TEST QUESTION FOR CHEMISTRY GENIUSES ONLY...

TEST QUESTION FOR CHEMISTRY GENIUSES ONLY...

Answers

Answer 1

Answer:

HBr has an electronegativity difference of .76 because Hydrogen's electronegativity is 2.2 and the electronegativity of Bromide is 2.96, and by the chart, it has a polar-covalent bond

Hope this helps!


Related Questions

In which way does asexual reproduction differ from sexual reproduction?

Answers

Answer:

MOUTHWASH lol lol lol lol.  im just kidding heres the answer Asexual reproduction involves one parent and produces offspring that are genetically identical to each other and to the parent. Sexual reproduction involves two parents and produces offspring that are genetically unique.

Answer:

Sexual Reproduction has to include 2 parents and it can cause different  genetic variety. While asexual reproduction is the parent (1) making copies of itself which has no genetic variety  (mainly single celled organisms like protists and such)

Explanation:

My explanation is your answer

A typical coal-fired electric generating plant will burn about 3 metric tons of coal per hour. Most of the coal burned in the United States contains 1 to 4 % by weight sulfur in the form of pyrite, which is oxidized as the coal burns: 4FeS2(s) 11 O2(g) 2 Fe2O3(s) 8 SO2(g) Once in the atmosphere, the SO2 is oxidized to SO3, which then reacts with water in the atmosphere to form sulfuric acid: SO3(g) H2O(l) H2SO4(aq) If 61.7 metric tons of coal that contains 1.20 % by weight S is burned and all of the sulfuric acid that is formed rains down into a pond of dimensions 397 m x 258 m x 5.64 m, what is the pH of the pond

Answers

Answer:

the pH of the pond is 4.0963

 

Explanation:

 Given the data in the question;

4FeS₂(s) + 11O₂(g)  ------>  2Fe₂O₃(s) + 8SO₂(g)

and oxidation of sulfur dioxide to trioxide

SO₃(g) + H₂O(l)  --------> H₂SO₄(aq)

given that; coal = 61.7 metric tons = 61700 kg

1.20 % by weight S, therefore mass of sulfur in coal will be;

⇒ 61700 × 1.20% = 740.4 kg

moles of sulfur = (740.4 × 1000 g) / 32 g/mole = 23,137.5 moles

moles of so₂ produced

= same moles of so₃ and same moles of H₂SO₄ = 23,137.5 moles

volume of pond = 397 m x 258 m x 5.64 m = 577,682.64 m³ = 577682640 L

Molarity = moles / volume = 23,137.5 / 577682640 = 4.0052 × 10⁻⁵ M

now each mole of  H₂SO₄ will give 2 moles of H⁺

[H⁺] = 2 × 4.0052 × 10⁻⁵ =  8.0104 × 10⁻⁵ M

pH = -log[H⁺]  

pH = -log [ 8.0104 × 10⁻⁵ M ]

pH = 4.0963

Therefore, the pH of the pond is 4.0963

The element with the symbol Na

Select one

Cell

Metalloid

Non metal

Metal

Answers

Answer:

metal

Explanation:

it's a soft silvery metal

Take your time please.​

Answers

Answer:

1. Observing

2. Classifying

3. Predicting

4. Making a hypothesis

5. Experimenting

6. Measuring

7. Communicating

8. Making an inference

9. Constant

10. Interpreting data

Explanation:

Hope this helps!!

Answers

observingclassifyingPredictingmaking hypothesisExperimentingmeasuringcommunicatingmaking an inferenceconstantinterpreting data

hope it is helpful to you

Identify what the element is on the periodic table

Answers

That is a Lithium atom!There are THREE protons in that atom. Lithium's atomic number is THREE. If you want to know what isotope that is, look at the neutrons and electrons.Please let me know if I am wrong.

A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. The concentration of acetic acid in the sample was ________ M. A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. The concentration of acetic acid in the sample was ________ M. 0.175 0.119 0.365 0.263 none of the above

Answers

This is all i know
First of all, let's write the equation of the reaction.
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
The formula to be used here is CaVa/CbVb = na/nb
where Ca is the concentration of the acid (?)
Cb is the concentration of the base (0.175M)
Va is the volume of the acid (25 mL)
Vb is the volume of the base (37.5 mL)
na is the number of moles of acid (1)
nb is the number of moles of base (1)
Ca × 25/0.175 × 37.5 = 1/1
Ca = 0.175 × 37.5 × 1 /25 ×1
Ca = 0.263 M
The concentration of the acid in the sample was 0.263 M

Answer:

= 0.2625M ≅ 0.26M (2 sig figs)

Explanation:

               HOAc                        +                    NaOH                 => NaOAc + H₂O

   25ml (Molarity of HOAc)       =\        37.5ml(0.175M NaOH)

Molarity of HOAc = 37.5ml(0.175M NaOH)/25ml

= 0.2625M ≅ 0.26M (2 sig figs)

Why don't the particles in a solid move past one another?

Answers

Answer:

the attractive forces keep the particles together tightly enough so that the particles do not move past each other.

Explanation:

In the solid the particles vibrate in place.

electronic configuration [Ne]3s2 3p6​

Answers

The answer is Argon! From Ne you go 2 3s level elements and then 6 3p level elements

Is this statement true or false?

Gymnosperms reproduce using seeds, but angiosperms do not.

Answers

Answer:

FALSE!

Explanation:

Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.

Answer:

False

Explanation:

At what temperature will 1.50 moles of nitrogen exert a pressure of 1.072 atm in a 20.0 L cylinder?

238 K
0.00574 K
337 K
174 K

Answers

Answer:

174 K

Explanation:

To answer this question we will use the PV=nRT formula, where:

P = 1.072 atmV = 20.0 Ln = 1.50 molR = 0.082atm·L·mol⁻¹·K⁻¹T = ?

We input the data given by the problem:

1.072 atm * 20.0 L = 1.50 mol * 0.082atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

T = 174 K

Meaning the correct answer is the fourth option, 174 K.

aluminium containers are used to store and transport nitric acid(HNO3) but not NAOH why?​

Answers

Answer:

(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.

Acid spills are often neutralized with sodium carbonate. For example
Na CO2 (s) + H2SO4 (aq) → Na2SO4 (aq) + CO2(g) + H20 (1)
An instructor dropped a 2.50 L bottle of 18.0 M H2SO4 on a cement floor.
How much sodium carbonate would be required to neutralize it?

Answers

Answer:

4770 grams of sodium carbonate

Explanation:

The reaction that takes place between sodium carbonate and sulfuric acid is:

Na₂CO₃ (s) + H₂SO₄ (aq) → Na₂SO₄ (aq) + CO₂(g) + H₂O (l)

First we calculate how many H₂SO₄ moles reacted, using the given concentration and volume of solution:

moles = Molarity * Liters

moles = 18.0 M * 2.50 L = 45 mol H₂SO₄

Then we convert H₂SO₄ moles into NaCO₂ moles, using the stoichiometric coefficients:  

45 mol H₂SO₄ * [tex]\frac{1molNa_2CO_3}{1molH_2SO_4}[/tex] = 45 mol NaCO₂

Finally we convert 45 NaCO₂ moles into grams, using its molar mass:

45 mol NaCO₂ * 106 g/mol = 4770 g

What process at the surface of the Earth is part of the formation of sedimentary rocks?
A. the cycle of day and night
B. water depositing sediment in layers
C. magma rising from the Earth's mantle
D. rain falling into the ocean

Answers

Answer:

Clastic sedimentary rocks are made up of pieces (clasts) of pre-existing rocks. Pieces of rock are loosened by weathering, then transported to some basin or depression where sediment is trapped. If the sediment is buried deeply, it becomes compacted and cemented, forming sedimentary rock.

please give brainliest

Methane is combusted with Oxygen to produce Carbon Dioxide and Water. How many grams of oxygen are required to react with 55 grams of
Methane?
A.55 g
B.110 g
C.165 g
D.220 g

Answers

The answer is B.110 g

An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the clement symbol, and determine the mass
number and charge for this atom or ion.

Answers

The atom is krypton and its symbol is Kr.

the mass number is 41 + 36 = 77

its charge is 0 as it is a noble gas.

How many atoms are present in one formula unit of barium acetate, Ba(C2H302)2? ​

Answers

Answer:

i think 15

Explanation:

Answer: About Barium Acetate

All metallic acetates are inorganic salts containing a metal cation and the acetate anion, a univalent (-1 charge) polyatomic ion composed of two carbon atoms ionically bound to three hydrogen and two oxygen atoms (Symbol: CH3COO) for a total formula weight of 59.05. Hopefully i helped

Explanation:

Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches.
Use the References to access important values if needed for this question.
Match the gas sample on the left with a description on the right.
You may use the same answer more than once.
Clear All
0.115 moles of Xe in a 4.87 L container at a temperature of 446K
0.599 moles of Xe in a 5.78 L container at a temperature of 306K
0.444 moles of Xe in a 2.39 L container at a temperature of 408K
0.556 moles of Xe in a 2.11 L container at a temperature of 446K
has the highest average molecular speed
has the lowest average molecular speed
has an average molecular speed between the highest and the lowest

Answers

Answer:

Container 2 has the lowest average molecular speed

Container 4 has the highest average molecular speed

Explanation:

Step 1: Data given

Atomic mass of Xe = 131.29 g/mol

Container 1: Number of moles Xe = 0.115 moles; volume = 4.87 L; temperature= 446K

Container 2: Number of moles Xe = 0.599 moles; Volume = 5.78 L; temperature= 306K

Container 3: Number of moles Xe = 0.444 moles; Volume = 2.39L; Temperature = 408K

Container 4: Number of moles Xe = 0.556 moles; Volume=2.11L; Temperature =446K

Step 2: Calculate average molecular speed

Average molecular speed V = √(8RT/πM)

→With R = he gas constant expressed in units of J/mol-K

→with T = the temperature in Kelvin

→with M = the molar mass of the gas

Average molecular speed depends on T and M

Since it's all Xenon, M is the samefor the 4 containers

Container 1:

V1 = √(8*8.314*446K/π*131.29)

V1 = 8.48

has an average molecular speed between the highest and the lowest

V2= √(8*8.314*306K/π*131.29)

V2= 7.03

has the lowest average molecular speed

V3 = √(8*8.314*408K/π*131.29)

V3 = 8.11

has an average molecular speed between the highest and the lowest

V4 = √(8*8.314*446K/π*131.29)

V4 = 8.48

Since the volume is smaller than in container 1 the average molecular speed will be a higher

has the highest average molecular speed

What is the total number of oxygen atoms on the left-hand side of this chemical equation?
2 Caz(PO4),(s)+48i0,(s) +12C(s) - 4 Casio2(3)+P4($)+12CO(g)

Answers

Answer:

Is the answer eight atoms

What is the delta H fusion used to calculate volume of a liquid frozen that produces 1 kg of energy?

Answers

Answer:

The correct option is C. 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

Explanation:

The change in enthalpy of fusion (ΔHfus) has units of energy divided into moles of substance:

ΔHfus = energy/mol of substance = J/mol or KJ/mol

Thus, we multiply the kJ of energy produced by the inverse of ΔHfus (in kJ/mol) we obtain the moles of substance:

energy (kJ) x 1/ΔHfus (mol/kJ) = moles of substance(mol)

Then, if we multiply the moles of substance by the molecular weight of the substance (in g/mol) we obtain the grams:

moles of substance(mol) x molecular weight (g/mol) = grams of substance (g)

Finally, if we multiply the grams of substance (in g) by the density of the substance (in g/ml) we obtain the volume (in ml):

grams of substance (g) x 1/density (ml/g) = volume (ml)

We combine all these parts to obtain the equation for the volume required to produce 1 kJ of energy:

energy (kJ) x 1/ΔHfus (mol/kJ) x molecular weight (g/mol) x 1/density (ml/g)

Therefore, the correct option is:

C → 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

1 kJ x 1/ΔHfus x g/mol x ml/g liquid

9. During which phase of Mitosis does the Cell start to get ready to divid
Prophase
O Metaphase
Anaphase
Telophase

Answers

Answer:

Hello,

QUESTION)Telephase

During telophase, the cell, each pole of which inherits the same number of single  chromosomes, begins to divide into 2: this is  cytodieresis.

10. Which of the following metals reacts vigorously with oxygen?
(A) Zinc (B) Magnesium (C) Sodium (D) Copper​

Answers

Answer: the answer is C

Um pls mark me as brainliest

Explanation:

give an example of biotic living conditions.

Answers

Answer:

plants and animals

Explanation:

Answer:

water, light, wind, soil, humidity, minerals, gases

Explanation:

i just know

Plz help Need Answer Quick

Answers

Answer:

The correct answer is - [tex]\frac{P}{4}[/tex].

Explanation:

By the ideal gas equation is PV=nRT, the relation between pressure and volume can be drive if the temperature remains constant:

At constant temperature, for a fixed amount of gas, P∝

so the pressure is inversely proportional to volume. Therefore, if the volume is increased in this condition the pressure will decrease in the same manner and A decrease in the volume will lead to an increase in pressure.

Volume increased here = four times = 4V

pressure is P will decrease four times = P/4

6. The drawing shows Samir riding his mountain bike.
i) Draw a circle around the places on the drawing where there
should be a lot of friction.
ii) Explain why there should be a lot of friction in these places.

Answers

Answer:

You Need To Upload The Photo Then I Will Help You :)

Explanation:

What pair of properties do all solids have?

Answers

Answer:

Has definite shape and volume

Solids have high melting point

Explanation:

What is the mass of 5.55 moles of carbon monoxide

Answers

Answer:

[tex]\boxed {\boxed {\sf 155 \ g\ CO}}[/tex]

Explanation:

To convert from moles to mass, the molar mass must be used.

First, write the chemical formula for carbon monoxide. Since the carbon (C) comes first without a prefix, there is 1 carbon atom. The prefix mono- before oxide means 1, so there is also 1 oxygen (O) atom. The formula is CO.

Next, look up their molar masses on the Periodic Table.

C: 12.011 g/mol O: 15.999 g/mol

Since there is 1 atom of each, the molar masses can be added.

CO: 12.011 g/mol + 15.999 g/mol = 28.01 g/mol

Use this molar mass as a ratio.

[tex]\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]

Multiply by the given number of moles:5.55

[tex]5.55 \ mol \ CO *\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]

The moles of carbon monoxide cancel.

[tex]5.55 * \frac {28.01 \ g \ CO} {1 }[/tex]

Multiply.

[tex]155.4555 \ g \ CO[/tex]

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, it is the ones place. The 4 in the tenths place tells us to leave the 5.

[tex]155 \ g\ CO[/tex]

5.55 moles of carbon monoxide is about 155 grams.

Which action is not an example of work?

A. pushing a box across the floor
B. picking up a box off the floor
C. holding a tray in the Cafeteria line
D. raising a barbell over your head

Answers

C. picking a tray in the cafeteria line

PLEASE ANSWER True or False: When adding reactions together to get a desired reaction you must also add their enthalpies to get the enthalpy of that desired reaction.

Answers

Answer:

true

Explanation:

Which phrase describes a compound that consist of two elements

Answers

Carbon dioxide, nitrous oxide, and methane are all compounds that consist of two elements

How many joules are needed to heat 20.0 g of Au from 10°C to 50°C?
show work

Answers

Answer:

297 J

Explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of 1 g of a given substance by 1∘C.

In your case, aluminium is said to have a specific heat of 0.90Jg∘C.

So, what does that tell you?

In order to increase the temperature of 1 g of aluminium by 1∘C, you need to provide it with 0.90 J of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by 1∘C. So if you wanted to increase the temperature of 10.0 g of aluminium by 1∘C, you'd have to provide it with

1 gram0.90 J+1 gram0.90 J+ ... +1 gram0.90 J10 times=10×0.90 J

However, you don't want to increase the temperature of the sample by 1∘C, you want to increase it by

ΔT=55∘C−22∘C=33∘C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1∘C10×0.90 J+1∘C10×0.90 J+ ... +

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