The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
N

Answer:

b

Explanation:

is correct .....................

i think

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex]  (1)

Where:

[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s

[tex]\omega_{0}[/tex]: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

[tex] \omega_{0} = \omega_{f} - \alpha t [/tex]   (2)

Now, by entering equation (2) into (1) we have:

[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]                        

[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]                              

[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

[tex] W_{r} = |F_{r}|*|d|*cos(\theta_{1}) [/tex]

Where:                

[tex]F_{r}[/tex]: is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

[tex] W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J [/tex]

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

[tex] W_{g} = |F_{g}|*|d|*cos(\theta_{2}) [/tex]  

The force of gravity is given by the weight of the bike.

[tex] F_{g} = -mgsin(24) [/tex]     

And the angle between the force of gravity and the direction of motion is 180°.

[tex] W_{g} = |mgsin(24)|*|d|*cos(\theta_{2}) [/tex]  

[tex] W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J [/tex]  

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.  

I hope it helps you!                                                                                          

Answer:

correct answer is A

Explanation:

The diagram shows a series circuit with three resistors and two power sources.

In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.

When the power sources are placed in opposite position the voltage between them is subtracted.

     V_b - 30 = I (10 + 4 + 6)

     V_b = I (20) - 30

      V_b = 30 - 2 20

       V_b = 10 V

the correct answer is A

Answer:

467

Explanation:

Answer:

Who is liang

Explanation:

i need more info if i'm going to help you out

He is most likely trying to figure out how to upload the picture to Brainly.

He knows that his question cannot be answered as long as nobody can see the picture.

Answer:

B. The "Learner" was working with Milgram.

Explanation:

just took the test

give brainliest, please. :)

Answer:

B to provide traction so that slipping does not occur

Explanation:

To increase friction between two surfaces, allow the objects to slide past each other thereby  force that is called friction.

Friction is  a type of force acting on an object to hinder its motion . It is negative by direction, since this force, hinder the motion of the object. Friction is also known as an opposing force because it always acts in the opposite direction of a moving or attempting to move body.

The virtue of friction causes a moving body to slow down. Friction is useful at times because it prevents car tires from skidding on the road and also allows us to walk on the pavement without slipping.

To increase friction , make an uneven, rugged, or sticky point of contact. When two or more bodies slide or rub against each other, three things can happen: small irregularities, nooks and crannies on the surfaces can catch on each other.

To find more on friction, refer here:

https://brainly.com/question/13000653

#SPJ2

Answer:

Friction.

Explanation:

Answer: He died later in 78 BC and was accorded a state funeral. Hearing of Sulla's death, Caesar felt safe enough to return to Rome. Lacking means since his inheritance was confiscated, he acquired a modest house in the Subura, a lower-class neighbourhood of Rome. hope this helps. Can u give me brainliest

Explanation:

Answer:

10kg

Explanation:

Weight is "how much does gravity drag this down".

Mass is "how much matter is there here".

The relation is:

[tex]F_g = mg[/tex]

where [tex]F_g[/tex] is the weight, [tex]m[/tex] is the mass and [tex]g[/tex] is the gravitational acceleration (roughly equal to 10N/kg on Earth).

From the task we know that:

[tex]F_g = 100N\\g = 10\frac{N}{kg}[/tex]

So let's input it into the relation:

[tex]100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg[/tex]

Answer:

can you explain yourself more please

Explanation:

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

Answer:

I hope it's helpful .............

Answer:

15.00000652 °C

Explanation:

From the question,

Q = cm(t₂-t₁)................ Equation 1

Where Q = heat gained by the liquid, c = specific heat capacity of the liquid, m = mass of the liquid, t₁ = Initial Temperature of the liquid, t₂ = Final temperature of the liquid.

Given: Q = 3.33 J, c = 511 J/kg°C, m = 1000 kg, t₁ = 15°C

Substitute these values into equation 1 and solve for t₂

3.33 = 511×1000(t₂-15)

3.33 = 511000(t₂-15)

(t₂-15) = 3.33/511000

(t₂-15) = 0.0000065

t₂ = 15+ 0.0000065

t₂ = 15.00000652 °C

Answer:

9.8 ×4 equal 39.2 m/s This is v intial

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μ[tex]_B[/tex]B × cos0°

= -μ[tex]_B[/tex]B × 1

= -μ[tex]_B[/tex]B

Final potential energy = -μ[tex]_B[/tex]B × cos180°

= -μ[tex]_B[/tex]B × -1

= μ[tex]_B[/tex]B

so change in energy will be;

ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )

ΔE = 2μ[tex]_B[/tex]B

now, difference in energy levels will be;

ΔE = hc/λ

2μ[tex]_B[/tex]B = hc/λ

2μ[tex]_B[/tex]Bλ = hc

B = hc /  2μ[tex]_B[/tex]λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

Answer:

0.8324 kgm^2/s

Explanation:

Attached below is the detailed solution to the given problem

First step :

Calculate mass moment of Inertia of the section about the axle

I axle = 0.20813 kgm^2

next : apply the principle of Angular impulse and momentum to determine the angular impulse imparted to the lug nut

Angular impulse imparted to lug nut = 0.8324 kgm^2/s

Answer:

C!

Explanation:

Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.

Answer:

I think not sure B sorry if this is wrong yay if im right

Explanation:

Answer:

A.  Kepler's second law says that the radius vector sweeps equal areas in             equal times.

Answer:

Do we have to choose out of those three?

Explanation:

Answer: See explanation

Explanation:

1. The collective name given to protons, neutrons in the nucleus of an atom is referred to as the nucleon.

2. The mass number simply means the total number of both the protons and the neutrons that we have in a nucleus.

3. Atomic number = Protons = 28

Mass number = 64.

Neutron = Mass Number - Protons

Neutron = 64 - 28 = 36

4. The number of Protons is also the number of atomic number which is 28.

Answer:

The distance traveled by the tuning fork is 9.37 m

Explanation:

Given;

source frequency, [tex]f_s[/tex] = 683 Hz

observed frequency, [tex]f_o[/tex] = 657 Hz

The speed at which the tuning fork fell is calculated by applying Doppler effect formula;

[tex]f_o = f_s [\frac{v}{v + v_s} ][/tex]

where;

[tex]v[/tex] is speed of sound in air = 343 m/s

[tex]v_s[/tex] is the speed of the falling tuning fork

[tex]657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s[/tex]

The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;

[tex]v_s^2 = v_o^2 + 2gh[/tex]

where;

[tex]v_o[/tex] is the initial speed of the tuning fork = 0

g is acceleration due to gravity = 9.80 m/s²

[tex]v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m[/tex]

Therefore, the distance traveled by the tuning fork is 9.37 m

Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

Answer:

[tex]2Al + N_{2} ==> 2AlN[/tex]

Explanation:

Answer:

the Gravitational potential energy is 13.23 J

Explanation:

The computation of the GPE is shown below:

GPE stands for Gravitational potential energy

The following formula should be used for the same

= mass × gravity × height

= 3000 g × 9.8m/sec^2 × 0.45 m

= 13.23 J

Hence, the Gravitational potential energy is 13.23 J

We simply applied the above formula so that we can easily determine the GPE