The answer to this math problem please.

Answer:

push-up = 1 second

sit-up = 3 seconds

Step-by-step explanation:

let p represent the # of push-ups

let s represent the # of sit-ups

System of equations:

19p+8s=43

12p+12s=48

i'll eliminate s by multiplying the top equation by 3 and the bottom equation by -2

57p+24s=129

-24p-24s=-96

33p=33

p=1 second

now solve for s (i'll plug p into the 2nd equation)

12(1) + 12s=48

12s=36

s=3 seconds

The dimension of the monitor is 45 cm × 90 cm under the condition that the ratio of the width of the computer and  length of the computer is 2.1.

The given ratio of length to width of a computer monitor is 2:1. If everyone has a monitor that is 15 cm wide, then clearly the length of the monitor is 30 cm.

Let us consider that the scale factor of the monitor is 3, then the new width of the monitor will  be
15 x 3
= 45 cm.

Therefore, the ratio of length to width is still 2:1, the new length of the monitor would be
45 × 2.1
≈ 90 cm

Hence, the dimensions of a monitor that has a scale factor of 3 are 45 cm x 90 cm.

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The number of milligrams of sugar his spoon holds is 1250 milligrams.

To find out how many milligrams of sugar Chad's spoon holds, we first need to know how much sugar he removed in total. To do this, we can subtract the amount of sugar he needed (280 grams) from the amount he poured (295 grams).

295 grams - 280 grams = 15 grams

Next, we need to divide the total amount of sugar Chad removed (15 grams) by the number of spoonfuls he used (12).

15 grams ÷ 12 = 1.25 grams per spoonful

Finally, we can convert grams to milligrams by multiplying by 1000.

1.25 grams x 1000 = 1250 milligrams

Therefore, Chad's spoon holds 1250 milligrams of sugar.

It's important to note that when cooking or baking, precise measurements are crucial to the success of the recipe. Even small changes can greatly affect the outcome. While it's great that Chad was able to remove the excess sugar, it's best to be as accurate as possible from the start.

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we can simplify |x + 3| to x + 3 when x is greater than 5.

The absolute value function |x| is defined as the distance of x from zero on the number line. This means that |x| is always non-negative, so it can be expressed as a non-negative number.

In this case, we are given that x > 5, which means that x is greater than 5. If we add 3 to both sides of this inequality, we get:

x + 3 > 5 + 3

x + 3 > 8

This tells us that x + 3 is also greater than 8. Therefore, when x is greater than 5, the expression |x + 3| represents the distance of x + 3 from zero, which is equal to x + 3 itself because x + 3 is positive.

As a result, we can simplify |x + 3| to x + 3 when x is greater than 5.

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The volume of small cone-shaped cups is 11.8 in³.

To find the volume of the small shake in a cone-shaped cup that is 7 inches tall and has a diameter of 3 inches, we can use the formula for the volume of a cone:

V = 1/3 πr²h

where V = volume

r = radius

h = height of the cone

Given, diameter of come is 3 inches

We know r = d/2

r = 3/2

= 1.5

Substituting the value in the formula

V = 1/3 × 3.14 × 7 × (1.5)²

= 11.78

Rounding to nearest tenth

V = 11.8

Hence, the volume of small cone-shaped cups is 11.8 in³.

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The function notation is E(h) = 8.5h where h represents the number of hours worked so the domain is {0, 1, 2, 3, 4, 5} and the range is {0, 8.5, 17, 25.5, 34, 42.5}.

Let E(t) be John's earnings in dollars after working t hours, where t is in the domain 0 ≤ t ≤ 5. Then E(t) = 8.50t, since John earns $8.50 per hour proofreading ads.

The domain of the function is 0 ≤ t ≤ 5, since John works no more than 5 hours per day.

The range of the function is 0 ≤ E(t) ≤ 42.50 since John earns $8.50 per hour and works no more than 5 hours per day.

Therefore, the maximum earnings he can make in one day is 5 hours multiplied by $8.50 per hour, which equals $42.50.

The minimum earnings are $0, which would occur if John does not work at all.

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The question is -

John can earn $8.50 per hour proofreading adverse at a local newspaper. He works no more than 5 hours a day. Write a function in function notation and find a reasonable domain and range of his earnings.

The unit rate of change of ddd with respect to ttt is 4/3.

To graph the proportional relationship between ddd and ttt, we first need to find the unit rate of change. Since an increase of 333 units in ttt corresponds to an increase of 444 units in ddd, we can calculate the unit rate as follows:

Unit Rate = (Change in ddd) / (Change in ttt) = 444 / 333 = 4/3

So, a change of 1 unit in ttt corresponds to a change of 4/3 units in ddd.

Now, let's graph the relationship. The equation representing this proportional relationship is:

ddd = (4/3)ttt

This is a linear relationship with a slope of 4/3 and passes through the origin (0,0). To plot the graph, start at the origin and use the slope to plot additional points, such as:
- For ttt = 3, ddd = 4 (since 4/3 * 3 = 4)
- For ttt = 6, ddd = 8 (since 4/3 * 6 = 8)

Plot these points and draw a straight line through them, representing the proportional relationship between ddd and ttt. The unit rate of change of ddd with respect to ttt is 4/3.

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To determine if x and y are proportional, we need specific values or a proportional relationship equation.

To determine whether x and y are proportional, we need to compare the ratio of their values. If the ratio of x to y remains constant as x and y vary, then they are proportional.

Mathematically, if x/y = k, where k is a constant, then x and y are proportional. However, without specific values or equations, it is not possible to ascertain their proportionality.

Without further information, we cannot determine whether x and y are proportional. Additional context, such as specific values or an equation relating x and y, is needed to make a conclusive statement about their proportionality.

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The total surface area of the prism is 282

From the question, we have the following parameters that can be used in our computation:

The net of a triangle prism.

The total surface area of the prism is the sum of the individual shapes

So, we have

Surface area = 2 * 1/2 * 6 * 5 + 3 * 6 * 14

Evaluate

Surface area = 282

Hence. the total surface area of the prism is 282

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Answer:

The total surface area is 282

Lee spent a total of 33 hours working on all the lawns, as calculated by multiplying the number of lawns for each size category by the respective time required for mowing, trimming, and sweeping.

In order to determine the total number of hours Lee spent working on all the lawns, we need to calculate the time for each task separately. For the average size lawn, Lee takes 1 hour to mow and 2 hours to trim and sweep, totaling 3 hours per lawn. For the large size lawn, Lee takes 3 hours to mow and 3 hours to trim and sweep, totaling 6 hours per lawn.

Given that Lee mowed, trimmed, and swept 5 average size lawns and 3 large size lawns in one week, we can calculate the total hours as follows:

Total hours for average size lawns = 5 lawns * 3 hours/lawn = 15 hours

Total hours for large size lawns = 3 lawns * 6 hours/lawn = 18 hours

Therefore, the total hours Lee spent working on all the lawns is 15 hours + 18 hours = 33 hours.

In conclusion, Lee spent a total of 33 hours working on all the lawns, as calculated by multiplying the number of lawns for each size category by the respective time required for mowing, trimming, and sweeping.

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Answer:

1) 1/2 + 1/4 = 2/4 + 1/4 = 3/4

2) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 9 is 63, so we can write:

3/7 * 9/9 + 2/9 * 7/7 = 27/63 + 14/63 = 41/63

3) To add these fractions, you need to find a common denominator. The smallest common multiple of 5 and 15 is 15, so we can write:

3/5 * 3/3 + 1/15 * 1/1 = 9/15 + 1/15 = 10/15

But we can simplify this fraction by dividing both the numerator and denominator by 5:

10/15 = 2/3

4) To add these fractions, you need to find a common denominator. The smallest common multiple of 9 and 8 is 72, so we can write:

1/9 * 8/8 + 7/8 * 9/9 = 8/72 + 63/72 = 71/72

5) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 21 is 21, so we can write:

6/7 * 3/3 + 2/21 * 1/1 = 18/21 + 2/21 = 20/21

6) To add these fractions, we need to find a common denominator first. The smallest number that both 6 and 10 divide into is 30. So, we convert 4/6 to 20/30 by multiplying both the numerator and denominator by 5, and we convert 2/10 to 3/15 by multiplying both the numerator and denominator by 3. Now we have:

20/30 + 3/15 = (20x1 + 3x2)/(30x2) = 23/60

Therefore, 4/6 + 2/10 = 23/60.

7) To add these fractions, we need to find a common denominator first. The smallest number that both 11 and 22 divide into is 22. So, we convert 1/11 to 2/22 by multiplying both the numerator and denominator by 2, and we convert 3/22 to 3/22 (it is already in terms of 22). Now we have:

2/22 + 3/22 = (2 + 3)/22 = 5/22

Therefore, 1/11 + 3/22 = 5/22.

8) To add these fractions, we need to find a common denominator first. The smallest number that both 4 and 20 divide into is 20. So, we convert 1/4 to 5/20 by multiplying both the numerator and denominator by 5, and we convert 8/20 to 8/20 (it is already in terms of 20). Now we have:

5/20 + 8/20 = (5 + 8)/20 = 13/20

Therefore, 1/4 + 8/20 = 13/20.

9) To add these fractions, we need to find a common denominator first. The smallest number that both 7 and 9 divide into is 63. So, we convert 4/7 to 24/63 by multiplying both the numerator and denominator by 3, and we convert 2/9 to 14/63 by multiplying both the numerator and denominator by 7. Now we have:

24/63 + 14/63 = (24 + 14)/63 = 38/63

Therefore, 4/7 + 2/9 = 38/63.

10) To add these fractions, we need to find a common denominator first. The smallest number that both 10 and 30 divide into is 30. So, we convert 6/7 to 18/30 by multiplying both the numerator and denominator by 3, and we convert 2/30 to 1/15 by multiplying both the numerator and denominator by 15. Now we have:

18/30 + 1/15 = (18x1 + 1x2)/(30x2) = 37/30

Therefore, 6/7 + 2/21 = 37/30.

The incorrect statement about the intersecting triangles is A. CG ≅ FG.

With intersecting triangles, it is not always guaranteed that segments like CG and FG will be congruent. The lengths of CG and FG will depend on the specific configuration of the chords and their intersection point G.

However, CE/EG = FD/DG statement is TRUE. This is a consequence of the Intersecting Chords Theorem. When two chords intersect inside a circle, the products of their segments are equal.

Since ∠CEG ≅ ∠FDG intersect inside a circle, the corresponding intercepted arcs create equal angles at the intersection point. Therefore the statement is true.

ΔCEG ~ ΔFDG is also true because we know that the triangles share an angle and have proportional sides.

The answer above is in response to the full question below;

In the diagram of circle A shown below , chords CD and EF intersect at G, and chords CE and FD and drawn

Which statements is not always true?

a. CG ≅ FG    

b. CE/EG = FD/ DG

c. ∠CEG ≅ FDG  

d. ΔCEG ~ ΔFDG

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The sum of the interior angles of a triangle is 180 degrees.

Sure, here's a question related to the Triangle Sum and Exterior Angle Theorem: Consider triangle ABC. The measure of angle A is 60 degrees, and the measure of angle B is 80 degrees. What is the measure of angle C? Using the Triangle Sum Theorem, we know that the sum of the interior angles of a triangle is always 180 degrees.

Additionally, the Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the measures of the two opposite interior angles.  

Based on this information, determine the measure of angle C in triangle ABC and provide a step-by-step explanation of how you arrived at your answer.

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Hence, the required equation of the quintic with double roots –4 and 2 is [tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex].

Given, an equation of a quintic with double roots –4 and 2, that goes through the origin as well as (4, 4).

Let r be the remaining root of the equation.

Let the required equation in factored form is

[tex]f(x)=a(x+4)^2(x-2)^2(x-r)[/tex]

Given, the quintic goes through the origin.

Then, we know that f(0) = 0.

[tex]f(0)=a(0+4)^2(0-2)^2(0-r)[/tex]

0 = a(16)(4)(-r)

0 = -64ar

64ar = 0

either a = 0 or r = 0.

if a = 0

then the equation reduces to f(x) = 0, which is not a quintic.

a ≠ 0

This means that r = 0

So equation becomes [tex]f(x)=a(x+4)^2(x-2)^2(x)[/tex]   ...(1)

Given, the quintic goes through the point (4, 4)

So, f(4) = 4

[tex]f(4)=a(4+4)^2(4-2)^2(4)[/tex]

4 = 1064 a

a = 4/1064

a = 1/256

Putting in equation (1)

[tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex]

Hence, the required equation of the quintic with double roots –4 and 2 is [tex]f(x)=\frac{1}{256} (x+4)^2(x-2)^2(x)[/tex].

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The equation y = |x - 5| + |x + 5| can be rewritten as:

y = { -2x - 10, for x < -5,

 { 10, for -5 ≤ x ≤ 5,

 { 2x + 10, for x > 5.

When -5 < x < 5, both |x - 5| and |x + 5| are non-negative. So we can rewrite y = |x - 5| + |x + 5| as follows:

If x < -5, then x - 5 < -5 and x + 5 < 0, so we have:

y = -(x - 5) - (x + 5) = -2x - 10

If -5 ≤ x ≤ 5, then x - 5 < 0 and x + 5 ≥ 0, so we have:

y = -(x - 5) + (x + 5) = 10

If x > 5, then x - 5 ≥ 0 and x + 5 > 5, so we have:

y = (x - 5) + (x + 5) = 2x + 10

Therefore, the equation y = |x - 5| + |x + 5| can be rewritten as:

y = { -2x - 10, for x < -5,

 { 10, for -5 ≤ x ≤ 5,

 { 2x + 10, for x > 5.

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Given question is incomplete, the complete question is below

Rewrite each equation without absolute value for the given conditions. y = |x-5| + |x+5| if -5 < x < 5

The factored form of 21r-56 is: 21r-56 = 7r(-5) or 7r*(-5)

Factoring is the process of finding the factors (or divisors) of a given mathematical expression or number. In algebra, factoring involves breaking down an expression into simpler parts (called factors) that can be multiplied together to obtain the original expression. The goal of factoring is to simplify the expression or solve an equation by expressing it in terms of its factors.

In the given question,

To factor 21r-56, we first need to find the greatest common factor (GCF) of the two terms. The GCF of 21 and 56 is 7. We can also factor out r since it is a common factor of both terms. Therefore, we can write:

21r-56 = 7r(3-8)

Simplifying the expression inside the parentheses, we get:

21r-56 = 7r(-5)

Therefore, the factored form of 21r-56 is:

21r-56 = 7r(-5) or 7r*(-5).

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The best prediction for the bacteria population after 8 days is approximately 14,301.67 bacteria.

To find the predicted population of bacteria after 8 days, we need to apply the given growth rate of 220% per day to the initial population of 50 bacteria for each day, starting from day 1 and continuing to day 8.

For each day, the population of bacteria is expected to be 220% or 2.2 times the population of the previous day. So, we can use the formula:

P = P0 [tex]x (1 + r)^n[/tex]

where P is the predicted population after n days, P0 is the initial population, r is the growth rate per day (as a decimal), and n is the number of days.

Substituting the given values, we get:

P = 50[tex]x (1 + 2.2)^8[/tex]

P ≈ 14,301.67

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The probability of P(2 | 2 of hearts) is 1/51, P(heart | 2 of hearts) is 12/51, P(club | 2 of hearts) is 13/51 and P(9 | 2 of hearts) is 4/51.

Since Sara did not replace the first card, there are now only 51 cards left in the deck, and only one of them is the 2 of hearts. Therefore, the probability that the second card is another 2 is

P(2 | 2 of hearts) = 1/51

After drawing the 2 of hearts, there are now 12 hearts left in the deck out of 51 cards. So the probability that the second card is another heart is

P(heart | 2 of hearts) = 12/51

Similarly, there are 13 clubs left in the deck out of 51 cards. So the probability that the second card is a club is

P(club | 2 of hearts) = 13/51

There are four 9s left in the deck out of 51 cards. So the probability that the second card is a 9 is

P(9 | 2 of hearts) = 4/51

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The relation of function is False.

This relation is not a function because the input value -2 is associated with two different output values (4 and -1). In a function, each input can only have one corresponding output.

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To find the area of each shaded sector and round to the hundredths place, I'll need some more information, such as the radius of the circle and the measure of the central angle of the sector. Please provide these details so I can assist you with the calculation.

The area of the shaded sector is 1330.81 ft²

Given, ∠GKH = 26° and ∠JKI = 90°

The area that is not shaded has a total of 90° + 26° = 116°.

A circle has a total angle of 360°, so the area that is shaded must be

360° - 116° =  244°

Given, HK = 25 ft

Radius of circle = 25 ft

We know that the formula for the area of the sector of a circle is

Area = [tex]\frac{\pi \theta r^2}{360^\circ}[/tex]

= (π × 244 × (25)² )/ 360

= 7625π/18

= 1330.81 ft²

Hence, the area of the shaded sector is 1330.81 ft²

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Given question is incomplete, the complete question is below

Find the area of each shaded sector. round to the hundredths place.

If at the previous appointment the baby weighed 10 pounds and 8 ounces, then the baby has gained 12 ounces since the last appointment.

To calculate this, we need to subtract the weight at the previous appointment from the weight at the current appointment:

11 pounds and 4 ounces - 10 pounds and 8 ounces = 12 ounces

So the baby has gained 12 ounces since the last appointment. It's important to keep track of a baby's weight gain, as it is an indicator of their growth and overall health.

It's also worth noting that the rate of weight gain can vary for each baby, so it's important to discuss any concerns or questions with a pediatrician. Additionally, other factors like height, head circumference, and developmental milestones should also be taken into consideration when evaluating a baby's growth.

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Answer: the minimum distance from P to the circle is approximately 2.97, and the maximum distance is approximately 3.89.

Step-by-step explanation:

To find the minimum and maximum distances from the point P(-3, 9) to the circle defined by (x-3)^2 + (y-1)^2 = 25, we can use the fact that these distances are given by the perpendiculars from the point P to the line passing through the center of the circle.

The center of the circle is (3,1), so we can find the equation of the line passing through P and the center of the circle as follows:

The slope of the line passing through P and the center of the circle is (1-9)/(3-(-3)) = -8/6 = -4/3.

Using the point-slope form of a line, the equation of the line passing through P and the center of the circle is y - 9 = (-4/3)(x + 3).

Now we can find the points where this line intersects the circle. Substituting y = (-4/3)(x+3) + 9 into the equation of the circle, we get:

(x-3)^2 + ((-4/3)(x+3) + 8)^2 = 25

Expanding and simplifying this equation gives a quadratic equation in x:

25x^2 + 96x + 80 = 0

Solving this quadratic equation using the quadratic formula, we get:

x = (-96 ± sqrt(96^2 - 42580)) / (2*25)

x = (-96 ± 56) / 50

x = -2.04 or x = -1.52

Substituting these values of x into y = (-4/3)(x+3) + 9 gives the corresponding values of y:

When x = -2.04, y = 6.24

When x = -1.52, y = 7.27

So the two points of intersection are approximately (-2.04, 6.24) and (-1.52, 7.27).

Finally, we can find the distances from P to each of these points using the distance formula:

The distance from P to (-2.04, 6.24) is sqrt[(-3 - (-2.04))^2 + (9 - 6.24)^2] ≈ 3.89.

The distance from P to (-1.52, 7.27) is sqrt[(-3 - (-1.52))^2 + (9 - 7.27)^2] ≈ 2.97.

Therefore, the minimum distance from P to the circle is approximately 2.97, and the maximum distance is approximately 3.89.

A geometric sequence is a type of sequence where each term is found by multiplying the previous term by a constant factor. This means that each term is a multiple of the one before it. In contrast, an arithmetic sequence is a type of sequence where each term is found by adding a constant value to the previous term.

This means that each term is a sum of the one before it and a fixed value.

To answer your question, whether a geometric sequence will always grow faster than an arithmetic one depends on the values of the constant factor and fixed value in each sequence. In general, if the constant factor in a geometric sequence is greater than 1, the terms will grow at an increasingly faster rate than in an arithmetic sequence.

However, if the constant factor is between 0 and 1, the terms will grow at a decreasing rate, meaning that the sequence will actually grow more slowly than an arithmetic one.

It's important to note that the rate of growth is not the only factor to consider when comparing geometric and arithmetic sequences. The actual values of the terms in each sequence can also differ significantly, depending on the starting term and the values of the common ratio and common difference.

In some cases, an arithmetic sequence may actually have higher values than a geometric one, even if it grows more slowly.

In summary, whether a geometric sequence will always grow faster than an arithmetic one depends on the specific values of each sequence. However, in general, if the constant factor in a geometric sequence is greater than 1, it will grow faster than an arithmetic sequence.

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Using the Law of Sines and Cosines, we get all possible values of ∠H are approximately 60.6° and 69.0°.

We can use the Law of Cosines to find the length of side GH

GH² = g² + h² - 2gh cos(G)

GH² = (9.3)² + (9.6)² - 2(9.3)(9.6)cos(109°)

GH ≈ 3.585 cm

Next, we can use the Law of Sines to find the measure of angle H

sin(H)/GH = sin(G)/HI

sin(H)/3.585 = sin(109°)/HI

sin(H) ≈ 3.585(sin 109°)/HI

H ≈ arcsin[3.585(sin 109°)/HI]

Since we do not know the length of side HI, we cannot determine the exact value of angle H. However, we can find the possible range of angle H by assuming that HI is the longest side of the triangle (making angle H the smallest) and the shortest side of the triangle (making angle H the largest).

If HI is the longest side, then H ≈ arcsin[3.585(sin 109°)/9.3] ≈ 60.6°

If HI is the shortest side, then H ≈ arcsin[3.585(sin 109°)/9.6] ≈ 69.0°

Therefore, the possible values of angle H are between approximately 60.6° and 69.0°.

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x = 0, π, 2π, 3π, 4π, 5π, 6π, π/3, 5π/3

These are the exact solutions of the given equation on the interval [0, 21). To find all exact solutions of the equation sec(x) sin(x) - 2 sin(x) = 0 on the interval [0, 21), we will use the factoring method:

First, we can factor out the sin(x) term:

sin(x) (sec(x) - 2) = 0

Now, we have two separate equations to solve:

1) sin(x) = 0
2) sec(x) - 2 = 0

For equation (1), sin(x) = 0 at x = nπ, where n is an integer. We need to find the values of n that give solutions in the range [0, 21):

0 ≤ nπ < 21
0 ≤ n < 21/π
n = 0, 1, 2, 3, 4, 5, 6

x = 0, π, 2π, 3π, 4π, 5π, 6π

For equation (2), sec(x) - 2 = 0, or sec(x) = 2. We know that sec(x) = 1/cos(x), so:

1/cos(x) = 2
cos(x) = 1/2

The values of x for which cos(x) = 1/2 in the range [0, 21) are x = π/3 and x = 5π/3.

Combining both sets of solutions, we have:

x = 0, π, 2π, 3π, 4π, 5π, 6π, π/3, 5π/3

These are the exact solutions of the given equation on the interval [0, 21).

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The number of whole numbers whose square roots of a natural number from 1 to 200 will be 14

The natural number of square roots from 1 to 200 are mentioned below

1² = 1,

2² = 4,

3² = 9,

4² = 16,

5² = 25,

6² = 36,

7² = 49,

8² = 64,

9² = 81,

10² = 100,

11² = 121,

12² = 144,

13² = 169,

14² = 196

The number of whole numbers = 14

Above 14 the square will be greater than 200

All the whole numbers are natural number except zero. zero is a whole number not a natural number.

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The temperature of 80°F is equivalent to 48°C.

To convert 80°F to Celsius degrees using the formula C = (F - 32), we substitute the given Fahrenheit temperature into the formula.

C = (80 - 32) = 48

Therefore, the temperature of 80°F is equivalent to 48°C.

The Celsius scale is commonly used in scientific and international contexts, while the Fahrenheit scale is more prevalent in the United States. The conversion formula allows us to convert temperatures between these two scales.

Rounding to the nearest tenth of a degree, we find that 48°C remains unchanged.

It's worth noting that the Celsius scale sets the freezing point of water at 0°C and the boiling point at 100°C at standard atmospheric pressure. In contrast, on the Fahrenheit scale, water freezes at 32°F and boils at 212°F.

Learn more about Celsius degrees, and Fahrenheit temperature.

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Answer:

C. Scalene

Step-by-step explanation:

Equilateral triangle has all sides equal.

Isosceles triangle has exactly 2 sides equal.

All side lengths in a Scalene triangle are distinct.