Answer:
2.75 × 10⁻⁶ M/s
1.69 × 10⁻⁶ M/s
9.23 × 10⁻⁻⁷ M/s
4.43 × 10⁻⁻⁷ M/s
2.1 × 10⁻⁻⁷ M/s
Explanation:
We have the following information for the isomerization of methyl isonitrile
Time (s) [CH₃NC] (M)
0 0.0165
2000 0.0110
5000 0.00591
8000 0.00314
12000 0.00137
15000 0.00074
To calculate the average rate of reaction (r) for each interval, we need to use the following expression:
r = -Δ[CH₃NC]/Δt
Interval 0-2000 s
r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s
Interval 2000-5000 s
r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s
Interval 5000-8000 s
r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s
Interval 8000-12000 s
r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s
Interval 12000-15000 s
r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s
The average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
From the question,
We are to calculate the average rate of reaction for each of the measurement.
First, we will create a proper table for the data
Time (s) [CH3NC] (M)
0 0.0165
2,000 0.0110
5,000 0.00591
8,000 0.00314
12,000 0.00137
15,000 0.00074
The average rate of reaction is given by the formula
[tex]Average\ rate\ of\ reaction = \frac{Final\ concentration - Initial\ concentration}{Final\ time - Initial\ time}[/tex]
1.
[tex]Average\ rate\ of\ reaction = \frac{0.0110-0.0165}{2000 -0 }[/tex]
Average rate of reaction = 2.75×10⁻⁶ M/s
2.
[tex]Average\ rate\ of\ reaction = \frac{0.00591-0.0110}{5000 -2000 }[/tex]
Average rate of reaction = 1.70×10⁻⁶ M/s
3.
[tex]Average\ rate\ of\ reaction = \frac{0.00314-0.00591}{8000 -5000 }[/tex]
Average rate of reaction = 9.23×10⁻⁷ M/s
4.
[tex]Average\ rate\ of\ reaction = \frac{0.00137-0.00314}{12000 -8000 }[/tex]
Average rate of reaction = 4.43×10⁻⁷ M/s
5.
[tex]Average\ rate\ of\ reaction = \frac{0.00074-0.00137}{15000 -12000 }[/tex]
Average rate of reaction = 2.10×10⁻⁷ M/s
Hence, the average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
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When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..
How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?
0.5 moles
50 moles
25 moles
2 moles
50 moles
The formula used in this question is-
Mole= Molarity*Volume(in Litre)
So after putting the value
= (25)*(2)
=50 moles
What is molarity?
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
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How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
Answer is 1048 mL solution but how do I get to the answer?
Answer:
1048 mL
Explanation:
Step 1: Given data
Concentration of the solution: 0.2560 MMass of KCl (solute): 20.00 gStep 2: Calculate the moles corresponding to 20.00 g of KCl
The molar mass of KCl is 74.55 g/mol.
20.00 g × 1 mol/74.55 g = 0.2683 mol
Step 3: Calculate the volume of the solution
Molarity is equal to moles of solute divided by liters of solution.
M = moles of solute / volume of solution
volume of solution = moles of solute / M
volume of solution = 0.2683 mol / (0.2560 mol/L)
volume of solution = 1.048 L = 1048 mL
what are the advantages and disadvantages of rusting
Answer: The rusting of iron is more of a disadvantage than an advantage. Rusting forms an iron oxide which is more brittle than the iron. It less resistance to environmental degradation and permeability by water and air, therefore cannot be used for coating.
Explanation: plzz mark as brainliest
The pH of an acidic solution is 5.59. What is [H+]?
Answer:
[H⁺] = 2.57x10⁻⁶ M
Explanation:
This problem can be solved using the definition of pH:
pH = -log[H⁺]
Now we isolate [H⁺] in the equation:
-pH = log[H⁺]
[tex]10^{-pH}[/tex]=[H⁺]
As we are given the pH by the problem, we can now proceed to calculate the [H⁺]:
[H⁺] = [tex]10^{-5.59}[/tex]
[H⁺] = 2.57x10⁻⁶ M
Thus, when the pH of a solution is 5,59; the molar concentration of H⁺ species is 2.57x10⁻⁶.
What are types of Kinetic energy?
Answer:
Machical Engery
Electrical Engery
Rhermal Engery
Sound Energy
Explanation:
Explanation:
There are five types of kinetic energy:
RadiantThermalSoundElectrical and Mechanical.Thus, There are five types of kinetic energy
-TheUnknownScientist
Can somebody please help me!!!
Answer:
javier applied force how this helps
Please help it’s for 100 points
Has your cell phone ever not had enough battery when you really needed it? What did you do?
Answer:
Yes
Explanation:
There are some times when I will need my cell phones but it will have not battery. At this point, I look for a means to charge it or I could probably use power bank to charge. I always have an extra battery, so when the other battery is flat, I will replace it with the second charged one. But when both batteries are flat, I will look for a means to charge it using generator or wait till I have access to power supply.
Name
Period
GAS STOICHIOMETRY REVIEW
Please answer the following on separate paper using proper units and showing
all work. Please note that these problems require a balanced chemical
equation.
1. Carbon monoxide reacts with oxygen to produce carbon dioxide. If 1.0 L of
carbon monoxide reacts with oxygen at STP,
a. how many liters of oxygen are required to react?
b. How many liters of carbon dioxide are produced?
Answer:
don't trued the ebitly dude. rub
If an ultraviolet photon has a wavelength of 77.8 nm calculate the energy of one mole ultraviolet photon.
Answer:
Explanation:
E = (hc)/(λ)
E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /
(77.8x10^(-9)m)
E = 2.55 x 10^(-11) J
Plz I need helpppppp
1. Which of these is not a macromolecule? a) Alab) protein c) polysaccharide d) nucleic
acid
Answer:
a) alab
Explanation:
Two of the main macromolecules are proteins and nucleic acid, and a polysaccharide is multiple monomers (monosaccharide) that join to create another macromolecule called carbohydrates.
C. 2.86 g
D. 1.22 g
13. At what Kelvin temperature will 25.2 mol of Xe occupy a volume of 645 L at a pressure of 732 torr?
A. 361 K
B. 291 K
C. 402 K
D. 300 K
Calculate the mass percent of hydrogen in 70 g of C4H8O3?
Answer:
7.14%
Explanation:
From the question,
percentage by mass hydrogen in C₄H₈O₃ (h) = mass of hydrogen present in C₄H₈O₃(m)/molar mass of C₄H₈O₃ (m')
h = (m'/m)×100..................... Equation 1
Given: m' = (14×4)+(1×8)+(16×3) = 56+8+48 = 112 g, m = (1×8) = 8 g
Substitute these values into equation 1
h = (8/112)×100
h = 7.14%.
Hence the percentage of hydrogen in 70 g of C₄H₈O₃ is 7.14%
Which is the best analogy of a wave?
A wave is like building a ramp.
A wave is like shaking a hand.
A wave is like water rippling in a pond.
A wave is like knocking down a building.
The best analogy that can be use to describe a wave is that a wave is like a rippling in a pond.
What is a wave?A wave is a disturbance or vibrations that occur in a particle and travel from one medium to another medium thereby transporting energy form the origin of it to another location where is is utilized.
Therefore, The best analogy of a wave is a wave is like water rippling in a pond.
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arrange the following in order of ionization energy, Na, Na+, C, O
Answer:
Na+, O, C, Na
(Na+ has more ionization energy and Na has less ionization energy)
How many grams of Mg(NO3), are necessary to
make 1500 mL of a 0.50 M solution?
Answer:
1.1 × 10² g
Explanation:
Step 1: Given data
Concentration of the solution (C): 0.50 M (0.50 mol/L)Volume of solution (V): 1500 mL (1.500 L)Step 2: Calculate the moles of Mg(NO₃)₂ (solute)
Molarity is equal to the moles of solute (n) divided by the liters of solution.
C = n/V
n = C × V
n = 0.50 mol/L × 1.500 L = 0.75 mol
Step 3: Calculate the mass corresponding to 0.75 moles of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.3 g/mol.
0.75 mol × 148.3 g/mol = 1.1 × 10² g
1
Select the correct answer.
How long is the term of a federal judge in a constitutional court?
OA.
two years
OB
four years
Ос.
six years
OD.
lifetime
Answer:
Judges and justices serve no fixed term — they serve until their death, retirement, or conviction by the Senate. By design, this insulates them from the temporary passions of the public, and allows them to apply the law with only justice in mind, and not electoral or political concerns.
please write the equation and help me solve. please no links
Answer: The molality of solution is 1.2 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
[tex]Molality=\frac{n}{W_s}[/tex]
where,
n = moles of solute
[tex]W_s[/tex] = weight of solvent in kg
Given : 10 g of glycerol is present in 100 g of solution
moles of glycerol = [tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{10g}{92g/mol}=0.108mol[/tex]
mass of water (solvent )= (100-10) = 90 g = 0.09 kg
Now put all the given values in the formula of molality, we get
[tex]Molality=\frac{0.108mol}{0.09kg}=1.2mole/kg[/tex]
Therefore, the molality of solution is 1.2 mole/kg
gloves worn when working with liquid oxygen must be able to resist.
Answer:
What is your question?
Explanation:
Can you give more context to ur question?
which is an example of a sale laboratory procedure
Why is it hard to predict the weather more than a few days in advance?
Answer:
Because the weather is complex and dynamic.
Explanation:
The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.
Answer:
0.0542 M
Explanation:
Let;
CA = concentration of Ce4+ solution = 0.1741 M
VA = volume of Ce4+ solution = 18.68 mL
CB = concentration of H3AsO3 = ?
VB = volume of H3AsO3 = 30.00 mL
NA = Number of moles of Ce4+ solution = 2
NB = Number of moles of H3AsO3 = 1
From;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.1741 * 18.68 * 1/30.00 * 2
CB = 0.0542 M
provide the electronic structure diagram of propene showing all molecular orbitals
Answer:
Explanation:The pi-molecular orbitals in propene (CH3-CH=CH2) are essentially the ... This central carbon thus provides two p-orbitals – one for each pi bond – and these two different p-orbitals have to be perpendicular, leading to a twisted structure as shown: ... It all comes down to where the location of the electron-deficient carbon
Observe the map what do the grey scar like represent?
Answer:
mid ocean ridge
Explanation:
The gas phase decomposition of nitrogen dioxide at 383 °C
NO2(g)NO(g) + ½ O2(g)
is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.
Answer:
[tex][NO_2]=0.112M[/tex]
Explanation:
Hello there!
In this case, since the second-order integrated law is given by the following equation:
[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]
Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:
[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]
[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]
Best regards!
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent yield if 5.40 g of "hydrogen gas" are collected?
Answer:
1040%
Explanation:
To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:
Percent yield = Actual yield (5.40g) / Theoretical yield * 100
Moles Fe -Molar mass: 55.845g/mol-:
10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.
For a complete reaction of these moles there are necessaries:
0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.
As there are 14.8 moles of the acid, Fe is limiting reasctant.
The moles of H2 produced are:
0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2
The mass is:
0.277 moles H2 * (2.016g/mol) = 0.558g H2
Percent yield is:
5.40g / 0.558g * 100 = 1040%
It is possible the experiment wasn't performed correctly
please help does anyone know this// science!
Answer:
its A
Explanation:
The only one that makes sense
A chemist prepares a solution of silver(I) nitrate AgNO3 by measuring out 62.3μmol of silver(I) nitrate into a 50.mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in /molL of the chemist's silver(I) nitrate solution. Be sure your answer has the correct number of significant digit
*please write the answer without any files disturbance*
Answer:
0.0012 mol/L.
Explanation:
From the question given above, the following data were obtained:
Number of mole of AgNO₃ = 62.3 μmol
Volume = 50 mL
Molarity of AgNO₃ =?
Next, we shall convert 62.3 μmol to mole. This can be obtained as follow as follow:
1 μmol = 10¯⁶ mole
Therefore,
62.3 μmol = 62.3 × 10¯⁶
62.3 μmol = 62.3×10¯⁶ mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the concentration of AgNO₃ in mol/L as follow:
Number of mole of AgNO₃ = 62.3×10¯⁶ mole
Volume = 0.05 L
Molarity of AgNO₃ =?
Molarity = mole /Volume
Molarity of AgNO₃ = 62.3×10¯⁶ / 0.05
Molarity of AgNO₃ = 0.0012 mol/L
Thus, the concentration of AgNO₃ is 0.0012 mol/L
Consider the following exothermic process at equilibrium:
CO(g)+H2O(g)⇌CO2(g)+H2(g)
Which of the following changes would increase the amount of H2(g) present in the equilibrium mixture?
Consider the following exothermic process at equilibrium:
Which of the following changes would increase the amount of present in the equilibrium mixture?
decrease the temperature
increase [CO2]
increase [CO]
increase the volume of the container in which the reaction occurs.
more than one of the above
(Answer is not increase [CO])
For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
How is equilibrium affected by changes?When a perturbation is done on a system at equilibrium, it shifts its equilibrium position to counteract the perturbation.
Let's consider the following exothermic process at equilibrium.
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)
Which of the following changes would increase the amount of H₂(g) present in the equilibrium mixture?
decrease the temperature. NO. For an exothermic reaction, a decrease in the temperature will shift the equilibrium towards the reactants.increase [CO₂]. NO. This would shift the equilibrium towards the reactants.increase [CO]. YES. This would shift the equilibrium towards the products.increase the volume of the container in which the reaction occurs. NO. This wouldn't affect the equilibrium since the number of gaseous moles is the same on both sides.more than one of the above. NO.For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
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