Solve for x. The triangles are similar.

Answer:

x • (2xt + 7y)

Step-by-step explanation:

1. ((5xy-((x2)•t))+2xy)+(3x2•t)

2. Pull out like factors :

  2x2t + 7xy  =   x • (2xt + 7y)

Final result

x • (2xt + 7y)

Answer:

[tex]7xy + {x}^{2} t[/tex]

Step-by-step explanation:

[tex](5xy + 2xy) + ( - 2 {x}^{2} t + 3 {x}^{2}t) [/tex]

Answer:

The range is all real numbers.

Step-by-step explanation:

The function shown is a line (and not a horizontal line).

The range is all the y's on the graph or all the y's that can be generated by the equation of the function.

f(x) = 3x + 9

You could put ANY, literally any, number in place of the f(x) and be able to calculate an x for it. Looking at the graph of this line, you could go up and down the y-axis to infinity in either direction, and the graph of the line would be there.

The range is All Real Numbers.

The sum of the interior angle is 1080 and each angle measure is 135 degrees.

A polygon is a geometric figure with a finite number of sides in two dimensions. On the sides or edges of a polygon, straight-line segments are joined end to end to form a closed shape. The vertices, also known as corners, are the points where two line segments meet and form an angle.

We have an octagon

In an octagon the number of sides = 8

The sum of the angles in the octagon is given by:

= (n - 2)×180

n = 8

= (8 - 2)180

= 6×180

The sum of the interior angle = 1080

Each angle = 1080/8 = 135 degree

Thus, the sum of the interior angle is 1080 and each angle measure is 135 degrees.

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Answer:

3.256*10³2

Step-by-step explanation:3.256 * 1000 = 3256 1000 =10³

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.

Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

The zeroes of the function f(x) = x (x – 8) will be 0 and 8.

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The function is given below.

f(x) = x (x – 8)

The zeroes of the function f(x) is given by the factor equals to zero.

Then we have

      f(x) = 0

x(x – 8) = 0

          x = 0, 8

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Answer:

parallel

a quadrilateral can be a parallelogram only and only if pair of opposite sides are equal and parallel.

The value of z is 119° and the value of y is 28°.

When two parallel lines meet any other line, comparable angles are generated in matching corners or corresponding corners with the transversal, these angles are called corresponding angles.

If the given diagram is modified a bit it will look as shown below, the two angles will be 61° because the two angles are corresponding angles.

Now, since 61° and x lie on the same side of the line, therefore, the sum of the two angles will be,

61° + x = 180°

x = 119°

Also, the angles measured at 61° and (3y-23)° lie on the same side of the transversal, therefore, these two angles are corresponding angles. Thus,

61° = (3y-23)°

61 = 3y - 23

y = 28

Hence, the value of z is 119° and the value of y is 28°.

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Answer:

C

Step-by-step explanation:

7 × ln(x) = 2.4

ln(x) = 2.4/7 = 0.342857143...

x = e^0.342857143... = 1.408967466... ≈ 1.41

perimeter of octagon

Now area

Area of square

Area of shaded region

Answer:

C.  647 square units

Step-by-step explanation:

To find the shaded area, subtract the area of the unshaded square from the area of the octagon.

Area of the octagon

[tex]\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}[/tex]

where:

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}[/tex]

[tex]\implies \textsf{Area}=\sf \dfrac{1631.76}{2}[/tex]

[tex]\implies \textsf{Area}=\sf 815.88\:\:square \:units[/tex]

Area of the square

[tex]\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units[/tex]

Area of the shaded region

= area of the octagon - area of the square

= 815.88 - 169

= 646.88

= 647 square units (nearest square unit)

[tex]\textsf {Finding y :}[/tex]

[tex]\implies \mathsf {1^{2} + y^{2} = 3^{2}}[/tex]

[tex]\implies \mathsf {y^{2} = 8}[/tex]

[tex]\implies \mathsf {y = 2\sqrt{2}}[/tex]

[tex]\textsf {Finding z :}[/tex]

[tex]\implies \mathsf {(2\sqrt{2})^{2}+8^{2}=z^{2}}[/tex]

[tex]\implies \mathsf {z^{2} = 72}[/tex]

[tex]\implies \mathsf {z = 6\sqrt{2}}[/tex]

Answer:

z =8.49 or 6[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Do the Pythagorean theorem = [tex]a^{2} +b^{2} =c^{2}[/tex]

Length of hypotenuse = 8+1=9

length of one side = 3

so, a²+3²=9²

     a²+3²=9²

     a²=81-9

     a²=72

     a=√72=8.49 or 6[tex]\sqrt{2}[/tex]

Answer:

$17131.50

Step-by-step explanation:

23500 decrease 10% =

23500 × (1 - 10%) = 23500 × (1 - 0.1) = 21150

21150 decrease 10% =

21150 × (1 - 10%) = 21150 × (1 - 0.1) = 19035

19035 decrease 10% =

19035 × (1 - 10%) = 19035 × (1 - 0.1) = 17131.5

Answer:

66m

Step-by-step explanation:

Answer:

66 m

Step-by-step explanation:

ok so if you think about it, when she runs diagonal she's creating a triangle where she is running along the hypotenuse. we can now use the Pythagorean Theorem a^2 + b^2 = c^2 to solve for the other side with two of them being known.

plug values in

100^2 + w^2 = 120^2

square known values

10,000 = w^2 = 14,400

subtract 10,000 from both sides

w^2 = 4400

take the square root

w = 66 (rounded to the nearest whole number)

the first definition of an element was made by

Answer:

48

Step-by-step explanation:

Answer:

48

Step-by-step explanation:

edge 2023

Answer:

Which one does not belong to the group

At least 1 right angle = A, C and E

At least 2 sides of equal length = B and E

At least 1 pair of parallel sides= B and E

Parallel lines are those lines that are apart and they never meet till infinity.

Example of shapes that have sides with parallel line are the rectangle and parallelograms.

The shape B and E are rectangles and parallelograms respectively.

The shape that has angle 90° are right angle triangles and trapezium.

Therefore, the shapes that has right angles are A which is a trapezoid and E which is a rectangle.

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Here, ΔTPQ is isosceles and TO is the angle bisector of ∠PTO.

[∵ TP=TQ = Tangents from T upon the circle]

⠀⠀⠀⠀⠀⠀⠀⠀∴ OT⊥PQ

⠀⠀⠀

___________________________________________

[tex]\longmapsto{}[/tex]By Applying Pythagoras Theorem in ∆OPR :

OR = √OP² - PR²

OR = √5² - 4²

OR = 3cm

__________________________________________

Now,

[tex]\leadsto[/tex]∠TPR + ∠RPO = 90° (∵TPO=90°)

[tex]\leadsto[/tex]∠TPR + ∠PTR (∵TRP=90°)

[tex]\leadsto[/tex]∴ ∠RPO = ∠PTR

⠀⠀

∴ Right triangle TRP is similar to the right triangle PRO. [By A-A Rule of similar triangles]

⟼[tex]\frac{TP}{PO} = \frac{RP}{RO} [/tex]

⟼[tex]\frac{TP}{5} = \frac{4}{3} [/tex]

⟼[tex]TP= \frac{20}{3} [/tex]

⠀⠀⠀⠀⠀

Answer: -8

Step-by-step explanation:

Answer:

7(w+13)=35

7w + 91 =35

7w=35-91

7w= -56

7w/7 = -56/7

w=-8

Answer:

b(n) = -11 + (n-1)*8

Step-by-step explanation:

Let n be the sequence number, with n=1 the first number b(1) -11

The sequence changes by +8 each step.

b(1)   -11         + 8 =   -3

b(2)   -3          + 8 =    5

b(3)   5         + 8 =   13

b(4) 13

b(1) = -11

b(2) = -3.   or b(1) + 1*8

b(3) =  5,    or b(1) + 2*8

b(4) =  13,   or b(1) + 3*8

We note that each step adds a multiple of 8 to the initial value of -11.  This can be stated as (n-1)*8

The formula for this sequence would be b(n) = b(1) + (n-1)*8

b(n) = -11 + (n-1)*8

Check:  Does n=3 return the value of 5?

b(n) = -11 + (n-1)*8

b(3) = -11 + ((3)-1)*8

b(3) = -11 + (2)*8

b(3) = -11 + 16

b(3) = 5   YES

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The height of Jake's tree is 17.325 trees.

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Given Josh is 31.2 meters away from the Red Pine tree. The angle of elevation from Josh to the top of the tree is 48º. Therefore, the height of the Josh tree will be,

Tan(48°) = Height of the tree/ Distance between Josh and tree

Height of the tree = Tan(48°) × 31.2 meter = 34.65 meters

Now, Jake's tree is half as tall as Josh's tree. Therefore, the height of Jake's tree is,

Height of Jake's tree = 34.65 meters = 17.325 meters

Hence, the height of Jake's tree is 17.325 trees.

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Answer:

B. -2

Step-by-step explanation:

-12x -2(x+9) = 5(x+4)

*ALWAYS REMEMBER YOUR BODMAS*

-12x -2x - 18 = 5x + 20

*group the like terms*

-14x - 5x = 20 + 18

-19x = 38

x = -2

The value of x that makes the equation true is: x = -2.

B. -2.

Here, we have to find the value of x that makes the equation true, we need to solve for x.

Let's solve the equation step by step:

-12x - 2(x + 9) = 5(x + 4)

Distribute the -2 and 5 on the right side of the equation:

-12x - 2x - 18 = 5x + 20

Combine like terms on both sides:

-14x - 18 = 5x + 20

Move the variable terms (5x) to one side of the equation and the constant terms to the other side.

Let's subtract 5x from both sides:

-14x - 5x - 18 = 5x - 5x + 20

-19x - 18 = 20

Move the constant term (-18) to the other side of the equation.

Let's add 18 to both sides:

-19x - 18 + 18 = 20 + 18

-19x = 38

Finally, divide both sides by -19 to isolate x:

x = 38 / -19

x = -2

So, the value of x that makes the equation true is: x = -2.

B. -2.

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The given sequence;–3.2, 4.8, –7.2, 10.8, is a geometric progression common ratio of -1.5.

When all the terms of a geometric sequence are added, then that expression is called geometric series.

The given sequence ;

–3.2, 4.8, –7.2, 10.8, …

The common ratio

= -4.8/ 3.2

= - 1.5

The terms having a common ratio of -1.5 best describe the relationship between the successive terms in the sequence of the terms.

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Any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.

The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In △ABD and △ACB,

∠A = ∠A (common)

∠ADB = ∠ABC (both are right angles)

Thus, △ABD ∼ △ACB (by AA similarity criterion)

Similarly, we can prove △BCD ∼ △ACB.

Thus △ABD ∼ △ACB,

Therefore, AD/AB = AB/AC.

We can say that AD × AC = AB².

Similarly, △BCD ∼ △ACB.

Therefore,

CD/BC = BC/AC.

We can also say that

CD × AC = BC².

Adding these 2 equations, we get

AB² + BC² = (AD × AC) + (CD × AC)

AB² + BC² =AC(AD +DC)

AB² + BC² = AC²

Hence proved

Thus, any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.

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Answer:

$5.88

Step-by-step explanation:

3 erasers ⇒ $4,41

4 erasers ⇒ $A

A = 4 erasers * $4.41 / 3 erasers

A = $ 5.88

Answer:

see below

Step-by-step explanation:

Proportion:

4.41 is to 3 erasers as   'x' is to 4 erasers:

4.41 /3     =  x / 4       <======this is your proportion

 or rearrange

      4 *  4.41/3   = x  

(this results in x = $ 5.88  for 4 erasers )

jAlright, let's take this problem step-by-step:

What is the perimeter:

 ⇒ all the side-lengths added up

    ⇒ need to find side-length using distance formula

                [tex]Distance_._. Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                         - (x₁,y₁): first point

                         - (x₂,y₂): second point

Let's solve:

           ⇒ first point: (5,7)

           ⇒ second point: (3,3)

           [tex]Distance =\sqrt{(3-5)^2+(3-7)^2} =\sqrt{4+16} =\sqrt{20} =4.472[/tex]

          ⇒ first point: (5,7)

          ⇒ second point:(8,6)

           [tex]Distance=\sqrt{(8-5)^2+(6-7)^2} =\sqrt{9+1} =\sqrt{10}=3.162[/tex]

          ⇒ first point: (8,6)

          ⇒ second point: (3,3)

           [tex]Distance = \sqrt{(3-8)^2+(3-6)^2} =\sqrt{25+9} =\sqrt{34}=5.831[/tex]

Now let's solve for the perimeter:

  [tex]Perimeter = 4.472+ 3.126+ 5.831=13.429[/tex]

Answer: 13.43 (rounded to the nearest hundredth)

Hope that helps!

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