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The specific heat of mercury is 0.138 J/g Celsius. If 452 g of mercury at 85.0 Celsius are placed in 145 g of water at 23.0 Celsius, what will be the final temperature for both the mercury and the water?

Answers

Answer 1

Answer: Thus the final temperature for both the mercury and the water is [tex]28.8^0C[/tex]

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]heat_{released}=heat_{absorbed}[/tex]

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)][/tex]

Q = heat absorbed or released

[tex]m_1[/tex] = mass of mercury= 452 g

[tex]m_2[/tex]= mass of water = 145 g

[tex]T_{final}[/tex]  = final temperature = ?

[tex]T_1[/tex]   = temperature of mercury = [tex]85.0^0C[/tex]

[tex]T_2[/tex] = temperature of water = [tex]23.0^0C[/tex]

[tex]c_1[/tex]   = specific heat of mercury  = [tex]0.138J/g^0C[/tex]

[tex]c_2[/tex]   = specific heat of water= [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]-[452\times 0.138\times (T_f-85.0)^0C]=145\times 4.184\times (T_f-23.0)^0C[/tex]

[tex]T_f=28.8^0C[/tex]

Thus the final temperature for both the mercury and the water is [tex]28.8^0C[/tex]


Related Questions



Suppose that you place an object along the principal axis of a concave spherical mirror, exactly halfway to the center of the curvature (half of the radius). What will the result be?

Answers

Answer:

There will be no clear image of the object.

Explanation:

For a concave spherical mirror, we have the distance from center of curvature to the mirror is the radius of curvature, R, and half of the length of the radius of curvature is the focal length, f, of the mirror, that is we have;

[tex]f = \dfrac{R}{2}[/tex]

From the equation of a mirror in optics we have;

[tex]\dfrac{1}{f} = \dfrac{1}{d_o} + \dfrac{1}{d_i}[/tex]

Where:

[tex]d_o[/tex] = Distance of the object from the mirror

[tex]d_i[/tex] = Distance of the image from the mirror

Hence, where the object distance is half the radius of curvature or f, we have;

[tex]\dfrac{1}{f} = \dfrac{1}{f} + \dfrac{1}{d_i}[/tex]

Therefore, the location of the image formed will be at;

[tex]\dfrac{1}{d_i}= \dfrac{1}{f} - \dfrac{1}{f} = 0[/tex]

[tex]d_i = \dfrac{1}{0}= \infty[/tex]

Hence, since the location of the image formed will be at infinity there will be no clear image of the object.

Answer:

A clear image of that object won't be formed at all.

Explanation:

PF The point exactly halfway to the center of curvature of a concave spherical mirror is called the center of curvature. The point exactly halfway from the mirror to the center is called the focal point (or focus) of the mirror. When the object is exactly at the focus of the mirror, the reflecting rays are parallel and therefore won't meet to form an image.

An iceberg has a volume of 0.1642 ML. What is the mass of the ice(in kg) composing the iceberg( at 0o C)? The density of ice at 0o C is 0.917g/cm^3

Answers

Answer:

1.5x10¯⁴Kg

Explanation:

Data obtained from the question include the following:

Volume = 0.1642mL = 0.1642cm³

Density = 0.917g/cm³

Mass =.?

The Density of a substance is simply defined as the mass per unit volume of the substance. Mathematically, it is represented as:

Density = Mass /volume

With the above formula, we can calculate the mass of the ice as follow:

0.917 = Mass / 0.1642

Cross multiply

Mass = 0.917 x 0.1642

Mass = 0.151g

Finally, we shall convert 0.1506g to kg. This is illustrated below:

1000g = 1k

Therefore, 0.151g = 0.151/1000 = 1.5x10¯⁴Kg

354.5 g of chlorine gas (MW = 70.9 g/mol) is held in a vessel with a fixed volume of 70. L.


What is the pressure of the gas in atmospheres if it's temperature is 30.0°C?


___ atm

Answers

Answer:

1.77 atm

Explanation:

We have to check the values that gives the problem:

V= 70 L

mass =354.5 g

Molas weight= 70.9 g/mol

T=30 ºC

P= ?

We can find the moles of chlorine if we use the molar weight:

[tex]354.5g~\frac{1~mol}{70.9~g}[/tex]

[tex]5~mol[/tex]

Now, we have the moles, volume, temperature therefore we can use the ideal gas equation:

[tex]P*V=n*R*T[/tex]

We know the R value:

[tex]0.082\frac{atm*L}{mol*K}[/tex]

We have “K” units for the temperature, so we need to do the conversion:

[tex]30+273.15=303.15~K[/tex]

With all the data we can plug the values into the equation:

[tex]P*70L=5mol*303.15K*0.082\frac{atm*L}{mol*K} [/tex]

[tex]P=\frac{5mol*303.15K*0.082\frac{atm*L}{mol*K}}{70L}[/tex]

[tex]P=1.77~atm [/tex]

I hope it helps!

Calculate the molar mass of a vapor that has a density of 7.125 g/L at 13 ∘C and 741 torr .

Answers

Answer:

Molar Mass = 171.6 g/mol

Explanation:

Here we can use the equation PV = nRT, where n could stand for m / M, considering M = Molar Mass. Now we can rearrange this equation to isolate M, as we have to determine the " molar mass " of this vapor,

PV = ( m / M )RT,

density = mass / volume = PM / RT -

M = dRT / P

First convert celcius to kelvins and torr to " standard atmosphere " before plugging in the known values,

13 C = 286 K,

741 torr = 0.975 atm -

__________________________________________

M = (7.125)(0.0821) (286) / 0.975

M = 171.6 g /mol

Please balance the following equation: NH4NO3 ---> N2 + O2 + H2O
Please show your work, I keep getting it wrong and I don't know what I'm doing wrong.

Answers

Answer:

2NH4NO3->2N2+O2+4H2O

Explanation:

U have to ensure that they are equal both side s hope it helps

Suppose of nickel(II) chloride is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the nickel(II) chloride is dissolved in it.

Answers

Answer: Molarity of chloride anion = 0.32 M

Note: the question is missing some values. The full question is given below;

Suppose 7.26 g of nickel(II) chloride is dissolved in 350 mL of a 0.50 M aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the nickel(II) chloride is dissolved in it. Be sure your answer has the correct number of significant digits.

Explanation:

Molarity or molar concentration is the number of moles (mol) of component per volume (liters) concentration of solution in mol/L or M

The mass of nickel (II) chloride is 7.26 g.

The volume of potassium carbonate is 350 mL = 0.35 L

The molarity of potassium carbonate solution is 0.50 M

The reaction of nickel (II) chloride and potassium carbonate is given below.

NiCl₂(aq) + KCO₃(aq) --------> KCl(aq) +NiCO₃(s)

The dissociation of nickel (II) chloride is given below.

NiCl₂   -----> Ni²⁺ + 2Cl⁻

The molar mass of nickel (II) chloride is  129.6 g/mol

The moles of nickel (II) chloride can be calculated by the formula given below;

No of moles  = mass(g) / molar mass (g/mol)

No of moles = 7.26 / 129.6 = 0.056 moles

Therefore, molarity of NiCl₂ = 0.056 moles/ 0.35 L = 0.16 M

The molarity of 1 mole nickel (ii) chloride is 0.16 m and according to dissociation of nickel (II) chloride, 1 mole of nickel (II) chloride gives 2 moles of chloride anion.

Therefore, the molarity of chloride anion = 0.16 * 2 = 0.32 M

The temperature of your water was 22.4 degrees Celsius. The volume of hydrogen collected was 37.1 mL. The atmospheric pressure in the lab room was 29.18 inches Hg. The difference in the water level between the beaker and the burette is 18.4 cm. What was the mass of the magnesium ribbon used?

Answers

Answer:

The correct answer is 27.22 mg.

Explanation:

Based on the given information, the temperature of the water given is 22.4 degree C or 22.4 + 273 = 295.4 K

The volume of the gathered hydrogen is 37.1 ml or 0.0371 L

The pressure mentioned in the lab room is 29.18 in Hg or 29.18 × 2.54 = 74.1172 cm Hg.

18.4 cm is the difference given in the water level between the burette and the beaker, so the pressure is,

74.1172 cm - 18.4 cm = 55.7172 cm Hg or 557.172 mmHg

760 mmHg is equal to 1 atm, therefore, 557.172 mmHg will be equal to,

557.172 mm Hg / 760 mm Hg × 1 atm = 0.733 atm

The moles of hydrogen gas can be calculated by using the ideal gas equation, that is, PV = nRT

n = PV / RT

Putting the values we get,

n = 0.733 atm × 0.0371 L / 0.0821 atm L mol⁻¹ K⁻¹ × 295.4 K

n = 0.00112 mol

Let us consider the equation,

2 HCl + Mg ⇒ H₂ + MgCl₂

By seeing the reaction it is clear that for the generation of 1 mole of hydrogen gas, 1 mole of magnesium is needed.

The moles of magnesium is 0.00112 moles and the molecular mass of magnesium is 24.305 gram per mol

The mass of magnesium ribbon can be determined by using the formula, mass = mole × molecular mass

mass = 0.00112 mole × 24.305 g/mol

mass = 0.02722 grams or 27.22 mg.

The catalyst used in the industrial production of ammonia: Select the correct answer below: A. enables equilibrium to be reached more quickly B. increases the equilibrium constant C. shifts the equilibrium of the reaction to favor the products D. none of the above

Answers

Answer: A. enables equilibrium to be reached more quickly..

Explanation:

The catalyst can be define as an important ingredient may be a protein in the form of enzyme that is used to speed up the rate of the chemical reaction. The catalyst cause a transformational change in the substrate to produce product. The catalyst do not get consumed in the reaction. In the availability of the catalyst, the forward and reverse rates of the reactions will speed up this will allow the equilibrium to reach faster.

Why does a skunk have very few predators

Answers

Answer:

because of their chemical defenses. (more info below)

Explanation:

Skunks have relatively few natural predators of their species. This is a testament to the effectiveness of their chemical defenses. Unfortunately, several skunks are killed when they cross busy roads at night. Deterrence is also not effective against a predator with a poor sense of smell like a Great Horned Owl.

hope I helped!

What formula would I use if I was given [OH-] and wanted to find POH?*
1 point
pH = -log[H+]
[H+]= 10^-pH
pOH = -log [OH-]
O [OH-] = 10^-POH

Answers

Answer:

pOH = -log[OH-]

Explanation:

Hello,

To calculate the pH or pOH of a substance, we relate it the negative logarithm of either the H+ or OH- concentration.

pOH is used to find the alkalinity of a solution my measuring the concentration of the hydroxide ion [OH-]. Solutions having a pOH value that is greater than 7 are said to be acidic while solutions with value less than 7 are alkaline.

pH = -log[H+]

While

pOH = -log[OH-]

Note: the pOH value of a solution depends on the concentration of the hydroxide ion in the solution.

17. Consider the reaction shown and identify the statement that is not true.
825°C
CaCO3(s)
+ CaO(s) + CO2(g)
a.
This reaction is balanced as written.
b. The reactant must be heated for this reaction to occur.
c. The products are a solid and a gas.
d. Water must be present for this reaction to occur.
There are no solutions used in this reaction.
e.

Answers

Answer: Water must be present for this reaction to occur.

Explanation:

Decomposition reactions require breaking of bonds which require energy and thus all of the decomposition reactions are endothermic reactions.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) whereas liquids are represented by (l) and gases are represented by (g) after their chemical formulas.

The balanced chemical reaction of [tex]CaCO_3[/tex] decomposition is:

[tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex]

The decomposition of [tex]CaCO_3[/tex] requires heat and leads to formation of CaO as solid and [tex]CO_2[/tex] as product.

Thus the the statement that is not true is Water must be present for this reaction to occur.

2. Convert 6.578 x 1023 atoms of magnesium to moles.
6.578 x 1023 atoms x
mol
atoms

Answers

Answer:

1.092 moles of Mg

Explanation:

Avogadro's number is a constant that define the number of particles (Such as atoms, molecules, electrons, ions) that you have in 1 mole. That means in 1 mole you have 6.022x10²³ of the particle in question.

If you have 6.578x10²³ atoms of Mg -and 1 mole of Mg contains 6.022x10²³ atoms of Mg-:

6.578x10²³ atoms of Mg × (1 mole Mg / 6.022x10²³ atoms of Mg) =

1.092 moles of Mg

How many moles are in 87.62 grams of strontium?

Answers

Explanation:

it's one mole because the atomic mass is treated as molar mass and the atomic mass of strontium is 87.62 grams/mol

A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 coulombs, what was the oxidation state of the manganese produced

Answers

Answer:

Oxidation state of Mn = +4

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = [tex]\frac{mass}{charge}[/tex]

i.e Z = [tex]\frac{m}{Q}[/tex] = [tex]\frac{0.225g}{1580C}[/tex] = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ [tex]\frac{55}{valency}[/tex] = 0.0001424 × 96,485

∴ Valency of Mn = +4

John Adams was the first US president to

Answers

Answer:

To live in the White House

Explanation:

While George Washington was in office, the white house was still in the stages of being built. Hence John Adams was the first president to reside and live in the White house.

Answer:

It's B to live in the white house.

Explanation:

1. An electric iron has a
power rating of 750W
a. How many joules of
electric energy does it
change into heat energy
every second?
b. How many joules of
work can it do in 3
seconds
c. How long does it take
the iron to do 1500J of
work?
2. Use the kinetic particle
theory to explain why a
solid has a definite shape
and liquid has none.​

Answers

Explanation:

a) E = P × t

E = 750 × 1 s = 750 J

b) E = P × t

E = 750 × 3s = 2250 J

c) E = P × t

1500 = 750 × t

t = 1500/750

t = 2 s

In the reaction A + B → C, the initial concentration of A is 0.054 M. After 1.5 minutes, [A] = 0.032 M. Calculate the rate of the reaction in M/sec.

Answers

Answer:

2.4 × 10⁻⁴ M/s

Explanation:

Step 1: Given data

Initial concentration of A ([A]₀): 0.054 MConcentration of A after a certain time ([A]): 0.032 MTime (t): 1.5 min

Step 2: Convert the time to seconds

We will use the relationship 1 min = 60 s.

[tex]1.5min \times \frac{60s}{1min} =90s[/tex]

Step 3: Calculate the rate of the reaction

Since A is a reactant, we will calculate the rate of the reaction (r) using the following expression.

[tex]r=-\frac{\Delta [A]}{t} =-\frac{[A]-[A]_0}{t} =-\frac{0.032M-0.054M}{90s} =2.4 \times 10^{-4} M/s[/tex]

8.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 176./gmol, is burned completely in excess oxygen, and the mass of the products carefully measured:

Product mass
Carbon dioxide 12.75g
Water 3.48g

Use this information to find the molecular formula of X.

Answers

Answer:

Molecular formula = [tex]C_{3} H_{4} O_{8}[/tex]

Explanation:

CO2 -

12.75g / 44g/mol = 0.29

H2O -

3.48g/18g/mol = 0.19

(dividing through by the smallest mole)

Ratio of CO2 to H2O = 1.5 : 1

[tex][(CO_{2} )_{1.5} + (H_{2} O)_{1}]x[/tex] = 176

[12 × 1.5 + 16×2×1.5 + 1×2 + 16)x = 176

(18 + 48 + 2 + 16)x = 176

x = 176/84 = 2

Molecular formula = [tex]C_{3} H_{4} O_{8}[/tex]

Check: Molar mass of C3H4O8 = 176g/mol.

A 8.05 grams of a certain compound is known as to be made by the carbon and hydrogen have more mass of 176./g mol.

The compound X is carbon, hydrogen, and Oxygen which has a molecular M that is burned down, and measured as water and carbon.They are burned completely and exceeds oxygen and mass is produced and measured.Molecular formula =  CO2-  12.75g / 44g/mol = 0.29H2O - 3.48g/18g/mol = 0.19.

Learn more about Compound X, known to be made of carbon.

brainly.com/question/20984525.

Is a forward or reverse reaction favored?
Review the reversible reactions given, along with the associated equilibrium constant Kat room temperature. In each case, determine whether the forward or reverse reaction is favored. CH3COOH – CH3C00++ H+ Choose... Ka=1.8 x 10-5 Choose... AgCl → Agt + Cl Ksp=1.6 x 10-10 Al(OH)3 + A13+ + 30H Choose... Ksp=3.7 x 10-15 A+BAC Choose... K=4.9 x 103

Answers

Answer:

(a) [tex]CH_3COOH \rightleftharpoons CH_3COO^-+ H^+[/tex]: reverse reaction is favored.

(b) [tex]AgCl \rightleftharpoons Ag^+ + Cl^-[/tex]: reverse reaction is favored.

(c) [tex]Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-[/tex]: reverse reaction is favored.

(d) [tex]A+B\rightleftharpoons C[/tex]: forward reaction is favored.

Explanation:

Hello,

(a) [tex]CH_3COOH \rightleftharpoons CH_3COO^-+ H^+[/tex]:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (acetic acid) will tend to have a higher concentration.

(b) [tex]AgCl \rightleftharpoons Ag^+ + Cl^-[/tex]:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (silver chloride) will tend to have a higher concentration.

(c) [tex]Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-[/tex]

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (aluminium hydroxide) will tend to have a higher concentration.

(d) [tex]A+B\rightleftharpoons C[/tex]

In this case, since the Ka is greater than 1, we infer the forward reaction is favored since the product (C) will tend to have a higher concentration.

Regards.

The number of nitrogen atoms in one mole of nitrogen gas are...

Answers

Explanation:

The number of nitrogen atoms in one mole of nitrogen gas are 6.02214179×1023 nitrogen atoms.

Hope this helps...

what forms of technology are scientists using to study El Nino

Answers

Answer:

a network of buoys.

Explanation:

It is operated by noaa. The buoys transmit some of the data on a daily basis to NOAA through a satellite in space.

Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing carbon dioxide gas and water vapor. Calculate the moles of acetylene needed to produce of carbon dioxide. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.

Answers

Answer:

2.25 moles ≈ 2.3 moles

Explanation:

Full Question:

Acetylene C2H2 gas is often used in welding torches because of the very high heat produced when it reacts with oxygen O2 gas, producing carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.5mol of water. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.

First off, let's put the equation of the reaction sown;

C2H2 + O2 → H2O + CO2

Upon balancing, we have;

2C2H2 + 3O2 → 2H2O + 4CO2

So from the equation;

3 mole of oxygen is required in order to produce 2 mole of water vapour.

The question asks to calculate moles of oxygen needed to produce 1.5mol of water

This leads us to;

3 moles = 2 moles

x moles = 1.5 moles

x = ( 1.5 * 3 ) / 2

x = 4.5 / 2 = 2.25 moles ≈ 2.3 moles

Determine the boiling point of a solution that contains 70.6 g of naphthalene (C10H8, molar mass = 128.16 g/mol) dissolved in 722 mL of benzene (d = 0.877 g/mL). Pure benzene has a boiling point of 80.1°C and a boiling point elevation constant of 2.53°C/m.

Answers

Answer:

Boiling point of the solution is 82.3°C

Explanation:

Boiling point elevation is defined as the increasing of a boiling point of a substance by the addition of a solute. The formula is:

ΔT = K×m×i

Where ΔT is change in temperature (Final T - 80.1°C), K is boiling point elevation constant (2.53°C/m), m is molality of the solution (moles of naphthalene / kg of benzene) and i is Van't Hoff factor (1 for Naphthalene)

Moles of 70.6g of naphthalene are:

70.6g × (1mol / 128.16g) = 0.5509 moles

Kg of 722mL of benzene are:

722mL × (0.877g / mL) × (1kg / 1000g) = 0.633kg of benzene

Replacing in boiling point elevation formula:

(T - 80.1°C) = 2.53°C/m×(0.5509mol / 0.633kg)×1

T - 80.1°C = 2.2°C

T = 80.1°C + 2.2°C

T = 82.3°C

Boiling point of the solution is 82.3°C

The boiling point of the solution is 82.21°C.

Number of moles of solute = 70.6 g/128.16 g/mol = 0.55 moles

Mass of solvent= density of solvent× volume of solvent

= 722 mL × 0.877 g/mL = 633.2 g or 0.6332 Kg

Molality of the solution = 0.55 moles/0.6332 Kg = 0.869 m

We know that;

ΔT = K m i

ΔT = Boiling point depression

K = Boiling point constant

m = molality of solution

i = Van't Hoff factor

ΔT =  2.53°C/m × 0.869 m × 1

ΔT = 2.2°C

Recall that;

ΔT = Boiling point of solution-  Boiling point of pure solvent

Boiling point of solution = Boiling point of pure solvent + ΔT

Boiling point of solution =  80.1°C + 2.2°C

Boiling point of solution = 82.21°C

Learn more: https://brainly.com/question/2510654

The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue, a teal, and a red line. Calculate the energy of one photon of this light.

Answers

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

[tex]E=h\upsilon =\frac{hc}{\lambda}[/tex]

On putting the estimated values, we get

⇒          [tex]=\frac{1241.5 \ ev\ nm}{486 \ nm}[/tex]

⇒          [tex]=2.554 \ ev[/tex]

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, [tex]E=2.554\times 1.6\times 10^{-19}[/tex]

⇒               [tex]=4.08\times 10^{-19} Joule[/tex]

Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced equations.

__Al+ __HCl→ __AlCl3+ __H2


__NaCl → __Na + __Cl2


__Na2S+__HCl→__NaCl+ __H2S


Please help!!

Answers

Answer: See below

Explanation:

To balance equations, you want to have the same amount of elements on the product and reactants side.

__Al+ __HCl→__AlCl₃+ __H₂

We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.

__Al+ 6HCl→__AlCl₃+ __H₂

Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.

__Al+ 6HCl→ 2AlCl₃+ 3H₂

All we have left is to fill in Al.

2Al+ 6HCl→ 2AlCl₃+ 3H₂

-----------------------------------------------------------------------------------------------------------------

__NaCl→ __Na+ __Cl₂

Since we have 2 Cl on the products, we must put 2 on the reactants.

2NaCl→ __Na+ 1Cl₂

With 2 NaCl, we can fill in Na.

2NaCl→ 2Na+ 1Cl₂

-----------------------------------------------------------------------------------------------------------------

__Na₂S+ __HCl→ __NaCl+ __H₂S

We see 2 Na on reactants, so we can put 2 on the products.

__Na₂S+ __HCl→ 2NaCl+ __H₂S

With 2 H and 2 Cl on the products, we can put a 2 at HCl.

1Na₂S+ 2HCl→ 2NaCl+ 1H₂S

The reaction that takes place in a hydrogen-oxygen fuel cell is


2H2(g)+O2(g)⟶2?


Select the major product of the reaction and determine whether the reaction is exothermic or endothermic.



H2O2 , endothermic


H2O2 , exothermic


H2O , endothermic


H2O , exothermic

Answers

Answer:

H20; exothermic

Explanation:

A fuel cell is a device that converts chemical potential energy (energy stored in molecular bonds) into electrical energy. A PEM (Proton Exchange Membrane) cell uses hydrogen gas (H2) and oxygen gas (O2) as fuel. The products of the reaction in the cell are water, electricity, and heat.

Consider the following reaction where Kc = 77.5 at 600 K: CO(g) + Cl2(g) COCl2(g) A reaction mixture was found to contain 4.24×10-2 moles of CO(g), 4.48×10-2 moles of Cl2(g) and 0.114 moles of COCl2(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: T 1. In order to reach equilibrium COCl2(g) must be produced. T 2. In order to reach equilibrium Kc must decrease. T 3. In order to reach equilibrium CO must be produced. F 4. Qc is greater than Kc. F 5. The reaction is at equilibrium. No further reaction will occur.

Answers

Answer:

The reaction mentioned in the question is:  

CO (g) + Cl₂ (g) ⇔ COCl₂ (g), the equilibrium constant or Kc will be 77.5 at 600 K. In the given mixture, the moles of CO given is 4.24 × 10⁻² moles, the moles of Cl₂ given is 4.48 × 10⁻² moles, and the moles of COCl₂ given is 0.114 moles. The volume of the container is 1.00 L.  

The concentration or Molarity can be determined by using the formula, concentration (M) = mole/volume (L),  

The molarity of CO = 4.24 × 10⁻² moles / 1.00 L = 4.24 × 10⁻² M

The molarity of Cl₂ = 4.48 × 10⁻² moles / 1.00 L = 4.48 10⁻² M

The molarity of COCl₂ = 0.114 moles / 1.00 L = 0.114 M

The reaction quotient or Qc,  

Qc = [COCl2]/[CO][Cl2]  

Qc = 0.114 / 4.24 × 10⁻² × 4.48 × 10⁻²

Qc = 60.03

Thus, Qc is less than Kc. Hence, the reaction will proceed in forward direction so that equilibrium can be attained, that is, until Qc becomes equal to Kc.  

Therefore, the product (COCl₂) will be produced, and the reactants CO and Cl₂ will get consumed.  

1. The given statement is true.  

2. The given statement is true.  

3. The given statement is false. In order to reach equilibrium, the reactants must be consumed.  

4. The given statement is true.  

5. The given statement is false, that is Qc is not equal to Kc.  

explain to me why a rotting banana is a chemical change??

Answers

The chemical change in a rotting banana is the chemicals breaking down the flesh of the banana. The chemicals come from the air and get in the banana

What is an oxidation state?

Answers

Answer:

Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state

The total enthalpy of the products in a reaction is 0 kJ, and the total enthalpy of the reactants is 100 kJ. What is the ΔH for the reaction? Choose the correct answer. –393.5 kJ –100 kJ 0 kJ +100 kJ

Answers

Answer: -100 kJ

Explanation:

Heat of reaction or enthalpy of the reaction is the energy released or absorbed during the course of the reaction.

Heat of reaction is represented by the symbol [tex]\Delta H[/tex].

[tex]\Delta H=H_{products}-H_{reactants}[/tex]

[tex]\Delta H[/tex] = enthalpy of reaction = ?

[tex]H_{products}[/tex] = enthalpy of products = 0 kJ

[tex]H_{reactants}[/tex] = enthalpy of reactants = 100 kJ

[tex]\Delta H=0kJ-100kJ[/tex]

[tex]\Delta H=-100kJ[/tex]

Thus the ΔH for the reaction is -100kJ

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