The glucometer applies a potential difference of 0.90 volts across a blood sample. The glucose concentration of the blood sample is 0.98 grams/litre. Determine the current in the blood sample. ​

Answer: 1.32 x 10^-9 m

Explanation:

The formula for the radius of nth orbital is:

[tex]r_{n}=\frac{n^{2}}{Z} \times 0.528 \text { Angstorms }[/tex]

For hydrogen, Z= 1, so we have:

[tex]$$\begin{aligned}r_{n} &=5^{2} \times 0.528 \text { Angstorm } \\&=13.2 \text { Angstorms } \\&=13.2 \times 10^{-10} \mathrm{~m} \\&=1.32 \times 10^{-9} \mathrm{~m}\end{aligned}$$[/tex]

Answer: 1.32*10^-9

Explanation: I had the same question and here's what I got:

rn = n2(r1)

n = 5

r = 5.29*10^-11

rn = n^2(r1)

= 5^2(5.29*10^-11)

r = 1.32*10^-9

Becky's acceleration is 5.45 [tex]ms^2[/tex].

Acceleration = [tex]\frac{v-u}{t}[/tex]

where v= final velocity , u= initial velocity , t= time taken

according to the question :

initial veocity = 0 (it is at stop initially)

final velocity = 30m/s

time taken = 5.5 s

according to the formula acceleration = [tex]\frac{30-0}{5.5}[/tex]=[tex]5.45[/tex]

Hence Becky's acceleration is 5.45 [tex]ms^2[/tex].

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Answer:

D

Explanation:

Mass is the amount of matter your body has ....does not change on the Moon.

there is less gravity .....so your WEIGHT would decrease

Answer:

it is double the temperature change of iron

Answer:

A.) It decreases

Explanation:

Generally, as you go from the top to the bottom of the periodic table (down a column), the electronegativity values of the elements decrease.

Also, as you move to the right of the periodic table (across a period), the electronegative values increase. The most electronegative elements are located on the top-right of the periodic table.

All elements in the same group have the same number of electrons in the outermost energy level. Option C is correct.

The periodic table is an organization of all known elements in order of increasing atomic number and repeating chemical characteristics.

They are organized in a tabular format, with a row representing an era and a column representing a group. E elements are ordered in increasing atomic number order from left to right and top to bottom.

Thus, Elements of the same group will have the same valence electron configuration and, as a result, will have comparable chemical characteristics.

Each set of elements has an equal amount of electrons in the outer orbital. Valence electrons are another name for the outer electrons.

They are the electrons interacting with other elements in chemical bonding. Each element in group one, the first column, has one electron in its outer shell.

Hence option C is correct.

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Find refractive index first

[tex]\\ \rm\Rrightarrow \mu=\dfrac{c}{v}[/tex]

[tex]\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}[/tex]

[tex]\\ \rm\Rrightarrow \mu =0.75[/tex]

Now

[tex]\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr[/tex]

[tex]\\ \rm\Rrightarrow sinr=0.94[/tex]

[tex]\\ \rm\Rrightarrow r=sin^{-1}(0.94)[/tex]

[tex]\\ \rm\Rrightarrow r=70^{\circ}[/tex]

Answer:

42.9°C

Explanation:

Resistance of a conducting material is directly proportion to Temperature, that is, when being heated, their is more of collisions between the molecules of the material which as a result offers more opposition to the flow of current through it.

therefore R=kT

where R=resistance of the wire

T=Temperature

k= proportionality constant

when R=1.05 T=30°C

so k=1.05/30

k=0.035

when R=1.5 k=0.035

so T=1.5/0.035

T=42.9°C. or 43°C approximated

Answer:

D. 0.43 A

Explanation:

First you will find the total resistance which is

R=R¹+R²

R=2+12

R= 14 ohms

I = V/R

I = CURRENT

V= VOLTAGE

R = RESISTANCE

I= 6/14

I =0.43 A

Answer:

F = G M m / R^2        gravitational force on satellite of mass m

Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2

Fma / Fmb = 1 * 4 = 4

The force on A is 4 times the force on B

The time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

The time taken for the star fish to travel the given distance is calculated as follows;

s = ut + ¹/₂at²

55 = 11.8t + (0.5)(6.39)t²

55 = 11.8t + 3.195t²

3.195t² + 11.8t - 55 = 0

solve the quadratic equation using formula method,

where;

a = 3.195, b = 11.8, c = -55

t = 2.7 s

Thus, the time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

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The gravity force between Jupiter and Io will be 6.343 × 10²² N.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data;

Mass of Jupiter,[tex]\rm m_j = 1.9 \times 10^{27} \ kg[/tex]

Mass of moon of Jupiter,[tex]\rm m_{i_0}= 8.9 \times 10^{22} \ kg[/tex]]

The gravitational constant is,[tex]\rm G = 6.67 \times 10^{-11 } \ m^3 kg^{-1} s^{-2}[/tex]

Distance between Jupiter and Io, R = 421,700 km = 4,217,00,000 m

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

The gravitational force is found as;

[tex]\rm F = G \frac{ m_J m_{I_0}}{R^2} \\\\\ F = (6.67\times 10^{-11}) \frac{( (1.9\times 10^{27})\times (8.9\times 10^{22} )} { (421700000)^2}\\\\ F_g = 6.343 \times 10^{22} \ N[/tex]

Hence, the gravity force between Jupiter and Io will be 6.343 × 10²² N.

The complete question is

"Jupiter has a mass of 1.9 × 1027 kg, and its moon Io has a mass of 8.9 × 1022 kg. Their centers are separated by a distance of 421,700 km what is the force of gravity acting on Io? "

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Q in = Q out

mcΔt in = mcΔt out (c = equal)

mΔt in = mΔt out

200 x  (75-25) = M x (25-5)

M = 500 g

∆T for hot water

∆T for cold water

Both are equal according law of conservation of energy

[tex]\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta [/tex]

[tex]\\ \rm\Rrightarrow 200(50)=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow 10000=m_2(20)[/tex]

[tex]\\ \rm\Rrightarrow m_2=500g=0.5kg[/tex]

The height of the image is -6 cm.

The reflecting surface of a concave mirror is curled inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given that, an object placed 36 cm from a concave mirror having the focal length of 12 cm and height of image is 2.50 cm

We have to find height of the Image

Using Mirror Formula:

1/f = 1/v + 1/u

Where,

f = focal length

v =  Image distance from the mirror

u = object distance from the mirror (concave)

Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.

1/(-12) = 1/v + 1/(-36)

1/(-12) = 1/v - (1/36)

1/v = -0.055

v = -18 cm

Therefore, Image distance the from the concave mirror is -18 cm.

Now,

m = -v/u = hi/h

Substitute the values,

-(-18)/(-36) = hi/12

-0.5 = hi/12

-6 = hi

Therefore, the height of the image is -6 cm.

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Bobby and Alice are pushing a stalled car in the same direction. The mass of the car is 2,000 kg. Bobby applies 400 N to the car while Alice applies 300 N. A force created by friction is 500 N in the opposite direction is the acceleration of the car is 0.1 m/sec.

An acceleration, fee at which pace adjustments with time, in phrases of each velocity and direction. A factor or an item shifting in a direct line is expanded if it hurries up or slows down.

Is summarized via way of means of the equation: Force (N) = mass (kg) × acceleration (m/s²).The mass = 2000 kg and force= 1200 N. So mass / force = 2000/1200 = 0.1 m/sec.

Thus, the acceleration of the car s 0.1 m/sec.

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Explanation:

The light is bent away from the normal

(a.1) The component of displacement along the East is  7.36 km.

(a.2) The component of displacement along the North is  4.25 km.

(b)  When the East and North legs are reversed in order, you will still travel 8.5 km.

dx = d cosθ

dx = 8.5 km x cos(30)

dx = 7.36 km

dy = d sinθ

dy = 8.5 km x sin(30)

dy = 4.25 km

dx = 4.25 km

dy = 7.36 km

Resultant displacement;

R = √(dx² + dy²)

R = √(4.25² + 7.36²)

R = 8.5 km

Thus, when the East and North legs are reversed in order, you will still travel 8.5 km.

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Answer:

decreases

Explanation:

because all the particles are wanting to say together and hit each other in a small area

Answer:

Fritional force

Explanation:

Fritional force is a force that always opposes the motion of an object and is frequently ignored

C

Explanation:

Applied force, air resistance

Explanation:

Power= 40 W

cost=21¢/kWh

t=1 month=30 days = 720h

Energy= power*time

E= 40W* 720h = 28800kWh

Cost= Energy*rate

cost= 28800kWh*21¢/kWh

cost=604800¢

The speed of sound waves in air at room temperature T=20° is 344.035 m/s.

The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is  17.20 m to  0.0172 m.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = c/f

where c is the speed of sound wave.

Given the room temperature T = 20 +273 = 293K

The velocity of sound wave is given by

v = √(γRT/m)

​where γ =1.4 , m = 28.8×10⁻³ kg/mol  R = 8.31 J/K.mol

Substituting the values, we get

v = 344.035 m/s

Thus, the speed of sound wave is 344.035 m/s

​

The human ear can hear frequencies in the range of 20 – 20,000Hz.

The wavelength corresponding to 20Hz is

λ = c/f

λ =  344.035 /20

λ  = 17.20 m

The wavelength corresponding to 20,000Hz is

λ =  344.035 /20000

λ  = 0.0172 m

Thus, the range of wavelength is 17.20 m to  0.0172 m sensitive to human ear.

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Answer:

(D)6 times

Explanation:

Hello !

Because when we see the equation of momentum P=mv, where p=momentum

m=mass of the object&

v=velocity of the object

And, p is directly propositional to both mass and velocity.

Thus, p=mv

Therefore, we can conclude by when the mass is tripled and the velocity is doubled the momentum is increased by 6 units.

(a) The initial speed must the object be launched so that it reaches

the surface of Planet 2 with zero speed is  √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) An inequality between M₁ and M₂ that represents when (a)

can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

(c)  if R₁ = R₂, then M₁ must be greater than M₂ is proved.

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.

If v is the launch velocity, then initial total energy will be

T.E  = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)

The final total energy will be

T.E  =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

From energy conservation principle, we get

1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) an inequality between M₁ and M₂  so that object reaches the surface of Planet 2 with zero speed is

[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

Thus, this is an inequality between M₁ and M₂.

(c) If R₁ = R₂, then

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L) / R (R+L)   ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L)  ≥ 0

M₁L - M₂L  ≥ 0

M₁ ≥ M₂

M₁ must be greater than M₂.

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[tex]\large\boxed{Formula: I= \frac{Q}{t}}[/tex]

Let's solve!

The formula is given above.

Let's substitute the values according to the formula.

We'll have to divide the measure of charge by the given time.

[tex]I= \frac{40}{10}[/tex]

Final answer:

[tex]\large\boxed{= 4 \: Amps \: (A)}[/tex]

Hence, the current is 4 amps.

Answer:

The scientific method

Explanation:

According to Piaget, that means that she has made the transition from the sensorimotor to preoperational stage

The first of Piaget's four stages of cognitive development is the sensorimotor stage.

A child's understanding that the outside world exists apart from them is what distinguishes it.

Within Piaget's stages of development, the kid will advance to the following stage after they have completely grasped this.

"Charlene has just begun to be able to form a mental representation of an object that is not visibly present.

According to Piaget, that means that she has made the transition from the sensorimotor to preoperational stage

Only recently has Charlene been able to create a mental image of something that is not physically present.

That indicates that she has moved from the sensorimotor to the preoperational level, in accordance with Piaget.

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The sled accelerates with magnitude [tex]a[/tex] such that

[tex]\left(2.3\dfrac{\rm m}{\rm s}\right)^2 = 2a(9.2\,\mathrm m) \implies a = 0.2875\dfrac{\rm m}{\mathrm s^2}[/tex]

By Newton's second law, the net force in the plane of motion (parallel to the ground) is

[tex]31\,\mathrm N - F_{\rm friction} = (17 \,\mathrm{kg}) \left(0.2875 \dfrac{\rm m}{\mathrm s^2}\right)[/tex]

so that the force of friction exerts a magnitude of

[tex]F_{\rm friction} = 26.1125 \,\mathrm N[/tex]

Perpendicular to the ground, the sled is in equilibrium, so Newton's second law says

[tex]F_{\rm normal} - (17\,\mathrm{kg})g = 0 \implies F_{\rm normal} = 166.6 \,\mathrm N[/tex]

The magnitude of friction is proportional to the magnitude of the normal force by a factor of [tex]\mu_k[/tex], the coefficient of kinetic friction. It follows that

[tex]F_{\rm friction} = \mu_k F_{\rm normal} \implies \mu_k = \dfrac{26.1125\,\rm N}{166.6\,\rm N} \approx \boxed{0.16}[/tex]

(and the coefficient is dimensionless).

Answer:

I actually did that but I fprgot

Answer: 0.0387

Explanation: I had the same problem and here's what I got:

Values:

ε (Voltage) = 240

ω (Angular velocity) = 37.7

B (Magnitude) = 0.200

N (Number of loops) = 822

ε = NABω (Rearrange to get A)

A = ε/WBN

= (240)/(37.7)(0.200)(822)

A = 0.0387 (FINAL ANSWER)

Answer:

r= 1.09×10^-4

Explanation:

Given

V=speed=4.0×10^5 m/s

B= magnetic field= 0.040 T

©=angle= 35°

m= mass of electron= 9.11×10^-31

q= charge of electron= 1.60×10^-19

solution

qv×B= mv²/r

qvBsin©=mv²/r

qBsin©=mv/r

r=mv/qBsin©

r=9.11×10^-31× 4.0×10^5/1.064×10^-19×0.04T(sin35°)

r= 1.09×10^-4 m

a) r = 1.09 * [tex]10^{-4}[/tex] m

b) Distance travelled : 6.845 *  [tex]10^{-4}[/tex] m    

An electron is a  stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

given

charge of electron : 1.6 * [tex]10^{-19}[/tex] C

mass of electron = 9.11 * [tex]10^{-31}[/tex] kg

v = 4.0 x 10 m/s

B =  0.040 T

theta = 35 degrees

since ,

force in magnetic field on electron = centripetal force

a) q(v*B) = m [tex]v^{2}[/tex] / r

q v B sin(theta) =  m [tex]v^{2}[/tex] / r

r =m v /q B sin(theta)

r =  9.11 * [tex]10^{-31}[/tex] * 4.0 x [tex]10^{5}[/tex]/ 1.6 * [tex]10^{-19}[/tex] sin (35)

r = 1.09 * [tex]10^{-4}[/tex] m

b)  far forward will the electron have moved after completing one circle will be equal to circumference of the circle = 2πr

 = 2 * 3.14 * 1.09 * [tex]10^{-4}[/tex] m  = 6.845 *  [tex]10^{-4}[/tex] m  

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