Regardless of what state a substance is in, it is always that substance

True
False

Answer:

70-100 BPM

Explanation:

Answer:

The height of the cliff is 121.276 m

Explanation:

Given;

initial velocity of the projectile, v₁ = 75 m/s

final velocity of the projectile, v₂ = 90 m/s

spring compression = 5 m

Apply the law of conservation of energy;

mgh₀ + ¹/₂mv₁² = mgh₂ + ¹/₂mv₂²

gh₀ + ¹/₂v₁² = gh₂ + ¹/₂v²

gh₁  - gh₂ = ¹/₂v₂² - ¹/₂v₁²

g(h₀  - h₂) = ¹/₂ (v₂² - v₁²)

h₀  - h₂ = ¹/₂g (v₂² - v₁²)

h₀ = h(cliff) + 5m

when the projectile hits the ground, Final height, h₂ = 0

[tex]h_o - 0 = \frac{1}{2g}(v_2^2-v_1^2)\\\\h_{cliff} + 5= \frac{1}{2g}(v_2^2-v_1^2)\\\\h_{cliff} = \frac{1}{2g}(v_2^2-v_1^2) - 5\\\\h_{cliff} = \frac{1}{2*9.8}(90^2-75^2) - 5\\\\h_{cliff} = 121.276 \ m[/tex]

Therefore, the height of the cliff is 121.276 m

Answer:

5694000 min

Explanation:

Let's suppose the average American watches 4 hours of TV every day. First, we will calculate how many minutes they watch per day. We will use the conversion factor 1 h = 60 min.

(4 h/day) × (60 min/1 h) = 240 min/day

They watch 240 minutes of TV per day. Now, let's calculate how many minutes they watch per year. We will use the conversion factor 1 year = 365 day.

240 min/day × (365 day/year) = 87600 min/year

They watch 87600 min/year. Finally, let's calculate how many minutes they spend watching TV in 65 years.

87600 min/year × 65 year = 5694000 min

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Note: The question is in complete. The complete question is given below:

Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information?

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Rhea is standing still after kicking the ball, and Sean is running away from Rhea.

Both soccer players are standing still after the ball is kicked.

Both soccer players are running while the ball is in motion.

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Note: The question is in complete. The complete question is given below:

Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information?

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Rhea is standing still after kicking the ball, and Sean is running away from Rhea.

Both soccer players are standing still after the ball is kicked.

Both soccer players are running while the ball is in motion.

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Answer:

10 mls2

Explanation:

speed =distance /time

Answer:

What do you mean ma´am/sir?

Explanation:

Answer:

a) The work done by gravity on the coin as it falls is 17.653 joules.

b) The kinetic energy of the coin at a speed of 60 meters per second is 10.8 joules.

c) The work lost due to air resistance is 6.853 joules.

d) The average force exerted on the coin due to air resistance as it fell is 0.023 newtons.

Explanation:

a) We must remind that situation with Earth-coin system must be represented by Principle of Energy Conservation and Work Energy Theorem. According to this latter, work done by gravity equals to the change in gravitational potential energy:

[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (Eq. 1)

Where:

[tex]\Delta U_{g}[/tex] - Change in gravitational potential energy, measured in joules.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational accelerations, measured in meters per square second.

[tex]\Delta z[/tex] - Height of the skyscraper, measured in meters.

If we know that [tex]m = 0.006\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 300\,m[/tex], the work done gravity on the coin is:

[tex]\Delta U_{g} = (0.006\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (300\,m)[/tex]

[tex]\Delta U_{g} = 17.653\,J[/tex]

The work done by gravity on the coin as it falls is 17.653 joules.

b) By definition of translation kinetic energy, we get the following model:

[tex]K = \frac{1}{2}\cdot m\cdot v^{2}[/tex]

Where:

[tex]K[/tex] - Kinetic energy of the coin right before hitting the street, measured in joules.

[tex]v[/tex] - Speed of the coin, measured in meters per second.

If we get that [tex]m = 0.006\,kg[/tex] and [tex]v = 60\,\frac{m}{s}[/tex], the kinetic energy at this speed is:

[tex]K = \frac{1}{2}\cdot (0.006\,kg)\cdot \left(60\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 10.8\,J[/tex]

The kinetic energy of the coin at a speed of 60 meters per second is 10.8 joules.

c) The work lost due to air resistance is obtained derived from Principle of Energy Conservation and Work-Energy Theorem:

[tex]W_{lost} = \Delta U_{g}-K[/tex] (Eq. 2)

Where [tex]W_{lost}[/tex] is the work lost due to air resistance, measured in joules.

If we know that [tex]\Delta U_{g} = 17.653\,J[/tex] and [tex]K = 10.8\,J[/tex], the work lost due to air resistance is:

[tex]W_{lost} = 17.653\,J-10.8\,J[/tex]

[tex]W_{lost} = 6.853\,J[/tex]

The work lost due to air resistance is 6.853 joules.

d) The average force exerted on the coin due to air resistance can be determined by applying definition of work, as air resistance force was antiparallel to the displacement of the coin. That is:

[tex]W_{lost} = F\cdot \Delta z[/tex]

[tex]F = \frac{W_{lost}}{\Delta z}[/tex] (Eq. 3)

Where [tex]F[/tex] is the average force exerted on the coin due to air resistance, measured in newtons.

If we know that [tex]W_{lost} = 6.853\,J[/tex] and [tex]\Delta z = 300\,m[/tex], then the average force exerted on the coin is:

[tex]F = \frac{6.853\,J}{300\,m}[/tex]

[tex]F = 0.023\,N[/tex]

The average force exerted on the coin due to air resistance as it fell is 0.023 newtons.

Answer:

Function

Explanation:

This question defines a function. It is any consequence that is made up of positive structures which has a way of affecting the society in a positive way. And it also has a way of impacting structural continuity in the society. The functionalism idea has the postulation that all cultural or social phenomena is of positive function and cannot be ignored

Answer:

function

Explanation:

answer EDGE2020

The answer is A I Hope this answer helps you (i got the question right)

Answer:

A. As speed increases, kinetic energy increases exponentially.

Explanation:

The amount of kinetic energy an object has depends on the speed. Kinetic energy is also known as "motion energy." This being said, if speed is increasing, decreasing, or staying constant, the kinetic energy of the object will too.

Answer:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

Explanation:Hope this helps :)

By definition, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

First of all, an atom is the smallest constituent unit of ordinary matter that has the properties of a chemical element.

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

In other words, every atom consists of a nucleus in which neutrons and protons meet and energy levels where electrons are located.

This is, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.

In summary, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

Learn more:

Answer:

43200 J

Explanation:

(1/2(mass)) (speed)^2

Answer:

Thanks!!!!! adding this so it doesn’t get deleted.

Explanation:

1. Electrostatic forces are trillions of times stronger than gravitational forces. 2. normal force and friction 3. contact forces 4. The electrostatic forces from the contact of the hands with the paper causes the paper molecules to separate. 5. The electrostatic forces between the molecules of the board prevent the force of gravity from breaking the board apart.

The correct statement over here is that electrostatic forces are trillions of times stronger than gravitational forces. Hence, option C is correct.

One of the basic forces in the cosmos is electrostatic force. In the universe, there are four basic forces. These include gravitational force, electromagnetic force, weak nuclear force, and strong nuclear force. Under the umbrella of electromagnetic force is electrostatic force. Two charges placed apart are subject to the electrostatic force. The size of each charged and the separation between them determines how much electrostatic force there will be.

When two charges of the same type are brought together, whether positive or negative, they repel one another. It is known as the electrostatic force of repelling when it operates among two charges that are similar.

Therefore, the electrostatic forces are trillions of times stronger than the gravitational forces.

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Answer:

it depend what you are.rolling down and how far would be the lighter the object the farther like a marble

Answer:

Probability = 0.0244

Explanation:

Probability that Junior Non Physics Major & then a Freshman Non Physics Major are chosen:

Prob (Jr No-Ph Mjr)  = Jr No-Ph Mjr / Total

= 18 / 82 = 0.2195

Prob (Fr No-Ph Mjr) = Fr No-Ph Mjr / Total (remaining)

= 9 / 81 = 0.1111

Prob [ Jr No-Ph Mjr & Fr  No-Ph Mjr ] = 0.2195 x 0.1111 = 0.02439

≈  0.0244

Answer:

skeletal,cardiac,and smooth.

Explanation:

Answer:

Skeletal, smooth, and cardiac.

Explanation:

Skeletal Muscles:

Skeletal muscles are the most familiar type of muscles; they make up most of the muscle mass in the body. Flexible bands of connective tissue called tendons attach these muscles to the bones in the body. Skeletal muscles control voluntary movement in the body.

Smooth Muscles:

Smooth muscles are involuntary muscles that we don’t consciously control. They are found within the walls of many organs and control the movement of these organs. For example, they enable the movement of food through the digestive system.

Cardiac Muscles:

Cardiac muscles are a special type of involuntary muscle. Located in the heart, these muscles control the contractions of the heart.

can u give me brainliest???

Answer:

K and I

Explanation:

Contour maps use lines that represent spaces in a map that have the same elevation, this means that all the lines should be continuous and closed, in this case, we are not able to see the full extent of most of the lines, but since the points are located in different lines we can assume that they are at different heights, so since only point K and point I are on the same line, we know that these two points are at the same height.

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 500 N

distance = 4 m

We have

workdone = 500 × 4

We have the final answer as

Hope this helps you

Answer:

The length of the spring is 44.92 cm

Explanation:

Hooke's Law

Suppose a spring of constant k and natural length x0. If a force F is applied to the spring and it stretches to a distance x1. Hooke's Law states that:

[tex]F=k.x[/tex]

Where x is the elongation of the spring:

[tex]x=x1-x0[/tex]

We are given the characteristics of a spring of x0=31 cm. When a mass of m=8 Kg is hung from the spring, it stretches to x1=36.9 cm. We need to calculate the force of the mass of 8 Kg. It can be done by calculating the weight:

[tex]F = m.g=8\ Kg\cdot 9.8\ m/s^2[/tex]

[tex]F=78.4\ N[/tex]

The elongation of the spring is

[tex]x=36.9\ cm - 31\ cm = 5.9\ cm[/tex]

Converting to meters:

[tex]x=5.9/100=0.059\ m[/tex]

(a)

From Hooke's Law, we solve for k:

[tex]\displaystyle k=\frac{F}{x}=\frac{78.4}{0.059}[/tex]

[tex]k=1,329\ N/m[/tex]

(b) With the value of k, the equation for the spring is:

[tex]F=1,329.x[/tex]

Now if a weight of F=185 N is hung from the spring, the elongation is:

[tex]\displaystyle x=\frac{F}{1,329}=\frac{185}{1,329}[/tex]

[tex]x=0.1392\ m=13.92\ cm[/tex]

Thus, the length of the spring is:

[tex]x1=xo+x=31\ cm+13.92\ cm=44.92\ cm[/tex]

The length of the spring is 44.92 cm

(a)The spring constant will be 1,329 N/m.

(b)The length of the spring will be 44.92 cm.

Spring constant is defined as the ratio of force per unit displaced length. The spring force is balanced by the weight;

The given data in the problem is;

L₁  is the long spring is hung vertically from a ceiling= 31.0 cm

L₂  = 36.9 cm

m is the mass= 8.00 kg

The net elongation of the spring is

x= 36.9-31 =5.9 cm = 0.059 m

The force acted on the spring due to which the elongation is done;

F=mg

F= 8 × 9.81

F=78.4 n

From the Hooke's law the spring constant is found as;

[tex]\rm K = \frac{F}{x} \\\\ \rm K = \frac{78.4}{0.059} \\\\ \rm K = 1,329 \ N/m[/tex]

Hence the spring constant will be 1,329 (in N/m).

(b) The length of the spring will be 44.92 cm.

For the  weight of F=185 N is hung from the spring, the elongation is:

[tex]\rm x= \frac{185}{1,329} \\\\ \rm x=0.10392 m = 13.92 \ cm[/tex]

The length of spring is;

[tex]\rm x_1 = x_0+x \\\\ \rm x_1 = 31+13.92 \\\\ \rm x_1=44.92\ cm[/tex]

Hence the length of the spring will be 44.92 cm.

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Answer:

83.5%

Explanation:

Answer:

Yes

Explanation:

The variables change in and experiment.

Answer:

If you are carefully enough to control everything, then everything that could change the result of your experiment won't happen.

Explanation:

Answer:

hi

Explanation:

hiijjjjjjjjjjjjjjj

Answer:

When scientists in the same or similar field of study judges the quality of a fellow scientist’s scientific claim, it is known as peer review.

When scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claim it is called Peer review.

Scientific claims are statements made in science based on an experiment.

These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.

Peer review is done when scientists in the same or similar field of study judge the quality of a fellow scientist’s scientific claims.

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Answer:

a) Δf = 0.7 n , e)   f = (15.1 ± 0.7) 10³ Hz

Explanation:

This is an error about the uncertainty or error in the calculated quantities.

Let's work all the magnitudes is the SI system

The frequency of oscillation is

        f = n / 2π L² √( E /ρ)

where n is an integer

Let's calculate the magnitude of the oscillation

       f = n / 2π (0.2335)² √ (210 10⁹/7800)

       f = n /0.34257 √ (26.923 10⁶)

       f = n /0.34257    5.1887 10³

       f = 15.1464 10³ n

a) We are asked for the uncertainty of the frequency (Df)

       Δf = | df / dL | ΔL + df /dE ΔE + df /dρ Δρ

in this case no  error is indicated in Young's modulus and density, so we will consider them exact

       ΔE = Δρ = 0

       Δf = df /dL  ΔL

       df = n / 2π   √E /ρ   | -2 / L³ | ΔL

       df = n / 2π 5.1887 10³ | 2 / 0.2335³) 0.005 10⁻³

       df = n 0.649

Absolute deviations must be given with a single significant figure

        Δf = 0.7 n

b, c) The uncertainty with the width and thickness of the canteliver is associated with the density

In your expression there is no specific dependency so the uncertainty should be zero

The exact equation for the natural nodes is

          f = n / 2π L² √ (E e /ρA)

where A is the area of ​​the cantilever and its thickness,

In this case, they must perform the derivatives, calculate and approximate a significant figure

        Δf = | df / dL | ΔL + df /de  Δe + df /dA  ΔA

        Δf = 0.7 n + n 2π L² √(E/ρ A) | ½  1/√e | Δe

               + n / 2π L² √(Ee /ρ) | 3/2 1√A23  |

the area is

        A = b h

        A = 24.9  3.3  10⁻⁶

        A = 82.17 10⁻⁶ m²

        DA = dA /db ΔB + dA /dh Δh

        dA = h Δb + b Δh

        dA = 3.3 10⁻³ 0.005 10⁻³ + 24.9 10⁻³ 0.005 10⁻³

        dA = (3.3 + 24.9) 0.005 10⁻⁶

        dA = 1.4 10⁻⁷ m²

let's calculate each term

         A ’= n / 2π L² √a (E/ρ A) | ½ 1 /√ e | Δe

         A ’= n/ 2π L² √ (E /ρ)      | ½ 1 / (√e/√ A) |Δe

        A ’= 15.1464 10³ n ½ 1 / [√ (24.9 10⁻³)/ √ (81.17 10⁻⁶)] 0.005 10⁻³

        A '= 0.0266  n

        A ’= 2.66 10⁻² n

       A ’’ = n / 2π L² √ (E e /ρ) | 3/2  1 /√A³ |

       A ’’ = n / 2π L² √(E /ρ) √ e | 3/2  1 /√ A³ | ΔA

       A ’’ = n 15.1464 10³ 3/2 √ (24.9 10⁻³) /√ (82.17 10⁻⁶) 3 1.4 10⁻⁷

       A ’’ = n 15.1464 1.5 1.5779 / 744.85 1.4 10⁴

       A ’’ = 6,738 10²

we write the equation of uncertainty

     Δf = n (0.649 + 2.66 10⁻² + 6.738 10²)

The uncertainty due to thickness is

    Δf = 3 10⁻² n

The uncertainty regarding the area, note that this magnitude should be measured with much greater precision, specifically the height since the errors of the width are very small

     Δf = 7 10² n

 d)    Δf = 7 10² n

e) the natural frequency n = 1

       f = (15.1 ± 0.7) 10³ Hz

Answer:

 a = - 9.8 j ^   m/s²

Explanation:

This is a projectile launch problem, they give us the initial velocity in the two components

         v₀ₓ = 17.1 m / s

         [tex]v_{oy}[/tex] = 14.7 m / s

They indicate that the only acceleration that exists is the acceleration of gravity, which acts in the direction towards the center of the Earth, in general in a coordinate system it coincides with the direction of the y axis.

           a = - g j ^

           a = - 9.8 j ^  m /s²

Answer:

leather

Explanation:

plz mark as brainliest......hope it helps

Answer:

a. leather

Explanation:

Hello friend!!!!

a. leather is the correct option because jute, wool and cotton are all natural fibres whereas leather is a synthetic fibre.

Hope this helps

plz mark as brainliest!!!!!!

Answer:

4.8min

Explanation:

The police car is traveling at 100/km and is 1.6km away from red car that is traveling at 80/km

Answer:

40

Explanation:

Answer:

Just to help, periods on the periodic table are those running horizontally from left to right

Answer:

The answer is A.Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.

Explanation:

just took test

Answer:

The force is     [tex] F_c  =  789.03 \  N [/tex]    

Explanation:

From the question we are told that

   The tangential  resistive force is [tex]F_t  =   115 \ N[/tex]

   The mass of the wheel is  m  = 1.80 kg

  The diameter of the wheel is  [tex]d =  50.0 cm  = 0.5 \ m[/tex]

   The diameter of the sprocket is  [tex]d_c  =  8.50 \ cm =0.085 \ m[/tex]

  The angular acceleration considered is  [tex]\alpha  =  4.30\ rad/s^2[/tex]

Generally the radius of the wheel is

       [tex]r = \frac{d}{2}[/tex]

=>     [tex]r = \frac{0.5}{2}[/tex]

=>     [tex]r = 0.25 \ m [/tex]

Generally the radius of the sprocket is

       [tex]r_c = \frac{d_c}{2}[/tex]

=>     [tex]r_c = \frac{0.085}{2}[/tex]

=>     [tex]r_c = 0.0425 \ m [/tex]

Generally the moment of inertia of the wheel is mathematically represented as

      [tex]I  =  m  *  r^2[/tex]

=>    [tex]I  =  1.80  *  0.25^2[/tex]

=>    [tex]I  = 1.1125 \ kg \cdot m^2[/tex]

Generally the torque experienced by the wheel due to the forces acting on it  is mathematically represented as

      [tex]\tau =  F_c *  r_c  -  F_t  * r  [/tex]

Here  [tex]F_c[/tex] is the force acting on the sprocket

So  

      [tex]\tau =  F_c *  0.0425 - 115  * 0.25  [/tex]

       [tex]\tau = 0.0425F_c  -  28.75  [/tex]

Generally the torques that will cause the wheel to move with [tex]\alpha  =  4.30\ rad/s^2[/tex] is mathematically represented as

       [tex]\tau  =  I  * \alpha[/tex]

So

        [tex] 0.0425F_c  -  28.75  =   I  * \alpha  [/tex]

        [tex] 0.0425F_c  -  28.75  =   1.1125  *4.30 [/tex]    

       [tex] 0.0425F_c  -  28.75  =   1.1125  *4.30 [/tex]    

        [tex] F_c  =  789.03 \  N [/tex]