Ronald is calculating the density of oranges in a crate. He knows the number of oranges in the crate and the volume of the crate. Which of the following formulas can be used to calculate the density of oranges in the crate? (6 points) Density = volume of crate over number of oranges Density = number of oranges over volume of crate Volume of shelf = density over number of oranges Number of books = density over volume of crate

Answer:

What up why is there no question

Step-by-step explanation:

Answer:

The answer is D

Step-by-step explanation:

Answer:

The numerical coefficient in the expression 4x2y−23xy+25xy2 is 4,2−3,25 respectively

The numerical coefficient in the expression 3−5x2y+47xyz+3 is 3−5,47 respectively.

3 is a constant term.

Answer:

Each friend started with $9

Step-by-step explanation:

45 / 5 = 9

Answer:

I think it's 1,125 and 4485

Step-by-step explanation:

25x13x3

115x13x3

Answer:

The derivative is:

[tex]f^{\prime}(x) = -\frac{5}{x^2-6x+9}[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \frac{5}{3-x}[/tex]

Derivative of a quotient:

Suppose we have a quotient:

[tex]f(x) = \frac{g(x)}{h(x)}[/tex]

The derivative is:

[tex]f^{\prime}(x) = \frac{g^{\prime}(x)h(x) - h^{\prime}(x)g(x)}{h(x)^2}[/tex]

In this question:

Numerator [tex]g(x) = 5, g^{\prime}(x) = 0[/tex]

Denominator [tex]h(x) = 3 - x, h^{\prime}(x) = -1[/tex]

So

[tex]f^{\prime}(x) = \frac{0(3-x) - 5}{(3 - x)^2} = -\frac{5}{x^2-6x+9}[/tex]

The derivative is:

[tex]f^{\prime}(x) = -\frac{5}{x^2-6x+9}[/tex]

Answer:

228 x y or x^2+3x+2

Step-by-step explanation:

the ratio of 12x 19y

Answer:

for 6, you drag 36. for 7, you drag 42.

Step-by-step explanation:

It is using time tables by x6

Answer:

256

Step-by-step explanation:

Answer:

16 is the answer because 64/4 is 16 so 16*4 is 64 meaning that there are 16 books on each shelf

Step-by-step explanation:

hope this helped

pi = 180

3(180)             540

--------    =        -------

5                        5

Answer is 108 degrees

Answer:

true

Step-by-step explanation:

i think

Answer:

a

Step-by-step explanation:

8x-20 and 3x together will equal 90

Answer:

The answer is D

Step-by-step explanation:

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of u in common, so we can pull it out to give us the factored expression u(12-v).

Note on factoring:

Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.

Answer:

Someone gave me da link to dis

Step-by-step explanation:

Answer:

The shoes belonging to my three uncles are always dirty.

Answer:

angle7 = 80 (because vertically opposite angles are always equal)

angle7 + angle5 = 180 (because is a straight line)

80 + angle5 = 180

angle5 = 180 - 80

angle5 = 100

Answer:

[tex]\frac{2}{5}[/tex]

Step-by-step explanation:

Use the following equation:

slope (m) = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

Let:

[tex](x_1 , y_1) = (4 , 4)\\(x_2 , y_2) = (9 , 6)[/tex]

Plug in the corresponding numbers to the corresponding variables:

m = [tex]\frac{6 - 4}{9 - 4} = \frac{2}{5}[/tex]

[tex]\frac{2}{5}[/tex] is your slope.

Answer:

[tex]m = \frac{2}{5} [/tex]

Step-by-step explanation:

Slope is equal to the change in y over the change in x, or rise over run.

[tex]m = \frac{change \: in \: y}{cahnge \: in \: x} [/tex]

The change in x is equal to the difference in x-coordinates  and the change in y is equal to the difference in y-coordinates.

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

Substitute in the values of x and y into the equation to find the slope.

[tex]m = \frac{4 - (6)}{4 - (9)} [/tex]

Simplify.

[tex]m = \frac{2}{5} [/tex]

Therefor, the answer is m = 2/5.

Answer:

4 POUNDS OF FLOUR

Step-by-step explanation:

The number of cups of flour he added is 4.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Bowl weight = 1(1/2) pounds

Number of cups of flour weight = x pounds

Now,

Total weight = 2(3/4) pounds

1(1/2) + x = 2(3/4)

x = 11/4 - 3/2

x = (11 - 6)/4

x = 5/4

Now,

Weight of each cup of flour = 5/16 pounds

Now,

The number of cups of flour.

= 5/4 ÷ 5/16

= (5 x 16) / (4 x 5)

= 4

Thus,

The number of cups of flour is 4.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ2

Answer:

380-5%

Step-by-step explanation:

Answer:

£399

Step-by-step explanation:

personally its easier to find 1% first then multiply it by how many percent are needed to be found.

380/100=1%

380/100=3.8

3.8x5=5%

3.8x5=19

380+19=usual price

380+19=199

Answer:

x+3 units and x+6 units

Step-by-step explanation:

Give the total area of a rectangle is represented by (x²+9 x+18) sq units.F

Factorize

x²+9 x+18

- x^2 + 6x + 3x + 18

= x(x+6) + 3(x+6)

= (x+3)(x+6)

Since Area = Length * Width

The dimensions of the rectangle are x+3 and x+6 units

Answer:

2. is b

3.is d

4.is b

5

Step-by-step explanation:

I've done these before

have a good grade

Answer:

The sample mean is of 1970 daily calories.

The margin of error is of 120 daily calories.

The sample standard deviation is of 12.3 daily calories.

Step-by-step explanation:

Mean number of daily calories consumed by participants in a medical study is (1850, 2090).

The sample mean is the mean of the bounds of the confidence interval. So

[tex]M = \frac{1850 + 2090}{2} = 1970[/tex]

The sample mean is of 1970 daily calories.

Margin of error:

The margin of error is the difference between the bounds and the sample mean. So

2090 - 1970 = 1970 - 1850 = 120

The margin of error is of 120 daily calories.

Sample standard deviation:

Now I have to expand a bit into the t-distribution. So

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.08

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}}[/tex]

In which s is the standard deviation of the sample.

Since [tex]M = 120, T = 2.08, n = 22[/tex]

[tex]120 = 2.08\frac{s}{\sqrt{22}}[/tex]

[tex]s = \frac{120}{2.08\sqrt{22}} = 12.3[/tex]

The sample standard deviation is of 12.3 calories.

Answer:

it depends how fat you are....BUT the average speed would be 8 I THINK but i might be right

Step-by-step explanation:

Answer:

1/15

Step-by-step explanation:

no. of students who participate in all of the three activities is 2.

So, the possibility is 2/15 = 1/15

Ans: 1/15

I'll do problem 3 to get you started.

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Part 1) Finding the mean:

The mean is found by adding up all the numbers and dividing by n, where n is the number of items in the set.

We sum the numbers to:

5+8+5+9+6+15+9+3+8+7+10+12 = 97

Then we divide over n = 12

mean = sum/n = 97/12 = 8.083333 approximately

This rounds to 8.08

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Part 2) Finding the standard deviation:

I'm assuming your teacher is talking about the population standard deviation, as opposed to the sample standard deviation.

First subtract each value from the mean. It helps to make a table as shown in the attachment below.

Column A is the original data set. Column B is when we subtract each data item x from the mean M.

Column C is where we square each item in column B.

Adding up everything in column C leads to 118.916666666667 which is approximate. This value is highlighted in the table diagram. Divide this over n = 12 to get 9.90972222222222 which is also approximate

The last step is to apply the square root to that and we get 3.1479711279

This rounds to 3.15

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Part 3) Finding the min:

From here on out, we have fairly simple calculations and don't need to involve a spreadsheet or any complicated formulas.

The min value is the smallest value of the set. So that would be 3

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Part 4) Finding the value of Q1, first quartile:

Sort the items in ascending order, ie from smallest to largest.

You should get this set: {3, 5, 5, 6, 7, 8, 8, 9, 9, 10, 12, 15}

There are n = 12 items here, so the median is between slot 12/2 = 6 and slot 7. The values in slot 6 and 7 are the two copies of '8'. That must mean the median is (8+8)/2 = 8.

Now break up the set into two equal halves

L = {3, 5, 5, 6, 7, 8} = lower half of six items

U = {8, 9, 9, 10, 12, 15} = upper half of six items

The median of set L is exactly the value of Q1, so that would be (5+6)/2 = 11/2 = 5.5; note how this is exactly between the two middle most values of 5 and 6.

---------------------------------------------------------

Part 5) Finding the median:

We found that earlier in part 4. The median is 8.

---------------------------------------------------------

Part 6) Finding the value of Q3, third quartile:

Focus on set U = {8, 9, 9, 10, 12, 15}, which was the upper set of values, ie values larger or equal to the median.

The middle two values here are the '9' and '10'. The median is at the midpoint of these values: (9+10)/2 = 19/2 = 9.5

We have Q3 = 9.5

---------------------------------------------------------

Part 7) Finding the max:

The max is the largest item in the original set

Refer to the sorted set {3, 5, 5, 6, 7, 8, 8, 9, 9, 10, 12, 15} and we see that 15 is the max.

---------------------------------------------------------

Part 8) Finding the IQR (interquartile range):

Subtract the values of Q3 and Q1 to get the IQR

IQR = Q3 - Q1

IQR = 9.5 - 5.5

IQR = 4

---------------------------------------------------------

Part 9) Finding the range:

The range is a similar idea as the IQR; however, we'll subtract the max and min this time.

Range = max - min = 15 - 3 = 12

The range is 12.

The range, IQR and standard deviation all help us determine the spread of the data. The larger the value gets, the more spread out the data is.

---------------------------------------------------------

Summary:

Side note: The phrase "five number summary" refers to the five values of: min, Q1, median, Q3, max. All of which are needed to form a box-and-whisker plot.