Answer:
Calcium hydride
Explanation:
In an oven, 7000 kg of limestone are heated to over 900ºC to give lime and carbon dioxide. Assuming all calcium carbonate reacts. How much lime do you get? What volume of CO2 is emitted into the atmosphere? Atomic weights: Ca: 40; C: 12; O: 16.
Answer:
3920kg of lime(CaO) 1568m^3 of CO2
Explanation:
I attached the explanation!
also for calculating the volume I assumed Standard Temperature and Pressure(STP).
You decide to focus on pickling cucumbers. The cucumbers that you have are all approximately 12 cm in length and 3 cm in diameter. If the diffusion coefficient for H+ ions in cucumbers is the same as in water, 7 x 10-5 cm2/sec, how long will it take for the protons to reach the center of the cucumbers? Enter your answer in minutes without including the units.
Answer:
0.0036
Explanation:
SEE THE ATTACHMENT BELOW FOR DETAILED EXPLANATION
moles of Fe in 3.13×1022 atoms of Fe
Answer: 0.05 moles
Explanation:
To convert from atoms to moles, you will need Avogadro's number.
Avogadro's number: 6.022×10²³atoms/moles
(3.13×10²²atoms)×(moles/6.022×10²³ atoms)=0.05 moles
The atoms would cancel out and we will be left with our moles.
What is the Electronegativity difference of F and CI
The element fluorine is more electronegative than the element chlorine. Fluorine has an electronegativity value of 4.0 and Carbon has an electronegativity value of 2.5.
What is electronegativity ?The term electronegativity is defined as a chemical property that describes the capacity of an atom or a functional group to attract electrons toward itself.
Electronegativity is refer to the ability of an atom to attract shared electrons in a covalent bond. The grater the value of the electronegativity, the more strongly that element attracts the shared electrons.
In fluorine electronegativity value is more than carbon. Therefore, it strongly attracts the shared electrons.
Thus, The element fluorine is more electronegative than the element chlorine.
To learn more about an electronegativity, follow the link;
https://brainly.com/question/17762711
#SPJ2
As a quality control check, a sample of acetone is taken from a process to determine the concentration of suspended particulate matter. An 850 mL sample was placed in a beaker and evaporated. The remaining suspended solids were determined to have a mass of 0.001 g. The specific gravity of acetone is 0.79 g/cm.
(a) Determine the concentration of the sample as mg/L.
(b) Determine the concentration of the sample as ppm (problem from EPA Air Pollution Training Institute)
Answer:
The volume of the sample given is 850 ml, the density given is 0.79 gram per cm. Now the weight of the sample will be,
Weight = volume × density = 850 × 0.79
= 671.5 grams
Weight of the suspended solids given is 0.001 gram
The concentration of the sample can be determined by using the formula,
Concentration = wt. of sample/volume
= [671.5 - 0.001) 10³ mg / 0.85 L
= 789998.82 mg/L or 789998.82 ppm
Now the concentration of suspended solids is.
Css = 0.001 × 10³ mg / 0.85 L = 1.1764 mg per L or 1.1764 ppm
(a) Give systematic names or the chemical formulas for the following. Remember, names must
be spelled correctly!
1.) [Ni(CO)2C2O4]
2.) K3[Fe(NCO)3(OCN)3]
3.) diammineaquahydroxoplatinum(II) ion
4.) Al[Co(CO3)2(CN)2]
5.) ethylenediaminedinitritozinc(II)
Answer:
[Ni(CO)2C2O4]- Dicarbonyloxalatonickel(0)
K3[Fe(NCO)3(OCN)3-potassiumtricyanatotriisocyanatoferrate II
diammineaquahydroxoplatinum(II) ion- [Pt(NH3)2(H2O)(OH)]^+
Al[Co(CO3)2(CN)2- Aluminiumdicarbonatodicyanocobalt III
ethylenediaminedinitritozinc(II)- Zn(en)(NO2)2
Explanation:
The international Union of Pure and applied chemistry published a set rules for the nomenclature of inorganic compounds in 1985. This set of rules have been consistently revised ever since.
The rules stipulate the order for naming positive ions, negative ions and neutral ligands and the allowed order of preference for naming. It also stipulates the proper endings for ligands which are positive ions, negative ions or neutral ligands as the case may be.
The compounds named above were named in accordance with the revised IUPAC nomenclature for inorganic compounds.
Convert the average temperatures for each collected data point given below from °C to K. Plot the average cell potentials E (y-axis) vs T (x-axis). The plot should be approximately linear. Add a trendline to find the best linear fit and write down the y-intercept and slope (b and m from the linear equation) for the trendline below.
Average Temperature in °C - Average Cell Potential (V)
15 - 0.465
18 - 0.467
21 - 0.468
24 - 4.69
27 - 0.471
30 - 0.472
33 - 0.474
Answer:
Explanation:
The equation of above line , y = 0.0005x+ 0.458
This can be compared with y = mx+c
Hence slope, m = 0.0005 and Y-intercept, c = 0.458
Or it can be plotted manually where straight line has to be drawn touching maximum number of data points. After drawing a straight linear line, we need to take any two points from the straight line and slope is calculated
Slope,
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
and y -intercept is calculated using extraplotting backwards such that it touches the Y-axis. the point where straight line touches Y-axis is Y-intercept (c).
Plot the average cell potentials E (y-axis) vs T (x-axis). image attached
Atoms of the same element are alike because they must have the same number of
Answer:
They must have the same number of protons.
Explanation:
Protons determine the identity of an element. However, the neutrons can vary, resulting in different masses.
Answer:
Atoms of the same element can have different numbers of neutrons, however. Atoms of the same element (i.e., atoms with the same number of protons) with different numbers of neutrons are called isotopes. Most naturally occurring elements exist as isotopes.
Explanation:
The standard free energy change in physiological conditions (G') for the reaction catalyzed by malate dehydrogenase in the citric acid cycle malate + NAD+ oxaloacetate + NADH + H+ is ~+29 kJmol-1 Calculate the actual G' at 37C if Keq' is 1.02 × 10-5
Answer: The actual value of [tex]\Delta G[/tex] is -618 J/mol
Explanation:
Relation of ree energy change and equilibrium constant
[tex]\Delta G=\Delta G^0+2.303\times RT\times \log K_{eq}[/tex]
where,
[tex]\Delta G[/tex] = Free energy change
[tex]\Delta G^o[/tex] = standard free energy change = +29 kJ/mol =
R = universal gas constant
T = temperature = [tex]37^0C=(37+273)K=310K[/tex]
[tex]K_{eq}[/tex] = equilibrium constant = [tex]1.02\times 10^{-5}[/tex]
[tex]\Delta G=+29000J/mol+2.303\times 8.314J/Kmol\times 310K\times \log (1.02\times 10^{-5})[/tex]
[tex]\Delta G=29000J/mol-29619J/mol=-618J/mol[/tex]
The actual value of [tex]\Delta G[/tex] is -618 J/mol
A chemist performed a calibration method analysis to determine the concentration of vitamin c in a fruit sample. The standard vitamin c samples were prepared by mixing a complexing agent with the standard solution. The absorbance of the resulting solution was obtained. Once the absorbance of each standard solution was measured, he prepared the following calibration curve.y = 1.6421x -0.1113The unknown sample was prepared by taking 2.0 g of crushed fruit and extracting the concentrated juice. The extracted juice was added to 100.0 mL volumetric flask and the final volume was adjusted 100.0 mL with DI water. 10.0 mL of diluted fruit extra was pipetted into 50.0 mL volumetric flask and after adding 5.0 mL of complexing agent, the DI water was added until the final volume of the solution reaches 50.0 mL. This solution gave an absorbance of 0.461. I. Find the concentration of vitamin C in the original fruit sample. II. What is the total mass of vitamin C in the sample? III. Calculate the wt% of vitamin C in the fruit sample.
Answer:
I. 1.743mg/mL
II. 0.174g
III. 8.7 wt%
Explanation:
As absorbance is directly proportional to concentration. The calibration curve was:
Y = 1.6421X - 0.1113
Where Y is absorbance of sample and X its concentration in mg/mL
The diluted sample obtains an absorbance of 0.461, that means its concentration is:
0.461 = 1.6421X - 0.1113
0.3485mg/mL = X
I. The sample was diluted to 50.0mL from an aliquot of 10.0mL, thus, concentration in the original fruit sample was:
0.3485mg/mL × (50.0mL / 10.0mL) = 1.743mg/mL
II. The total mass of vitamin C in the sample (100.0mL) is:
100.0mL × (1.743mg/mL) = 174mg = 0.174g
III. As the fruit sample was of 2.0g, the wt% is:
0.174g / 2.0g = 8.7 wt%
how many significant figures are in 11.005 g
Answer:
Number of Significant Figures: 5
The Significant Figures are 1 1 0 0 5
Explanation:
What is the volume in a 2. 00M solution containing 8.00 moles of solute?
Answer:
4000cm³
Explanation:
2.0moles-1000cm³
8.0moles-?
(8.0×1000)÷2
=4000cm³
How many molecules are in 0.3672 moles of LiBr?
Answer:
2.21×10²³molecules
Explanation:
Hello,
The question requires us to calculate the number of molecules present in a given number of mole.
Numbe of mole = 0.3672 moles
According to mole ratio concept, one mole of any substance is equal to Avogadro's number of particles, atoms or molecules. I.e,
1 mole = Avogadro's number
Avogadro's number = 6.022×10²³ atoms/molecules/particles or ions
1 mole = 6.022×10²³molecules
0.3672 mole = x molecules
x = 0.3672 × 6.022×10²³
X = 2.21×10²³molecules
Therefore, 0.3672moles of LiBr contains 2.21×10²³molecules
2 MnO4−(aq) + 10 Cl−(aq) + 16 H+(aq) → 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l) Oxidizing agent: Reducing agent:
Answer:
MnO4 is the oxidizing agent.
Cl is the reducing agent.
Explanation:
To know which is oxidizing agent and which is reducing agent, let us calculate the change in oxidation number of each element in the equation below:
2MnO4−(aq) + 10Cl−(aq) + 16H+(aq) → 5Cl2(g) + 2Mn2+(aq) + 8H2O(l)
Please note:
1. The oxidation state of oxygen is always –2 except in peroxide where it is –1
2. The oxidation state of Hydrogen is always +1 except in hydrides where it is –1
3. The oxidation state of chlorine is always –1
For Mn:
At left hand side
MnO4 = –1
Mn + 4O = –1
O = –2
Mn + (4 x –2) = –1
Mn – 8 = –1
Collect like terms
Mn = –1 + 8
Mn = +7
At the right hand side, Mn is +2.
The oxidation state of Mn changes from +7 to +2.
For Cl:
At the left hand side
Cl = –1
At the right hand side
Cl = 0
The oxidation state of Cl changes from – 1 to 0.
The oxidation state of O and H are unchanged.
Since the oxidation state of Mn changes from +7 to +2 i.e reduced, MnO4 is the oxidizing agent.
Since the oxidation state of Cl changes from – 1 to 0 i.e increase, Cl is the reducing agent.
please help me with this!
Answer:
mole fraction of Oxygen = mole of oxygen/ total mole
Explanation:
Can the ph scale be utilized for all acids (Arrhenius, Bronsted-Lowery, and Lewis)? Explain reasoning.
Answer:
No, the pH scale can not be utilized for all types of acids known
Explanation:
The pH scale is a scale that shows the degree of acidity or alkalinity of a substance. The pH scale is graduated from 0-14. The pH scale is mostly applied to Arrhenius acids. Recall that in the Arrhenius definition, an acid produces hydrogen ion in solution while a base produces hydroxide ion in solution. Hence we could easily measure or calculate the pH and pOH of Arrhenius acids. Arrhenius acids apply mostly to acid-base discussion in Aqueous media.
Beyond aqueous media, we can still apply the Brownstead-Lowry and Lewis definitions for acid and base. Some of these substances to which we apply these other definitions of acid and base do not necessarily contain hydrogen or hydroxide ions hence the pH scale can not be utilized in discussing their acid-base properties, hence the answer.
three requirements to start a fire
Aluminum metal reacts with sulfuric acid according to the equation:2Al(s) + 3H2SO4(aq) --> Al2(SO4)3(s) + 3H2(g)If 46 g of aluminum reacts with excess sulfuric acid, and 108 g of Al2(SO4)3 are collected, what is the percent yield for the reaction?
Answer:
Percentage yield = 38.37%
Explanation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃
2 moles of Al contains = (2 × 27) = 54g of Al
1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃
54g of Al produces 342.15g of Al₂(SO₄)₃,
46g of Al will produce x g of Al₂(SO₄)₃
Solve for x
X = (46 × 342.15) / 54
X = 15738.9 / 54
X = 281.46g
Theoretical yield of Al₂(SO₄)₃ = 281.46g
Percentage yield of a substance = (actual yield / theoretical yield) × 100
Actual yield = 108g
Theoretical yield = 281.46
% yield = (108 / 281.46) × 100
% yield = 0.3837 × 100
%yield = 38.37
The percentage yield of Al₂(SO₄)₃ is 38.37
Answer: Percentage yield = 38.37%
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂ from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃ .
2 moles of Al contains = (2 × 27) = 54g of Al
1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃
54g of Al produces 342.15g of Al₂(SO₄)₃,
46g of Al will produce x g of Al₂(SO₄)₃
Solve for x
X = (46 × 342.15) / 54
X = 15738.9 / 54
X = 281.46g
Theoretical yield of Al₂(SO₄)₃ = 281.46g
Percentage yield of a substance = (actual yield / theoretical yield) × 100
Actual yield = 108g
Theoretical yield = 281.46
% yield = (108 / 281.46) × 100
% yield = 0.3837 × 100
%yield = 38.37
The percentage yield of Al₂(SO₄)₃ is 38.37
what type of reaction is Cl2(g) + 2Kl(aq) arrow 2KCl(aq) + I2 (s)
A certain compound is made up of one carbon (C) atom, two fluorine (F) atoms, and one oxygen (O) atom. What is the chemical formula of this compound?
Answer:
CF₂O
Explanation:
To determine how the molecule will be made think about the valence number of each element in molecule:
F= -1 , O= -2 , C= +4
because the C is positive atom it will be the central atom with a double bond to the O and a single bond to each F.
this way all atoms completed the octet and stability
Fe3O4(s) + CO(g) → FeO(s) + CO2(g) What coefficients will balance the equation? 3, 1, 1, 1 1, 1, 3, 1 3, 3, 1, 1 2, 2, 6, 4
Answer:
1, 1, 3, 1.
Explanation:
When balancing chemical equations, the amount of moles of each element on both sides of the equation should be equal.
Looking at the original equation, we can see that there are 3 mols of iron on the reactants side and 1 on the products. We can simply add a coefficient of '3' to 'FeO' to balance the iron.
For Oxygen, we can see 5 on the reactants side. However, since we already added a coefficient of '3' to 'FeO', this already balanced out the oxygen for us. We have 5 mols in the reactants, and 5 in the products.
Carbon is already balanced on both sides.
Therefore, the final formula is [tex]Fe_{3}O_{4} + CO -> 3FeO + CO_{2}[/tex], with coefficients of 1, 1, 3, and 1.
Answer:
B
Explanation:
Fe3O4(s) + CO(g) →FeO(s) + CO2(g)
Left side
Fe =3
O = 5
C = 1
Right side
Fe =1
O = 3
C = 1
Balance by finding common denominator
We'll make Fe 3 on the left side
Fe3O4(s) + CO(g) →3FeO(s) + CO2(g)
Left side
Fe =3
O = 5
C = 1
Right side
Fe =3
O = 5
C = 1
Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?
Answer:
6.460 gm is the correct answer .
Explanation:
Given
Kate’s blood volume=[tex]3.8L[/tex]
blood glucose=[tex]170\ mg/dL[/tex]
As we know that
[tex]1\ dL= 10^{-1}\ litre[/tex]
The [tex]10^{-1}[/tex] includes the blood glucose of the [tex]170\ mg/dL,[/tex]
So [tex]3.8L.[/tex] of the Kate’s blood volume can be determined by
[tex]=\ \frac{170 * 3.8 }{10^{-1} }[/tex]
[tex]=170 * 38 \ mg[/tex]
[tex]=6460\ mg[/tex]
To convert into the gm we have divided by the 1000
[tex]6.460 \ gm[/tex]
Therefore the glucose in her blood=
[tex]6.460 \ gm[/tex]
Answer:
6.460 g
Explanation:
Glucose is a simple carbohydrate molecule which circulates in the blood along with other substances. The amount of glucose is measured to treat the medical conditions of patients which is measured as mg/dL.
1 liter of liquid contains 10 deciliters therefore 1 dL will have 0.1 liter or
1 dL= 10^-1 liter (0.1)
In the given question,
the total volume of blood = 3.8 L
1 dL of blood contains = 170 mg
3.8 L will have = (3.8 x 170)/0.1
=6460 mg
= 6.460 g
Thus, 6.460 g is the correct answer.
Can you please answer Question 9 please
1.09 grams of H2 to moles
The thyroid, parathyroid, and thymus are located in the
The adrenals, pancreas, testes, and ovaries are located in the
The pineal, hypothalamus, and pituitary are located in the
Answer:
The pineal, hypothalamus, and pituitary are located in the BRAIN
The thyroid, parathyroid, and thymus are located in the THROAT
The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY
Explanation:
The pineal, hypothalamus, and pituitary are located in the BRAIN
The thyroid, parathyroid, and thymus are located in the THROAT
The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY
Answer:
Throat
Abdomen
Brain
Explanation:
These are correct!
What is the chemical formula for a compound between Al and F? AlF AlF 3 AlF 2 Al 3F
Answer:
AlF3
Explanation:
Aluminum fluoride (AlF3) is an inorganic compound in which aluminum and fluoride has ionic bond between each other.
Aluminum ( atomic number - 13) has 3 valence electrons and can lose 3 electrons to get a stable configuration while fluorine (atomic number - 9) can gain one electron to make a stable configuration. So in order to attain a stable configuration one aluminum (Al) atom form ionic bond with three fluorine atoms and form AlF3.
Hence, the chemical formula between Al and F is AlF3.
Answer:
Explanation:
mmmmmmmmmmmmmh,mm
The total enthalpy of the products in a reaction is 0 kJ, and the total enthalpy of the reactants is 100 kJ. What is the ΔH for the reaction? Choose the correct answer.
a.–393.5 kJ
b.–100 kJ
c.0 kJ
d.+100 kJ
Answer: b. -100 kJ
Explanation:
Heat of reaction is the energy released or absorbed during the course of the reaction. It is represented by the symbol [tex]\Delta H[/tex].
[tex]\Delta H=H_{products}-H_{reactants}[/tex]
[tex]\Delta H[/tex] = enthalpy of reaction = ?
[tex]H_{products}[/tex] = enthalpy of products = 0 kJ
[tex]H_{reactants}[/tex] = enthalpy of reactants = 100 kJ
[tex]\Delta H=0kJ-100kJ[/tex]
[tex]\Delta H=-100kJ[/tex]
Thus the ΔH for the reaction is -100kJ
Calculate the empirical formula of a compound with the following
percentage composition: 31,8% K; 29,0% C1; 39,2% O
The empirical formula of ethane is CH. Its molar mass is 30 g.mol-
Answer:
The empirical formula for this compound is thus CH2.
Explanation:
How many moles of iron(III) sulfide,
Fe2S3, would be produced from the
complete reaction of 449 g iron(III)
bromide, FeBr3?
Answer:
0.76 mole of Fe2S3.
Explanation:
Step 1:
Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:
Mass of FeBr3 = 449g
Molar mass of FeBr3 = 56 + (80x3) = 296g/mol
Mole of FeBr3 =..?
Mole = Mass /Molar Mass
Mole of FeBr3 = 449/296
Mole of FeBr3 = 1.52 moles
Step 2:
The balanced equation for the reaction. This is given below:
2FeBr3 + 3Na2S —> 6NaBr + Fe2S3
Step 3:
Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:
From the balanced equation above,
2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.
Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.
Therefore, 0.76 mole of Fe2S3 is produced from the reaction.
Answer: 0.76
Explanation:
How many mL of a 0.4 M nitric acid solution are required to neutralize 200 mL of a 0.16 M potassium hydroxide
Answer:
80 ml.
Explanation:
The balanced equation is:
KOH + HNO3 ----> KNO3 + H2O
So 1 mole of KOH reacts with 1 mole of HNO3
200ml of 0.16M KOH contains 0.16 * 200/1000
= 0.16 * 0.2
= 0.032 M KOH.
So we need the volume (V) of 0.4 M HNO3 which contains 0.032 moles.
0.4 * V = 0.032
V = 0.032 / 0.4
V = 0.08 liters
= 80 mls.
