several balls and sticks glued together to represent a molecule

Answers

Answer 1

Answer:

The different elements are represented by their symbols one line shows a single bond and two lines show a double bond. This written representation is called a structural diagram

Related Questions

A calorimeter absorbs 2,508 J of energy from the snack shown in the data below. How much energy does the snack provide per
gram (J/g) according to the experiment?

Answers

The energy provided by the snack is obtained as 1254 J/g.

What is the energy of the snack?

The calorimeter is used to measure the energy content of food. The food is burnt in the calorimeter in order to determine the amount of energy that it contains. The mass of the food burnt is converted to energy.

Mass of food burnt = 3.52 g - 1.52 g = 2 g

The energy that is provided by the snack in J/g = 2,508 J/ 2 g

= 1254 J/g

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Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo

Answers

Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liters}[/tex].

Definition of molar mass

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Mass of NaF required

In this case, you know:

molarity= 0.15 M= 0.15 [tex]\frac{moles}{L}[/tex]number of moles= ?volume= 600 mL= 0.6 L

Replacing in the definition of molarity:

[tex]0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}[/tex]

Solving:

0.15 [tex]\frac{moles}{L}[/tex] × 0.6 L= number of moles

0.09 moles= number of moles

The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?

[tex]mass=\frac{0.09 molesx41.9 grams}{1 mole}[/tex]

mass= 3.771 grams

Finally, the mass of NaF required is 3.771 grams.

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How many grams of Ag2S2O3 form
when 125.0 g AgBr reacts completely
according to the reaction below?

2AgBr + Na2S2O3 → Ag2S₂O3 + 2NaBr

Answers

Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

Reaction stoichiometry

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgBr: 2 moles Na₂S₂O₃: 1 moleAg₂S₂O₃: 1 mole NaBr: 2 moles

The molar mass of the compounds is:

AgBr: 187.77 g/moleNa₂S₂O₃: 158 g/moleAg₂S₂O₃: 327.74 g/moleNaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgBr: 2 moles ×187.77 g/mole= 375.54 gramsNa₂S₂O₃: 1 mole ×158 g/mole= 158 gramsAg₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 gramsNaBr: 2 moles ×102.9 g/mole= 205.8 grams

Mass of Ag₂S₂O₃ formed

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

[tex]mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}[/tex]

mass of Ag₂S₂O₃= 109.09 grams

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

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