Rain, snow, hail, and sleet are examples of
a
bad weather.
b condensation.
C precipitation.
d evaporation

Answers

Answer 1

Answer:

C. Precipitation

It made me put more on my answer.

Answer 2
precipitation! i answered this on my edg.21 and it was right

Related Questions

A chromophore is:______

a. an unsaturated organic functional group that absorbs ultraviolet or visible radiation.
b. a biochemical species, such as NADH, that strongly absorbs ultraviolet or visible radiation.
c. an ion or complex of elements from the first two transition series that absorbs visible radiation.
d. a molecule that contains an electron-donor group bonded to an electron-acceptor. When radiation is absorbed, an electron is transferred from the donor to an orbital of the acceptor.

Answers

a. an unsaturated organic functional group that absorbs ultraviolet or visible radiation.

Hope this helps :D

look at the picture and select the answer quicly

Answers

I believe c. I hope it helps :)

Composition of the air breathed in and the air breathed out changes

Answers

Answer:

breathed in air contains oxygen while breathed out air contains higher percentage of CO2

How many moles are in 30.68 grams of potassium nitrate? Molar mass of potassium nitrate is 101.11 g/mol.
A. 1.36 moles
B. 1.02 x 10^-22 moles
C. 3,102.05 moles
D. 0.303 moles

Answers

The answer should be B

what is the xonclusion of separating acetone and water by simple and fractional distillation

Answers

Answer:

In conclusion, acetone was determined to be the unknown used in the simple distillation and acetone- water was separated successfully by fractional distillation. Introduction Distillation is the chief technique used to separate and purify liquids.

Determine the mass in grams of 4.69 x 1021 atoms of barium. (The
mass of one mole of barium is 137.33 g.)

Answers

Answer:

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

[tex]4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa[/tex]

Best regards!

If you picked up a hot coffee mug with lots of thermal energy using your hand, where will the thermal energy transfer to?

Answers

Answer:

It will go to your hand.

Explanation: If you touch a hot cup/mug you'll most likely burn yourself, so it would probably go to your hand.

What is standard pressure in atmospheres?

a.10
b.1
c.5
d.2

Answers

The answer is d. 2 hope this helps

I GIVE 40 POINTS PLZ ANSWER

Order the following aqueous solutions from lowest freezing point to highest freezing point: 1 M NaNO3, 1 M Li3PO4, 1 M Ca(NO3)2, 1 M C6H12O6s

Answers

Answer:

1 M C6H1206s

1 M NaNO3

1 M Ca(NO3)2

1 M Li3PO4

Explanation:

Hope it helps!

The order of solutions from lowest freezing point to highest freezing point of the given compounds are Li₃PO₄ < Ca(NO₃)₂ < NaNO₃ < C₆H₁₂O₆.

How we calculate the depression in freezing point?

Depression in freezing point will be calculated from the following reaction as:

ΔTf = i × Kf × m, where

ΔTf = change in freezing point

i = Vant Hoff factor

Kf = freezing constant

m = concentration in terms of molality

In the question concentration of compounds are given in molarity and for all compounds it is same, so the depression in freezing point will directly depends on the Vant Hoff factors of given compounds.

Vant Hoff factor for NaNO₃ is 2.Vant Hoff factor for Li₃PO₄ is 4.Vant Hoff factor for Ca(NO₃)₂ is 3.Vant Hoff factor for C₆H₁₂O₆(s) is 1.

From the above data it is clear that Li₃PO₄ will have the lowest freezing point and C₆H₁₂O₆ will have the highest and sequence from lowest to highest will be shown as:
Li₃PO₄ < Ca(NO₃)₂ < NaNO₃ < C₆H₁₂O₆.

Hence the required order is Li₃PO₄ < Ca(NO₃)₂ < NaNO₃ < C₆H₁₂O₆.

To know more about Vant Hoff factor, visit the below link:
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What volume in milliliters of 0.100 M HCIO3 is required to neutralize
40.0 mL of 0.165 M KOH?

Answers

Answer:

66.0 mL HClO3

Explanation:

M1V1 = M2V2

M1 = 0.100 M HClO3

V1 = ?

M2 = 0.165 M KOH

V2 = 40.0 mL KOH

Solve for V1 --> V1 = M2V2/M1

V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3

A gas has a volume of 13.4 L at 17°C. What is the volume of the gas at standard temperature?

Answers

Answer:

V=12.6148888506L

Explanation:

using charles law Volume1/Temperature1 = Volume2/Temperature2

13.4L/(17C+273.15C)=V/273.15K

remember gas equations require kelvin not celcius so converting celcius to kelvin is Celcius + 273.15 which is standard temperature conditions

A student mixes 50.0 mL of 1.00 M Ba(OH)2 with 72.8 mL of 0.375 M H2SO4.
a)Calculate the mass of BaSO4 formed.
b)Calculate the pH of the mixed solution.

Answers

Answer:

The correct answer should be 12.72 pH of the mixed solution and 9.94g mass of solid BASO4 formed.

The molecules of Ba(OH)2 are : 1.00M x 0.05L = 0.05 ( moles )

The molecules of H2SO4 are : 0.494M x 0.0864L = 0.0426816

Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O

0.0426816<--- 0.0426816

The mixed solution is Ba(OH)2 with 0.05 - 0.0426816 = 0.0073184

The concentration of mixed solution is : 0.0073184 : ( 0.05 + 0.0864 ) = 0.054 M

The pH of mixed solution is 14 - -log[0.054] = 14 - 1.27 = 12.73 PH

And the mass of BaSO4 is 0.0426816 x ( 137 + 32 + 16 x 4 ) = 9.94 gams.

When is energy released during a chemical reaction?
A. when chemical bonds break and form
B. when chemical bonds form
C. when chemical bonds break

“Don’t click links if answers have one!”

Answers

C. When chemical break and form

which of the following are the correct formulas for potassium oxide and calcium oxide respectively

Answers

Explanation:

potassium oxide is K2O

calcium oxide is CaO

calcium oxide is used to make glass

potassium oxide is used in fertilizer

What is the chemical formula for Manganese (IV) biphosphate?
Group of answer choices

Mn(HPO4)2

Mn2(HPO4)4

Mn4(HPO4)2

Mg2(HPO4)4

No correct response

Answers

I believe its the first one because manganese is mn and IV is 4 but the cross thing thing will making it the second one but then you have to simplify making it the first one i hope that helps:)

How many moles of carbon dioxide gas occupy a volume of
81.3 L at 204 kPa and a temperature of 95.0 °C?
mol CO2

Answers

Answer:

5.42

Explanation:

I used a calculator

Answer: 5.42 mol CO2

Explanation: Uses idea gas law

Identify the following for an atom with 8 protons, 8 electrons, and 7 neutrons.
a. Atomic number:
b. Mass number:
c. Nuclear Notation:
d. Hyphen Notation:

please help

Answers

Answer:

i thinks its a. but iam not sure

From the choices provided below, list the reagent(s) in order that will react with 3-pentanone to form 3-pentanol.

a. H2/Pt
b. H2SO4, Δ
c. OsO4, H2O
d. CH2MgBr
e. H3O+
f. PhMgBr
g. H3O+
h. H3O+
i. RCO3H
j. KOH

Answers

Answer:

NaBH4

H3O+

Explanation:

The conversion of 3-pentanone to form 3-pentanol is a reduction reaction. The first step of the reaction is the transfer of a hydride ion to the carbonyl from the reducing agent sodium borohydride.

After the transfer of the hydride ion, transfer of a proton from H3O+ completes the reaction mechanism hence 3-pentanol is formed from 3-pentanone.

can boron bond with lithium

Answers

Answer:

No, they are not able to bond.

Explanation:

Hello there!

In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.

Best regards!

The question is on the picture

Answers

The answer would be D because n2 h2 nh3 added up make less blue

Nitrogen reacts with Hydrogen to form Ammonia gas by Haber's Process.

N₂ + 3H₂ → 2NH₃

What is Law of conservation of Mass?

This law states that Mass can neither be created, nor destroyed and it can just be transformed from one form to another. This law has application as balancing of the reaction.

Balancing of a reaction is done according to the "Law of conservation of mass" and balancing helps in solving stoichiometry questions correctly as if we will not balance the reaction then the quantitative results in a particular question doesn't come correctly.

Balancing of a reaction helps in mole concept as well and it is one of the laws of chemical reactions as well.

Some examples of balanced chemical reaction are-

2Mg(s) + O₂(g) ⟶ 2MgO(g)

According to the given picture,

Correct option is C. It consists 1 molecule of Nitrogen gas, 3 moles of Hydrogen gas and 2 moles of Ammonia gas.

Therefore, Nitrogen reacts with Hydrogen to form Ammonia gas by Haber's Process.

Learn more about Haber's Process, here:

https://brainly.com/question/30928282

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Directions: Read each sentence carefully. Write the letter of the
correct answer on the answer sheet provided.
1. What is produced when two surfaces rub against each other?
A. air
B. pressure
C. motion
D. friction
2. Which surface increases friction?
A. polished B. rough
C. lubricated
D. shiny
3. What causes falling objects to fall?
A. speed
B. gravity
C. acceleration
D. wind
4. Which surface decreases friction?
A. smooth B. rugged
C. rough
D. rocky
5. Why do you move faster when running down a hill?
A. Gravity pulls you up.
C. Gravity pulls you down.
B. Wind pushes you back.
D. Wind pulls you.​

Answers

Answer:

1 - D) friction

2- B) rough

3- B) gravity

4- A)smooth

5- C)gravity pulls you down


A roller coaster is travelling without friction as
shown in the diagram. If the speed of the roller
coaster at A is 3.0 m/s, what is the speed at B?

Answers

Answer:

Thus, the speed at B = 13 m/s

Explanation:

From the attached image:

Using the conservation of energy;

Iinital M.E = Final M.E

where;

M.E = mechanical energy

[tex]\dfrac{1}{2} \times m \times v_A^2+ mgh_A = \dfrac{1}{2} \times m \times v_B^2+ mgh_B[/tex]

[tex]\dfrac{1}{2} \times m \times 3^2+m \times 9.8 \times 15 = \dfrac{1}{2} \times m \times v_B^2+ m\times 9.8 \times 7 \\ \\ \dfrac{1}{2} \times 3^2 + 9.8 \times 15 = \dfrac{1}{2} \times v^2 + 9.8 \times 7 \\ \\ \implies 151.5 = 0.5 v^2 + 68.6 \\ \\ 0.5v^2 = 151.5 - 68.6 \\ \\ 0.5 v^2 = 82.9 \\ \\ v^2 = \dfrac{82.9}{0.5} \\ \\ v^2 = 165.8 \\ \\ v = \sqrt{165.8} \\ \\ v = 12.9 \ m/s\\ \\ \mathbf{v \simeq 13 \ m/s}[/tex]

Which cross section below best shows the locations of high air pressure and low air pressure near a beach on a hot, sunny, summer afternoon?

Answers

Locations of high air pressure is the beach whereas the location of low air pressure is in the sea on a hot, sunny, summer afternoon.

Where is low and high air pressure exists?

Areas where the air is warmed have lower pressure because the warm air rises in the air. These areas are known as low pressure systems. Places where the air pressure is high, are called high pressure systems. These are places where air is cold.

So we can conclude that Locations of high air pressure is the beach whereas the location of low air pressure is in the sea on a hot, sunny, summer afternoon.

Learn more about pressure here: https://brainly.com/question/25736513

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A scuba tank has a volume of 10.3 L and a pressure of 19,300 kPa. If the gas is transferred to a 50.0 L container, what is it's new pressure?

Answers

Hi there!

Here's a screenshot of the problem being solved.

What is the net ionic equation for the reaction between Na2SO4 and CaCl2?
A. 2Na+(aq) + 2Cl-(aq) 2NaCl(aq)
B. Na2SO4(aq) + CaCl2(aq) CaSO4(s) + 2NaCl(aq)
C. SO42-(aq) + Ca2+(aq) CaSO4(s)
D. 2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+ + 2Cl-(aq)

Answers

The net ionic equation for the reaction between Na₂SO₄ and CaCl₂ is:

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

(Option C)

Dissociation equation

In solution, Na₂SO₄ and CaCl₂ will dissociate as follow

Na₂SO₄(aq) —> 2Na⁺(aq) + SO₄²¯(aq)

CaCl₂(aq) —> Ca²⁺(aq) + 2Cl¯(aq)

How to write the net ionic equation

Na₂SO₄(aq) + CaCl₂(aq) —>

2Na⁺(aq) + SO₄²¯(aq) + Ca²⁺(aq) + 2Cl¯(aq) —> CaSO₄(s) + 2Na⁺(aq) + 2Cl¯(aq)

Cancel out the spectator ions (i.e Na⁺ + Cl¯) to obtain the net ionic equation

SO₄²¯(aq) + Ca²⁺(aq) —> CaSO₄(s)

Learn more about chemical equation:

https://brainly.com/question/7181548

What is the pH of a 0.00530 M solution of HCI?

Answers

Answer:

2.28

Explanation:

HCl(l) ===> H+ + cl-

HCl is a very strong acid. Almost all of it will decompose to the right. That means the concentration of H+ is 0.00530

pH = - log [H+]

pH = - log[0.00530]

pH = - - 2.2757

pH = 2.2757

Rounded this 2.28

c) A student titrated 50.0mL of a 0.10M solution of a certain weak acid with NaOH(aq) . The results are given in the graph above. (i) What is the approximate pKa of the acid?

Answers

Answer:

3.2

Explanation:

The missing graph is attached in the image below:

Initially, p.H from the graph is approximately 2.1

Therefore; the hydrogen ion concentration is

[tex][H^+] = 10^{-2.1}[/tex]

[tex][H^+] = ({k_a \times 0.10})^{\dfrac{1}{2}}[/tex]

[tex]{k_a} = 6.3 \times 10^{ -4}[/tex]

pKa = [tex]-log ( 6.3 \times 10^{-4})[/tex]

pKa = 3.2

Which of these are found in eukaryotic cells?
1. nucleoid
2. vacuole
3. mitochondria
4. Golgi apparatus
O A. 1, 3, 4
O B. 1, 2,4
O C. 2, 3, 4
O D. 1, 2, 3

Answers

Answer:

C

Explanation:

nucleoid is prokaryotic

Answer:

mitochondria is found in eukaryotic cells.

How many moles are in 3.86 x 1023 molecules of Carbon Dioxide (CO2)?

Answers

Answer:

0.64 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} [/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

[tex]n = \frac{3.86 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.86}{6.02} \\ = 0.641196...[/tex]

We have the final answer as

0.64 moles

Hope this helps you

How many grams are in 3.4 moles of C2H5OH molecules? (use molar mass and round answer to the correct number of sig figs)

Answers

molar mads of C2H5OH:
12*2+1*5+16+1
24+5+17
46
no of moles = mass in grams/molar mass
3.4=m/46
3.4*46=m
m=156.4
m=156g
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