Someone please help me with this question

Answer:

Step-by-step explanation:

y - 4 = -5(x + 1)

y - 4 = -5x - 5

y = -5x - 1

Answer:

x/2-10=18

Step-by-step explanation:

An equation is formed of two equal expressions. The given statement The quotient of a number and -2, less 10, is -18 can be written as an equation as (x/-2)-10=-18.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the number be represented by x. Therefore, the given statement can be written as,

(x/-2)-10=-18

Hence, the given statement The quotient of a number and -2, less 10, is -18 can be written as an equation as (x/-2)-10=-18.

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Answer:

u = 66°

v = 38°

Step-by-step explanation:

If this is a parallelogram:

u = 66°, angle opposite 3v = 3v

All four interior angles total 360°

Then:

3v + 3v + 66° + 66° = 360°

combine like terms:

6v = 228°

v = 38°

Answer:

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

Answer:

Area of the enclosed figure = 3148.74 [tex]m^{2}[/tex]

Step-by-step explanation:

Area enclosed by the figure = 2 x area of the semicircle + area of the square

For the semicircle,

radius = [tex]\frac{diameter}{2}[/tex]

          = [tex]\frac{42}{2}[/tex]

          = 21 m

area of a semicircle = [tex]\frac{1}{2}[/tex] x [tex]\pi r^{2}[/tex]

                                = [tex]\frac{1}{2}[/tex] x 3.14 x [tex](21)^{2}[/tex]

                                = 692.37 [tex]m^{2}[/tex]

area of a square = length x length

                            = 42 x 42

                            = 1764 [tex]m^{2}[/tex]

Thus,

area enclosed by the figure = 2 x 692.37 + 1764

                                              = 3148.74 [tex]m^{2}[/tex]

The total area enclosed bu the figure is 3148.74 [tex]m^{2}[/tex]

Answer:

The right answer is x = 8, y = 40.

Step-by-step explanation:

Since this triangle is isosceles we know that...

∠ACB = ∠ABC

40° = (5x)°

40 = 5x

x = 40 / 5

x = 8

We also know that the sum of all angles inside the triangle is equal to 180°, therefore...

∠BAC = 180° - ∠ACB - ∠ABC

(2y + 20)° = 180° - 40° - 40°

2y + 20 = 100

2y = 100 - 20

2y = 80

y = 80 / 2

y = 40

From this, we know that the right answer is x = 8, y = 40.

Answer:

{0, 1, 16, 81}

Step-by-step explanation:

If the domain of this function is the set {0, 1, 4, 9}, we find the set representing the range by evaluating the function at each of the four values in the domain.

f(0) = 0

f(1) = 1

f(4) = 16

f(9) = 81

and so the range is the set {0, 1, 16, 81}.

Answer:

option d. 6/10

.....................

Answer:

it would have to be 3/5 i think but i actually think option 1 or 4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Division by zero is undefined, so the only restriction on the domain, the values of x is that x cannot equal 9. So the domain is all real numbers except 9. Or in interval notation

x=(-oo,9),(9,+oo)

Answer:

All real numbers

Step-by-step explanation:

y = (x+1)(x-9)

y = x² - 8x - 9

There are no asymptotes, restrictions of x, or holes.

Answer:

A or B! Im not sure which one but B

Step-by-step explanation:

Answer:

$840 for a dozen

Step-by-step explanation:

Find out the cost for one book. Then multiply that number by 12 (dozen).

Answer:

840

Step-by-step explanation:

490 ÷ 7 = 70

70 x 12 = 840

Answer:

5 m²

Step-by-step explanation:

please mark me as brainliest

Answer:sum =378 according to your new questions.

to find average temperature

use formula

average =sum of temperature /no of measuring day

=378/9=42 is your answer

Answer:

270 calories

Step-by-step explanation:

Answer:

Triangle A and Triangle B

Answer:

EASY. x=-3

Step-by-step explanation:

You need to divide 21 by -7. You'll get the same answer as me

Hope this helped!!

Answer:

[tex] \sf \: x = - 3[/tex]

Step-by-step explanation:

Given equation,

[tex] \sf \rightarrow \: \frac{21}{x} = - 7[/tex]

Now the value of x will be,

[tex] \sf \rightarrow \: \frac{21}{x} = - 7 [/tex]

[tex] \sf \rightarrow \: - 7x = 21[/tex]

[tex] \sf \rightarrow \: x = \frac{ \: 21 \: }{ - 7 \: } [/tex]

[tex] \sf \rightarrow \boxed{ \sf x = - 3}[/tex]

Hence, the value of x is -3.

Answer:

The ideal equation form to write this in would be "y=mx+b" because it involves a starting amount (which is represented by "b") and a certain constant amount of something ("m") being fed into that starting amount over time ("x" which will be substituted for "w" because the math problem wants us to substitute). Plugging in the number's you get:

y=30w+200

Step-by-step explanation:

y---> total amount saved after plugging in all numbers including time

m--> amount of money/stuff being added to the starting point over time

x---> can represent time, or basically any independent variable that decides how long has the stuff been being fed into the overall number

b---> the starting point (in this case it is 200, in other cases it can be anything, even a negative number)

Have a wonderful day!

Stay safe, stay loved, stay blessed. :)

Answer:

D

Step-by-step explanation:

Plug in every scenario, in see if it equal to each other.

D is the only one that is equal.

Answer:

x = 55

y = 45

Step-by-step explanation:

In similar triangles, the ratio between similar sides are the same. So,

AB/ED = BC/EF = AC/DF

Substitute values that they give

6/15 = 18/y = 22/x

Solve 6/15 = 18/y by cross-multiplying

6y = 15*18 = 324

Divide both sides by 6

y= 45

Solve 6/15 = 22/x by cross-multiplying.

6x = 22*15 = 330

Divide both sides by 6.

x = 55

Because there is some dispute between the answers, let's check the ratios.

6/15 = 18/45 = 22/55

0.4 = 0.4 = 0.4

True, x = 55 and y=45

since triangle abc~ def

their sides will be proportional

AB/de=ac/df

6/15=22/x

doing crisscrossed multiplication

6x=22×15

x=22×15/6=55

again

AB/de=BC/EF

6/15=18/y

doing crisscrossed multiplication

6y=15×18

y=15×18/6=15×3=45

Answer:

The Jason's company charges more than the contractor's company.

Step-by-step explanation:

There are two expressions given for total charges for two companies as 81 x+108 and 103 x+64.

Here x represents number of hours.

We are asked to find difference in total charges if that takes 45 minutes.

45 minutes = [tex]\frac{3}{4}[/tex] hours.

Plug in this value for x.

81x+108 =[tex]81*\frac{3}{4} +108[/tex]

Simplify it

60.75 +108 =168.75

Now, for 103x+64 =[tex]103 *\frac{3}{4} +64[/tex]

Simplify it,

77.25+64=141.25

If we see the total charge for both companies for 45 minutes, the Jason's business computers charges more than contractor's company.

Answer: 16,17,18

Step-by-step explanation:

(x)+(x+1)+(x+2) = 51

x+x+x+1+2=51

3x+3=51

3x=51-3

3x=48

x=16

x+1 = 17

x+2= 18

Let, the three consecutive integers be x, x+1 and x+2.

[tex] \star \: \underline{\frak{ \purple{According \: to \: the \: question \orange{,}}}}[/tex]

[tex] \longrightarrow \: \: \pmb{ \sf{x + (x+1) + (x+2) = 51}}[/tex]

[tex] \mapsto \: \: \: \sf{3x + 3 = 51}[/tex]

[tex]\mapsto \: \: \: \sf{3x = 51 – 3}[/tex]

[tex]\mapsto \: \: \: \sf{3x = 48}[/tex]

[tex]\mapsto \: \: \: \sf{x =  \frac{48}{3} }[/tex]

[tex]\mapsto \: \: \: \sf{x = 16}[/tex]

•°• the integers are :

The answers are 3 and -13

You need to plug 3 and -5 into x

By doing this, you get :

12 - 3^2       and

12 - (-5)^2

those expressions equal

12 - 9

12 - 25

So you get

3

-13

Answer:

Charlotte finished the word search in 16 minutes

Step-by-step explanation:

Terrence finished a word search in 3/4 the time it took frank. charlotte finished the word search in2/3 the time it took terrence. Frank finished the word search in 32 min. how long did it take charlotte to finish the word search

Frank finished the word search in 32 min

Terrence finished a word search in 3/4 the time it took frank

Terrence = 3/4 of 32 min

= 3/4 × 32 minutes

= (3×32)/4

= 96/4

= 24 minutes

Terrence finished a word search in 24 minutes

Charlotte finished the word search in 2/3 the time it took Terrence

Charlotte = 2/3 of 24 minutes

= 2/3 × 24

= (2×24)/3

= 48/3

= 16 minutes

Charlotte finished the word search in 16 minutes

Answer:

mode is 0 shshshshsbsbsbbsnsnsnsjsnsns

Answer:

Mode 34,700

Median 35,750

Mean 35,150

Answer:OK ILL HELP

Step-by-step explanation:Combine  

1

2

and  

x

.

y

=

x

2

−

3

Answer:

Amplitude: 4

Period: π

midline: y = 1

Step-by-step explanation:

r(x) = -4 sin(2x) + 1

r(x) = a sin(bx + c) + d where |a| is the amplitude and |b| for the period

a = -4         |a| = 4 :   Amplitude = 4

b = 2          |b| = 2     period of sin(x) = 2π

                                period of sin(bx + c) = 2π/|b| = 2π/2 = π

range of sin(2x) ... -1 ≤ sin(2x) ≤ 1

range of -4 sin(2x) + 1: -4+1 ≤ -4 sin(2x) + 1 ≤ 4+1    

-3 ≤ -4 sin(2x) + 1 ≤ 5

midline: y = (-3 + 5) / 2 = 1        y = 1

Answer:

Part A: The amplitude [tex]\displaystyle r[/tex]is [tex]\displaystyle 4.[/tex]

Part B: The period of [tex]\displaystyle r[/tex]is [tex]\displaystyle \pi.[/tex]

Part C: The equation of the midline of [tex]\displaystyle r[/tex]is [tex]\displaystyle y = 1.[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{r(x) = -4cos\:(2x - \frac{\pi}{2}) + 1} \\ \\ r(x) = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle r(x) = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

Keep in mind that although this IS a sine function, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the centre photograph displays the trigonometric graph of [tex]\displaystyle r(x) = -4cos\:2x + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre photograph] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle r(x) = -4cos\:(2x - \frac{\pi}{2}) + 1.[/tex]So, with all that being said, to find the period, again, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]Now, the amplitude is obvious to figure out because it is the A-term. Moreover, the midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. Now, there is one more piese of information you should know -- the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

g - 74 = 220

g - 74+74 = 220 +74

g = 220 + 74

g = 294

Answer:

20

Step-by-step explanation: