Someone please help with this !!!!!

Answer:

x(x - 2)

Step-by-step explanation:

x² - 2x ← factor out x from each term

= x(x - 2)

Answer:

8x

Step-by-step explanation:

Greatest common factor is the factor of 24, 56 and 16. Since 16x only has the power of 1, then then the answer should be on power of 1.

Answer:

Given the 24x⁵ - 56x³ + 16x contains numbers and variables, there are two steps to finding the GCF. Find the GCF for the numeric part, then find the GCF for the variable part.

Steps to find the LCD of 24x⁵ - 56x³ + 16x

Find the common factors of the numerical part: 24, −56, 16

The factors for 24 are −24,−12,−8,−6,−4,−3,−2,−1,1,2,3,4,6,8,12,24.

The factors for −56  are−56,−28,−14,−8,−7,−4,−2,−1,1,1,2,2,4,4,7,7,8,8,14,14,28,28,56,56.

The factors for 16  are −16,−8,−4,−2,−1,1,2,4,8,16.

List all the factors 24,−56,16 to find the common factors.

The common factors for 24,−56,16 are −8,−4,−2,−1.−8,−4,−2,−1

The GCF of the numerical part is 8.

[tex]\bf{GCF_{Numerical}=8 }[/tex]

Then find the common factors for the variable part:

x⁵, x³, x

The factors for x⁵ are:

x · x · x · x · x

The factors for x³ are:

x · x · x

The factors for x¹ are:

x

List all the factors x⁵, x³, x¹ to find the common factors.

x⁵ = x · x · x · x · x

x³ = x · x · x

x¹ = x

The common factor of the variables x⁵, x³, x¹ is x.

The LCD of the variable part is x.

[tex]\bf{GCF_{Numerical}=x }[/tex]

Multiply the LCD of the numerical part 8 and the GCF of the variable part x.

8x

There is no absolute value function when graphed, will be wider than the graph of the parent function f(x) = |x|

An absolute value function is a function such that,

[tex]|x|=-1 when x\geq 0 and |x|=1 when x\leq 0[/tex]

For the given example,

We have been given a parent function f(x) = |x|

We need to find the absolute value function, when graphed, will be wider than the graph of the parent function.

Consider the graph of all absolute value functions.

The graph of f(x) = |x| + 3 is represented blue color.

The graph of f(x) = |x − 6| is represented green color.

The graph of f(x) = |x| is represented red color.

The graph of f(x) = 9|x| is represented violet color.

From this graph, we can observe that,

f(x) = |x| + 3 is as wise as the parent absolute value function f(x) = |x| translated up by 3 units.

Similarly, the function f(x) = |x - 6| is as wise as the parent absolute value function f(x) = |x| translated right by 6 units.

This means, there is no absolute value function when graphed, which will be wider than the graph of the parent function f(x) = |x|

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Answer:

I believe the answer is C. F(x)= 1/3|x|

Step-by-step explanation:

i hope this helps.

Answer:

10x + 332

when, x=0

Step-by-step explanation:

Please give me brainlist.

Answer:

The choice D.

[tex]f(x) = 3 {(0.2)}^{x} [/tex]

Answer:

D

Step-by-step explanation:

Order of elimination:

1. the graph is going down exponentially. This means that the base is less than 1.

A and C are eliminated.

2. When x is equal to 0, f(x) = 3.

Substitute x for 0, and you'll find out that the only one possible is D.

1. The range of the given function y = 3x² for the given domain: {- 2, - 1, and 0} is {12, 3, 0}.

2. The range of the given function y = 8x + 1, where x > 2 is (17, ∞).

3. The range of the given function y = 5x + 2, where x > -2 is (- 8, ∞).

We know that the range of a function is the entire set of all possible values for the dependent variable (typically y), after substituting the domain.

1. For the function y = 3x²,

Here the domain is {- 2, - 1, and 0}. So, we have to find the y values for the x values - 2, - 1, and 0 to find the range of the function.

Now, at x = - 2,

y = 3(- 2)² = 3 × 4 = 12

At x = - 1,

y = 3(- 1)² = 3 × 1 = 3

At x = 0,

y = 3(0)² = 3 × 0 = 0

So, the range of this function is {12, 3, 0}.

2. Now, for the function y = 8x + 1,

At x = 2,

y = 8 × 2 + 1 = 16 + 1 = 17

Since the domain is x > 2, we can say that the range set will contain values greater than 17.

So, the range of this function is (17, ∞).

3. For the function y = 5x + 2,

Now, at x = - 2,

y = 5 × (- 2) + 2 = - 10 + 2 = - 8

Since the domain is x > - 2, we can say that the range set will contain values greater than - 8.

So, the range of this function is (-8, ∞).

1. Therefore, the range of the given function y = 3x² for the given domain: {- 2, - 1, and 0} is {12, 3, 0}.

2. The range of the given function y = 8x + 1, where x > 2 is (17, ∞).

3. The range of the given function y = 5x + 2, where x > -2 is (- 8, ∞).

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Answer:

question 3: n is bigger than or equal to 0

question 5: n is bigger than or equal to 0 (the same as question 3)

Step-by-step explanation:

solve the same way as a equation. just remember the symbols

The equation of the line in slope-intercept form is [tex]\bf{y= \frac{3}{2} x + \frac{9}{4}} [/tex].

The first step is to calculate the slope of the line.

[tex]\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }[/tex]

Slope

[tex] = \frac{ - 3 - 0}{ - 5 -( - 3)} [/tex]

[tex] = \frac{ - 3}{ - 5 + 3} [/tex]

[tex] = \frac{ - 3}{ - 2} [/tex]

[tex] = \frac{3}{2} [/tex]

Substitute the value of m into y= mx +c:

[tex]y = \frac{3}{2} x + c[/tex]

Next, substitute a pair of coordinates that the line passes through. Here, I will substitute (-3, 0) into the equation.

When x= -3, y= 0,

[tex]0 = \frac{3}{2} ( - 3) + c[/tex]

Find the value of c:

[tex]0 = - \frac{9}{2} + c[/tex]

[tex]c = \frac{9}{2} [/tex]

Substitute the value of c into the equation:

Thus, the equation of the line is [tex]y = \frac{3}{2} x + \frac{9}{2} [/tex].

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Two pairs of corresponding angles are congruent, so the triangles are similar.

The correct option is (A).

Two triangles are similar if they have the same ratio of corresponding sides and equal pair of corresponding angles.

As, the measurement of two angles are equal.

So, the angles are congruent.

Hence, by AA criteria the triangles are similar.

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Answer:

A

Step-by-step explanation:

Answer:

x + 6

Step-by-step explanation:

consider the x- coordinates of the right angle

x- coordinate of A = - 4

x- coordinate of B = 2

then

| 2 - (- 4) | = | 2 + 4 | = | 6 | = 6

the x- coordinate has been shifted 6 units to the right , so the rule is

x + 6

Answer:

D.  4

Step-by-step explanation:

Given expression:

[tex]-2x^2-4x+10[/tex]

To find the value of the expression when x = -3, substitute x = -3 into the expression:

[tex]\implies -2(-3)^2-(-3)x+10[/tex]

Apply exponent rule  [tex](-a)^2=a^2[/tex]:

[tex]\implies -2(3^2)-4(-3)+10[/tex]

[tex]\implies -2(9)-4(-3)+10[/tex]

[tex]\implies -18-4(-3)+10[/tex]

Apply rule [tex]-(-a)=a[/tex] :

[tex]\implies -18+(4)(3)+10[/tex]

[tex]\implies -18+12+10[/tex]

Add/subtract from left to right:

[tex]\implies -6+10[/tex]

[tex]\implies 4[/tex]

Let's find

Answer: (x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x =  1

x + 1 = 0, so x =  -1

x + 5 = 0, so x = -5

The values for y are i, 0, √3 and 2√2

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable.

Given:

F(x)= y = √(x-5) -1

At x=5,

y=  √(5-5) -1

y= i

At x= 6

y= √(6-5) -1

y=0

At x= 9

y= √(9-5) -1

y=√3

At x= 14

y= √(14-5) -1

y=√8= 2√2

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The value of a is 1 if the area of square ABCD is 10 cm² showing that x²+6x=a where a is a constant.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

The question is incomplete.

The question is:

The area of square ABCD is 10 cm² showing that x²+6x=a where a is a constant to be found.

The missing figure is attached; please refer to the picture.

As we can see in the figure we have given a rectangle.

Area of rectangle = (3 + x)(3 + x)

10 = (3 + x)(3 + x)

or

10 = (3 + x)²

10 = 9 + 6x + x²

After rearranging:

x² + 6x = 1

We have equation:

x² + 6x = a

After comparing:

a = 1

Thus, the value of a is 1 if the area of square ABCD is 10 cm² showing that x²+6x=a where a is a constant.

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Answer:

x = 8

Step-by-step explanation:

[tex]\sf If\:\: \overline{NO} \parallel \overline{KJ}\:\:then\:\: \triangle LNO \sim\triangle LKJ[/tex]

Therefore:

[tex]\implies \sf \overline{LN} : \overline{LO} = \overline{LK} : \overline{LJ}[/tex]

[tex]\implies (x-3):(x-4)=(x-3)+(x+2):(x-4)+x[/tex]

[tex]\implies \dfrac{x-3}{x-4}=\dfrac{2x-1}{2x-4}[/tex]

[tex]\implies (x-3)(2x-4)=(2x-1)(x-4)[/tex]

[tex]\implies 2x^2-10x+12=2x^2-9x+4[/tex]

[tex]\implies -10x+12=-9x+4[/tex]

[tex]\implies 12=x+4[/tex]

[tex]\implies x=8[/tex]

Answer:

4064265.104

Step-by-step explanation:

Use PEMDAS :

Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

We only have multiplication and addition/subtraction to do. Multiplication and Division can go in either order depending on which comes first reading left to right. It's the same with Addition and Subtraction: we will first subtract 918 and then add 12.5.

Let's start by Multiplying. 391.92 x 10372.45 = 4065170.604.

Now, subract 918. 4065170.604-918 = 4064252.604.

Finally, add back 12.5. 4064252.604. +12.5 = 4064265.104 !

Answer:

170

Step-by-step explanation:

each little mark is adding 20 to the 100 you see there and because the arrow is pointing somewhere in between two of the marks, it means it's just adding 10. Now you have to add 100 + the marks + 10

* remember you have three marks and each one of them is equal to 20 so when you add them, you get 60.

100 + 60 + 10 = 170

The simple interest is $24.75.

The simple interest that is paid on an amount of money is a function of the amount deposited, time and interest rate.

Simple interest = amount deposited x time x interest rate

$375 x 0.022 x 3 = $24.75

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Answer:

Which of the following completes Ted's proof?

In square ABCD; angle ADC = angle BCD

In square ABCD; angle ADP = angle BCP

In triangles APD and BPC; angle ADC = angle BCD

In triangles APD and BPC; angle ADP = angle BCP\

Answer:

Option 1

Step-by-step explanation:

Angle bisector:

  Angle bisector is a line that divides the angle into two equal angles.

⇒ ∠KLM = ∠MLN

Answer:

15

Step-by-step explanation:

"one number is three more than twice the second number"

15 * 2 = 30

30 + 3 = 33

15 + 33 = 48

Answer:

15

Step-by-step explanation:

The key to most problems of this type is carefully translating the word problem into math ... an equation.

"The sum of two numbers is 48."

"Sum": Add

"two numbers": we'll need two numbers... let's call them x & y

"is": =

"48": 48

So, the first sentence means:  [tex]x+y=48[/tex]

Note that we have two unknowns here.  To solve for them, we'll need another equation... at least as many equations as unknowns (2 unknowns, needs 2 equations).

"If one number is three more than twice the second number..."

"one number": x

"is": =

"three more than": +3

"twice": 2*

"the second number": y

So, the second sentence introductory clause means: [tex]x=2y+3[/tex]

We have a system of equations. We need as many equations as we have unknowns.  We currently have two equations, and two unknowns.  Let's try to solve the system:

[tex]x+y=48[/tex]

[tex]x=2y+3[/tex]

There are two main methods to solve systems of equations:  Substitution & Elimination

To use the Substitution Method, we'll need to isolate one of the variables in one of the equations, substitute, and solve.

To use the Elimination Method, we'll need to align like terms, find or build matching coefficients with opposite signs, add to eliminate, and solve.

Given that equation 2 already has x isolated, this system is already ready to use the Substitution method, so let's do that.

[tex]x+y=48\\x=2y+3[/tex]

[tex](2y+3) + y = 48[/tex]

[tex]2y+3 + y = 48[/tex]

[tex]3y+3 = 48[/tex]

[tex]3y= 45[/tex]

[tex]y= 15[/tex]

To find x, substitute back into one of the equations:  Equation 2 already has x isolated, so it will be easy to solve for x.

[tex]x=2(15)+3[/tex]

[tex]x=30+3[/tex]

[tex]x=33[/tex]

So the solution we found is x=33 and y=15.

The sum of the numbers is 48:

[tex]x+y=(33)+(15)\\x+y=48[/tex]

One number is three more than twice the second number

[tex]x=2y+3[/tex]

[tex](33)\text{ ?=? }2(15)+3[/tex]

[tex]33=33[/tex]

Our answer satisfies all of the original conditions, so our answer works.

The question finally asks, "...which of the following is the smaller number?"

Of the two numbers, the smaller number is 15.

Answer:

8.31752 to correct 3 decimal places =

Step-by-step explanation:

8.318

brainiest pls it helps

Answer:

D

Step-by-step explanation:

The domain are the x values. When you plug those values into the equation, you get 34, 6, 22.

3(-3²) - 2(-3) + 1                     Negative * Negative = Positive

3(9) + 6 + 1

34

3(-1²) - 2(-1) + 1

3 + 2 +1

6

3(3²) -2(3) + 1

3(9) - 6 + 1

22

The measure of the angle x is 117 degrees

To determine the value of x in the given diagram, we will use the alternate angles theorem

The value of x is expressed as shown;

p + q= x

If the value of p = 51, then;

51 + q. = x

Determine the value of. q

q = 108 - 42

q = 66

Determine the value of x

x = 66 + 51

x = 117 degrees

Hence the measure of the angle x is 117 degrees

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Answer

Step by step explanation

Hope this helps you

........

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The value of f(x) when the value of x is 9 is 38.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The given data points are in a linear relation, therefore, if we find the slope of the line on which these data points will be located. Then the slope will be,

m = (17-5)/(2+2) = 3

Now, equate any point and the slope in the general equation of line, therefore, the equation will be,

y = 3x + c

17 = 3(2) + c

17 - 6 = c

c = 11

Further, the value of f(x) when the value of x is 9 will be,

f(x) = 3x + 11

f(9) = 3(9) + 11

f(9) = 38

Hence, the value of f(x) when the value of x is 9 is 38.

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Answer:

D) -12

Step-by-step explanation:

[tex]3(x-4)+(2-x)-x^2[/tex]

Replace X With 5

[tex]3(5-4)+(2)(5)-5^2[/tex]

[tex]=-12[/tex]

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