The dean of students at a large college is interested in learning about their opinions regarding the percentage of


first-year students who should be given parking privileges in the main lot. He sends out an email survey to all


students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors


reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of


students who believe first-year students should be given parking privileges in the main lot to be (0. 71, 0. 79). Which


of the following may have an impact on the confidence interval, but is not accounted for by the margin of error?


O response bias


O nonresponse bias


O sampling variation


O undercoverage bias


Mark this and retum


Save and Exit


Next


Submit

Answer:  csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]

Step-by-step explanation:

The csc is related to sin

csc x =  1/sin x

find sin M first  then flip it to find csc M

sin M= opposite/hypotenuse

sin M= [tex]\frac{8}{\sqrt{86} }[/tex]                >flip that

csc M =  1/sin M

csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]              >root cannot be simplified it breaks down into 2 and 43

                                     which are 2 prime numbers

The intermediate step in completing the square for x^2= -16x-37 is (x+8)^2=27.

To complete the square for the given equation, we need to add a constant value to both sides of the equation such that we can factor the left-hand side as a perfect square.

x^2 + 16x = -37

To determine the constant value we need to add to both sides, we take half the coefficient of x (which is 16/2 = 8) and square it to get 64. Then we add 64 to both sides of the equation:

x^2 + 16x + 64 = 27

Now we can factor the left-hand side as a perfect square:

(x + 8)^2 = 27

So the intermediate step in completing the square for x^2= -16x-37 is (x+8)^2=27.

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1) The distance left in the race is  554.93km

2) The total amount earned is $2,178.91

We know that the total race is of 1000km, to find the distance missing, we need to take that total distance and subtract the amounts that the cyclist already traveled.

Then we will get:

distance left = 1000km - 145.8km - 136.65km - 162.62 km

distance left = 554.93km

That is the distance left in the race.

2) We know that each piece costs $19.99, and 109 pieces are sold, then the amount earned is the product between these two numbers.

Earnings = 109*$19.99  = $2,178.91

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The ratio of adult to boys is 35:24

A ratio is a comparison of two or more numbers that indicates their sizes in relation to each other. For example, if the ratio of boys to girls in a class is 4:1. This means that the for every 4 boys therefore is a girl.

Represent the total number of adult, boys and girls in the club by x

This means number of boys = 4/7× x

number of adult = 5/6 × x

Therefore the ratio of adults to boys will be

5x/6 : 4x/7

= 5/6 : 4/7

multiply through by 42

= 35 : 24

therefore the ratio of adult to boys is 35: 24

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The mean of a single roll is given as μ = 3.5, and the variance is given as [tex]σ^2[/tex] = 2.92.

The sample size for the first five rolls is n1 = 5, and the sample size for the remaining ten rolls is n2 = 10.

The mean of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

μ(x¯1−x¯2) = μ(x¯1) - μ(x¯2) = μ - μ = 0

The variance of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

σ^2(x¯1−x¯2) = (σ^2(x¯1)/n1) + (σ^2(x¯2)/n2)

where σ^2(x¯1) is the variance of the sample mean for the first five rolls and σ^2(x¯2) is the variance of the sample mean for the remaining ten rolls.

Since each roll of the die is independent, the variance of the sample mean for each sample is given as:

σ^2(x¯1) = σ^2/ n1 = 2.92/5 = 0.584

σ^2(x¯2) = σ^2/ n2 = 2.92/10 = 0.292

Substituting these values in the above equation, we get:

σ^2(x¯1−x¯2) = (0.584/5) + (0.292/10) = 0.1468

Therefore, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is:

σ(x¯1−x¯2) = sqrt(σ^2(x¯1−x¯2)) = sqrt(0.1468) = 0.3835 (rounded to four decimal places)

Hence, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is 0.3835.

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If and only if the alternating sum of the two-digit chunks of a number n is divisible by m, then n is divisible by m.

Let's denote the two-digit chunks of n as a₁a₂, a₃a₄, ..., where a₁, a₂, a₃, a₄, ... are the digits from the ones place onward.

The alternating sum of these two-digit numbers is given by a₁a₂ - a₃a₄ + a₅a₆ - a₇a₈ + ...

We can rewrite n as (a₁a₂ × 100) + (a₃a₄ × 10) + (a₅a₆ × 1) + ...

The alternating sum expression can be written as (a₁a₂ × 100) - (a₃a₄ × 10) + (a₅a₆ × 1) - ...

If n is divisible by m, we have n ≡ 0 (mod m).

Rewriting n in terms of the alternating sum, we get (a₁a₂ × 100) - (a₃a₄ × 10) + (a₅a₆ × 1) - ... ≡ 0 (mod m).

Factoring out each two-digit chunk, we have (a₁a₂ - a₃a₄ + a₅a₆ - ...) ≡ 0 (mod m).

This implies that n is divisible by m if and only if the result of the alternating sum process is divisible by m.

m is the value that makes the alternating sum of the two-digit chunks of n a divisibility test for n.

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Based on simultaneous equations, the number of children and adults who swam at the public pool that hot summer's day is as follows:

Simultaneous equations are two or more equations solved concurrently.

Simultaneous equations are also referred to as a system of equations because the equations are solved at the same time.

The total number of people who used the public swimming pool = 670

The unit price for children = $1.25

The unit price for adults = $2.00

The total amount collected that day = $1,118

Let the number of children who swam at the public pool that day = x

Let the number of adults who swam at the pool that day = y

x + y = 670 ... Equation 1

1.25x + 2y = 1,118 ... Equation 2

Multiply Equation 1 by 2:

2x + 2y = 1,340 Equation 3

Subtract Equation 2 from Equation 3:

2x + 2y = 1,340

-

1.25x + 2y = 1,118

0.75x = 222

x = 296

y = 670 - 296

= 374

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The expression (x + 1)(x - 3) represents the Area of base of the prism.

a crystal is a polyhedron containing a n-sided polygon base, a respectable halfway point which is a deciphered duplicate of the first, and n different countenances, fundamentally all parallelograms, joining relating sides of the two bases. Translations of the bases exist in every cross-section that runs parallel to the bases.

The volume of a rectangular prism is given by the formula V = Bh, where B is the area of the base and h is the height of the prism. In this case, the base is a square with edge length (x + 1), so its area is (x + 1)^2. The volume of the prism is given as (x + 1)^2(x - 3).

We can find the height of the prism by dividing the volume by the area of the base:

B = V/h = (x + 1)^2(x - 3)/(x + 1) = (x + 1)(x - 3)

Therefore, the expression (x + 1)(x - 3) represents the Area of base of the prism.

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The confidence level represents the degree of certainty that the interval contains the true population parameter.

The statement "determines with 95% confidence that the true mean number of suitable apples produced per tree is between 375 and 520" means that if the farmer were to repeat the sampling process many times and calculate the confidence interval each time, 95% of those intervals would contain the true mean number of suitable apples per tree.

Therefore, we can be 95% confident that the true mean number of suitable apples produced per tree is within the interval of 375 to 520 for this particular sample of 40 trees.

The confidence level represents the degree of certainty that the interval contains the true population parameter.

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The volume of the obtained solid is 36 units³.

Given that a rectangle of dimension 9 units x 2 units, has been rotated to form a solid we need to find its volume,

So we know that a rectangle rotated to form a rectangular prism.

Volume of a rectangular prism = product of the dimensions.

The dimensions of the obtained solid will be 9 units x 2 units x 2 units,

So the volume = 9 x 2 x 2 = 36 units³

Hence the volume of the obtained solid is 36 units³.

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The correct expression that is equal to 4.6 is option c. [1.6 + (3 × 4)] – (2 ÷ 2)

Let's evaluate each expressions using the BODMAS rule of mathematics,

a. 1.6 + (3 × 4) – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

b. 1.6 + 3 × 4 – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

c. [1.6 + (3 × 4)] – (2 ÷ 2)

= [1.6 + 12] - 1

= 12.6

d. (1.6 + 3) × (4 – 2) ÷ 2

= 4.6 × 2 ÷ 2

= 4.6

BODMAS is an acronym used to remember the order of operations in mathematics: Brackets, Orders, Division, Multiplication, Addition, Subtraction. It is used to perform calculations in the correct order to obtain the correct result. Therefore, the correct answer is (c).

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Complete question - Which expression is equal to 4.6?

a. 1.6 + (3 × 4) – 2 ÷ 2

b. 1.6 + 3 × 4 – 2 ÷ 2

c. [1.6 + (3 × 4)] – (2 ÷ 2)

d. (1.6 + 3) × (4 – 2) ÷ 2

If we have 30 total participants in a between-subjects design with three groups, we can assign any number of participants to each group as long as the sum of participants in each group adds up to 30. The number of participants in each group is 10 in the 8-ounce group, 15 in the 24-ounce group, and 5 in the no-caffeine group.

If we have a total of 30 participants in a between-subjects design, we need to divide them into three groups according to the conditions.

Let x be the number of participants who received 8 ounces of a caffeinated beverage, y be the number of participants who received 24 ounces of a caffeinated beverage, and z be the number of participants who received no caffeine. Since we have a total of 30 participants, we can write

x + y + z = 30

We don't know the specific number of participants in each group, but we do know that they must add up to 30.

However, we also know that each participant can only be in one group, which means that we have mutually exclusive groups. Therefore, we can assume that there is no overlap between the groups, which means that the total number of participants in each group is

x + y + z = 30

z = 30 - (x + y)

So, we can assign any value to x and y, as long as the sum of x and y is less than or equal to 30. Then, we can find the value of z using the equation above.

For example, if we assign 10 participants to the 8-ounce group and 15 participants to the 24-ounce group, we would have

x = 10

y = 15

z = 30 - (10 + 15) = 5

So, there would be 10 participants in the 8-ounce group, 15 participants in the 24-ounce group, and 5 participants in the no-caffeine group.

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The shopkeeper sold an average of 40.5 eggs per day during the given interval.

To calculate the average number of eggs sold per day, add up the total number of eggs sold and divide by the number of days.

Total number of eggs sold = 42 + 49 + 61 + 35 + 27 + 36 + 50 + 34 + 31 + 40 = 405

Number of days = 10

Average number of eggs sold per day = 405 / 10 = 40.5

The shopkeeper sold an average of 40.5 eggs per day during the given interval.

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The shopkeeper sold every day the number of eggs is recorded. At equal intervals group 42, 49, 61, 35, 27, 36, 50, 34, 31, 40

What is the average number of eggs sold per day by the shopkeeper over the given interval?

sin 2u = -1/2, cos 2u = -1/2, tan 2u = 1, because cot u = sqrt(2) and the range of u is between pi and 3pi/2.

Given cot u = sqrt(2) and the range of trigonometric of u, we can determine the values of sine, cosine, and tangent of 2u using the double-angle formulas. First, we can find the value of cot u by using the fact that cot u = 1/tan u, which gives us tan u = 1/sqrt(2). Since u is in the third quadrant (i.e., between pi and 3pi/2), sine is negative and cosine is negative.

Using the double-angle formulas, we can express sin 2u and cos 2u in terms of sin u and cos u as follows:

sin 2u = 2sin u cos u

cos 2u =[tex]cos^2[/tex] u - [tex]sin^2[/tex] u

Substituting the values of sine and cosine of u, we get:

sin 2u = 2*(-sqrt(2)/2)*(-sqrt(2)/2) = -1/2

cos 2u = (-sqrt(2)/2[tex])^2[/tex] - (-1/2[tex])^2[/tex] = -1/2

To find the value of tangent of 2u, we can use the identity:

tan 2u = (2tan u)/(1-[tex]tan^2[/tex] u)

Substituting the value of tan u, we get:

tan 2u = (2*(1/sqrt(2)))/(1 - (1/sqrt(2)[tex])^2[/tex]) = 1

Therefore, sin 2u = -1/2, cos 2u = -1/2, and tan 2u = 1.

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The correct sequence of steps for copying Line Segment DE using dynamic geometry software is in the order of 2,1,4,3. So, correct option is C.

The correct sequence of steps for copying Line Segment DE using dynamic geometry software is:

1.) Draw Line Segment DE with endpoint H on the circle.

2.) Draw a point and label it G.

3.) Construct a circle centered at the point G with radius Line Segment DE.

4.) Line Segment DE ≅ Line Segment GH

Therefore, option c.) 2,1,4,3 is the correct sequence of steps. The first step is to draw the original line segment DE with endpoint H on the circle.

The second step is to draw a point and label it G. The third step is to construct a circle centered at G with the same radius as Line Segment DE. Finally, in the fourth step, the line segment GH is drawn such that it is congruent to Line Segment DE, completing the copy of Line Segment DE.

So, correct option is C.

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A piggy bank is a small container typically used by children to save money. In this scenario, Todd had a piggy bank holding $384 and began taking out money each month. The table provided shows the amount remaining in the piggy bank, in dollars, after each of the first four months. This information can be used to track Todd's spending and savings habits.

In the first month, Todd took out $60, leaving him with $324 in his piggy bank. In the second month, he took out an additional $48, leaving him with $276. By the third month, Todd had taken out a total of $105, leaving him with $279 in his piggy bank. Finally, in the fourth month, he took out $62, leaving him with $217.

By tracking his spending and savings over the course of these four months, Todd can assess his financial habits and make any necessary adjustments. It is important for individuals to develop good financial habits early on in life, and using a piggy bank can be a fun and effective way to do so.

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The Experimental probability of  rolling the color green is 0.15

The experimental probability of rolling the color green can be calculated by dividing the number of times the die lands on green by the total number of rolls:

Experimental probability of green = Number of green rolls / Total number of rolls

Experimental probability of green = 18 / 120

Experimental probability of green = 0.15 or 15%

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Answer:

y = -2x + 14

Step-by-step explanation:

OK so first u have to do y = -2x + b cuz its parallel

then u gotta just plug in the ordered pair so

6 = -2(4)+b

6 = -8 +b

14 = b

So now u have to do

y = -2x + 14

we find that the solutions to the equation are:x ≈ -1.283, x ≈ 4.283.

To solve the equation 2x(x+0.5) = -(x+2.5)² + 5.5 by graphing, we can first rearrange it to the standard form:

x² - 3x - 2 = 0.5(x+2.5)²

Then we can plot the two functions y = x² - 3x - 2 and y = 0.5(x+2.5)² - 5.5 on the same graph and find their intersection points, which represent the solutions to the equation.

Enter the two functions in separate equations:

[tex]y_1 = x^2 - 3x - 2[/tex]

[tex]y_2 = 0.5(x+2.5)^2 - 5.5[/tex]

Adjust the zoom level and position of the graph to see the intersection points.

Click on the intersection points to see their coordinates.

Round the coordinates to the nearest thousandth.

After following these steps, we find that the solutions to the equation are:

x ≈ -1.283

x ≈ 4.283

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The final exponential function using the values of 'a' and 'b':
y = (1/2)(4^x)

To find an exponential function that passes through the points (2,8) and (4,128), follow these steps:

Step 1: Recall the general form of an exponential function: y = ab^x
Here, 'a' and 'b' are constants that need to be determined using the given points.

Step 2: Substitute the first point (2,8) into the equation:
8 = ab^2

Step 3: Substitute the second point (4,128) into the equation:
128 = ab^4

Step 4: Divide the second equation by the first equation to eliminate 'a':
(128 = ab^4) / (8 = ab^2)
16 = b^2

Step 5: Solve for 'b':
b = √16
b = 4

Step 6: Substitute the value of 'b' back into the first equation:
8 = a(4^2)

Step 7: Solve for 'a':
8 = 16a
a = 8/16
a = 1/2

Step 8: Write the final exponential function using the values of 'a' and 'b':
y = (1/2)(4^x)

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The value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

Given, [tex]\lim_{x \to 3} f(x)=0[/tex]

[tex]\lim_{x \to 3} g(x)=4[/tex]

[tex]\lim_{x \to 3} h(x)=2[/tex]

We have to find the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex]

[tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)=\lim_{x \to 3} \frac{6h(x)}{4f(x)+g(x)}[/tex]

[tex]= \frac{\lim_{x \to 3}6h(x)}{\lim_{x \to 3}4f(x)+\lim_{x \to 3}g(x)}[/tex]

[tex]=\frac{6\times 2}{4\times0+4}[/tex]

= 12/4

= 3

Hence, the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

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Answer:

30π cm

Step-by-step explanation:

if r = 15 cm

circumference = π2r

= π × 2 × 15

= 30π cm

A value that is less than 2 1/5% from the given data is 0. 0215. Option A is the correct answer.

A fraction represents a part of a number or any number of equal parts. There is a fraction, containing numerator and denominator.

To find a value that is less than 2 1/5% we need to find the decimal number of a given fraction. to convert the given fraction into decimal form we need to divide the given fraction by 100.

= 2 1/5% / 100

= (2 + (1/5)) / 100

= 0.022

A value that is less than 0.022 from the given data is 0. 0215.

Therefore, a value less than 2 1/5% is 0. 0215.

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The height of the cone that the volume of a cylinder is twice the volume of a cone is 7.5 meters.

Let's first define some variables to represent the dimensions of the cone and cylinder. Let's use r for the radius of both shapes, h for the height of the cone, and 5 for the height of the cylinder.

The volume of a cone is given by V_cone = (1/3)πr^2h, and the volume of a cylinder is given by V_cylinder = πr^2h.

We are told that the volume of the cylinder is twice the volume of the cone:

V_cylinder = 2V_cone

Substituting the formulas for the volumes of the cone and cylinder, we get:

πr^2(5) = 2[(1/3)πr^2h]

Simplifying, we can cancel the π and the r^2 terms on both sides:

5 = (2/3)h

Multiplying both sides by 3/2, we get:

h = 7.5

Therefore, the height of the cone is 7.5 meters.

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The quotient of 4.082 and 10,000 is 0.000004082.

To find the quotient of 4.082 and 10,000, we need to divide 4.082 by 10,000. However, dividing a decimal by another decimal can be tricky, so we need to move the decimal point of the dividend (4.082) and the divisor (10,000) to make the division easier.

We can move the decimal point of 4.082 four places to the left to obtain 0.04082. This is because moving the decimal point to the left makes the number smaller. For example, moving the decimal point in 4.082 one place to the left gives us 0.4082, which is ten times smaller than 4.082. Moving the decimal point four places to the left gives us a number that is 10,000 times smaller than 4.082.

Similarly, we can move the decimal point of 10,000 four places to the right to obtain 100,000,000. This is because moving the decimal point to the right makes the number larger. For example, moving the decimal point in 10,000 one place to the right gives us 1,000, which is ten times larger than 10,000. Moving the decimal point four places to the right gives us a number that is 10,000 times larger than 10,000.

Now we can divide 0.04082 by 100,000,000, which gives us the quotient of 0.000004082. Therefore, to find the quotient of 4.082 and 10,000, we need to move the decimal point in 4.082 four places to the left and move the decimal point in 10,000 four places to the right, and then divide the resulting numbers.

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Using  net worth statement, Andre's net worth is $159,573.

Andre's net worth can be calculated by subtracting his total liabilities from his total assets.

Total assets = $155,000 (condominium) + $8,100 (stock portfolio) + $9,100 (car value) + $2,600 (bank account) = $174,800

Total liabilities = $3,300 (car loan) + $7,600 (student loans) + $4,327 (credit card balance) = $15,227

Net worth = Total assets - Total liabilities = $174,800 - $15,227 = $159,573

Therefore, Andre's net worth is $159,573.

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The length of the trail is determined as 1.3 miles.

The length of the trail is calculated as follows;

The circumference of the circle is calculated as;

S = πd

where;

S = π x 2 ft

S = 2π ft

I revolution = 1 circumference = 2π ft

1 rev = 2π ft

1,100.5 rev = ?

= 1,100.5 rev/rev x 2π ft

= 6,914.65 ft

5280 ft -------> 1 mile

6,914.65 ft ------> ?

= 1.3 miles

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Let's label the 3 points as A;B;C, where BC is the hypotenuse and AB is the shortest side, and x as AH.

We can see that triangle AHC is similar to triangle CAB, and triangle ACH is similar to triangle BCA, so therefore triangle AHC is similar to triangle CHA (i might've messed up the order but you get it)

Because they are similar, we get the ratio : x/12 = 40/x, or x^2 = 480.

So, x = [tex]\sqrt{480}[/tex], or 21.9 (1 d.p)

Answer:

-----------------------

According to the right triangle altitude theorem:

We see x is the altitude and 12 & 40 are the segments formed on the hypotenuse.

Applied to the given triangle, we get following equation: