Answer:
D
Explanation:
Kinetic energy = 1/2mV^2
From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,
K.E = V^2
Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.
Answer:
Its D
Explanation:
Question 9 of 10
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Answer:
v = C / n light slows entering a medium of higher index of refraction
ni sin theta i = nr sin theta r Snell's Law where i refers to incidence and r refers to refraction
sin theta r = (ni / nr) sin theta i
So if the index of refraction is greater than the angle of incidence then the light ray would be refracted towards the normal
Answer:
A. It slows down, and the angle decreases.
Explanation:
got it right, trust
An iron wire has a length of 1.50 m and a cross sectional area of 0.450 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.800 V is maintained across its length, determine the current in the wire (in A)
Answer:
2400A
Explanation:
R=pL/A
R-Resistance
p-Resistivity=10.0 x 10^-8
L-1.5m
A-Cross sectional Area=0.00045
R=10.0 x 10^-8 x 1.5 ÷ 0.00045
and=0.000333333
I-current
V-potential difference
I=V/R
0.800÷0.000333333
Ans=2400A
two automobiles a and b are travelling in the same direction in adjacent lanes are stopped at a traffic signal. as the signal turns green, automobile a accelerates at a constant rate of 2 m/s2. two seconds later, automobile b starts and accelerates at a constant rate of 3.6 m/s2. determine (a) when b will overtake a, (b) the speed of each automobile at that time, and c) the location where b overtakes a relative to the traffic signal. -truck
Answer:
a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m
Explanation:
(a) when b will overtake a,
Using s = ut + 1/2at² we express the distance moved by each automobile.
Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking
So s = 0 × t + 1/2at²
s = 0 + 1/2at²
s = 1/2at²
Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²
So, s = 1/2 × 3.6 m/s² × t² = 1.8t²
Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,
s = 1/2 × 2 m/s² × (t + 2)²
s = (t + 2)²
Since both distances are equal at overtaking
(t + 2)² = 1.8t²
t² + 4t + 4 = 1.8t²
1.8t²- t² - 4t - 4 = 0
0.8t² - 4t - 4 = 0
dividing through by 0.8, we have
0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0
t² - 5t - 5 = 0
Using the quadratic formula to find t,
[tex]t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s[/tex]
t ≅ 5.85 or -0.85
We take the positive answer since t cannot be negative.
So, t = 5.85 s
So, b will overtake a 5.85 s later.
(b) the speed of each automobile at that time,
Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile
i. Speed of automobile a
For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²
So, v = u + at
= 0 m/s + 2 m/s² × 7.85 s
= 0 m/s + 15.7 m/s
= 15.7 m/s
ii. Speed of automobile b
For automobile a, its time of travel is t s = 5.85 s and its acceleration is 3.6 m/s²
So, v = u + at
= 0 m/s + 3.6 m/s² × 5.85 s
= 0 m/s + 15.7 m/s
= 21.06 m/s
≅ 21.1 m/s
c) the location where b overtakes a relative to the traffic signal. -truck
The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²
Using s = (t + 2)²
= (5.85 + 2)²
= 7.85²
= 61.6225 m
≅ 61.62 m
an object has a velocity of 0.12 rad/s. how many revolutions will the object make after traveling for 30 seconds?
Answer:
We can write S = v * t where S is the distance traveled in time t
S = .12 rad/sec * 30 sec = 3.6 rad distance traveled
Also 2 * pi * N = S since there are 2 * pi rad / revolution
So 2 * pi * N = 3.6
N = 3.6 / (2 * pi) = .573 revolutions
How are newtons third law and his law of universal gravitation are connected
Answer:
please give me brainlist and follow
Explanation:
Gravitational force keeps it attracted to the Earth, and centripetal force keeps it moving in a circle. ... Explain how Newton's third law and his law of universal gravitation are connected. His third law states that every force has an equal opposite force attracted to it, and that force is caused by gravity.
the ice and steam point on a thermometer are found to be 96ml apart. what temperature is recorded when the length of mercury thread is 33.6ml above the ice point
Answer:
33.6 / 96 is the fraction of the temperature between ice and freezing
33.6 / 96 = .35
So C = .35 * 100 = 35 deg C where the ice point would be 0 deg C
You can convert C to F
F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F
How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
Which of these is an example of tertiary prevention?
A. Getting screened for skin cancer
B. Avoiding smoking and drinking alcohol
C. Dialysis for damaged kidneys
D. Washing hands
Explanation:
because a tertiary prevention is when the person is already infected with the disease
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim ([tex]s[/tex]), in centimeters, is determined by using this expression:
[tex]s = \omega \cdot r\cdot t[/tex] (1)
Where:
[tex]\omega[/tex] - Angular speed, in radians per second.
[tex]r[/tex] - Radius of the disk, in centimeters.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]\omega \approx 10.472\,\frac{rad}{s}[/tex], [tex]r = 50\,cm[/tex] and [tex]t = 30\,s[/tex], then the travelled distance of the point is:
[tex]s = \omega \cdot r\cdot t[/tex]
[tex]s = 15708\,cm[/tex]
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Why do astronomers use frequencies other than the visible ones when they are
investigating the universe?
Select the correct answer.
Which type of energy is thermal energy a form of
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.01 mm apart and position your screen 3.09 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 639 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
[tex]0.00195\ \text{m}[/tex]
[tex]0.00293\ \text{m}[/tex]
Explanation:
m = Order = 1
D = Distance between screen and slit = 3.09 m
d = Slit distance = 1.01 mm
[tex]\lambda[/tex] = Wavelength = 639 nm
Distance from the first bright fringe from the central bright fringe is given by
[tex]y=\dfrac{m\lambda D}{d}\\\Rightarrow y=\dfrac{1\times 639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00195\ \text{m}[/tex]
Distance from the first bright fringe from the central bright fringe is [tex]0.00195\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is given by
[tex]y=(m+\dfrac{1}{2})\dfrac{\lambda D}{d}\\\Rightarrow y=(1+\dfrac{1}{2})\dfrac{639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00293\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is [tex]0.00293\ \text{m}[/tex].
Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer higher resistance and the wires are made of copper as the electrical conductivity of copper is low
a)Both A and R are true and R is the correct explanation of A.b)Both A and R are true, and R is not the correct explanation of A.c)A is true, but R is false. d)A is false, but R is true. e)Both A and R are false.
There actually three assertions here: one in A and two more in B.
All three assertions, as well as the reasoning described in this mess, are all False.
The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.
what is a black whole why does it exist
Answer:
A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.
A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answer:
Explanation:
My name is Jeff
From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?
A. Gases, solids, liquids
B. Gases, liquids, solids
C. Solids, liquids, gases
D. Solids, gases, liquids
Answer:
C. Solids,Liquids, Gases
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is [tex]\underline{6.9 . \overline 3 \times 10^{-3}} \ m[/tex]Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]
The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]
Learn more here:
https://brainly.com/question/20905151
represent 11 by 9 on a number line
The weight of an object is the force pulling the object:
a. upward
b. to the side.
c. in all directions
d. downward
Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)
Answer: 9.42
Explanation: yes
sinat
Accelerationa
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TABLE
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2.29 1.25 1.28 1.271.61
2 460 = 0.00 4.59 1.16 1.081.12 1-25
3 so = 0.12 6.89 0.88
097 0.53
4. = 0.16 9.210.8
9.21 0.850.796. 82/0.67
(So
0.72 0.77 0.75 l 0-56/
0.28
49. al
27. 49
13 11%.
41. 2L
= 0.2 11.54
Answer:
so you have a question
Explanation:
either way,you have a nice day
All objects have an electric charge, what are the options they could have select all that apply.
Positive
Negative
Neutral
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describe the human condition before Science and technology was practice.
You need to design a spring that will launch a 1060 kg satellite with a speed of 3.35 m/s relative to an orbiting space station. The maximum safe acceleration of the satellite is 5.00g, (g being the usual gravitational field constant on the surface of the Earth). The spring's mass, the recoil kinetic energy of the space station, and changes in gravitational potential energy will all be negligible.What must the force constant of the spring be
Answer:
226.8 kN/m
Explanation:
The work done by the spring, W equals the kinetic energy of the satellite, K
W = K
work done by the spring, W = 1/2kx² where k = force constant and x = extension of spring
kinetic energy of the satellite, K = 1/2mv² where m = mass of satellite = 1060 kg and v = speed of satellite = 3.35 m/s
1/2kx² = 1/2mv²
k = mv²/x²
Also, the spring force F = kx where k = force constant and x = extension of spring.
k = F/x
equation both expressions for k, we have
mv²/x² = F/x
x = mv²/F since F = ma where m = mass of satellite and a = maximum acceleration of satellite = 5.00g and g = 9.8 m/s²
x = mv²/ma = mv²/5.00mg = v²/5.00g
Substituting the values of the variables into the equation, we have
x = v²/5.00g
= (3.35 m/s)²/(5.00 × 9.8 m/s²)
= 11.2225 m²/s²/49 m/s²
=0.229 m
Now k = F/x = 5.00mg/x
Substituting the values of the variables into the equation, we have
k = 5.00mg/x
k = 5.00 × 1060 kg × 9.8 m/s²/0.229 m
k = 51940 kgm/s²/0.229 m
k = 51940 N/0.229 m
k = 226812.23 N/m
k = 226.81223 kN/m
k ≅ 226.8 kN/m
A 0.40 kg block can slide up and down a rough a 10-m-high, 30-m-long slope. At the bottom, a stiff spring with spring constant 800 N/m is compressed 0.50 m and used to launch the block up the slope. The friction force on the block from the slope is 1.2 N. What is the speed of the block when it reaches the top of the slope, in m/s
Answer:
[tex]v=11.135m/s[/tex]
Explanation:
From the question we are told that
Mass [tex]m=0.40kg[/tex]
Frictional friction [tex]f=1.2[/tex]
Spring constant [tex]k=800N/m[/tex]
Compressed [tex]x=0.50[/tex]
Generally the energy balance equation is mathematically given as
[tex]1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2[/tex]
if [tex](sin=10/30-1/3)[/tex]
[tex]1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2[/tex]
[tex]100=36+39.2+0.20v^2[/tex]
[tex]v^2=\frac{24.8}{0.20}[/tex]
[tex]v=\sqrt{124}[/tex]
[tex]v=11.135m/s[/tex]
What is the equivalent resistance of the circuit?
Answer:
(B) 80 ohms
Explanation:
Since the circuit is a series connection, simply add the two resistances together to get 80 ohms.
Which machine do you think will last longer, the traditional battery and motor, or the free energy machine?
Answer:
it will most likely be the free energy
Why do you think geologists were able to use these P and S seismic waves to confirm that the outer core is liquid?
Using waves of frequency and pich
Explanation:
There's always been water around us
WHY ARE ALL GIRLS THE SAME, don't even say their not cause if you say that then I guess you don't have a life!!!!!
