Answer:
A) T1 = 566 k = 293°C
B) T2 = 1132 k = 859°C
Explanation:
A)
The average kinetic energy of the molecules of an ideal gas is givwn by the formula:
K.E = (3/2)KT
where,
K.E = Average Kinetic Energy
K = Boltzman Constant
T = Absolute Temperature
At 10°C:
K.E = K10
T = 10°C + 273 = 283 K
Therefore,
K10 = (3/2)(K)(283)
FOR TWICE VALUE OF K10:
T = T1
Therefore,
2 K10 = (3/2)(K)(T1)
using the value of K10:
2(3/2)(K)(283) = (3/2)(K)(T1)
T1 = 566 k = 293°C
B)
The average kinetic energy of the molecules of an ideal gas is given by the formula:
K.E = (3/2)KT
but K.E is also given by:
K.E = (1/2)(m)(vrms)²
Therefore,
(3/2)KT = (1/2)(m)(vrms)²
vrms = √(3KT/m)
where,
vrms = Root Mean Square Velocity of Molecule
K = Boltzman Constant
T = Absolute Temperature
m = mass
At
T = 10°C + 273 = 283 K
vrms = √[3K(283)/m]
FOR TWICE VALUE OF vrms:
T = T2
Therefore,
2 vrms = √(3KT2/m)
using the value of vrms:
2√[3K(283)/m] = √(3KT2/m)
2√283 = √T2
Squaring on both sides:
(4)(283) = T2
T2 = 1132 k = 859°C
A) The temperature at which the average kinetic energy will have a value of 2K10 is; T1 = 293 °C
B) The temperature at which the molecules have twice the rms speed, 2vrms is; T2 = 859 °C
A) We are given;
Initial temperature; T = 10°C = 283 K
Initial kinetic energy; KE = K10
Final kinetic energy; KE1 = 2K10
Now,formula for average kinetic energy of the molecules of an ideal gas is given as;
KE = (3/2)kT
Where;
k is Boltzmann constant
T is temperature
We are told that in the second case, KE = 2K10. Thus;
2K10 = (3/2)kT1
K10 = ¾kT1 - - - (eq 2)
In the first instance, we have;
K10 = (3/2)kT - - - (eq 1)
Put (3/2)kT for K10 in eq 2 to get;
(3/2)kT = ¾kT1
k will cancel out to get;
(3/2)T = ¾T1
Make T1 the subject to get;
T1 = 2T
Thus;
T1 = 2 × 283
T1 = 566 K
Converting to °C gives;
T1 = 293 °C
B) We want to find the temperature T2 (in degrees Celsius) at which the molecules will have twice the rms speed, 2v_rms.
Formula for kinetic energy is also;
KE = ½mv²
Thus;
½m(v_rms)² = (3/2)kT
v_rms = √(3kT/m) - - - (eq 1)
When rms speed is 2v_rms, we have;
½m(2v_rms)² = (3/2)kT2
v_rms = √(¾kT2/m) - - - (eq 2)
Thus;
√(3kT/m) = √(¾kT2/m)
Square both sides to get;
(3kT/m) = (¾kT2/m)
4T = T2
T2 = 283 × 4
T2 = 1132 K
Converting to °C gives;
T2 = 859 °C
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23 POINTS! Does the period of a pendulum depend on the mass? Explain
Answer:
The period of a pendulum does not depend on the mass of the ball, but only on the length of the string.
Explanation:
Two pendula with different masses but the same length will have the same period. Two pendula with different lengths will different periods; the pendulum with the longer string will have the longer period.
Which situation involves an object that can be considered to be in free fall?
A) a bungee jumper just before reaching the bottom of a jump.
B) a ball at the top of its motion after being thrown straight up in the air.
C) a helicopter that is hovering above a freeway. D) a meteor traveling through the atmosphere
Answer:
B: Only the ball experiences no resistive force to its state of motion.
what is electrical power ???
Answer:
Electric power is the rate, per unit time, at which electrical energy is transferred by an electric circuit. The SI unit of power is the watt, one joule per second.
Answer:
Explanation shown below.
Explanation:
Is one generated from the movement of free moving electrons.
Electric energy can be harnessed from different sources.
Which statements describe how a machine can help make work easier? Select two options.
It can put out more force than the input force by decreasing the distance through which force is applied.
It can increase the amount of work performed if the output force is in the same direction as the input force.
It can apply a force to an object in a different direction than the force applied to the machine.
It can increase the distance through which a force acts by exerting less force than was used on it.
It can exert a greater force through a greater distance than the force used on the machine.
Answer:
It can put out more force than the input force by decreasing the distance through which force is applied.It can apply a force to an object in a different direction than the force applied to the machine.Explanation:
Assuming the machine is a simple machine, such as a lever or pulley, the machine will not do any more work than is put into it. However, it can change the magnitude or direction (or both) of the input force required to achieve a particular output force.
Because the machine does not increase the work done, if the output force is greater, the output distance must be less.
The applicable observations are ...
It can put out more force than the input force by decreasing the distance through which force is applied.It can apply a force to an object in a different direction than the force applied to the machine.
An open-pipe resonator has a length of 2.39 m. Calculate the frequency of its third harmonic if the speed of sound is 343 m/s.
80 Hz
115.7 Hz
215.27 Hz
100.1 Hz
Answer:
f = 215.27 Hz
Explanation:
We have,
An open-pipe resonator has a length of 2.39 m.
It is required to find the frequency of its third harmonic if the speed of sound is 343 m/s.
For third harmonic, its length is equal to, [tex]l=\dfrac{3\lambda}{2}[/tex]
So,
[tex]\dfrac{3v}{2f}=2.39[/tex]
f is frequency in its third harmonics
[tex]f=\dfrac{3v}{2\times 2.39}\\\\f=\dfrac{3\times 343}{2\times 2.39}\\\\f=215.27\ Hz[/tex]
So, the frequency of its third harmonic is 215.27 Hz.
a wheel at rest gains an angular momentum of 10.7kgm²/s in 8s. if the moment if inertia of the wheel is 2.2kgm², how many revolutions will be made before the wheel attains an angular velocity of 30rad/s
Answer:
Revolutions made before attaining angular velocity of 30 rad/s:
θ = 3.92 revolutions
Explanation:
Given that:
L(final) = 10.7 kgm²/s
L(initial) = 0
time = 8s
Find Torque:Torque is the rate of change of angular momentum:
[tex]T = \frac{L(final)-L(initial)}{t}\\T = \frac{10.7-0}{8}\\T=1.34 Nm[/tex]
Find Angular Acceleration:We know that
T = Iα
α = T/I
where I = moment of inertia = 2.2kgm²
α = 1.34/2.2
α = 0.61 rad/s²
Find Time 't'
We know that angular equation of motion is:
ω²(final) = ω²(initial) +2αθ
(30 rad/s)² = 0 + 2(0.61 rad/s²)θ
θ = (30 rad/s)²/ 2(0.61 rad/s²)
θ = 24.6 radians
Convert it into revolutions:
θ = 24.6/ 2π
θ = 3.92 revolutions
Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends toward the normal.
Which statement best describes Cleo’s mistake?
A. Light travels through air and water in angled, scattered paths.
B. Light does not change direction when it moves from air into water.
C. Light slows down when it moves from air into water.
D. Light bends away from the normal when it moves from air into water.
Answer:
light bends away from the normal when it moves from air into water-refraction
Answer: C.) Light slows down when it moves from air into water.
Explanation: i hope this helps :)
20. Threshold braking in the vehicle's braking system
occurs when
a. the brake pedal is pushed, heel on floorboard,
with full foot pressure.
b. the brakes are exerting full braking power,
without traction loss.
C. the driver begins pushing down the brake pedal,
with moderate slowdown.
d. the brakes just begin to take hold with a gradual
slowdown.
a spring is compressed by 0.02m. Calculate the energy stored in the spring if the force constant is 400Nm-1
Answer:
0.08 J
Explanation:
EE = ½ kx²
EE = ½ (400 N/m) (0.02 m)²
EE = 0.08 J
The energy stored in the spring, if the force constant is 400N/m is 0.08 J.
What is spring potential energy?When the spring is compressed, it gets compressed up to its elastic limit. When load is removed from the spring, it regains its shape and obtains equilibrium position. The energy stored in this process is called as spring potential energy.
Given a spring is compressed by 0.02m. The force constant is 400N/m. The energy stored in the spring is given by
SPE = ½ kx²
SPE = ½ (400 N/m) (0.02 m)²
SPE = 0.08 J
Thus, the energy stored in the spring is 0.08 J.
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which temperature is warmer than the freezing point of water
A. 0 F
B. 0 k
C. 1 C
D. 33 K
Answer:
1°C
Explanation:
Water freezes at 0°C, 32°F, and 273°K.
The only temperature warmer than the freezing point is 1°C.
Answer:
A. 0 F
Explanation:
Test approved
Evaluate: (5x + 4y)/2, which is an expression of a certain experimental procedure. lf x represents the valence of Argon and y represents the summation or valencies of sulphur and Neon
Answer: 48
Explanation:
Given the expression (5x + 4y)/2
Where x represents the valence of Argon and y represents the summation or valencies of sulphur and Neon
A neutral Argon, Sulphur and Neon will have :
The valence of Argon = 8
The valence of sulphur = 6
The valence of Neon = 8
Therefore, X = 8 and Y = 6 + 8 = 14
Substitute x and y into the expression.
(5x + 4y)/2 = (5×8 + 4×14)/2
(40 + 56)/2 = 96/2 = 48
Evaluating: (5x + 4y)/2 = 48
2 Points
Mechanical energy is the ___
of kinetic energy and potential energy.
Hey!!!
Mechanical energy is the sum of kinetic energy and potential energy.
Hope it helps..
Good luck on your assignment
what is the process where dna can change in many ways?
Answer:
process of recombination
Explanation:
this process happens when 2 molecules of DNA exchange pieces of their genetic material with each other
the role of hydrochloric acid in the stomach
Answer:
1. For acidifying stomach content. Hydrochloric acid is the main component
2. Prevents Infections. Hydrochloric acid acts as a barrier against foreign microorganisms
3. Helps in digestion of food. The hydrochloric acid present in the gastric acid.
So basically it helps digest food in the stomach.
Which of these objects are malleable? Check all that apply.
tin fork and knife from a camping set
antique ceramic vase
steel pole fence post
marble sculpture
glass tabletop
copper coin
Answer:
The tin fork and knife, the copper coin, and the steel fence pole.
Explanation:
Those are both what people would call soft metals so they are malleable to the extent of probably not needing heavy duty equipment. It depends on you description of malleable because the steel fence pole could be malleable with the correct equipment and not snap in half if bent slowly enough.
The definition of malleable: (of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking.
But the glass table, marble sculpture and antique ceramic vase are nowhere near malleable because if you tried bending them they wouldn't bend but would shatter and break into pieces.
The tin fork and knife, the copper coin, and the steel fence pole are malleable, the correct option is A, C, and F.
What are malleable objects?A malleable material is one that can be easily formed into a thin sheet by hammering. The most malleable metal is gold. In contrast, ductility is a solid material's ability to deform under tensile stress.
Metals are malleable because when a force is applied, layers of ions can slide over each other. Metallic bonding allows metal to change shape without breaking.
Gold, iron, aluminum, copper, silver, and lead are examples of malleable metals. Ductility and malleability do not always correlate; for example, gold is both ductile and malleable, whereas lead is only malleable.
Tin fork and knife, copper coin, and steel fence pole are all malleable.
Thus, the correct options are A, C, and F.
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How much would it cost to operate five incandescent light bulbs for the months of April and May, collectively, given that each bulb is one hundred and fifty Watts, electricity for home use is 0.3AED per kilowatt-hour, and that the light s will be on for three hours per day during this two month period.
please i need an answer fast or my teacher will kill me
Answer:
Total Cost is 41.18 AED
Explanation:
Per day number of hours light bulbs were on=3hours
5 bulbs power consumption = 150Wx5 = 750W
Electricity usage per day = 750 x 3 = 2250Wh = 2.25kWh
April has 30 days and May has 31 days. Therefore totals days = 61days
Total power consumption = 2.25x 61 = 137.25kWh
Total Cost = 137.25x 0.30 = 41.175 AED
To run the physics cart, the fan speed of the cart is manipulated. This is the (blank) variable. The cart accelerates due to the speed of the fan. Acceleration is therefore the (blank) variable. A "constant" is a parameter that stays the same regardless of the variables. One parameter of the cart that is held constant is the (blank) .
Answer:
A) Independent
B) Dependent
C) Mass
Explanation:
The speed applied to the physics cart is manipulated. This doesn't depend on another variable. Thus, speed is the (independent) variable.
The cart accelerates due to the speed applied to the cart. Acceleration depends on the speed applied. Thus, acceleration is therefore the (dependent) variable.
A “constant” is a parameter that remains the same regardless of the variables.
One parameter of the cart that is held constant is the (mass).
The interference between the two wave pulses shown above will
result in a wave with an amplitude of
Select one
Answer:
can you make it clear i do not understand.
Explanation:
4) Un péndulo tiene un período de oscilación de 4 seg (T) , realizando su
movimiento desde su posición de equilibrio, si la aplitud del movimiento es de
10 cm y el ángulo de desfase es de 20 grados. Calcular:
La posición en la que se encuentra a los 5 segundos de haber iniciado el
movimiento.
Answer:
x = 1.43 cm
Explanation:
The horizontal displacement of the pendulum can be found using the following equation:
[tex] x(t) = x_{0}*sin(\omega*t + \phi) [/tex]
Where:
x₀: is the initial horizontal displacement = 10 cm
ω: is the angular frequency
t: is the time = 5 s
Φ: is the phase shift = 20° = 20*2π/360 = 0.35 rad
The angular frequency can be calculated using the oscillation perid (T):
[tex] \omega = \frac{2\pi}{T} = \frac{2\pi}{4 s} = 1.57 rad/s [/tex]
The horizontal displacement is:
[tex] x(t) = x_{0}*sin(\omega*t + \phi) = 10 cm*sin(1.57 rad/s*5 s + 0.35 rad) = 1.43 cm [/tex]
Therefore, the displacement of the pendulum at 5 s is 1.43 cm.
I hope it helps you!
Match each vocabulary word with appropriate definition. chemical property chemical change reactivity combustibility
Answer:
1.) Chemical Change - a change in matter that results in a change in its identity and properties
2.) Combustibility - the ability of a substance to burn
3.) Reactivity - The ability of a substance to combine Chemically with another
4.) Chemical Property - the ability of matter to change into a different substance
Explanation:
Proof: -Image Below & the definitions for each word-
Chemical Change- Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. ... An example of a chemical change is the reaction between sodium and water to produce sodium hydroxide and hydrogen.
Combustibility- Combustibility is a measure of how easily a substance bursts into flame, through fire or combustion. This is an important property to consider when a substance is used for construction or is being stored. It is also important in processes that produce combustible substances as a by-product.
Reactivity- In chemistry, reactivity is the impetus for which a chemical substance undergoes a chemical reaction, either by itself or with other materials, with an overall release of energy.
Chemical Property- A chemical property is any of a material's properties that becomes evident during, or after, a chemical reaction; that is, any quality that can be established only by changing a substance's chemical identity. ... They can also be useful to identify an unknown substance or to separate or purify it from other substances.
Have a nice day!
Chemical change - A change in a substance that brings a change in its identity and properties
Combustibility - The ability of a substance to bursts into the combustion
Reactivity - The ability of a matter to chemically combine with others.
Chemical Property - The ability of a substance to change into a completely different substance.
What are chemical properties, chemical change, reactivity, and combustibility?Chemical changes take place when a substance combines with another substance to create a new substance, called chemical synthesis. An example of a chemical change is the formation of sodium hydroxide and hydrogen by the reaction between sodium and water.
Combustibility determines how easily a substance can burst into flame, through combustion. The combustibility is a property to consider when a substance is used for storage or for construction. It is also an important property in processes where the formation of combustible substances is a side product.
In chemistry, reactivity is the property of a chemical substance that undergoes a chemical reaction with itself or with other chemicals, and the overall release of energy.
Chemical properties are the characteristics of a particular substance that can be noticed during a chemical reaction. Some major chemical properties include heat of combustion, flammability, rate of radioactive decay, toxicity, pH value, and chemical stability.
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Two simple pendulum of slightly different length , are set off oscillating in step is a time of 20s has elasped , during which time the longer pendulum has completed exactly 10 oscillations .Find the length of each pendulum.
Answer:
Length of longer pendulum = 99.3 cm
Length of shorter pendulum = 82.2 cm
Explanation:
Since the longer pendulum undergoes 10 oscillations in 20 s, its period T = 20 s/10 = 2 s.
From T = 2π√(l/g), the length of the pendulum. l = T²g/4π²
substituting T = 2s and g = 9.8 m/s² we have
l = T²g/4π²
= (2 s)² × 9.8 m/s² ÷ 4π²
= 39.2 m ÷ 4π²
= 0.993 m
= 99.3 cm
Now, for the shorter pendulum to be in step with the longer pendulum, it must have completed some oscillations more than the longer pendulum. Let x be the number of oscillations more in t = 20 s. Let n₁ = number of oscillations of longer pendulum and n₂ = number of oscillations of longer pendulum.
So, n₂ = n₁ + x. Also n₁ = t/T₁ and n₂ = t/T₂ where T₂ = period of shorter pendulum.
t/T₂ = t/T₁ + x
1/T₂ = 1/T₁ + x (1)
Also, the T₂ = t/n₂ = t/(n₁ + x) (2)
From (1) T₂ = T₁/(T₁ + x) (3)
equating (2) and (3) we have
t/(n₁ + x) = T₁/(T₁ + x)
substituting t = 20 s and n₁ = 10 and T₁ = 2s, we have
20 s/(10 + x) = 2/(2 + x)
10/(10 + x) = 1/(2 + x)
(10 + x)/10 = (2 + x)
(10 + x) = 10(2 + x)
10 + x = 20 + 10x
collecting like terms
10x - x = 20 - 10
9x = 10
x = 10/9
x = 1.11
x ≅ 1 oscillation
substituting x into (2)
T₂ = t/n₂ = t/(n₁ + x)
= 20/(10 + 1)
= 20/11
= 1.82 s
Since length l = T²g/4π²
substituting T = 1.82 s and g = 9.8 m/s² we have
l = T²g/4π²
= (1.82 s)² × 9.8 m/s² ÷ 4π²
= 32.46 m ÷ 4π²
= 0.822 m
= 82.2 cm
It is a way to display to number of ________ for elements. This chart will show the correlation between ______ number and the number of valence electrons
Answer:
Electrons
Atomic number
Explanation:
The question describes a period table which is a chart of the elements.
The Periodic Table of elements shows the arrangement of elements based on their increasing atomic number.
In a neutral atom, the number of electrons will equal the number of protons, so we can easily determine electron number from atomic number. In addition, the position of an element in the periodic table—its column, or group, and row, or period—provides useful information about how those electrons are arranged (electronic configuration) in their different shells.
It is a way to display to number of ____electrons____ for elements. This chart will show the correlation between __atomic____ number and the number of valence electrons
Francium-233 has a half-life of 22 minutes.A Geigor counter gives a reading of 58 counts per minute (cpm) from a sample of francium-233.What will the reading be 22 minutes later?You can ignore background radiation
Answer:
The reading of the Geiger counter, 22 minutes later = 29 counts per minute (cpm)
Explanation:
Half life is defined as the time taken for the amount ( or activity) of a substance to reduce to half its original value.
As stated in the question, the half life of Francium-233 is 22 minutes, [tex]t_{1/2} = 22 minutes[/tex]. This means that it takes 22 minutes for the activity of Francium-233 to reduce to half of its original value.
The original activity of Francium-233 = 58 counts per minute (cpm)
By the end of 22 minutes, the activity measured by the counter would have halved.
Activity of Francium-233 after 22 minutes = 58/2
Activity of Francium-233 after 22 minutes = 29 counts per minute (cpm)
Which of the following statements is INCORRECT based on our Ray Model of Light?
Select one or more:
a. Light moves in a circular motion and diffracts when it encounters an obstacle, which is why shadows exist.
b. The ray of light approaching a mirror is the incident ray, and the ray of light that leaves a mirror is the reflected ray.
c. In order to view an object, light rays from that object must enter your eye.
d. The distance from all plane mirrors to any object is equal to the distance from the mirror to the image.
Answer:
a and c
Explanation:
a)light moves in a straight line and distracts when it encounters an obstacle forming a shadow
c)the light rays from that object or also tgose from the image must enter your eye for you to see that image
A dog walks 14 meters to the west and then 20 meters back
to the east.
Answer 34
Explanation:
Answer:
The dog moved 6 meters west and 34 meters total
Explanation:
A block of wood of mass 24 kg floats on water. The volume of the block below the surface of the water and the density of the wood.( Density of water= 1000kgm-3
Answer:
0.024m^3
Explanation:
=======
Answer:
=======
Given:-
Mass of the block of wood = 24 kg
Volume of wood = 0.032 m^3
Density of water = 1000kg/m^3
Now,
Density of wood is given by,
\frac{m}{v} = \frac{24}{0.032} \\
\frac{m}{v} = 750 \: kg/m ^{3}
Therefore,
The density of wood is 750kg/m^3
By principle of floatation,
Mass \:of\: wood = Mass\: of\: liquid \:displaced
Therefore,
Mass of liquid displaced = 24kg
Volume of liquid displaced (v),
\frac{m}{v} = \frac{24}{1000} \\
\frac{m}{v} = 0.24m ^{3}
Now,
Since the volume of the wood is equal to the volume of water displaced, it is 0.024m^3
=====
Note:
=====
=> The volume of the wood below the water surface is the volume of water displaced.
=> Buoyant\: force = Weight\: of\: the \:displaced\: water.
in which electric circuit would the voltmeter read 10 volts ?
Given that,
Voltage = 10 volt
Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.
We need to calculate the equivalent resistance
Using formula of parallel
[tex]\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}[/tex]
Put the value into the formula
[tex]\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}[/tex]
[tex]\dfrac{1}{R}=\dfrac{1}{4}[/tex]
[tex]R=4\ \Omega[/tex]
We need to calculate the current in the circuit
Using ohm's law
[tex]V=IR[/tex]
[tex]I=\dfrac{V}{R}[/tex]
Where, V = voltage
R = resistance
Put the value into the formula
[tex]I=\dfrac{10}{4}[/tex]
[tex]I=2.5\ A[/tex]
Hence, The current in the circuit is 2.5 A
Which statements apply to transverse waves? Check all that apply.
The question is incomplete as it does not have the options which are:
The waves have a trough.
Particles move only small distances.
particles travel the length of the wave, moving in an up-and-down motion.
The waves have a crest.
The energy is transferred perpendicular to the direction of the wave motion.
Answer:
The waves have a trough. Particles move only small distances. The waves have a crest. The energy is transferred perpendicular to the direction of the wave motion.Explanation:
Transverse waves are the waves which can be characterised easily by their oscillation in a perpendicular direction to the path of the wave propagation.
The particle follows the wave nature and moves only to a small distance like ripples in the water and these waves possess the trough, the lower part and the crest the upper part.
These waves can be observed in ripples of the water, in a string of the guitar while playing and the electromagnetic waves.
Thus, the selected options are correct.
How does matter affect the way you perceive and use light
Answer:
The relationship between light and matter produces three phenomena, namely:
reflectionabsorption transmission and EmissionExplanation:
Reflection: This happens when matter deflects light in another direction
In everyday use, reflective materials are used on construction apparel, handheld electric torch, headlamp of vehicles etc.
2. Absorption: When matter captures electromagnetic radiation, it converts the energy of photons into internal energy and absorption is said to have taken place.
Light absorption by the chlorophyll in plants for use in production is an example of how humans use light absorption albeit indirectly.
3. Transmission
When matter is transparent or semi-transparent it allows light to pass through. For semi-transparent matter, some of the light is absorbed.
Transmission of light is used predominantly in various kinds of lighting effects for interior decoration and houses.
4. Emission
When matter releases energy as light, it is said to have emitted light.
Examples of everyday emission of light include Light Emitting Diode which is used in remote controls.
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A farm would feel hotter on a sunny summer day than New York City.
True
False
false
hope this help
lf I'm write can you give me a brainlist please
