Suppose a square had an area measured in square inches, with a numerical value that is 12 more than that of its perimeter, measured in inches.


Write an equation that can be used to find the dimensions of the square

Answer:

Step-by-step explanation:

Unfortunately, there is no table provided in your question. However, we can still solve the problem based on the given information.

Let's assume that Ronald buys "x" pounds of apples and "y" pounds of peaches. We know that the cost of apples is $5 per pound, and the cost of peaches is $6 per pound.

So, the total cost of apples will be 5x, and the total cost of peaches will be 6y. We also know that Ronald has $60 to spend. Therefore, we can write the following equation:

5x + 6y = 60

This is the equation that represents the total cost of apples and peaches that Ronald can buy with $60.

However, we want to find the function that relates the number of pounds of apples, x, and the number of pounds of peaches, y, that Ronald can purchase. To do this, we need to solve the above equation for y in terms of x:

5x + 6y = 60

6y = 60 - 5x

y = (60 - 5x)/6

This is the function that relates the number of pounds of apples, x, and the number of pounds of peaches, y, that Ronald can purchase with $60.

Projection of vector u onto vector v is approximately (1.33, 0.76, -0.57).

We'll use the following formula:

projection of u onto v = (u•v / ||v||²) * v

First, we need to calculate the dot product (u•v) and the magnitude squared (||v||²) of vector v.

1. Dot product (u•v):
u•v = (5 * -7) + (-9 * -4) + (-5 * 3) = -35 + 36 - 15 = -14

2. Magnitude squared (||v||²):
||v||^2 = (-7)² + (-4)² + (3)² = 49 + 16 + 9 = 74

Now, we'll plug these values into the projection formula:

projection of u onto v = (-14 / 74) * v

We'll multiply each component of vector v by the scalar (-14/74):

projection of u onto v = (-14/74) * (-7, -4, 3) = (1.33, 0.76, -0.57)

So, the projection of vector u onto vector v is approximately (1.33, 0.76, -0.57).

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The one critical point at (0, 0).

The critical point (0, 0) is a saddle point, and the critical point (-9, -3) is a relative minimum.

To find the critical points of the given function f(x, y) = x^2 - 6xy - 2y^3, we need to find the points where the partial derivatives with respect to x and y are equal to zero.

Calculate the partial derivative with respect to x (f_x):

f_x = 2x - 6y

Calculate the partial derivative with respect to y (f_y):

f_y = -6x - 6y^2

Set both partial derivatives equal to zero and solve the system of equations:

2x - 6y = 0 ---(1)

-6x - 6y^2 = 0 ---(2)

From equation (1), we can rearrange it to solve for x:

2x = 6y

x = 3y

Substituting x = 3y into equation (2):

-6(3y) - 6y^2 = 0

-18y - 6y^2 = 0

-6y(3 + y) = 0

Now, we have two possible cases:

a) -6y = 0

b) 3 + y = 0

a) -6y = 0

This implies y = 0

Substituting y = 0 into equation (1):

2x - 6(0) = 0

2x = 0

x = 0

So, we have one critical point at (0, 0).

b) 3 + y = 0

This implies y = -3

Substituting y = -3 into equation (1):

2x - 6(-3) = 0

2x + 18 = 0

2x = -18

x = -9

So, we have another critical point at (-9, -3).

Now, to classify each critical point as a relative maximum, relative minimum, or a saddle point, we need to analyze the second-order partial derivatives.

Calculate the second partial derivative with respect to x (f_xx):

f_xx = 2

Calculate the second partial derivative with respect to y (f_yy):

f_yy = -12y

Calculate the mixed partial derivative (f_xy):

f_xy = -6

Now, evaluate the discriminant D = f_xx * f_yy - (f_xy)^2 at each critical point:

For the critical point (0, 0):

D = f_xx * f_yy - (f_xy)^2

= 2 * (-12 * 0) - (-6)^2

= 0 - 36

= -36

For the critical point (-9, -3):

D = f_xx * f_yy - (f_xy)^2

= 2 * (-12 * -3) - (-6)^2

= 72 - 36

= 36

Analyzing the discriminant:

For the critical point (0, 0):

If D < 0, it is a saddle point. In this case, D = -36, so (0, 0) is a saddle point.

For the critical point (-9, -3):

If D > 0 and f_xx > 0, it is a relative minimum. In this case, D = 36 and f_xx = 2, so (-9, -3) is a relative minimum.

Therefore, the critical point (0, 0) is a saddle point, and the critical point (-9, -3) is a relative minimum.

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Answer:

27

Step-by-step explanation:

If 13 matches are played in total then, 7 2-player matches and 6 6-player matches are played.

Here we see that the table has two columns- 6 player Athletes and 2 player athletes. It is given that no athlete participates in both the type of games. Hence we can say that

If one match for 2 player game is held then 2 players are employed there.

Hence we have 48 players left

hence we will have 48/6 = 8 6-player matches.

Similarly, if 1 6-player match is played then 44 players applied for the 2-player match, hence, we have 44/2 = 22 2-player matches

If 4 2-player matches are held then we will have 8 players booked. Hence 42/6 = 7 6-player matches were held.

If 4 6-player matches were held then, we have 26/2 = 13 2-player matches.

Hence the table will be

Number of 6 Player Games                       Number of 2-player games

                     8                                                                 1

                     1                                                                 22

                     7                                                                 4

                     4                                                                 13

b)

Let the total 2-player games played be x and 6-player games be y

we have,

x + y = 13

2x + 6y = 50

or, 2(x + y) + 4y = 50

or, 26 + 4y = 50

or, 4y = 24

or, y = 6

Hence x = 7

Therefore, in total 7 2-player matches and 6 6-player matches are played.

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The independent variable is A, the number of frozen bags.

The independent variable is the number of bags of frozen vegetables, represented by b. This is because the company can choose to package any number of bags, which will then determine the total number of sliced carrots, represented by c. The number of sliced carrots is not independent because it depends on the number of bags of frozen vegetables being packaged. Therefore, the answer is A, the number of frozen bags.

In statistical analysis, the independent variable is the variable that is being manipulated or changed in an experiment to observe the effect on the dependent variable.

In this case, the number of bags of frozen vegetables is the variable being manipulated, while the total number of sliced carrots is the dependent variable being affected by the number of bags. This understanding of independent and dependent variables is crucial in designing experiments and interpreting results in various fields, including food science, agriculture, and health research.

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The amount of paper required to cover each memory box is 5220 square inches.

Considering the edge of the cube = L units.

Thus the area of one side of the cube will be equal to L² unit².

Now, there will be 6 such sides for a closed cube then the total surface area will be 6*(L)² unit²

The given length breadth and height of the box is 35in, 24in, and 30in.

The formula for the surface area of a rectangular prism is:

SA = 2(lw + lh + wh)

Where:

SA = surface area l = length w = width h = height

For this memory box, the given length (35 in), width (24 in), and height (30 in).

Substituting  these values into the formula the SA obtained will be:

SA = 2(35 × 24 + 35 × 30 + 24 × 30) SA

= 2(840 + 1050 + 720) SA

= 2(2610) SA = 5220inches²

Therefore, the answer will be 5220 square inches.

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a) The apple sample has a greater typical value or median than the orange sample.

b) The orange sample has a greater variability or spread than the apple sample.

a) The median of the apple sample is 150 grams, while the median of the orange sample is 130 grams. Therefore, the apple sample has a greater typical value or median.

b) The interquartile range (IQR) of the apple sample is 8 grams, while the IQR of the orange sample is 111 grams. Therefore, the orange sample has a greater variability or spread.

c) It is possible that the heaviest piece of fruit in the two samples was an orange, as the orange sample has a larger range of weights than the apple sample. However, without knowing the maximum weight in each sample, we cannot say for certain whether the heaviest fruit was an orange or an apple.

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Therefore , the solution of the given problem of unitary method  comes out to be  $52 10 units of coverage will be purchased.

To complete the work, the well-known straightforward strategy, actual variables, and any essential components from the very first and specialised inquiries can all be utilised. In response, customers might be given another opportunity to sample the product. Otherwise, important advancements in our comprehension of algorithms will be lost.

Here,

We are informed that the first unit of coverage will cost $16 and each additional unit will cost $4. We may calculate the price of x units of coverage using the following formula:

=> C(x) = 16 + 4(x-1)

The number of subsequent units of coverage following the initial unit is indicated by the (x-1) term in the calculation.

We may enter x=10 into the algorithm to get the price for 10 units of coverage:

=> C(10) = 16 + 4(10-1)

=> C(10) = 16 + 4(9)

=> C(10) = 16 + 36

=> C(10) = 52

For $52, 10 units of coverage will be purchased.

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The greatest possible width the land strip, in miles with the amount of material that has is 1/250 miles wide.

A quadrilateral with parallel sides that are equal to one another and four equal vertices is known as a rectangle. It is also known as an equiangular quadrilateral for this reason.

Rectangles can also be referred to as parallelograms since their opposite sides are equal and parallel.

A quadrilateral with equal angles and parallel opposing sides is referred to as a rectangle. Around us, there are a lot of rectangle items. The length and breadth of each rectangle serve as its two distinguishing attributes. The width and length of a rectangle, respectively, are its longer and shorter sides.

Let's say that her landing strip is x miles long, then its area would be:

1/6.x

We also know how big it is:

so,

1/6.x = 1/1500

x = 6/1500

x = 3/750

x = 1/250 miles

Therefore, possible width of the landing strip is 1/250 miles.

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Complete question:

Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing strip must be 1/6 of a mile long. With the amount of material that has , what is the greatest possible width the land strip, in miles?

The area of the rectangular park is equal to 0.233 sq miles.

The measurements of the park that are given in the question are given as 7/10 mile by 2/6 mile.

The length of the rectangle park is 7/10 and the width of the park is 2/6 mile. We know that the area of the rectangle park is given as the:

= length * width of the park.

= L * W

= (7/10) * (2/6)

we can reduce the fraction even further to make the calculation easy

= (7/10) * (1/3)

Multiplying the denominators we get

= 7/30

To make the answer even simpler it can be converted into a decimal form which will be:

= 0.233 sq miles.

Therefore, The area of the rectangular park is equal to 0.233 sq miles.

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Answer:

D. 4π

Step-by-step explanation:

Circumference: C = 2πr = 2π(8) = 16π

The distance = 1/4 circumference (angle is 90 degrees)

=> distance = 16π/4 = 4π

Using the federal list, the total amount of exemptions that Jerry would be allowed is $29,800.

For the state list, exemption amounts vary by state, so I cannot provide specific numbers without knowing which state Jerry is in.

To determine the total amount of exemptions Jerry would be allowed using the federal list and state list, we first need to examine the value of each asset. Jerry has a house with equity of $15,000, a car with equity of $2,500, household goods worth $6,000, and tools worth $5,800.

Using the federal list, the exemptions include:
1. Homestead exemption: up to $25,150 for the house equity
2. Motor vehicle exemption: up to $4,000 for the car equity
3. Household goods exemption: up to $13,400 (no single item over $625)
4. Tools of the trade exemption: up to $2,525 for tools needed for business

Jerry's federal exemptions would be:
1. $15,000 for the house (within the $25,150 limit)
2. $2,500 for the car (within the $4,000 limit)
3. $6,000 for household goods (within the $13,400 limit)
4. $5,800 for the tools (exceeds the $2,525 limit)

Using the federal list, the total amount of exemptions that Jerry would be allowed is $29,800 (15,000 + 2,500 + 6,000 + 2,525).

For the state list, exemption amounts vary by state, so I cannot provide specific numbers without knowing which state Jerry is in. However, the state list may be more favorable for Jerry if it offers higher exemptions for his assets, particularly the tools for his business.

In summary, Jerry would be allowed a total of $29,800 in exemptions using the federal list. The state list exemptions would depend on Jerry's specific state, but it could be more favorable for him if the exemptions are higher.

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The total amount of exemptions that Jerry would be allowed using the federal list is $13,100.

Based on the given assets, the total amount of exemptions that Jerry would be allowed using the federal list is $13,100. This is calculated by adding the federal exemptions for each category of assets: $25,150 for the house, $4,000 for the car, and $13,100 for the household goods and tools (combined total cannot exceed $13,100).
The state list varies depending on the state where Jerry resides. Without knowing the state, it is impossible to provide an accurate answer. However, it is generally true that the state list can be more favorable for the debtor, as some states have higher exemption amounts or allow for additional exemptions that are not available under federal law. Jerry should consult with a bankruptcy attorney in his state to determine the specific exemptions available to him.

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The calculated value of the expression that is equivalent to √(x¹²qr²) is x⁶r√q

From the question, we have the following parameters that can be used in our computation:

√x12qr²

Express properly

So, we have

√(x¹²qr²)

Evaluating the expression in the brackets using the law of indices

So, we have

√(x¹²qr²) = x⁶r√(q)

Next, we open the brackets

This gives

√(x¹²qr²) = x⁶r√q

Hence, the expression that is equivalent to √(x¹²qr²) is x⁶r√q

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Answer:

C - 136

Step-by-step explanation:

Something important to remember here is that whenever you replace a variable with something else, that something else needs to go in parentheses.

3(7)² - 2(7) + 3

Following PEMDAS, you need to take care of that exponent before anything else. While parentheses are included as coming first, that is referring to operations within parentheses, which we don't have here.

3(49) - 2(7) + 3

Multiplication is the next step...

147 - 14 + 3

And finally, addition and subtraction.

147 - 11

136

Answer:

136

Step-by-step explanation:

Since the question stated that x= 7 you simply substitute all x in the expression with 7 and it would look something like this

3 (7)^2 - 2 (7) +3

PLEASE BRAINLIEST

The equation that has given solutions x = -5 and x = 2 is [tex]x^2 + 3x - 10 = 0.[/tex]

If the given solutions of an equation are x = -5 and x = 2, then the equation can be written as a product of two linear factors, (x + 5) and (x - 2), because when either of these factors is equal to zero, the corresponding solution is obtained.

So, the equation is:

(x + 5)(x - 2) = 0

Expanding the product, we get:

[tex]x^2 + 3x - 10 = 0[/tex]

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Answer:

5

Step-by-step explanation:

The correct spot would be 5 because, on a number line, the opposite of a negative would be its positive counterpart and vise versa.

The location of the point P that is 2/5 of the way from A to B on the directed line segment AB is A(x, y) = (- 8, -2) and B(x, y) = (6, 19) is P(x, y) = (- 12/5, 32/5).

A line segment is generated from two distinct points set on a plane,  The location of the point P within the line segment can be found by means of the following vectoral formula below:

P(x, y) = A(x, y) + k · [B(x, y) - A(x, y)], 0 < k < 1     (1)

Where:

A(x, y) = Initial point

B(x, y) =  Final point

k =  Distance factor

We have that A(x, y) = (- 8, - 2), B(x, y) = (6, 19) and k = 2/5, then the location of the point P is:

P(x, y) = (- 8, -2)  + (2/5) · [(6, 19) - (- 8, -2)]

P(x, y) = (- 8, -2) + (2/5) · (14, 21)

P(x, y) = (- 12/5, 32/5)

In conclusion, the location of the point P that is 2/5 of the way from A to B on the directed line segment AB is A(x, y) = (- 8, -2) and B(x, y) = (6, 19) is P(x, y) = (- 12/5, 32/5).

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#complete question:

Find the point P that is 2/5 of the way from A to B on the directed line segment AB if A (-8, -2) and B (6, 19).

the solution to the differential equation is: x = (1/36) y² - (13/36) Note that this equation represents a parabolic curve in the (x,y)-plane, opening upwards and with its vertex at (-13/36,0).

We can start by separating the variables and integrating both sides of the equation:

1/9 y dy = 2 dx

Integrating both sides with respect to their respective variables, we get:

(1/18) y² = 2x + C

where C is the constant of integration.

Using the initial condition y(9) = 7, we can substitute x=9 and y=7 to solve for C:

(1/18) (7²) = 2(9) + C

C = 49/2 - 18 = 13/2

Substituting this value of C back into the general solution, we get:

(1/18) y² = 2x + 13/2

Simplifying and solving for x, we get:

x = (1/36) y² - (13/36)

Therefore, the solution to the differential equation is:

x = (1/36) y² - (13/36)

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Answer:

Hello! I'd be happy to help you with your math question. Based on the information you've provided, the aircraft flying in a north easterly direction turned through one whole number 2 over 3 right angle to the right of its path. To determine its new course, we need to know the original course of the aircraft. Do you happen to have that information? Once we have that, we can use some trigonometry to calculate the new course. Let me know and I'll be happy to guide you through the process.

Answer:

hope it helps________________

Step-by-step explanation:

673 children, 11 students, and 336 adults attended the movie.

How many children attended the movie?

How many students attended the movie?

How many adults attended the movie?

How to calculate the total ticket sales?

How to use equations to solve a word problem?

How to check if the obtained solution is valid?

Let's begin by defining some variables:

Let C be the number of children attending the movie.

Let S be the number of students attending the movie.

Let A be the number of adults attending the movie.

We know that the theater has a seating capacity of 323, so we can write an equation that relates the number of people attending the movie to the seating capacity:

C + S + A = 323

We also know that the theater charges $5.00 for children, $7.00 for students, and $12.00 for adults, and that there are half as many adults as there are children. Using this information, we can write another equation that relates the total ticket sales to the number of people in each category:

5C + 7S + 12A = 2348

We can use the fact that there are half as many adults as children to express A in terms of C:

A = 0.5C

Substituting this into the first equation, we get:

C + S + 0.5C = 323

Simplifying, we get:

1.5C + S = 323

Now we have two equations with two unknowns (C and S), which we can solve to find the values of these variables:

1.5C + S = 323 (equation 1)

5C + 7S = 2348 (equation 2)

Multiplying equation 1 by 5 and subtracting it from equation 2, we can eliminate S and solve for C:

5(1.5C + S) - 7S = 7.5C + 5S - 7S = 2348 - 5(323) = 1683

2.5C = 1683

C = 673.2

Since C must be a whole number, we can round down to the nearest integer:

C = 673

Now we can use this value of C to find S:

1.5C + S = 323

1.5(673) + S = 323

S = 323 - 1010.5

S = 10.5

Again, since S must be a whole number, we round up to the nearest integer:

S = 11

Finally, we can use the equation A = 0.5C to find A:

A = 0.5C = 0.5(673) = 336.5

Rounding down to the nearest integer, we get:

A = 336

Therefore, the number of children, students, and adults who attended the movie are:

673 children, 11 students, and 336 adults.

Answer:

(4,6) on the coordinate plane is the 1st quadrant. You start at the origin, go 4 to the right and 6 up.

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Given AB and AC are lines that are tangent to the circle with the measure of angle BAC = 40°, ∠BDC is 140°.

A tangent to a circle is a line that intersects the circle at a single point. The point at which the tangent intersects the circle is known as the point of tangency. The tangent is perpendicular to the circle's radius, with which it meets.

You've been handed two tangent lines. You will also be handed a four-sided figure. All four-sided figures have 360 degrees of rotation. At 90 degrees, a radius meets a tangent.

∠BDA = 90°

∠DCA = 90°

∠BCA = 40°

All the angles in total make 360°, so:

∠BDA + ∠DCA + ∠BCA + ∠BDC = 360

90 + 90 + 40 + ∠BDC = 360

220 + ∠BDC = 360

∠BDC = 360 - 220

= 140°

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Correct question:

Given AB and AC are lines that are tangent to the circle with the measure of angle BAC = 40°, what is the measure of angle BDC? Image is attached below.

The equation that represent the amount of caffeine C in a pregnant woman’s body t hours  is [tex]C = 260(0.05)^{(t)}[/tex], under the condition that pregnant women process caffeine at about 5. 6% per hour.

Now the amount of caffeine C in a pregnant woman’s body t hours after the coffee is  ingested can be projected  by the equation

[tex]C = 260(0.05)^{(t)}[/tex]
here
C = amount of caffeine in milligrams (mg)
t = time in hours since the coffee was consumed
0.05 is the convention of 5.6%

It's crucial to note that pregnant women metabolize caffeine gradually slower than non-pregnant women, and it can take 1.5–3.5 times longer to eliminate caffeine from their body. In fact, most experts agree that caffeine is safe during pregnancy if limited to 200 mg or less per day.

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The sum of all the terms in the arithmetic progression is 3507.

The common difference in an arithmetic progression is the difference between any two consecutive terms. Let the common difference be d. Then, the third term is 2 + d, the fourth term is 2 + 2d, and so on. Also, let the last term be n.

Since the last term is greater than 150, we can write n = 2 + (n-2)d > 150. Solving this inequality, we get d < 74. Therefore, the common difference can be 1, 2, 3, ..., 73.

Using the formula for the sum of an arithmetic progression, we get the sum of all the terms as (n/2)(first term + last term) = (n/2)(2 + n d) = (n/2)(11 + (n-1)d).

We can substitute n = (last term - first term)/d + 1 and solve for the sum. This gives us the final answer of 3507.

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The ounces of filler will the factory need in order to make meatballs out of this shipment of beef is  56.7 oz of filler.

A number of distinct units of mass, weight, or volume are derived from the uncia, an ancient Roman unit of measurement, including the ounce, which remains almost unmodified. The avoirdupois ounce, also known as the US customary and British imperial ounce, is equal to one-sixteenth of an avoirdupois pound.

One factory obtained 90 kg of beef from overseas.

They want to add 1.4oz of filler for each pound of beef.

Given is:

0.45 kg = 1 pound

So,  90 kg = 90 x 0.45 = 40.5 pounds

The company want to add 1.4 oz of filler for each pound of beef.

So for 1 pound we have 1.4 oz of filler

So, for 40.5 pounds they will need = x oz of filler.

x = 1.4 x 40.5 = 56.7

Therefore, the company needs 56.7 oz of filler.

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Complete question;

Factories often add filler when making meatballs sold by the bag. One factory obtained 90kg of beef from overseas. They want to add 1.4oz of filler for each pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef?

The exponential decay function to model this situation where t represents the number of years since 2007 and y is the amount of people is y = 19265 * (1 - 0.015)^t. The population for 2031 will be approximately 14,814 people.

To write an exponential decay function for this situation, you can use the formula:

y = P * (1 - r)^t

where y is the population at time t, P is the initial population, r is the annual decrease rate, and t represents the number of years since 2007.

In this case, P = 19265, r = 0.015 (1.5% expressed as a decimal), and t represents the number of years since 2007.

So, the exponential decay function is:

y = 19265 * (1 - 0.015)^t

To estimate the population for 2031, find the difference in years between 2031 and 2007 (2031 - 2007 = 24 years), and plug it into the formula as t:

y = 19265 * (1 - 0.015)^24

y ≈ 14814

So, the estimated population in 2031 will be approximately 14,814 people, rounded to the nearest person.

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length of AC in the triangle is 32 units.

The triangle proportionality theorem, also known as the side-splitter theorem, states that if a line is drawn parallel to one side of a triangle, then it divides the other two sides proportionally.  

In mathematical terms, let ABC be a triangle with a line parallel to one side, say line DE || AB, where D lies on BC and E lies on AC. Then, the theorem states that:

BD/DC = AE/EC

In the given triangle ABC;

GH and AC are parallel

AG=BG

BH=HC

Using proportional rule

BG/AB=GH/AC

BG/2BG=16/AC

1/2=16/AC

AC=32 units

Hence, length of AC in the triangle is 32units.

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Answer:

1. 32 units

Step-by-step explanation:

sorry abt the other person but the answer is 32... i just took it

The solution of initial value problem, y = 9/t - 1, t ≠ 0.

We can begin by rearranging the equation and separating the variables:

t^2 dy/dt - yt = t + 1

dy/(y+1) = (t+1)/t^2 dt

Integrating both sides, we get:

ln|y+1| = -1/t + t/t + C

ln|y+1| = -1/t + C

|y+1| = e^C /t

Using the initial condition y(1) = 8, we can find the value of C:

|8+1| = e^C /1

e^C = 9

C = ln 9

Substituting back into the general solution, we have:

|y+1| = 9/t

We can now solve for y in terms of t:

y+1 = ±9/t

If we take the positive sign, we get:

y = 9/t - 1

If we take the negative sign, we get:

y = -9/t - 1

Thus, the general solution to the initial value problem is:

y = 9/t - 1 or y = -9/t - 1

Using the initial condition y(1) = 8, we can see that the correct solution is:

y = 9/t - 1

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The function S(t) = 31,500(1.034)^t approximates the number of digital subscriptions for a large city newspaper after the launch of a new advertising campaign, with an initial number of 31,500 subscriptions and a growth rate of 3.4% per month.

To interpret the parameters of the function S(t) = 31,500(1.034)^t, which approximates the number of digital subscriptions for a large city newspaper after the launch of a new advertising campaign.

1. The initial number of digital subscriptions (S(0)): This is represented by the constant 31,500 in the equation. When t=0 (at the launch of the campaign), the function becomes S(0) = 31,500(1.034)^0 = 31,500. This means that at the start of the advertising campaign, there were 31,500 digital subscriptions.

2. The growth rate of digital subscriptions: This is represented by the factor 1.034 in the equation. The growth rate is 3.4% (since 1.034 = 1 + 0.034).

This means that the number of digital subscriptions is expected to increase by 3.4% each month after the launch of the advertising campaign.

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