i. Cube of any odd number is even. False
ii. A perfect cube does not end with two zeros. True
iii. If square of a number ends with 5, then its cube ends with 25. False
iv. There is no perfect cube which ends with 8. False
v. The cube of a two digit number may be a three digit number. False
vi. The cube of a two digit number may have seven or more digits. False
vii. The cube of a single digit number may be a single digit number. True
Reasons
i. Cube of any odd number is even. This statement is false because the cube of odd numbers are also odd
ii. A perfect cube does not end with two zeros. This statement is True because the cube of a two digit number cannot be a 3 digit number and therefore cannot end with two zeros.
iii. If square of a number ends with 5, then its cube ends with 25. This statement is False
Using the illustration
35^2 = 35 x 35= 1225 , its square ends with 5
35^3= 35 x 35 x 35= 42875 which ends with 75
iv. There is no perfect cube which ends with 8. This statement is False.
Using the illustration, the cube of 2 is given thus
2 * 2 * 2 = 8
The cube of 2 ends with 8
v. The cube of a two digit number may be a three digit number. This statement is False.
Using the illustration, 10 is a two digit number
10 * 10 * 10 = 1000
The cube of 10 which is a two digit number is not a three digit number and same applies to all two digit numbers
vi The cube of a two digit number may have seven or more digits. This statement is False because the cube of a two digit number can only be a four digit number.
vii. The cube of a single digit number may be a single digit number. This statement is True because the cube of a single digit number can be a single, two or three digit number.
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Given: Lines p and q are parallel and r is a transversal.
Prove: ∠2 ≅ ∠7
Parallel lines p and q are cut by transversal r. On line p where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 1, 2, 4, 3. On line q where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 5, 6, 8, 7.
A 2-column table with 4 rows. Column 1 is labeled statements with the entries p is parallel to q and r is a transversal, A, B, angle 2 is congruent to angle 7. Column 2 is labeled reasons with the entries given, vertical angles are congruent, correlated angle theorem, transitive property.
Which statements could complete the proof?
A:
B:
The statements that would complete the proof where ∠2 ≅ ∠7 by the transitive property are:
∠2 ≅ ∠3
∠3 ≅ ∠7
What is the Transitive Property?The transitive property states that if x = y, and y = z, then x = z.
From the image given below, we have:
∠2 ≅ ∠3 because they are vertical angles which must be congruent.
∠3 ≅ ∠7 because corresponding angles are congruent.
Applying the transitive property, we can state that: ∠2 ≅ ∠7.
Therefore, the statements that would complete the proof are:
∠2 ≅ ∠3∠3 ≅ ∠7Learn more about the transitive property on:
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Which function is positive for the entire interval [–3, –2]? On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3). On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5). On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5). On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2). Mark this and return
The function is shown to be positive throughout the whole range [-3, -2] in graph (B).
According to the question,
Four alternative graphs representing various functions are supplied to us; our task is to identify the function graph that is positive over the whole range [-3, -2]. A closed interval exists. Therefore, it includes both -3 and -2.The graph of the Y value must be in a positive area during this interval. Therefore, we must choose a function that is positive over the whole range [-3, -2].Looking at the graph, we can see that the graph B has positive y-values in the range [-3, -2].
Hence The function is shown to be positive throughout the whole range [-3, -2] in graph (B).
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For doing a certain a Job
Answer:
added in picture
Step-by-step explanation:
added in picture
Answer:
$71,744.53
Step-by-step explanation:
The earnings triple every day, so you can calculate them for the 15 days. For the total, you also have to add them up.
See the calculations in below picture.
Pls someone help me on this question
Answer: [tex]x=65^{\circ}, y=65^{\circ}, z=65^{\circ}[/tex]
Step-by-step explanation:
All radii of a circle are congruent, so by the base angles theorem
z = y = (180-50)/2 = 65.Also, angles x and y are inscribed in the same arc, and they are thus congruent, meaning x = 65.
The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width. What is the area of the new swimming pool, in square feet?
Answer:
[tex]3x^3 + 4x^2 -3x + 2[/tex]
Step-by-step explanation:
The area of the swimming pool will be equal to [tex]length * width[/tex].
We know that the length is [tex]3x^2-2x+1[/tex] and the width is [tex]x+2[/tex].
Therefore we can substitute those into the equation:
[tex](3x^2-2x+1)(x+2)\\[/tex]
Then, we expand the brackets using a grid (attached).
After this, we collect like terms to find the final answer:
[tex]3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2[/tex]
Our final answer is: [tex]3x^3 + 4x^2 -3x + 2[/tex]
Do this for me pls its mdths
Answer:
A = -1
B = -3
C = -7
Step-by-step explanation:
See attached image.
Which of the following is correct for determining the length of x to the nearest tenth of a metre?
cos 42 = x/6
tan 48 = x/5
sin 48 = x/5
tan 42 =x/6
how to apply Trigonometry in cricket?
Answer:
as we know that in cricket there is use of tan while doing bating
a researcher in north america discovers a fossil that contains 40% of its original amount of C-14
Using an exponential function, it is found that the substance is 7,535 years old.
What is the exponential function for the amount of a substance?
The function is given by:
[tex]A(t) = A(0)e^{-kt}[/tex]
In which:
A(0) is the initial amount.k is the rate of exponential decay.Carbon-14 has a half life of 5700 years, that is, A(5700) = 0.5A(0), hence we use this to find k.
[tex]A(t) = A(0)e^{-kt}[/tex]
[tex]0.5A(0) = A(0)e^{-5700k}[/tex]
[tex]e^{-5700k} = 0.5[/tex]
[tex]\ln{e^{-5700k}} = \ln{0.5}[/tex]
[tex]k = -\frac{\ln{0.5}}{5700}[/tex]
k = 0.00012160476
Hence:
[tex]A(t) = A(0)e^{-0.00012160476t}[/tex]
It was 40% of the amount when A(t) = 0.4A(0), hence we solve for t.
[tex]A(t) = A(0)e^{-0.00012160476t}[/tex]
[tex]0.4A(0) = A(0)e^{-0.00012160476t}[/tex]
[tex]\ln{e^{-0.00012160476t}} = \ln{0.4}[/tex]
[tex]t = -\frac{\ln{0.4}}{0.00012160476}[/tex]
t = 7535.
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The area of a rectangular piece of land is 2/3 square mile.
One dimension is 1 1⁄2 miles.
Answer:
4/9 miles
Step-by-step explanation:
[tex]\sf Area = \dfrac{2}{3} \ square \ miles\\[/tex]
[tex]\sf length = 1\dfrac{1}{2}=\dfrac{3}{2} \ miles[/tex]
[tex]\sf Width \ of \ rectangle = \dfrac{Area}{length}[/tex]
[tex]\sf = \dfrac{2}{3} \div \ \dfrac{3}{2}\\\\ =\dfrac{2}{3}*\dfrac{2}{3}\\\\ =\dfrac{4}{9} \ miles\\[/tex]
Use KCF method for faction division.
K- Keep the first fraction.
C - Change the division to multiplication.
F - Flip the second fraction.
Please Help Me! What is cos B?
Answer:
cos B = 0.4706
Step-by-step explanation:
The cosine of an angle in a right-angled triangle is the ratio of its adjacent side and the hypotenuse, so:
[tex]cos B = \frac{adjacent}{hypotenuse}\\\\cos B = \frac{8}{17} \\\\cos B = 0.4706[/tex]
Option B
Write 5.54 million in ordinary form
Answer:
5,540,000Step-by-step explanation:
Write 5.54 million in ordinary form
5.54 * [tex]10^{6}[/tex] =
5540000
or
5.54 * 1000000 =
5540000
A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Tariq designed the pool shown. The owner of the pool has one square cover to use. Find the area of the space that needs to be covered. (The four corners are squares.)
The area that needs to be covered is
ft2.
A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Find the Area of the Space.[tex] \mathbb{SOLUTION:} [/tex][tex] \bold{A = Length \: x \: Width} [/tex][tex] \bold{A = 12 \: ft \: x \: 4.2 \: ft } [/tex][tex] \blue{\bold{A = 50.4 \: ft} }[/tex][tex] \bold{ A\red{ = 50.4 } \: x \: 2 \: ft} [/tex][tex] \boxed{ \bold{ A = 100.80 ft²}}[/tex]"If the 2 is quantity use multiply it again"
••••••••••••••••••••••••••••••••••••••••••••••••NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).
"Problem has been solve"
(ノ^_^)ノ
[tex]\large\bold{SOLUTION} \\ [/tex]
GIVEN :-
A square with side lengths 12 feet.4.2 feet by 2 feet squares are cut out of each corner of the square .FIND :-
Find the area of the space that needs to be covered .By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .
[tex] \bold{Formula:}[/tex]
[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]
Now let's start solving :-
[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]
[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]
[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]
[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]
Therefore, the area of the space that needs to be covered is 100.80ft² .
[tex] \underline{ \rule{185pt}{3pt}}[/tex]
Hey can I have help on this question with an explanation please :)
Step-by-step explanation:
i hope this is helpful!........
1/(x+2)+1/(x+3)=2/x+9
Answer:
4x82x929wjdjdejdjekke
[tex] \frac{1}{x + 2} + \frac{1}{x + 3} = \frac{2}{x + 9 } \\ \frac{(x + 3 ) + (x + 2)}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ \frac{2x + 5}{ {x}^{2} + 5x + 6 } = \frac{2}{x + 9} \\ 2( {x}^{2} + 5x + 6) = (x + 9)(2x + 5) \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 5x + 18x + 45 \\ 2 {x}^{2} + 10x + 12 = 2 {x}^{2} + 23x + 45 \\ 2 {x}^{2} - 2 {x}^{2} + 10x - 23x + 12 - 45 = 0 \\ - 13x - 33 = 0 \\ - 13x = 33 \\ x = \frac{33}{ - 13} \\ x = - 2.54[/tex]
Hope it helps
Please give brainliest
Line mn is parallel to line pq, mp is perpendicular to mn, and nqis perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer. options:
The true statements are:
Lines mn and pq have the same slopeThe product of the slopes of mn and mp is -1How to determine the true statements?The lines are given as:
Lines mn, pq, mp, mn, nq and pq
From the question, the lines are either parallel lines or perpendicular lines
As a general rule,
Parallel lines have equal slope
This means that:
Lines mn and pq have the same slope
Assume two perpendicular lines have slopes m and n.
The relationship between their slopes is:
m * n = -1
This means that:
The product of the slopes of perpendicular lines mn and mp is -1
Hence, the true statements are (a) and (c)
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Complete question
Line mn is parallel to line pq, mp is perpendicular to mn, and nq is perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer.
Pptions:
Lines mn and pq have the same slopeThe slope of line pq is undefined. The product of the slopes of mn and mp is -1Lines mp and mq are parallel.Find y in terms with x
Help me pleaseee thank uu:)
Answer:
y = 90 -5/2 x
Step-by-step explanation:
The angle on the left equals x+3x+x = 5x
The angle on the right equals 2y
The two angles are same side interior angles which are supplementary because the lines are parallel
5x+2y = 180
Solving for y
2y = 180-5x
Divide by 2
2y/2 = 180/2 -5x/2
y = 90 -5/2 x
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\tt y = 90 \degree - \cfrac{5x}{2} [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
The two lines are parallel, henceforth we can apply Angle pair rules.
[tex]\qquad \tt \rightarrow \:(x + 3x + x) + 2y = 180[/tex]
[ Co - interior angles ]
[tex]\qquad \tt \rightarrow \:5x + 2y = 180[/tex]
[tex]\qquad \tt \rightarrow \:2y = 180 - 5x[/tex]
[tex]\qquad \tt \rightarrow \:y = \dfrac{180 - 5x}{2} [/tex]
[tex]\qquad \tt \rightarrow \:y = \cfrac{180 }{2} - \cfrac{5x}{2} [/tex]
[tex]\qquad \tt \rightarrow \:y = 90 \degree - \cfrac{5x}{2} [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
A pair of dice is rolled. What is the probability that the sum is 9 or that the first number is a 2?
Answer:
9/2 or 6/2
Step-by-step explanation:
The sum of nine should be amended by adding 6 + 2 +1 = 9
so when adding these numbers you will get the sum of 9
Given: a and b are parallel and c is a transversal.
Prove: ∠2 ≅ ∠7
Parallel lines b and a are cut by transversal c. On line b where it intersects with line c, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 1, 5, 6, 2. On line a where it intersects with line c, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 3, 7, 8, 4.
Use the drop-down menus to complete the paragraph proof showing that alternate interior angles are congruent.
We know that lines a and b are parallel and that line c is a transversal because that is given. We can tell that angles 2 and 5 are congruent because
angles are congruent. Angles 5 and 7 are congruent because angles by parallel lines cut by a transversal are congruent. Therefore, angles 2 and 7 are congruent based on the
.
The missing words to complete the proof are respectively; Vertical Angles; Corresponding angles; Transitive Property
How to prove congruent angles?The image of the transversal line is attached.
1) We know that lines a and b are parallel and that line c is a transversal because that is given.
2) We can tell that angles 2 and 5 are congruent because vertical angles are congruent.
3) Angles 5 and 7 are congruent because corresponding angles by parallel lines cut by a transversal are congruent.
4) Therefore, angles 2 and 7 are congruent based on the transitive property.
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Answer: vertical, corresponding, and transitive property
Step-by-step explanation: I got the correct answer on Edge 2022. The answer is correct trust me! Proof is shown down below.
Graph the linear equation. Find three points that solve the equation, then plot on the graph.
-3x + 2y = 2
Step-by-step explanation:
I have done it go and check it once
The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.
What is the greatest possible whole-number value of the congruent side lengths?
The unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.
What is the triangle?The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.
The question is incomplete.
The complete question is:
The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown. What is the greatest possible whole-number value of the congruent side lengths?
9 cm
10 cm
14 cm
15 cm
We have:
The longest side of an isosceles obtuse triangle measures 20 centimeters.
Let's assume the unknown side length is x:
In the isosceles obtuse triangle, two sides are congruent.
As we know the sum of the two sides in a triangle is greater than the third side length:
x + x > 20
2x > 20
x > 10
a² + b² < c²
14 will satisfy the above two inequaility.
Thus, the unknown side length will be 14 cm if the longest side of an isosceles obtuse triangle measures 20 centimeters option third 14 is correct.
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Quayleen wants to decorate her Christmas tree. She wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. She must know the exact quantity of paper to buy for this purpose. If the box has length, breadth and height as 80 cm, 40 cm and 20 cm respectively. How many square sheets of paper of side 40 cm would she require?
[tex]\bullet\:{\boxed{\tt{\red{{Given :}}}}}[/tex]
• Length of the wooden box [tex](l)[/tex] = 80cm.
• Breadth of the wooden box [tex](b)[/tex] = 40cm.
• Height of the wooden box [tex](h)[/tex] = 20cm.
• Side of the square sheet paper = 40cm.
[tex]\bullet\:{\boxed{\tt{\red{{To : Find :}}}}}[/tex]
The number of sheets required.
[tex] \bullet\:{\boxed{\tt{\red{{Formula \: \: used :}}}}}[/tex]
[tex] \star{\underline{\boxed{{\sf{{{TSA}} = \underline{\underline{{\purple\sf 2(lb+bh+hl)}}}}}}}} \star[/tex]
[tex]\star{\underline{\boxed{{\sf{{{Area \: of \: square}} = \underline{\underline{{\purple{\sf side \times side }}}}}}}}}\star[/tex]
[tex]\star{\underline{\boxed{{\sf{{{Number \: of \: sheets \: required} = {{{\purple{\sf \dfrac{TSA}{area \: of \: one \: sheet}}}}}}}}}}} \star[/tex]
[tex] \bullet\:{\boxed{\tt{\red{{Concept :}}}}}[/tex]
As Quayleen wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. So for knowing the number of sheets required, we need two things one the TSA and Area of one sheet. Once, we will get the values we will divide them to get the answer. Let's Start !!
[tex] \bullet\:{\boxed{\tt{\red{{Solution :}}}}}[/tex]
As we know that ::
Total surface area of cuboid [tex]\large[ \sf 2(lb+bh + hl)][/tex]
Here,
✧ Length [tex](l)[/tex] = 80cm
✧ Breadth [tex](b)[/tex] = 40cm
✧ Height [tex](h)[/tex] = 20cm
Now, by putting the values we get :
[tex] \longrightarrow 2 \bigg[ (80 \times 40) + (40 \times 20) + (20 \times 80) \bigg]\sf {cm}^{2}[/tex]
[tex]\longrightarrow 2 \bigg[ (3200) + (800) + (1600) \bigg] \sf {cm}^{2} [/tex]
[tex] \longrightarrow 2 \bigg[ 5600 \bigg] \sf {cm}^{2} [/tex]
[tex] \longrightarrow 11200 \: \sf {cm}^{2}[/tex]
Hence, the total surface area of the wooden box is 11200 cm²
Now,
The area of each sheet of paper will be :
[tex] \sf \longrightarrow side \times side[/tex]
[tex]\sf \longrightarrow (40 \times 40) \: {cm}^{2} [/tex]
[tex]\longrightarrow \sf (1600) \: {cm}^{2} [/tex]
Hence, the area of each sheet of paper is 1600 cm²
Now,
For finding the number of sheets required
[tex] \longrightarrow \tt \dfrac{total \: surface \: area \: of \: box}{ area \: of \: one \: sheet} [/tex]
[tex]\longrightarrow \sf\dfrac{ \cancel{11200}_{7}}{\cancel{1600}_{1}}[/tex]
[tex] \longrightarrow \purple{ \sf 7}[/tex]
Therefore, Quayleen requires 7 sheets.
[tex]\rule{280pt}{2pt}[/tex]
Investor Lucas just bought a large amount of stock in Company Y. What may have motivated his behavior? (5 points)
Lower shares prices
O Low real returns
O Higher shares costs
O High total ear
What must have motivated the behavior of the Investor to commit to such a large stock is; Option C: High Total Earnings
How to know the value of investing in stocks?A) Low real returns; This cannot be his motivation to buy large shares because real return is what is earned on an investment after accounting for taxes and inflation. Thus, the lower, the less encouraging to investors.
B) Higher shares costs; This only means that the share cost is currently high which indicates strength of the company but it does not guarantee that it will scale up at a very fast rate again.
C) High total earnings; Thus would be an encouragement to the investor because the higher the total earning potential of an investment, the more the profitability and the more attractive to others.
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ABC has the points A(1,7) B(-2,2) and C(4,2) as it’s vertices
The measure of the longest side of ABC is _ units. ABC is_triangle. If ABD is formed with the point D(1,2) as it’s third vertex, then ABD is _triangle . The length of side AD is_units
Part 1
Using the distance formula,
[tex]AB=\sqrt{(-2-1)^{2}+(2-7)^{2}}=\sqrt{34}\\\\BC=\sqrt{(-2-4)^{2}+(2-2)^{2}}=6\\\\AC=\sqrt{(1-4)^{2}+(7-2)^{2}}=\sqrt{34}[/tex]
So, the measure of the longest side is 6 units.
Part 2
Triangle ABD will have vertices A(1,7), B(-2, 2), and D(1,2).
We already know that [tex]AB=\sqrt{34}[/tex]
Using the distance formula,
[tex]AD=\sqrt{(1-1)^{2}+(7-2)^{2}}=5\\\\BD=\sqrt{(-2-1)^{2}+(2-2)^{2}}=3[/tex]
So, ABD is a scalene triangle.
Part 3
From part 2, we know that the length of side AD is 5 units.
When the expression 3(x²+6-3x) - (2x²-8) + 3(x² + 4x) is simplified, the coefficient
of x is
A. 7
B. 4
C. 3
D. 2
The correct answer is option C which is 3.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.
The given expression will be solved as follows:-
E = 3( x² +6 -3x)- ( 2x² - 8 ) +3(x² + 4x )
E = 3x²+18-9x-2x²+8+3x²+12x
E= 4x² +3x+8
We can see the coefficient of x is 3.
Therefore the correct answer is option C which is 3.
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The graphs below are both absolute value functions. The equation of the red
graph is f(x) = xl. Which of these is the equation of the blue graph, g(x)?
a. g(x)=|x-2|
b.g(x)=|x+2|
c. g(x)=1/2|x|
d. g(x)=2|x|
Answer:
c
Step-by-step explanation:
can someone please help me
Answer:
Domain: All real numbers
Range: y≤4
What is the distance between the tick marks on the number line?
A number line going from 0 to 2 in increments of 1. There are 5 equals spaces between each number.
One-fifth
One-fourth
4
5
Mark this and return
Answer:
1/5
Step-by-step explanation:
2 units divided into 5 marks each = 10 marks
2/10 = 1/5 unit each mark
can you write 3/5 as a recurring decimal?
can i also have an explanation please :)
Answer:
0.6
Step-by-step explanation:
You can literally put 3/5 into a calculator and you would get the answer 0.6, so I don't know what else to say. Whoever asked you this question, give them the above answer ask them what they were on, because the person was probably way high on LSD.
Match the function with the graph.
a. y = |x+ 5|
b. y= |x-5| + 2
c. y= |x-5|
d. y=|x| -5
i did a and it was wrong. i don’t understand lol please help
C. y= |x-5|
you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.
