consider the given reaction,

A+B +C

[tex]rate=k[A]^m[B]^m[/tex]

Reaction is first order with respect to reactant B.

The pseudo order rate is

[tex]rate=k_1 [B]^m,\\\\where k_1 =k[A]^m[/tex]

Pseudo order reaction is the reaction in which the reactant concentration remains constant; its concentration is very high so it does not involve in the rate of the reaction. Here, the concentration of  A is sufficiently high so this reaction becomes the pseudo first order reaction.

The reaction is first order with respect to [B] with rate constant k1 .

Using the given table, concentration of  B is decreasing the rate also decreasing

Therefore, order of the reaction with respect to A  is 1.

The order of the reaction in reactant A is 1, means the value of m for given rate should be 1.

Pseudo order reactions are those reactions in which two reactants are present but the concentration of one of the reactant is present in excess quantity and it seems like first order reaction.

Given chemical reaction is: A + B +C

According to the question, given reaction is first order with respect to the reactant B and rate law will be represented as:

Rate = k[A]m[B]m

Also given that reactant A is present in high concentration in the reaction, so the rate of pseudo order reaction is:

Rate = k1[B]n, where

k1 = k[A]m

According to the given table with respect to concentration of reactant B and rate k1, it is clear that rate of the reaction decreases as the concentration of reactant B decreses. So, to get the required result order of the reaction or value of m with respect to the reactant A should be 1.

Hence option (B) is correct i.e. 1.

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Answer:

Explanation:

Structural isomer is a type of isomer in which molecules with the same molecular formula have different bonding patterns and atomic organization.

For example Pentan-1-ol, pentan-2-ol, and pentan-3-ol are structural isomers that exhibit position isomerism.

Cyclohexane and hex-1-ene are examples of functional group structural isomers.