The distance from city a to city b is 256. 8 miles. The distance from city a to city c is 739. 4 miles how much farther is the trip to city c than the trip to city b

Answer:

29

Step-by-step explanation:

To solve this we have to add corresponding line segments and make them equal to each other.

We can see XZ is broken into XA and AZ.

We can also see that WY is broken into WA and AY.

We are given:

XA=12

AY=14

WA=3+3x

AZ=4x+1

So, we combine and make them equal to each based on their whole line segments:

[tex]12+4x+1=3+3x+14[/tex]

combine like terms

[tex]13+4x=17+3x[/tex]

subtract 13 from both sides

[tex]4x=4+3x[/tex]

subtract 3x from both sides

x=4

We aren't done yet, because the question is asking us to find XZ which is 12+4x+1:

substitute 4 for x

12+4(4)+1

multiply

12+16+1

=29

So, XZ is 29 units.

Hope this helps! :)

The probability of 3 rainy days in a row when the probability of rain on each single day is 56% ≈ 17.6%

The probability of 3 sunny days in a row when the probability of rain on each single day is 56% ≈ 8.5%

To determine the probability of 3 rainy days in a row, you need to multiply the probability of rain on each single day (56%). In percent form, this would be:

56% × 56% × 56% = 0.56 × 0.56 × 0.56 ≈ 0.175616

To express this as a percentage rounded to the nearest tenth, we have:

0.175616 × 100% ≈ 17.6%

Now, to determine the probability of 3 sunny days in a row, you first need to find the probability of a sunny day, which is the complement of the probability of rain:

100% - 56% = 44%

Next, multiply the probability of a sunny day (44%) for three days:

44% × 44% × 44% = 0.44 × 0.44 × 0.44 ≈ 0.085184

To express this as a percentage rounded to the nearest tenth, we have:

0.085184 × 100% ≈ 8.5%

So, the probability of 3 rainy days in a row is approximately 17.6%, and the probability of 3 sunny days in a row is approximately 8.5%.

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1. The price-demand equation for the trumpets is:

   x = 238.18 - 1.09p

2. The manufacturer should set the price of each trumpet at $296.50  to break even        

3. The manufacturer should set the price of each trumpet at $138.63 to maximize profit.

In this problem, the manufacturer has conducted a customer survey and found out that the price of each trumpet affects the demand for it. We need to analyze this data and come up with a price-demand equation that helps the manufacturer set the price of each trumpet to maximize profit.

To start with, we need to assume a linear model, where the demand for the trumpets is directly proportional to the price. We can represent the demand as "x" and the price as "p". Using the data from the survey, we can form two linear equations:

110 = ap + b     (1)

128 = cp + d    (2)

Here, a, b, c, and d are constants that we need to find. We can solve these equations simultaneously to get the values of a, b, c, and d.

Subtracting equation (2) from equation (1), we get:

-18 = (a-c)p + (b-d)   (3)

Dividing both sides of equation (3) by -18, we get:

p = (d-b)/(c-a)          (4)

Using equation (4), we can find the value of p, which is the price at which the demand for trumpets is equal to the values obtained from the survey. Substituting the values from either equation (1) or (2) into equation (4), we get:

p = ($160.74 x 110 - $220.18 x 128)/(-18 x 110 + 18 x 128)

  = $186.46

Therefore, the price-demand equation for the trumpets is:

x = 238.18 - 1.09p

To answer the second question, we need to find the price of each trumpet at which the manufacturer will break even. In other words, the revenue earned from selling the trumpets should be equal to the total cost incurred in making and selling them.

We know that the one-time cost of buying equipment is $3274.78, and each trumpet costs $90.05 to make. Let's represent the break-even price as "[tex]P_{be}[/tex]". Then we can form the following equation:

110[tex]P_{be}[/tex] = 3274.78 + 110 x 90.05

Solving for [tex]P_{be}[/tex], we get:

[tex]P_{be}[/tex]= $296.50

Therefore, the manufacturer should set the price of each trumpet at $296.50 to break even.

To answer the third question, we need to find the price of each trumpet that maximizes the profit for the manufacturer.

The profit is given by the revenue earned minus the total cost incurred. Let's represent the profit as "P" and the price as "p". Then the profit equation becomes:

P = xp - (3274.78 + 90.05x)

To find the price that maximizes profit, we need to take the derivative of the profit equation with respect to p and equate it to zero.

dP/dp = x - 90.05 = 0

Solving for x, we get:

x = 90.05

Substituting this value of x into the price-demand equation, we get:

p = $138.63

Therefore, the manufacturer should set the price of each trumpet at $138.63 to maximize profit.

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The dimensions of the poster with an area of 392 square inches is equal to 14 inches and 28 inches.

Area of rectangular poster to print = 392 square inches

Let us assume that dimensions of the posters are,

Width of the poster is x inches and the length of the poster is y inches.

Area of the rectangular poster is,

xy = 392

Add 2 inches to the top and bottom margins for a total of 4 inches

And 1 inch to the left and right margins for a total of 2 inches.

Total area of the poster including the margins using the following equation,

Total area = (x + 2) × (y + 4)

Minimize the total area of the poster while still satisfying the area constraint.

Use the first equation to solve for one variable

And substitute it into the second equation,

y = 392/x

Total area = (x + 2) × (392/x + 4)

⇒ Total area = 4x + 392 +784/x + 8

⇒Total area = 4x + 400 +784/x

Minimize the total area, take the derivative of this expression with respect to x and set it equal to 0,

d/dx (4x + 400 +784/x ) = 0

⇒  4 + 0 - 784/x² = 0

⇒ x² = 784 /4

⇒ x = 14

Substituting this value of x back into the equation for y, we get,

y = 392/14

  = 28

Therefore, the dimensions of the poster should be 14 inches by 28 inches.

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The correct option is D, the statement that best describes the expression 4+3x means "4 plus 3 times x".

An expression is a combination of numbers, symbols, and/or variables that represents a mathematical or logical statement. It can be as simple as a single number or letter, or as complex as a series of operations that involve multiple variables and functions. Expressions can be used to represent equations, inequalities, functions, and other mathematical concepts. They can be evaluated to produce a numerical value or a boolean value (true or false) depending on the values of the variables involved.

Expressions are used to represent calculations or logical conditions. They can be used to assign values to variables, manipulate data, and control the flow of a program. expressions are a fundamental concept in both mathematics and computer science, and play a critical role in solving problems and building complex systems.

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Out of 25 students in the class, 40% are male is: Descriptive statistics.

Descriptive statistics is the process of summarizing and organizing data from a sample or population in order to provide an overview of the main characteristics. In this case, the data provided tells us that out of 25 students in the class, 40% are male.

This information is a summary of the gender distribution within this specific class, rather than making any predictions or generalizations about a larger population.

In contrast, inferential statistics is the process of using data from a sample to make predictions or draw conclusions about a larger population. If we were given data about a sample of classes and asked to estimate the proportion of male students in all classes, that would be an example of inferential statistics.

To summarize, the situation you provided, which states that out of 25 students in the class, 40% are male, is an example of descriptive statistics as it only provides a summary of the data for that specific class.

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The length of the top of the ladder from the ground is 10m and the distance from wall to the bottom of ladder is 1.5m

Given that an ladder leans against a wall.

We have to find the length of the top of the ladder from the ground.

We know that tan function is the ratio of opposite side and adjacent side

Let x be the opposite side

tan 68 = x/4

2.475 = x/4

x= 4×2.475

x=9.9 m

x=10 m

So, the  length of the top of the ladder from the ground is 10m.

Now let us find the distance from wall to the bottom of ladder

cosine function is the ratio of adjacent side and hypotenuse

Cos 68 = x/4

0.374 =x/4

x=0.374×4

x=1.5m

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The required answer is x = 14

To solve this problem, we can use algebraic equations. Let's start by representing the number of points that Aisha has with the variable "x".

According to the problem, we know that Carter has 7.5 more points than Aisha, so we can write:
Carter = x + 7.5
An algebraic equation or polynomial equation is an equation in which both sides are polynomials (see also system of polynomial equations). These are further classified by degree: linear equation for degree one. quadratic equation for degree two.

We also know that Jamila has 4.5 more points than Carter, which means:

Jamila = (x + 7.5) + 4.5

a variable (from Latin variabilis, "changeable") is a symbol that represents a mathematical object. A variable may represent a number, a vector, a matrix, a function, the argument of a function, a set, or an element of a set.

Algebraic computations with variables as if they were explicit numbers solve a range of problems in a single computation. For example, the quadratic formula solves any quadratic equation by substituting the numeric values of the coefficients of that equation for the variables that represent them in the quadratic formula. In mathematical logic, a variable is either a symbol representing an unspecified term of the theory (a meta-variable), or a basic object of the theory that is manipulated without referring to its possible intuitive interpretation.
Finally, we know that Jamila has 26 points:

Jamila = 26

Now we can solve for x:

(x + 7.5) + 4.5 = 26

x + 12 = 26

x = 14

Therefore, Aisha has 14 points.

To show the work:

Aisha = x

Carter = x + 7.5

Jamila = (x + 7.5) + 4.5

Jamila = 26

(x + 7.5) + 4.5 = 26

x + 12 = 26

x = 14

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The width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

To solve the problem, we can draw a diagram and use the properties of ellipses.

First, we note that the major axis of the ellipse is 110 yards and the minor axis is 50 yards. We can find the distance between the two foci of the ellipse using the formula c^2 = a^2 - b^2, where c is the distance between the foci, and a and b are the lengths of the semi-major and semi-minor axes.

c^2 = 110^2 - 50^2

c^2 = 10800

c ≈ 104.0

Next, we draw the two foci of the ellipse and the rectangle as shown in the diagram below. We are given that the width of the rectangle is 30 yards (15 yards from either vertex). x be the length of the rectangle.

      A          B

   +-------+-------+

  /                  \

 /                    \

/                      \

C                        D

\                      /

 \                    /

  \                  /

   +-------+-------+

      E          F

We can see that the length of the rectangle is equal to the distance between points A and B, and the width of the rectangle is equal to the distance between points C and D. Using the Pythagorean theorem, we can find the length of the rectangle.

AB^2 = AE^2 + EB^2

AB^2 = (a/2)^2 + (c - b/2)^2

AB^2 = (55)^2 + (104 - 15)^2

AB^2 = 3025 + 7225

AB = sqrt(10250)

AB ≈ 101.2

Therefore, the length of the rectangle is approximately 101.2 yards.

To find the width of the rectangle, we can use the fact that the distance between points C and D is equal to twice the distance between the center of the ellipse and the minor axis. The center of the ellipse is the midpoint of the major axis, and the distance from the center to the minor axis is 25 yards.

CD = 2 * 25 = 50

Therefore, the width of the rectangle is approximately 50 yards.

In summary, the width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

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Willka would need approximately 0.2222 L of paint to cover 1 m² and approximately 2.2222 L of paint to cover 10 m².

Willka can cover 13.5 m² with 3 liters of paint. To find equivalent ratios, we can determine how much paint is needed to cover 1 m² and then use that to find how much paint is required for other areas.

To find the amount of paint needed for 1 m², divide the area covered by the paint used:
1 m² = (13.5 m²)/(3 L) = 4.5 m²/L

Now, we can use this ratio to complete the table:

Area covered (m²) - Paint (L)
13.5               - 3
1                  - (1/4.5) = 0.2222 L (approximately)
10                 - (10/4.5) = 2.2222 L (approximately)

So, the completed table is:

Area covered (m²) - Paint (L)
13.5               - 3
1                  - 0.2222
10                 - 2.2222

Using equivalent ratios, Willka would need approximately 0.2222 L of paint to cover 1 m² and approximately 2.2222 L of paint to cover 10 m².

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Answer:2,2

Step-by-step explanation:

The four ordered pairs relating the side length and the corresponding perimeter are (3,20), (4,24), (5,28), and (6,32).

The rule "Add 2" to the side length of a square means that if the original side length is x, the new side length will be x+2.

The rule "Add 8" to the square's perimeter means that if the original perimeter is 4x (since a square has four equal sides), the new perimeter will be 4(x+2), which simplifies to 4x+8.

To find four ordered pairs relating the side length and corresponding perimeter, we can plug in different values for x and use the above formulas to calculate the corresponding perimeters. For example, if we choose x=3, the new side length will be 3+2=5, and the new perimeter will be 4(3+2)=20. So, one ordered pair would be (3,20).

Similarly, if we choose x=4, the new side length will be 4+2=6, and the new perimeter will be 4(4+2)=24. So, another ordered pair would be (4,24).

By choosing different values for x, we can find four ordered pairs that relate the side length and corresponding perimeter. These ordered pairs are (3,20), (4,24), (5,28), and (6,32).

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The translation of the graph from y = x² to y = (x - 2)² +1 is describe by - B.   shift of 2 units left and then shift of 1 unit up.

In geometry, a translation is a transfer that occurs either horizontally to a left or right as well as vertically up or down. It may also consist of a mix of the two.

Given data:

Parent function- y = x²

New function -  y = (x - 2)² +1

Thus, the translation of the graph from y = x² to y = (x - 2)² +1 is describe by - B.   shift of 2 units left and then shift of 1 unit up.

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Complete question:

1. Which of the following most accurately describes the translation of the graph from y = x² to y = (x - 2)² +1?

A.  shift of 2 units right and then shift of 1 unit up.

B.   shift of 2 units left and then shift of 1 unit up.

If The area of a triangle is (27 + 13sqrt(2)) square feet. if the length of the base is (6 + sqrt(2)) feet, then the triangle's height is (27 - 13sqrt(2)) / 17 feet.

We are given the area A and the length of the base b. We can use this information to solve for the height h as follows:

A = (1/2)bh

2A = bh

h = (2A)/b

Substituting the given values, we get:

h = (2(27 + 13sqrt(2))) / (6 + sqrt(2))

We can simplify this expression by rationalizing the denominator as follows:

h = [(2(27 + 13sqrt(2))) / (6 + sqrt(2))] * [(6 - sqrt(2))/(6 - sqrt(2))]

h = [(54 - 26sqrt(2)) / (34)]

h = (27 - 13sqrt(2)) / 17

Therefore, the triangle's height is (27 - 13sqrt(2)) / 17 feet.

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The area of the wrapping paper would be = 72.5in².

To calculate the area of the wrapping paper, the figure is first divided into two leading to the formation of a triangle and a rectangle.

For the triangle, the formula use to calculate it's area is given as follows;

Area = 1/2 base × height

base = 15-10 = 5 in

height = 9-4 = 5 in

area = 1/2×5 × 5

= 25/2 = 12.5 in²

Area of a rectangle = length× width

width = 4 in

length = 15 in

area = 4×15 = 60in²

Therefore the area of the wrapping paper = 12.5+60 = 72.5in²

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Dexter has a better chance of winning in the long run with an expected value of $4/3 per game, while Thanh has an expected loss of $1/3 per game.

This is a game of probability that involves calculating expected values. Let's first calculate the probability of drawing a black chip:

Probability of drawing a black chip = (number of black chips) / (total number of chips) = 10 / 15 = 2/3

Similarly, the probability of drawing a white chip can be calculated as:

Probability of drawing a white chip = (number of white chips) / (total number of chips) = 5 / 15 = 1/3

Now, we can calculate the expected value of winning for each player.

For Dexter:

- If he draws a black chip, he will win $7 with probability 2/3

- If he draws a white chip, he will lose $10 with probability 1/3

Expected value of winning for Dexter = (7 x 2/3) + (-10 x 1/3) = 4/3

This means that on average, Dexter will win $4/3 per game.

For Thanh:

- If Dexter draws a black chip, Thanh will lose $7 with probability 2/3

- If Dexter draws a white chip, Thanh will win $10 with probability 1/3

Expected value of winning for Thanh = (-7 x 2/3) + (10 x 1/3) = 1/3

This means that on average, Thanh will win $1/3 per game.

So, based on these calculations, Dexter has a better chance of winning in the long run with an expected value of $4/3 per game, while Thanh has an expected loss of $1/3 per game.

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The volume of the block of wood is 78 cubic inches.

What is cube?

A cube is a three-dimensional geometric shape that has six equal square faces, 12 equal edges, and eight vertices (corners). All the angles between the faces and edges of a cube are right angles (90 degrees), and all the edges are of equal length. A cube is a special type of rectangular prism where all the sides are equal in length, making it a regular polyhedron.

To find the volume of the block of wood, you need to multiply its length, width, and height together.

Volume = length x width x height

Volume = 6.5 inches x 1.5 inches x 8 inches

Volume = 78 cubic inches

Therefore, the volume of the block of wood is 78 cubic inches.

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The equilibrium quantity is approximately 34.47 items and the producer surplus at the equilibrium quantity is approximately 396.11.

To find the equilibrium quantity, we need to find the quantity at which the demand and supply functions are equal:

Demand function: d(x) = 588.7 – 0.4x^2

Supply function: s(x) = 8(x) = 0.322

Setting these two functions equal to each other, we get:

588.7 – 0.4x^2 = 0.322x

Simplifying this equation, we get:

0.4x^2 + 0.322x - 588.7 = 0

Using the quadratic formula, we get:

x = (-0.322 ± √(0.322^2 + 40.4588.7)) / (2*0.4)

x ≈ 34.47 or x ≈ -43.67

Since we cannot have a negative quantity, the equilibrium quantity is approximately 34.47 items.

To find the producer surplus at the equilibrium quantity, we need to calculate the area between the supply curve and the equilibrium price, which is the price that corresponds to the equilibrium quantity. We can find the equilibrium price by plugging the equilibrium quantity into either the demand or supply function:

s(34.47) = 8(34.47) = 11.58

So the equilibrium price is approximately 11.58.

Now we can find the producer surplus by integrating the supply function from 0 to the equilibrium quantity, and subtracting the result from the area of a rectangle with height equal to the equilibrium price and width equal to the equilibrium quantity. The formula for producer surplus is:

Producer Surplus = (Equilibrium Price * Equilibrium Quantity) - ∫[0, Equilibrium Quantity] Supply Function dx

Plugging in the values we found, we get:

Producer Surplus = (11.58 * 34.47) - ∫[0, 34.47] 0.322 dx

Integrating the supply function, we get:

∫[0, 34.47] 0.322 dx = 0.322 * 34.47 ≈ 11.10

So the producer surplus is:

Producer Surplus ≈ (11.58 * 34.47) - 11.10 ≈ 396.11

Therefore, the equilibrium quantity is approximately 34.47 items, and the producer surplus at the equilibrium quantity is approximately 396.11.

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Answer:

To gain our understanding of the plot (13, 10) on graph paper. We need to look at the picture reflecting or "flipping" that point over the x-axis. In this case, it "flips the point down"  the original point was in first quadrant or Quadrant |, the reflected point is in the fourth quadrant of Queadrant ||||.  The x coordinate would stay the same, but the new y coordinate would be the "opposite" sign of the original.  So the reflected point is (13, -10)

Step-by-step explanation:

(x, y) → (x, - y)

Reflection over x-axis for (13,-20) → (13, 20)

Technically some of the explanations is above /\

Thus the answer is, To gain our understanding of the plot (13, 10) on graph paper. We need to look at the picture reflecting or "flipping" that point over the x-axis. In this case, it "flips the point down"  the original point was in first quadrant or Quadrant |, the reflected point is in the fourth quadrant of Queadrant ||||.  The x coordinate would stay the same, but the new y coordinate would be the "opposite" sign of the original.  So the reflected point is (13, -10)

The possible set of values for a, b, and c could be: a=2, b=4, c=5.

Here is a possible set of values for a, b, and c,

- a = 2 (since there are 7 houses with 1-2 bedrooms and 8 houses in total, we know that there must be at least 1 more house with 1-2 bedrooms, which could be house a)
- b = 4 (since the median number of bedrooms is 3 and there are 7+1+1=9 houses total with either 1, 2, or 3 bedrooms, we know that the median house must have either 3 or 4 bedrooms. Since b must be different from a and c, we can assign it to 4)
- c = 5 (since there are only 3 houses left and we need to assign one to each remaining number of bedrooms, we can assign c to 5)

Therefore, a possible set of values for a, b, and c could be: a=2, b=4, c=5.

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Answer: Therefore, the angle of the terminal side through the point p is 315.0 degrees (to the nearest tenth of a degree).

Step-by-step explanation:

The point p = (-√2/2,√2/2) lies on the unit circle, which is centered at the origin (0,0) and has a radius of 1. To find the angle of the terminal side through this point, we need to use the trigonometric ratios of sine and cosine.

Recall that cosine is the x-coordinate of a point on the unit circle, and sine is the y-coordinate. Therefore, we have:

cos(θ) = -√2/2

sin(θ) = √2/2

We can use the inverse trigonometric functions to solve for θ. Taking the inverse cosine of -√2/2, we get:

θ = cos⁻¹(-√2/2)

Using a calculator, we find that θ is approximately 135.0 degrees.

However, we need to ensure that the angle is between 0 and 360 degrees. Since the point lies in the second quadrant (i.e., x < 0 and y > 0), we need to add 180 degrees to the angle we found. This gives:

θ = 135.0 + 180 = 315.0 degrees

The angle of the terminal side through the point p is 315.0 degrees (to the nearest tenth of a degree).

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The probability that a) the sample has a proportion between 0.5 and 0.7 is 0.780. b) The probability that the sample has a proportion within 5% is 0.819. c) The probability that the sample has a proportion less than 0.50 is 0.001. d) The probability that the sample has a proportion greater than 0.80 is 0.000.

a) To calculate this probability, we first need to standardize the interval (0.5, 0.7) using the formula: z = (p - P) / (σ / √(n))

where p is the sample b, P is the population proportion, σ is the standard deviation of sample proportions, and n is the sample size. Substituting the values, we get:

z1 = (0.5 - 0.62) / (0.8 / √(40)) = -2.24

z2 = (0.7 - 0.62) / (0.8 / √(40)) = 1.12

Using the standard normal table or calculator, the area between -2.24 and 1.12 is 0.780. Therefore, the probability that the sample has a proportion between 0.5 and 0.7 is 0.780.

b) The probability that the sample has a proportion within 5% of the population proportion is 0.819. We can find the range of sample proportions within 5% of the population proportion by adding and subtracting 5% of the population proportion from it, which gives: P ± 0.05P = 0.62 ± 0.031

The interval (0.589, 0.651) represents the range of sample proportions within 5% of the population proportion. To calculate the probability that the sample proportion falls within this interval, we standardize it using the formula above and find the area under the standard normal curve between -1.55 and 1.55, which is 0.819.

c) The probability that the sample has a proportion less than 0.50 is 0.001. To calculate this probability, we standardize the value of 0.50 using the formula above and find the area to the left of the resulting z-score, which is: z = (0.50 - 0.62) / (0.8 / √(40)) = -4.46

Using the standard normal table or calculator, the area to the left of -4.46 is 0.001. Therefore, the probability that the sample has a proportion less than 0.50 is 0.001.

d) The probability that the sample has a proportion greater than 0.80 is 0.000. To calculate this probability, we standardize the value of 0.80 using the formula above and find the area to the right of the resulting z-score, which is: z = (0.80 - 0.62) / (0.8 / √(40)) = 5.60

Using the standard normal table or calculator, the area to the right of 5.60 is very close to 0.000. Therefore, the probability that the sample has a proportion greater than 0.80 is 0.000.

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Corbin's account will have a higher balance than Victoria's account at the end of 3 years" is true.

To calculate the balance at the end of 3 years, we can use the simple interest formula for Victoria's account and the compound interest formula for Corbin's account.

For Victoria's account:

Simple interest = P * r * t

= 2000 * 0.05 * 3

= $300

Balance after 3 years = P + Simple interest

= 2000 + 300

= $2300

For Corbin's account:

Balance after 3 years = [tex]P * (1 + r)^t[/tex]

= 1800 * (1 + 0.09)³

= $2401.40

Therefore, the statement "Corbin's account will have a higher balance than Victoria's account at the end of 3 years" is true.

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Answer:

16.7 units

Step-by-step explanation:

its a 45°-45°-90° right triangle, so n1=4.9

r=4.9[tex]\sqrt{2}[/tex] =6.9

perimeter = 4.9+4.9+6.9=16.7 units

A relation is a set of ordered pairs that define the relationship between two sets. And, a function is a relation in which each element of the domain is connected to a single element of the codomain. The evaluated function is -10.

To find the expression (f(7) - f(3))/ 7 -3, we need to first find f(7) and f(3).

Using the given function F(X) = - 8 - x^2, we can find:

f(7) = -8 - 7^2 = -57

f(3) = -8 - 3^2 = -17

Now, we can substitute these values into the expression:

(f(7) - f(3))/ 7 -3 = (-57 - (-17))/ (7-3) = -40/4 = -10

Therefore, the answer is -10.
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The height of the house by the given data is 4000ft.

We are given that;

Number of BTUs for heating= 52000

Now,

The time from minutes to hours by dividing by 60:

t=606.24​ hr

t≈0.104 hr

Then, we can plug in the values into the heat loss formula and solve for A, which is the surface area of the house:

Q=UAΔTt

52,000=0.25A×50×0.104

A=0.25×50×0.10452,000​ ft2

A≈4000 ft2

Therefore, by the algebra the answer will be 4000 ft.

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Answer:3.75 BTUs/ft

height=18 ft

Step-by-step explanation:

The solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

To solve this system of linear equations, we can use Gaussian elimination, which involves adding and subtracting equations to eliminate variables. Here are the steps:

x - 3y - 2z = 6

2x - 4y - 3z = 8

-3x + 6y + 8z = -5

Step 1: Add twice the first equation to the second equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

-3x + 6y + 8z = -5

Step 2: Add three times the first equation to the third equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

9y + 2z = 13

Step 3: Solve for z in the second equation:

4y + z = 20

z = 20 - 4y

Step 4: Substitute z into the third equation and solve for y:

9y + 2z = 13

9y + 2(20 - 4y) = 13

y = -3

Step 5: Substitute y into the second equation and solve for z:

4y + z = 20

4(-3) + z = 20

z = 8

Step 6: Substitute y and z into the first equation and solve for x:

x - 3y - 2z = 6

x - 3(-3) - 2(8) = 6

x = 1

Therefore, the solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

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The text format of the question in the picture:

15. The solution the system of linear equation of

x-3y-2z = 6

2x-4y-3z = 8

(-3x+6y+8z = -5 is

A) X=-1,y=-3, z=-2 B) X=-1,y=-3, z=2 C) X=1,y=-3, z=2 D) X = 1, y = 3, z=-2

The 95% confidence interval for the population proportion of city dwellers who would like to live at the beach is estimated to be between 0.56 and 0.62.

A statistical inference  is a range of values within which the true value of a population parameter, such as the proportion of city dwellers who would like to live at the beach, is likely to fall with a certain level of confidence. In this case, the chamber of commerce for a beach town asked a random sample of city dwellers whether they would like to live at the beach, and based on the survey results, they constructed a 95% confidence interval for the population proportion.

The 95% confidence interval they obtained was (0.56, 0.62). This means that if they were to repeat their survey many times and construct a confidence interval each time, approximately 95% of those intervals would contain the true value of the population proportion.

In practical terms, this means that the chamber of commerce can be reasonably confident that the true proportion of city dwellers who would like to live at the beach falls somewhere between 0.56 and 0.62. It also suggests that the proportion of city dwellers who would like to live at the beach is relatively high, with more than half of the sample expressing a desire to do so. However, it is important to keep in mind that this confidence interval is based on a sample of city dwellers, and the true population proportion could differ from this estimate.

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The 95% confidence interval for the mean score for all bowlers in the league is option (E) (179.9, 192.1).

To construct a 95% confidence interval for the mean score for all bowlers in the league, we can use the formula:

CI = X ± z* (σ/√n)

where X is the sample mean, σ is the population standard deviation (unknown), n is the sample size, and z* is the critical value for the desired confidence level (95% in this case).

Since the sample size is 50, we can assume that the population standard deviation is approximately equal to the sample standard deviation, which is 22. The critical value for a 95% confidence interval with a two-tailed test is 1.96.

Substituting the values, we get:

CI = 186 ± 1.96 (22/√50)

  = 186 ± 6.44

  = (179.56, 192.44)

Therefore, the answer is (B) (177.66, 194.34), which is the closest to the calculated confidence interval.

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a. The property damage insurance covers the damage to the fence.

b. The insurance company will pay $7,000 - $1,000 = $6,000 for the fence damage.

c. The insurance company will pay $24,000 for the bus damage and $2,100 - $1,000 = $1,100 for the car damage.

d. The collision insurance policy covers the damage to Stewart's car.

e. The insurance company will pay $3,600 - $1,000 + $2,100 - $1,000 = $3,700 for the damage to the car.

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