State whether the decay is linear or​ exponential, and answer the associated question.
The value of a car is decreasing by 12% per year. If the car is worth $9,000 ​today, what will it be worth in two​ years?

Answer:

The expression $11.75x + $20 represents the total price for the order, including delivery to the school.

In this expression, 'x' represents the number of boxes of paints being purchased, and $11.75 represents the cost of each box. The term $11.75x represents the total cost of the boxes of paints based on the number of boxes being purchased.

The term $20 represents the delivery cost to the school, which is added to the total cost of the boxes of paints.

By multiplying the cost per box ($11.75) by the number of boxes (x) and adding the delivery cost ($20), you can calculate the total price for the order, including delivery.

Answer:

77.53

Step-by-step explanation:

You just have to sum them up

Answer:

i think the answer is 77.53

Step-by-step explanation:

Answer:

12.8

Step-by-step explanation:

Quotient means the answer of two things divided.

62.72/4.9=12.8

Answer:x=-8

Step-by-step explanation:

3.2+(−1/2)x−2=4.8x+2−5.2x

−0.1x=0.8

x=-8

Answer:

x=-8

Step-by-step explanation:

x=-8

Answer:

We can write 4x^2 + y^2 - 4xy - 16 as the product:

(2x - y + 4)(2x - y - 4)

Step-by-step explanation:

To write 4x^2 + y^2 - 4xy - 16 as a product, we can use the technique of completing the square. First, we can rearrange the terms to group the x terms and the y terms:

4x^2 - 4xy + y^2 - 16

Next, we can complete the square for the x terms and the y terms separately. For the x terms, we can add and subtract (2x)^2:

4x^2 - 4xy + (2x)^2 - (2x)^2 + y^2 - 16

Simplifying the first three terms gives:

(2x - y)^2 - (2x)^2 + y^2 - 16

For the y terms, we can add and subtract 16:

(2x - y)^2 - (2x)^2 + (y - 4)^2 - 16^2

Simplifying the second term gives:

-(4x^2) + 16x - (y^2) + 16y - 16^2

Therefore, we can write 4x^2 + y^2 - 4xy - 16 as the product:

(2x - y + 4)(2x - y - 4)

The part of the cake with vanilla or lemon frosting is 1/5 by using arithmetic and algebraic expression.

Let's start by defining the variable "x" as the part of the cake with vanilla or lemon frosting.

According to the problem, Jonah uses vanilla frosting on 1/5 of the cake, which can also be written as x = 1/5.

Similarly, he uses lemon frosting on 2/5 of the cake, which can be written as x = 2/5.

We know that the sum of the parts of the cake with vanilla, lemon, and chocolate frosting should equal the whole cake. Since there are only three types of frosting, we can write:

x + x + chocolate frosting = 1

2x + chocolate frosting = 1

We also know that chocolate frosting covers the remaining part of the cake, which is 3/5. Therefore, we can write:

chocolate frosting = 3/5

Substituting this value into the previous algebraic expression, we get:

2x + 3/5 = 1

Subtracting 3/5 from both sides of the equation, we get:

2x = 2/5

x = 1/5

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The value of x and y will be

a) x= 48  y= 72

b) x= 10   y= 3

c) x= 18  y= 3

What is triangle proportionality theorem ?

Triangle Proportionality Theorem Statement

If a line is drawn parallel to any one side of a triangle so that it intersects the other two sides in two distinct points, then the other two sides of the triangle are divided in the same ratio.

DA/BD = EC/BE

How we can calculate the value of x and y from the figure ?

The value of x and y can be calculated as

a ) x/4 + 5 =x/2-7                  y/3-6=66-2/3y

   x/4- x/2 = -7-5                   y/3+ 2y/3= 66 + 6  

   x-2x/4=-12                          3y/3= 72

    x= 48                                   y=72

b) x/5 +3 = 4x-35                   2y + 1 = 5y-8

  x/5 - 4x = -35-3                    2y-5y= -8-1

 x-20x/5 = -38                        -3y=-9

 -1 9x/5 = -38                            y=3

    x= 10

c) x/3 + 2= 2x/3-4                    5y=7y/3+8

   x/3-2x/3= -4-2                      5y-7y/3=8

  -x/3 = -6                                  15y-7y=8x3

   x= 18                                           y=3

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The total cost of the fence needed for the Perimeter of the work site is $8,800. So the answer is option B.

Because the question involves many units of measurement, we must convert them all to the same unit in order to determine the answer.

1/4 mile is equivalent to 1320 feet (1 mile = 5280 feet).

The length of the fence required to surround the work site equals the perimeter of the work site. To calculate the length of the fence in yards, divide 1320 feet by 3 (since a yard is 3 feet long).

1320 feet ÷ 3 = 440 yards

So the length of the fence needed is 440 yards.

The fence costs $20.00 per yard, thus to get the total cost, multiply the length of the fence by the cost per yard:

440 yards x $20.00/yard = $8,800.00

Therefore, the total cost of the fence needed for the perimeter of the work site is $8,800.00.

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The solution to the exponential equation is given as follows:

x = 0.8.

The exponential equation in the context of this problem is defined as follows:

[tex]\left(\frac{1}{64}\right)^{0.5x - 3} = 8^{9x - 2}[/tex]

64 is the sixth power of two, while 8 is the third power of two, hence:

Applying the power of power rule, the equation can be given as follows:

[tex]2^{-6(0.5x - 3)} = 2^{3(9x - 2)}[/tex]

[tex]2^{-3x + 18} = 2^{27x - 6}[/tex]

Exponential functions are one-to-one, meaning that the solution is obtained as follows:

-3x + 18 = 27x - 6

30x = 24

x = 0.8.

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Answer:

54.6 square yards

Step-by-step explanation:

For any regular polygon, the area of the polygon is given by:

[tex]A_{regular~polygon}=\frac{1}{2}nsa[/tex], where

Heptagons are 7-sided polygons, so n=7.

The length of a side and the apothem are given, so substitute and calculate:

[tex]A_{heptagon}=\frac{1}{2}(7)sa[/tex]

[tex]A_{heptagon}=\frac{1}{2}(7)(3.9~yd)(4.0~yd)[/tex]

[tex]A_{heptagon}=54.6 ~yd^2[/tex]

After the first quarter, the interest earned would be:

$1,000.00 * 0.02 = $20.00

So the new balance would be:

$1,000.00 + $20.00 = $1,020.00

After the second quarter, the interest earned would be:

$1,020.00 * 0.02 = $20.40

So the new balance would be:

$1,020.00 + $20.40 = $1,040.40

After the third quarter, the interest earned would be:

$1,040.40 * 0.02 = $20.81

So the new balance would be:

$1,040.40 + $20.81 = $1,061.21

After the fourth quarter, the interest earned would be:

$1,061.21 * 0.02 = $21.22

So the final balance after 4 years would be:

$1,061.21 + $21.22 = $1,082.43

Therefore, the balance after 4 years would be $1,082.43.

"The line has a positive slope and passes through the x-axis at -2. Additionally, it crosses through point (2, 1).

The formula in this case is 2x-y = -4. When we set the value of y to 0, we can use this equation to calculate the x-intercept: 2x0=42x=4. When we multiply both sides by 2, we obtain 2x2=42x=2. The x-intercept is therefore -2.

We may use the slope-intercept version of the equation, y = mx + b, where m is the slope and b is the y-intercept, to graph the line y = 4x - 2.

We can observe that the slope is m = 4 and the y-intercept is b = -2 by comparing y = 4x - 2 to y = mx + b.

Starting with the y-intercept of -2 on the y-axis, we can graph line by finding other points on it using the slope of 4.

To get to the point, if we move two units to the right, we must move up eight units. (2, 6). To get to the point, if we move two units to the left, we must move down eight units. (-2, -10).

According to the description and choices given, "The line has a positive slope and passes through the x-axis at -2" is the option that most closely matches our graph. Additionally, it crosses through point (2, 1).

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The probability of randomly selecting a date in March and spinning the spinner once, resulting in an odd number and then blue, is 1/6.

To find the probability of an odd number and then blue, we need to consider the number of favorable outcomes for each event and the total number of possible outcomes.

Probability of an odd number:

The spinner has 6 equally likely outcomes (numbers 1 to 6), and out of these, 3 are odd numbers (1, 3, and 5).

Therefore, the probability of getting an odd number is 3/6, which simplifies to 1/2.

Probability of blue:

The spinner has 6 equally likely outcomes, and out of these, 2 are blue. Therefore, the probability of getting blue is 2/6, which simplifies to 1/3.

To find the probability of both events occurring, we multiply the probabilities of each event:

Probability of an odd number and then blue [tex]= Probability $ of an odd number \times Probability $ of blue[/tex]

[tex]= (1/2) \times (1/3)[/tex]

= 1/6.

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Question: A date in March is chosen at random, then the spinner below is spun once. Find the probability of an odd number, and then blue. Use the counting principle to find the probability.

The lower limit is 72.1 and the upper limit is 78.5.

The sample mean is 75.3, and the standard error is 1.613.

The standard deviation is a measurement of how differently distributed a set of data values are from their mean or average. Finding the square root of the variance, which is the sum of the squared deviations between each data point and the mean, is how it is determined.

To find the confidence interval, we can use the formula:

Confidence interval = sample mean ± (critical value) x (standard error)

where the standard error is the standard deviation of the sample mean and the critical value is based on the desired confidence level and the sample size.

Since we want a 95% confidence interval and the sample size is 50, we can find the critical value from a t-distribution with 49 degrees of freedom (n-1). Using a t-distribution instead of a normal distribution is appropriate here because the population standard deviation is not known.

From a t-distribution table or calculator, the critical value for a 95% confidence interval with 49 degrees of freedom is approximately 2.009.

The standard error can be found using the formula:

standard error = standard deviation / sqrt(sample size)

Substituting the given values, we get:

standard error = 11.4 / sqrt(50) = 1.613

Now we can plug in the values into the formula for the confidence interval:

Confidence interval = 75.3 ± 2.009 x 1.613 = (72.14, 78.46)

Therefore, the lower limit is 72.1 and the upper limit is 78.5. The sample mean is 75.3, denoted by X-bar and the standard error is 1.613, denoted by Ś.

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The scenario that can be represented by the inequalities 1.25 < x < 1.5 is: A. A container of milk costs at least $1.25 but less than $1.50

The inequality 1.25 < x < 1.5 represents a range of values between 1.25 and 1.5, where x falls within that range.

Option A, which states that a container of milk costs at least $1.25 but less than $1.50, fits this range.

Option B, which states that a student spends at least 1 hour 15 minutes, but no more than 1 hour 30 minutes on homework, does not fit this range, as it represents a range of time values and not a range of numerical values.

Option C, which states that a tip added to a restaurant bill is less than or equal to 25% or less than or equal to 50%, does not fit this range either, as it represents two separate ranges of values.

Option D, which states that the point value of a test item is more than 1.25 points and less than 1.5 points, fits this range as well.

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Therefore , the solution of the given problem of unitary method  comes out to be  a 95% degree of certainty that the genuine average commute time falls within this range.

To complete the work, the well-known straightforward strategy, actual variables, and any essential components from the very first and specialised inquiries can all be utilised. In response, customers might be given another opportunity to sample the product. Otherwise, important advancements in our comprehension of algorithms will be lost.

Here,

We may use the following calculation to determine the 95% confidence interval for the actual average commute time:

=> CI = x' ± t*(s/√n)

Finding the essential t-value is the first step. We can apply a two-tailed t-test with a significance level of = 0.05/2 = 0.025 because we have 16 useable findings (sample size: n = 16) and

we require a 95% confidence interval. The crucial t-value, which we determine using a t-distribution table or calculator, is roughly 2.131.

=> CI = 21.4 ± 2.131*(1.8/√16)

=>  21.4 ± 0.95

The genuine average commute time has a 95% confidence interval of 20.45 to 22.35 minutes.

Based on our sample of 16 travel times, we can thus say with a 95% degree of certainty that the genuine average commute time falls within this range.

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Answer:

distance = rate x time

where distance is 300 kilometers and time is t hours. Rearranging this formula to solve for rate, we get:

rate = distance / time

Substituting the given values, we get:

r = 300 / t

Therefore, the equation that represents the train's rate in kilometers per hour based on how many hours the trip takes is r = 300/t.

Step-by-step explanation:

A negative correlation may be seen on the graph. The birth rate declines over time. This indicates that the number of births per 1000 persons in the US has been declining over time.

The temperature at 1pm is -3°C, at 2pm it's -6°C, at 3pm it's -9°C, and at 6pm it's -18°C. The temperature t hours after noon is T = 0 - 3t

If the temperature is dropping at a rate of 3 degrees per hour, then the temperature t hours after noon can be represented by the equation T = 0 - 3t, where T is the temperature in degrees Celsius.

To find the temperature at a specific time after noon, we need to substitute the corresponding value of t into the equation and solve for T. For example:

At 1pm (t = 1), T = 0 - 3(1) = -3°C

At 2pm (t = 2), T = 0 - 3(2) = -6°C

At 3pm (t = 3), T = 0 - 3(3) = -9°C

At 6pm (t = 6), T = 0 - 3(6) = -18°C

To find the temperature t hours after noon, we can use the same equation: T = 0 - 3t. For example, if we want to find the temperature 4 hours after noon, we can substitute t = 4 into the equation: T = 0 - 3(4) = -12°C. So the temperature 4 hours after noon is -12°C.

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The total amount withdrawn from the account after five years is $24,927.38.

The future value of a series of annual deposits of $2000) can be calculated using the following formula:

FV = [tex]PMT x (((1 + r)^n^-^ 1) / r)[/tex]

where FV = the future value, PMT= the payment amount =  $2000 r =  the interest rate per period = 4% n =  the number of periods = 5

the interest rate and the number of periods are the same.

[tex]FV1 = $2000 x (((1 + 0.04)^5^-^ 1) / 0.04) = $11,025.52[/tex]

This is the amount that the deposits will grow to one year after the last deposit, at an interest rate of 4% per year.

We use compound interest:

FV = [tex]PV x (1 + r)^n[/tex]

we apply this formula with a present value of $11,025.52, an interest rate of 6%, and 4 periods, we get:

FV2 = [tex]$11,025.52 * (1 + 0.06)^4 = $13,901.86[/tex]

Therefore the total amount withdrawn = FV1 + FV2 = $11,025.52 + $13,901.86 = $24,927.38

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I'm taking linear algebra right now so this one hits home :)

Elementary Row Operations (EROs) are very important and not too difficult, so let's dive into the problem!

You're given the matrix below and asked to perform a single ERO to produce a matrix with a 1 at the position (1,1):

[tex]\begin{bmatrix}3 & 10 & 5\\2 & -1 & 1\end{bmatrix}[/tex]

Think of the two rows as separate entities in the matrix. Ultimately we want to have the index (1,1) currently holding the number 3 to become the number 1. To do this, logically you just need to subtract 2. Now, looking at the rows we have, a simple row operation is quite apparent.

Simply subtract row 2 from row 1, shown below:

[tex]\begin{bmatrix}3-2 & 10-(-1) & 5-1\\2 & -1 & 1\end{bmatrix}[/tex]

Now, simplify and you will have the answer:

[tex]\begin{bmatrix}1 & 11 & 4\\2 & -1 & 1\end{bmatrix}[/tex]

Notice that our matrix now has the required number 1 in row 1 and column 1, therefore, the matrix above is our answer! Let me know if you have any questions!

You are on the right track! To find the equation of the parabola given by the equation x^2 + 6x + 8 = 0, you can use the standard form of a quadratic equation, which is:

where (h, k) is the vertex of the parabola and a is a coefficient that determines the shape of the parabola.

To get the equation of your parabola, you first need to complete the square on the x terms of the given equation:

From this equation, you can see that the vertex of the parabola is at (-3, -1) and the value of a is positive. This means that the parabola opens upwards.

To find the value of a, you can compare the equation with the standard form of the quadratic equation:

where h = -3, k = -1, and a is the coefficient you need to find. Substituting these values into the equation gives:

So the equation of the parabola is:

To plot the parabola, you can use the vertex (-3, -1) as a starting point and then use the coefficient a to determine the shape of the parabola. Since a is positive, the parabola opens upwards.

Therefore , the solution of the given problem of parallel lines comes out to be parallel lines stay parallel option C is correct.

A parallelogram in Euclidean geometry is essentially a straightforward hexagon with two different groups & equal distances. When both sets of sides evenly share a horizontal path, a particular type of quadrilateral known as a parallelogram is created. There are four distinct types of parallelograms, three of them being incompatible. The four distinct forms are slightly parallelograms, rectangular shapes, squares, and parallelograms.

Here,

C. It is untrue that a line may be translated into two parallel lines.

A line can be translated into another line that runs parallel to the first line, but not into two parallel lines.

Every point on the line is rigidly transformed by a translation, which moves all of the points along the line uniformly and in one direction.

After a translation, parallel lines stay parallel.

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If "function-g" defined for all real numbers as g(x) = x² + 6, then the value of g(-5) = 31, g(-2) = 10 and g(-1) = 7.

In mathematics, a function is generally denoted by a symbol such as "f" or "g", and its definition is given by an equation or formula that specifies the relationship between the input and output values.

The function "g" is given as : g(x) = x² + 6;, which is defined for all "real-numbers",

So, to find g(-5), g(-2), and g(-1), we simply substitute these values of x into the function "g" and simplify the resulting expressions:

⇒ g(-5) = (-5)² + 6 = 25 + 6 = 31,

⇒ g(-2) = (-2)² + 6 = 4 + 6 = 10,

⇒ g(-1) = (-1)² + 6 = 1 + 6 = 7.

Therefore, g(-5) = 31, g(-2) = 10, and g(-1) = 7.

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The given question is incomplete, the complete question is

Suppose that the function G is defined for all real numbers as g(x) = x² + 6. Find g(-5), g(-2) and g(-1).

Tasheena's grade percentage in the class so far is approximately 71.00935%.

The percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

To compute Tasheena's grade percentage in the class so far, we can calculate the weighted average of her scores based on the weightage of each component of the final grade.

Given:

Quizzes: 15% weightage

Exams: 55% weightage

Projects: 25% weightage

Attendance: 5% weightage

Tasheena's scores:

Quizzes: 117 out of 150 points

Exams: 74, 86, and 91 on the first three exams (each worth 100 points)

Projects: 29 out of 25 possible points

Attendance: Perfect attendance

Let's calculate Tasheena's grade percentage:

Quizzes:

Tasheena's quiz score percentage = (117 / 150) * 100 = 78%

Exams:

Tasheena's exam average = (74 + 86 + 91) / 3 = 83.67

Tasheena's exam score percentage = (83.67 / 100) * 55 = 46.017%

Projects:

Tasheena's project score percentage = (29 / 25) * 100 = 116%

Attendance:

Tasheena's attendance score percentage = 100% (since she had perfect attendance)

Now, let's calculate the weighted average of Tasheena's scores:

Weighted average = (Quizzes weightage * Quiz score percentage) + (Exams weightage * Exam score percentage) + (Projects weightage * Project score percentage) + (Attendance weightage * Attendance score percentage)

= (15% * 78%) + (55% * 46.017%) + (25% * 116%) + (5% * 100%)

= 11.7% + 25.30935% + 29% + 5%

= 71.00935%

Hence, Tasheena's grade percentage in the class so far is approximately 71.00935%.

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The percentage of percentage of the apples have diameters that are between 6.34cm and 8.5cm is given as follows:

99.7%.

The Empirical Rule states that, for a normally distributed random variable, the symmetric distribution of scores is presented as follows:

The measures of 6.34 cm and 8.50 cm are the bounds exactly within three standard deviations of the mean, hence the percentage is given as follows:

99.7%.

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Answer:

what arecrosses on line 2

We can conclude that there is significant evidence that the number of complaints received by Lara music store is different from number of complaints received by music stores in general.

Here, we have,

H0 : μ ≥ 6

H1 : μ < 6

Test statistic :

n = 20

Sample Mean, x = 3

σ = 1.5

Test statistic = (x - μ) ÷ σ/sqrt(n)

Test statistic = (3 - 6) ÷ 1.5/sqrt(20)

Test statistic = - 3 / 0.3354101

Test statistic = −8.944271

Since, sample size is < 30 ;

Obtaining the Critical value using the from T;

Tcritical at 0.05, df = 19 = - 1.729

Tstatistic < Tcritical

−8.944271 < - 1.729

Hence, we reject the Null:

We can conclude that there is significant evidence that the number of complaints received by Lara music store is different from number of complaints received by music stores in general.

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1. normally distributed if the sample size is 30 or larger.

2. Not always normally distributed.

3. Skewed to the right is still normally distributed

4. normally distributed.

1. normally distributed if the sample size is 30 or larger.

2. If the population from which samples are drawn is not normally distributed, then the sampling distribution of the sample mean is not always normally distributed. It depends on the sample size and the shape of the population distribution.

3. The sampling distribution of the sample mean for a sample of 10 elements taken from a population with a bell-shaped distribution that is skewed to the right is still normally distributed, by the central limit theorem, as long as the sample size is sufficiently large (typically at least 30) or the population distribution is approximately normal. Therefore, the answer is normally distributed.

4. The sampling distribution of the sample mean for a sample of 36 elements taken from a population with a bell-shaped distribution is normally distributed regardless of the population's skewness. Therefore, the answer is "normally distributed".

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The volume of each cup shown above are as follows;

Volume of small cup = 50.24 in³.

Volume of medium cup = 127.56 in³.

Volume of large cup = 226.08 in³.

In Mathematics and Geometry, the volume of a cylinder can be calculated by using this formula:

Volume of a cylinder, V = πr²h

Where:

By substituting the parameters, we have:

Volume of small cylinder, V = 3.14 × 2² × 4

Volume of small cylinder, V = 50.24 in³.

Volume of medium cylinder, V = 3.14 × 2.5² × 6.5

Volume of medium cylinder, V = 127.56 in³.

Volume of large cylinder, V = 3.14 × (6/2)² × 8

Volume of large cylinder, V = 226.08 in³.

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