The following reaction was performed in a sealed vessel at 734 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3.75M and [I2]=2.15M . The equilibrium concentration of I2 is 0.0800 M . What is the equilibrium constant, Kc, for the reaction at this temperature? Express your answer numerically.

Answer:

1 inch = 2.54 centimeters

Explanation:

A conversion factor or unit conversion is used to change the units only without affecting the value.

1 inch = 2.54 centimeters

Given, height = 65 inches

So, the height of  that person in centimeters = 65 x 2.54

                                                                         = 165.1 cm    

Hence, the person's height in centimeters will be 165.1 cm.

Answer:

1.20 × 10⁻³ mol e⁻

Explanation:

There is some info missing. I think this is the original question.

Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.

Step 1: Given data

Step 2: Calculate the charge, in Coulomb, that travel through the wire

We will find the circulating charge (q) using the following expression.

[tex]q = I \times t = \frac{0.880C}{s} \times 132s = 116C[/tex]

Step 3: Calculate the moles of electrons with a charge of 116 C

We will use the relationship 1 mole of electrons = 96,486 C (Faraday's constant)

[tex]116C \times \frac{1mol\ e^{-} }{96,486 C} =1.20 \times 10^{-3} mol\ e^{-}[/tex]

Answer:

C

Explanation:

The correct option is C and the anming is 2-ethyl-3-methylhexane.

Isomers are compounds that have the same molecular formula but different structural formula; that s the way in which the atoms are arranged.

The Molecular formula of nonane is C9H20.

Answer:

C

Explanation:

Answer:

because no 2 or 3 bond so it is saturated

Answer:

(b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen.

Explanation:

The law of definite proportion states that a gen chemical compound always contains its constituent elements in a fixed ratio by mass, independent on the method of preparation.

The molar mass of Nitrogen and Oxygen would always remain the same, allowing for exact reactant masses (or mole ratio) irrespective of the given amount of sample.

Answer:

the reaction associated with the ionization energy of lithium

Explanation:

An endothermic process is any process which requires or absorbs energy from its surroundings, usually in the form of heat.

the reaction associated with the ionization energy of lithium:

Ionization energy is endothermic because it requires an energy input to occur, we need to supply energy to remove that outermost electron.

the formation of CO2 from its elements in their standard states:

This reaction is exothermic, heat is released per mole of CO2 formed.

the reaction associated with the heat of formation of Sr S:

Heat is giving off, so the process is an exothermic process.

the reaction associated with the lattice energy of Na Br:

Lattice energy is exothermic. Lattice energy is the energy released when gaseous cations and anions associate with each other to form a solid.

Answer:

87.3

Explanation:

To calculate the relative atomic mass

((84.9*15)+(86.9*12.9)+(87.9*72.1))/15+12.9+72.1

(1273.5 + 1121.01 + 6337.59) / 100

8732.1/100

87.321 = 87.3

Answer:

0.24375moles

Explanation:

Moles=mass/moler mass

Fe-56

O-16

(56×2)+(16×4)

=176

42.9÷176=0.24375moles

Answer:

CuI₂ + Br₂

Explanation:

Answer:

CuI₂ + Br₂

Explanation:

1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).

The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.

2) Choice 1: CuI₂ + Br₂

Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:

CuI₂ + Br₂ → CuBr₂ + I₂

Being I less active than Br, it cannot displace Br in CuBr₂.

3) Choice 2: Cl₂ + AlF₃

Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.

4) Choice 3: Br₂ + NaCl

Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.

5) Choice 4: CuF₂ + I₂

Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.

hope this helped!

Explanation:

The answer is the Calcium ion. It satisfies the conditions of the question.

Condition 1

The net ionic charge is one-tenth the nuclear charge.

In the Calcium ion,  Ca²⁺. The nuclear charge in this ion is 20. The net ionic charge is 2.

2 / 20 = 1 / 10. So the net ionic charge is indeed one tenth of the nuclear charge.

Condition 2

The number of neutrons is four more than the number of electrons.

Mass Number of Ca²⁺ = 44

Atomic Number = 20

Neutrons =  Mass Number - Atomic Number = 44 -20 = 24

Number of electrons = 20 - 2 = 18

Since Number of Neutrons = 22, Number of electrons = 18. This condition also holds.

As an ion and as an isotope = Ca²⁺, Ca - 42

Answer:

pH =1 2.84

Explanation:

First we have to start with the reaction between HCl and KOH:

[tex]HCl~+~KOH->~H_2O~+~KCl[/tex]

Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:

[tex]M=\frac{mol}{L}[/tex]

We know that [tex]10mL=0.01L [/tex] and we have the concentration of the HCl [tex]0.282M[/tex], when we plug the values into the equation we got:

[tex]0.282M=\frac{mol}{0.01L}[/tex]

[tex]mol=0.282*0.01 [/tex]

[tex]mol=0.00282[/tex]

We can do the same for the KOH values ([tex]50mL=0.05L[/tex] and [tex]0.141M[/tex]).

[tex]0.141M=\frac{mol}{0.05L}[/tex]

[tex]mol=0.141*0.05 [/tex]

[tex]mol=0.00705[/tex]

So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:

[tex]0.00705-0.00282=0.00423mol~of~KOH[/tex]

Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:

[tex]Total~volume=50mL+10mL=60mL[/tex]

[tex]60mL=0.06L[/tex]

Now we can calculate the concentration:

[tex]M=\frac{0.00423mol}{0.06L}[/tex]

[tex]M=0.0705[/tex]

Now, we can calculate the pOH (to calculate the pH), so:

[tex]pOH=-Log(0.0705)[/tex]

[tex]pOH=1.15[/tex]

Now we can calculate the pH value:

[tex]14=~pH~+~pOH[/tex]

[tex]pH=14-1.15=12.84[/tex]

Answer:

growth hormone is ur answer

Answer:

Explanation:

two hormones are secreted from posterior lobe i.e. oxytocin and vasopressin

Answer:

A

Explanation:

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618 [tex]\times[/tex] 0.067302) + ( ? [tex]\times[/tex] (1-0.067302)

39.0983 = 2.756811064 + ( ? [tex]\times[/tex] 0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ? [tex]\times[/tex] 0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

Answer:

38.96383282 amu

Explanation:

39.0983 = (40.9618  0.067302) + ( ?  (1-0.067302)

39.0983 = 2.756811064 + ( ?  0.932698)

subtract 2.756811064 from both sides

36.34148894 = ( ?  0.932698)

divide both sides by 0.932698

? = 38.96383282 amu

Answer:

The rate at which dihydrogen gas is being produced = 0.018 kg/s

Explanation:

Firstly, we write the balanced equation for the production of the synthesis gas

CH₄ + H₂O → CO + 3H₂

The rate of consumption of CH₄ is 159 litres per second. With the reaction ran at T = 294°C and a pressure of 0.86 atm

Using the ideal gas equation, we can convert the volumetric rate of consumption of methane to molar rate of consumption

PV = nRT

PV' = n'RT

P = pressure = 0.86 atm = 87,139.5 Pa

V' = 159 L/s = 0.159 m³/s

n' = ?

R = molar gas constant = 8.314 J/mol.K

T = absolute temperature in Kelvin = 294°C = 567.15 K

87,139.5 × 0.159 = n' × 8.314 × 567.15

n' = (87,139.5 × 0.159) ÷ (8.314 × 567.15)

n' = 2.9383547773 mol/s = 2.938 mol/s

From the stoichiometry of this reaction,

1 mole of methane gives 3 moles of dihydrogen gas

2.938 mol/s of methane will correspond to (3 × 2.938) mol/s of dihydrogen gas, that is, 8.815 mol/s.

Mass flowrate = (molar flowrate) × (molar mass)

Molar flowrate = 8.815 mol/s

Molar mass of dihydrogen gas = 2 g/mol = 0.002 kg/mol

Mass flowrate = 8.815 × 0.002 = 0.0176301287 kg/s = 0.018 kg/s to 2 s.f.

Hope this Helps!!!

Complete Question:

The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen.

Suppose a chemical engineer studying a new catalyst for the reform reaction finds that 924. liters per second of methane are consumed when the reaction is run at 261.°C and 0.96atm. Calculate the rate at which dihydrogen is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.

Answer:

Rate at which H₂ is produced = 0.12 kg/s

Explanation:

Volume of methane produced, V = 924 litres

Temperature, T = 261.°C = 261 + 273

T = 534 K

Pressure, P = 0.96 atm

Gas constant, R = 0.0821 L-atm/ K-mol

We will calculate the number of  moles of methane used in the reaction.

[tex]n_{methane} = \frac{PV}{RT} \\n_{methane} = \frac{0.96 * 924}{0.0821 * 534} \\n_{methane} = \frac{887.04}{43.8414}\\n_{methane} = 20.23 moles[/tex]

Equation of reaction:

[tex]CH_{4} + H_{2} O \rightarrow CO + 3H_{2}[/tex]

From the reaction above :

1 mole of methane produced 3 moles of H₂

20.23 moles of methane will produce (20.23 * 3 ) moles of H₂

Number of moles of H₂, [tex]n_{H_{2} } = 60.69 moles[/tex]

That is 60.69 moles of hydrogen is produced per second.

Number of moles = Mass/ Molar mass

[tex]n_{H_{2} } = \frac{Mass_{H_{2} }}{Molar mass_{H_{2} }} \\Mass_{H_{2}} = n_{H_{2} } * Molar mass_{H_{2} }\\Mass_{H_{2}} = 60.69 * 2.016\\Mass_{H_{2}} = 122.35 g[/tex]

Rate at which H₂ is produced = 122.35 g/s = 0.12 kg/s

Answer:

a) Methylcyclohexanol = 1-methylcyclohex-1-ene and methylenecyclohexane

b) 2-methyl-2-hexanol = 2-methylhex-1-ene and 2-methylhex-2-ene

Explanation:

We have to remember that the dehydration of alcohols follows the Zaitsev rule. So, the most substituted alkene would be the major product for both molecules

In the case of methylcyclohexanol we have several options to put the double bond. Inside of the cyclic structure (1-methylcyclohex-1-ene) or between the cyclic structure and the methyl group (methylenecyclohexane). The most substituted one is 1-methylcyclohex-1-ene, so this is our major product.

In the case of 2-methyl-2-hexanol we have again several options for the double bond. Between the tertiary carbon (the carbon that holds the "OH" group) and the carbon in the left (2-methylhex-2-ene). The other option is to put the double between the tertiary carbon the carbon in the right (2-methylhex-1-ene). The most substituted one is 2-methylhex-2-ene, so this is our major product.

See figure 1

I hope it helps!

Answer:

Yes that is why you can even see how some chemicals might react but that is if you are not considering temperature, pressure, or if catalyst are involved.

Answer:

Explanation:

One CH4 molecules = 10 electrons ( Carbon 6e + 4Hydrogen 4e)

A mole of any substance witll have = 6.023*10^23 atom/ molecuels,

One mole of any substnce is equal is nothing but its moalr mass

Molar mass of CH4 = 16.04

It mean,

16.04  g of CH4 has = 6.023*10^23 molecules of methane

but

4.2 gram of CH4   = 6.023*10^23 * 4.2 /16.04 = 1.58*10^23 molecuels of CH4

So one molecule has =10 electrons

1.58*10^23 molecuels will have = 1.58*10^23  * 10 = 1.58*10^24

Hope this help you

Complete Question

The complete question is shown on the first uploaded image

Answer:

 The kinetic order in HI is x=  2

Explanation:

Generally the slow step in a reaction mechanism is the rate determining step

  Now with this knowledge at the back of our minds we can see that  the number of moles of HI i s 2 which implies that the order of HI is 2m

So we can represent the rate law as

        [tex]Rate = k [CH_3 CHCH_2][HI]^2[/tex]

hence

x =  2

Complete Question

The complete question is shown on the first uploaded image

Answer:

The rate constant is  [tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]

Explanation:

From the question we are told that

The values for an enzyme is given as

     [tex]D_1 = 1.00 *10^{-7} \ cm^2 s^{-1}[/tex]

     [tex]r_1 = 40.0 \r A = 40*10^{-8} cm[/tex]

The values of a small molecular substrate is

     [tex]D_2 = 1.00 *10^{-5} \ cm^2 s^{-1}[/tex]

      [tex]r_2 = 5.00 \r A = 5.00*10^{-8} \ cm[/tex]

The equation relating the rate constant  is

      [tex]k_d = 4 \pi N_A (D_1 +D_2) (r_1 +r_2)[/tex]

substituting values

      [tex]k_d = 4 \pi (6.022 *10^{23})(1 *10^{-7} * 1*10^{-5} (40*10^{-8} + 5*10^{-8}))[/tex]

     [tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]

Answer:

Kc = 15.25

Explanation:

In this case, As I say in the comments, you are missing the following data of moles and volume which are:

Initial moles of ammonia = 29 mol

Final moles of nitrogen = 13 mol

Volume tank = 75 L

Now, if your data is different, just replace the values and follow the same procedure written here to get the accurate result.

With these data, let's write the equilibrium reaction that is taking place here:

2NH₃ <---------> N₂ + 3H₂     Kc = ?

To get the Kc, we need to use the following expression:

Kc = [N₂] [H₂]³ / [NH₃]²

This expression is only usable when we reach the equilibrium. But we don't have the concentrations in equilibrium of any species, so, we need to get those values. To get that, we need to do an ICE chart, write the initial and final concentrations given, and then, replace the values.

First, the concentrations of the species are:

[NH₃] = 29 / 75 = 0.3867 M

[N₂] = 13 / 75 = 0.1733 M

Now that we have these values, we will replace them in the ICE chart, and then, rewrite the Kc expression to get that value so:

       2NH₃ <---------> N₂ + 3H₂     Kc = ?

i)     0.3867               0        0

c)       -2x                 +x      +3x

e)   0.3867-2x          x         3x

However, as we already have the value for concentration of nitrogen, this will be the value of "x", therefore, our final values in equilibrium would be:

[NH₃] = 0.3867 - 2(0.1733) = 0.0401 M

[H₂] = 3(0.1733) = 0.5199 M

Now with these values, we can replace them in the Kc expression to get that value so:

Kc = (0.5199)³ * (0.1733) / (0.0401)²

Kc = 0.0244 / 0.0016

Kc = 15.25

And this is the value of Kc for this reaction.

Answer:

ΔGrxn for the reaction A(g)→B(g) will most likely to be negative under the PA=10.0atm ; PB=0.050atm condition

The FIRST option is correct

Explanation:

From Thermodynamics,

Using the Gibbs Free Energy (G) formula to determine the reaction A(g)→B(g) most likely to be negative.

Gibbs Free Energy (G) which is the energy associated with a chemical reaction that can be used to do work.

CHECK THE ATTACHMENT FOR THE DETAITALED EXPLANATION

Answer:

[tex]V_{HCl}=80mL[/tex]

Explanation:

Hello,

In this case, for the given reactants we identify the following chemical reaction:

[tex]KOH+HCl\rightarrow KCl+H_2O[/tex]

Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:

[tex]n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}[/tex]

Hence, we compute the volume of HCl as shown below:

[tex]V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL[/tex]

Best regards.

Answer: 44.8 L

Explanation:

To find the volume, we would need to use the ideal gas law.

Ideal Gas Law: PV=nRT

We take the given information and plug it into the equation, but first, we have to manipulate the equation so that we are finding volume.

[tex]V=\frac{nRT}{P}[/tex]

P= 1.00 atm (STP)

T= 273.15 K (STP)

R= 0.08206 Latm/Kmol

n= [tex]64g*\frac{1mol}{31.998 g O_{2} }=2 mol[/tex]

[tex]V=\frac{(2 mol)(0.08206Latm/Kmol)(273.15 K)}{1.00atm} =44.8 L[/tex]

Answer:

Which equation represents the reaction of a weak acid with water?  the equation is : HCl + H2O H3O+ + Cl- HCO3– + H2O H2CO3 + OH– H2O H + + OH- HCOOH + H2O H3O+ + HCOO

Explanation:

hope it helps : )

Answer:

Hey mate, here is your answer. Hope it helps you.

HCOOH + H2O ↔ H3O+ + HCOO-

Explanation:-

A strong acid is one which completely dissociates into its corresponding ions in aqueous medium.

In contrast,  a weak will only partially dissociate such that there is an equilibrium between the dissociated ions and the undissociated acid.

In the given examples:

HCl, HCO3- and H2CO3 are all strong acids. However, HCOOH i.e. formic acid is a weak acid which dissociates in water to form H3O+ and formate ion, HCOO-

HCOOH + H2O ↔ H3O+ + HCOO-

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

Regards.

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

A substance is acting as oxidising agent when is reducing its chemical state in the reaction.

In HNO3, Nitrogen has an oxidation state of +5 (Each oxygen is -2, 3 oxygens, -6, 1 hydrogen, +1). Thus, if the oxidation state of the nitrogen in the products is < +5, the nitrogen is reducing its oxidation state acting as oxidising agent.

In the reactions:

A. CuO + 2HNO3 → Cu(NO3)2 + H2O . In Cu(NO₃)₂, Nitrogen has an oxidation state of +5. Thus, nitric acid is not acting as oxidising agent.

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 . Also, oxidation state in Cu(NO₃)₂ does not have any change but there is another product, NO₂, where nitrogen has an oxidation state of +4. That means nitric acid is acting as oxidising agent.

C. Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2 . Here, in NaNO₃, oxidation state of nitrogen is +5 (Na: +1, 3 O: -6). Thus, nitrogen is not changing is oxidation state and nitric acid is not acting as oxidising agent.

D. NaOH + HNO3 → NaNO3 + H2O. Here, also, the product is NaNO₃. That means nitric acid is not acting as oxidising agent.

In order to use the energy stored in fat, the body breaks dow triglycerides into fatty acids, which individual cells burn for energy

Answer:

(D) - 16.6 kcal

Explanation:

Hello,

In this case, the Gibbs free energy for the given reaction is computed in terms of the Gibbs free energy of formation of each species involved in the chemical reaction:

[tex]\Delta _rG=2\Delta _fG_{NO_2}-2\Delta _fG_{NO}-\Delta _fG_{O_2}[/tex]

Thus, it is found for nitrogen monoxide, oxygen and nitrogen dioxide the following Gibbs free energies of formation: 87.6, 0 and 51.3 kJ/mol respectively, therefore we compute:

[tex]\Delta _rG=2(51.3kJ/mol)-2(87.6kJ/mol)=-72.6kJ*\frac{1kcal}{4.184kJ} \\\\\Delta _rG=-17.35kcal[/tex]

The closest result is (D) - 16.6 kcal, as such difference is noticed when different sources for thermochemical data are used, in this case, the NIST data were used.

Best regards.

Answer:

THE MOLECULAR FORMULA FOR THE COMPOUND IS C2 Cl2

Explanation:

mass = 0.04380 g

Volume = 10 mL = 10 / 1000 L = 0.010 L

Pressure = 1.10 atm

R = 0.082 L atm mol^-1 K^-1

Temperature = 290.5 K

Carbon = 25.305 %

Chlorine = 74.695 %

Atomic mass of carbon = 12

Atomic mass of chlorine = 35.5

First calculate the empirical formula by following these steps:

1. Write the percentage composition of the elements involved and divide by its atomic mass

Carbon = 25.305 / 12 = 2.10875

Chlorine = 74.695 /35.5 = 2.1040

2. Divide each by the smaller value

Carbon = 2.10875 / 2.1040 = 1.002

Chlorine = 2.1040 / 2.1040 = 1

3. Round up to the whole number

The empirical formula is C Cl

Next is to calculate the molar mass of the compound using ideal gas equation

PV = mRT/ MM

Mm = mRT / PV

Mm = 0.04380 * 0.082 * 290.5 / 1.10 * 0.010

Mm = 1.0433 / 0.011

Mm = 94.845 g/mol

Mm = 94.85 g/mol

Now that we know the molar mass, we can go on to calculate the molecular formula:

(C Cl) n = Molar mass

( 12 + 35.5) n = 94.85

(47.5)n = 94.85

n = 94.85 / 47.5

n = 1.9968

n ~ 2

The molecular formula can then be written as C2Cl2.